Compiling a program in a loop with qsub - bash

Question

I want to compile a program in a bash for loop. When I run the program from the command line it will compile but when I use qsub it doesn't compile.
Is there something I am missing?
Regards,
John
Bash File
#!/bin/bash
#$ -N runTest
#$ -m e
#$ -r y
cd /afs/crc.nd.edu/user/private/NDPICMCC/SAFECODE
thisDir="SAFECODE"
t=2000
originalGUILine="pres = 7.6E1"
oldGUILine="$originalGUILine"
GUIfile="GUIVars.f90"
for (( i = -3 ; i <= 1 ; i=i+1 ))
do
p="7.6E$i"
newGUILine="pres = $p"
sed -i "s/$oldGUILine/$newGUILine/g" "$GUIfile"
oldGUILine="$newGUILine"
make clean >& /dev/null
make 1D >& /dev/null
make 1D
./PressurePIC
cp "Anode_ele_eng.csv" "../results/T_${t}_P_${p}_Energies.csv"
done
sed -i "s/$oldGUILine/$originalGUILine/g" "$GUIfile"
makefile
CC=ifort
OPTIONS = -warn noalign -autodouble
PRNG = luxury.f90
MAIN = NDPIC1D.v0.f90 GUIVars.f90 GlobalVars.f90 StatisticalDistribution.f90 Emission.f90
TODO = ParticleInCell.f90 MonteCarloCollision.f90 Transformations.f90
EXE = PressurePIC
all:
#$(CC) $(PRNG) $(MAIN) $(TODO) -o $(EXE) $(OPTIONS)
1D:
#$(CC) $(PRNG) $(MAIN) $(TODO) -o $(EXE) $(OPTIONS)
2D:
#$(CC) $(PRNG) $(MAIN) $(TODO) -o $(EXE) $(OPTIONS)
clean:
#rm *.mod $(EXE)
run:
#./$(EXE)
info:
#echo $(EXE)

Answer 1

I'm not sure what flavour of qsub you are using so this may not help ...
Try including
#$ -V
at the start of your script. On some systems which process qsub it ensures that environment variables are exported from your environment to the environment in which the script eventually runs. These environments are not, generally, the same.