Can I expand macro JUST ONE TIME in specific target? - makefile

A = "demo"
%.o:%.cpp
$(CC) -c $^ $(A) -o $#
default:$(all_objs)
game:A = $(shell read -p 'Enter game version: ' gv && echo $$gv)
game:$(all_objs)
Just a snippet makefile above. If I make game, main problem is each compilation of sources will expand $(A) and it will request user to input game version over and over. $(A) has default content "demo" only if user doesn't make game target.
So, is there any way to set $(A) to be expanded && ?

game:A:=$(shell read -p 'Enter game version: ' gv && echo $$gv)
Notice ':='
Update:
Reading user input in real build targets is not a good idea. Make is widely used and whoever invokes it - they wouldn't expect this.
I see two ways to do what you wanted:
make version=some_version. It will override version variable (name may be almost anything). If you have assigned its default value in makefile - it will be changed to some_version (unless variable declared with override flag, which disables this behaviour)
Create make config rule, which would perform required configuration actions and save them into, say, config.mk. In makefile you could have -include config.mk ('-' sign says make that this file may be missing. If it is required (e.g. contains some mandatory configuration options), remove minus sign).

Related

Makefile passing additional arguments to targets command from make command

I have a Makefile that defines docker-compose project.
It essentially assembles me a command:
COMMAND := docker-compose --project-name=$(PREFIX) --file=$(FILE_PATH)
up:
$(COMMAND) up -d
I would like to add a target named dc to which I would be able to pass any arguments I want.
I know there is one solution:
target:
$(COMMAND) $(ARGS)
And then call it with make target ARGS="--help" for example.
But isn't there an easier way like in bash $# ? I would like to skip the ARGS=... part and send everything to the command after target name.
Not really. The make program interprets all arguments (that don't contain =) as target names to be built and there's no way you can override that. So even though you can obtain the list of arguments given on the command line (via the GNU make-specific $(MAKECMDGOALS) variable) you can't prevent those arguments from being considered targets.
You could do something like this, which is incredibly hacky:
KNOWN_TARGETS = target
ARGS := $(filter-out $(KNOWN_TARGETS),$(MAKECMDGOALS))
.DEFAULT: ;: do nothing
.SUFFIXES:
target:
$(COMMAND) $(ARGS)
(untested). The problem here is you have to keep KNOWN_TARGETS up to date with all the "real" targets so you can remove them from the list of targets given on the command line. Then add the .DEFAULT target which will be run for any target make doesn't know how to build, which does nothing. Reset the .SUFFIXES meta-target to remove built-in rules.
I suspect this still will have weird edge-cases where it doesn't work.
Also note you can't just add options like --help to the make command line, because make will interpret them itself. You'll have to prefix them with -- to force make to ignore them:
make target -- --help
Another option would be to add a target like this:
target%:
$(COMMAND) $*
Then you can run this:
make "target --help"
But you have to include the quotes.
In general I just recommend you reconsider what you want to do.
You could write a bash wrapper script to do what you'd like:
#/bin/bash
make target ARGS=\"$#\"
The reason you don't want to do it in make, is that make parses the command line parameters before it parse the makefile itself, so by the time you read the makefile, the targets, variables, etc have already been set. This means that make will have already interpreted the extra parameters as new targets, variables etc.
A target that re-run make containerized
.PHONY: all containerized
ifeq ($(filter containerized,$(MAKECMDGOALS)),containerized)
.NOTPARALLEL: containerized
MAKEOVERRIDES ?=
containerized: ## Build inside a container
#docker run image_with_make make $(MAKEOVERRIDES) $(filter-out containerized,$(MAKECMDGOALS))
else
# other targets here
all: xxxx
endif
Executing
make containerized all runs make all in container
The first answer is correct, no passthru of args. However, here is a plausible path for experimentation, use of branch by include selection:
# Makefile:
COMMAND := $(PYTHON) this_shit_got_real.py
LOCAL_MK ?= local.mk
# '-' important, absence of LOCAL_MK is not cause for error, just run with no overrides
- include $(LOCAL_MK)
target:
$(COMMAND) $(ARGS)
Now see how you add branching with env:
echo "ARGS=--help">>local.mk
# make target
And the other cli controlled branch
echo "ARGS=--doit">>runner.mk
# LOCAL_MK=runner.mk make target

GNU make - transform every prerequisite into target (implicitly)

I have another make-like tool that produces an XML as an artifact after parsing my makefile which I'll then further process with Python.
It'd simplify things for me - a lot - if I could have make consider every single prerequisite to be an actual target because then this other tool
will classify each and every file as a "job".
This is a fragment of my makefile:
.obj/eventlookupmodel.o: C:/Users/User1/Desktop/A/PROJ/src/AL2HMIBridge/LookupModels/eventlookupmodel.cpp C:\Users\User1\Desktop\A\PROJ\src\AL2HMIBridge\LookupModels\eventlookupmodel.h \
C:/Users/User1/Desktop/A/PROJ/qt5binaries/include/QtCore/qabstractitemmodel.h \
C:/Users/User1/Desktop/A/PROJ/qt5binaries/include/QtCore/qvariant.h \
...
I'd want for make to think I have a dummy rule for each prerequisite such as below:
C:/Users/User1/Desktop/A/PROJ/qt5binaries/include/QtCore/qvariant.h:
#echo target pre= $#
C:/Users/User1/Desktop/A/PROJ/qt5binaries/include/QtCore/qabstractitemmodel.h:
#echo target pre=$#
C:/Users/User1/Desktop/A/PROJ/src/AL2HMIBridge/LookupModels/eventlookupmodel.cpp :
#echo target pre=$#
C:\Users\User1\Desktop\A\PROJ\src\AL2HMIBridge\LookupModels\eventlookupmodel.h:
#echo target pre=$#
I don't care about the exact form of the rule just that each file is considered an actual target.
My method of passing in this rule would be by setting the MAKEFILES variable like so
make all MAKEFILES=Dummy.mk
with Dummy.mk containing this rule so that I do not modify the makefiles.
I've tried the following so far.
Dummy.mk:
%.h:
#echo header xyz = $#
%:
#echo other xyz= $#
This partially works.
I run make all --trace --print-data-base MAKEFILES=Dummy.mk and I can see that
make does "bind" the %.h: rule to the header files. In the --print-data-base section, I see that rule being assigned to the header files.
C:/Users/User1/Desktop/A/QNX_SDK/target/qnx6/usr/include/stddef.h:
# Implicit rule search has been done.
# Implicit/static pattern stem: 'C:/Users/User1/Desktop/A/QNX_SDK/target/qnx6/usr/include/stddef'
# Last modified 2016-05-27 12:39:16
# File has been updated.
# Successfully updated.
# recipe to execute (from '#$(QMAKE) top_builddir=C:/Users/User1/Desktop/A/HMI_FORGF/src/../lib/armle-v7/release/ top_srcdir=C:/Users/User1/Desktop/A/HMI_FORGF/ -Wall CONFIG+=release CONFIG+=qnx_build_release_with_symbols CONFIG+=rtc_build -o Makefile C:/Users/User1/Desktop/A/HMI_FORGF/src/HmiLogging/HmiLogging.pro
', line 2):
#echo header xyz = $#
However, I do NOT see the "echo header xyz $#"-rule being executed.
Regarding the %: rule, it is neither executed for the .cpp files nor "bound" to them in the --print-data-base section.
However, it is bound and executed for existing targets which have no suffix i.e.
all: library binary
binary: | library
ifs: | library
For the %: rule, the reason for this behavior is because of 10.5.5 Match-Anything Pattern Rules: If you do not mark the match-anything rule as terminal, then it is non-terminal. A non-terminal match-anything rule cannot apply to a file name that indicates a specific type of data. A file name indicates a specific type of data if some non-match-anything implicit rule target matches it.
If I make it non-terminal - no double colon - then the rule doesn't apply to built-in types like .cppunless I un-define the built-in rules that negate my intended %: rule.
If I make it terminal, "it does not apply unless its prerequisites actually exist". But a .h or .cpp doesn't technically have prerequisites; can I just create a dummy file and have that as its prerequisite?
NOTE: This has NOTHING to do with gcc -M generation. Yes the -M option would help in the specific case of header and source files but this question is for more generic targets and prerequisites that already exist in the makefile when make is launched.
This may take a few iterations. Try:
%.h: null
#echo header xyz = $#
%: null
#echo other xyz= $#
null:
#:
Try generating static pattern rules for the header files. See one of the answers to Make ignoring Prerequisite that doesn't exist.
Static pattern rules only apply to an explicit list of target files like this:
$(OBJECTS): %.o: %.c
*recipe here*
where the variable OBJECTS is defined earlier in the makefile to be a list of target files (separated by spaces), for example:
OBJECTS := src/fileA.c src/fileB.c src/fileC.c
Note that you can use the various make utility functions to build that list of target files. For example, $(wildcard pattern), $(addsuffix), etc.
You should also ensure that the recipe "touches" the header file to change the timestamp.
I've found that using static pattern rules instead of pattern rules fixes problems where make doesn’t build prerequisites that don’t exist, or deletes files that you want.
Here is an example of using wildcard to copy files from one directory to another.
# Copy images to build/images
img_files := $(wildcard src/images/*.png src/images/*.gif src/images/*.jpg \
src/images/*.mp3)
build_images := $(subst src/,$(BUILD_DIR)/,$(img_files))
$(build_images): $(BUILD_DIR)/images/% : src/images/%
mkdir -p $(dir $#)
cp -v -a $< $#
There are other make functions like addprefix that could be used to generate a more complex file specification.

OpenCobol Makefile

I am trying to compile an OpenCobol program using make. I am always getting "make: Nothing to be done for test1.cob". Here is my makefile. I had put a TAB before cobc. But still I am getting that message. Please help.
Thanks.
COBCWARN = -W
%: %.cob
cobc $(COBCWARN) -free -x $^ -o $#
And here is my cobol program.
IDENTIFICATION DIVISION.
PROGRAM-ID. TEST1.
PROCEDURE DIVISION.
DISPLAY 'Hello world!'.
STOP RUN.
Your makefile contains no actual targets. You have defined only a pattern rule which tells make how to build targets that match the pattern. But make doesn't go looking for targets out on the filesystem that could match the pattern, it only checks the pattern against targets that have been specifically requested.
You don't have any specific targets (files) listed in your makefile, so the only way make can know about a target is if you give the target to be built on the command line.
You are running this command from within vim, using the % special token, which expands to the name of the file currently being edited. That means you are running the command:
make test1.cob
because you are editing the file test1.cob. So, you are telling make "please try to create the target (file) test1.cob". But, that file already exists (it's the file you're writing). So make says "nothing to do".
If you run make and ask it to create the target you really want created, it will work:
make test1
Now the file test1 doesn't exist, and make can find a pattern rule that knows how to build it, so make will run that rule.
Alternatively, you can edit your makefile to add the specific target, like this:
COBCWARN = -W
test1: test1.cob
%: %.cob
cobc $(COBCWARN) -free -x $^ -o $#
Then you can run make with no arguments at all. Without any command line arguments, make will look in the makefile for explicit targets and find test1 as the first one. It sees that there is a rule (the pattern rule) that matches that target, so it will build that target.
UPDATE
If you want to allow a simple command make to build multiple programs, write your makefile like this:
COBCWARN = -W
all: test1 test2 test3
.PHONY: all
%: %.cob
cobc $(COBCWARN) -free -x $^ -o $#
Now from vim you can just say :!make and that's it.
If you run make with no arguments then it will find the first explicit target in the makefile and build that. In this example the first target is all, and its prerequisites are the possible programs to build. To build each one make sees that it can apply the pattern rule, and so it will do so (if the .cob file has been modified since the last time the program was built).

Variable for '%' in multiple files matching

I would like to make a complete text document from several sources (since one of the file source change, I want the doc to change).
I have to pass it through a translator I develop. I would like to pass the language as argument, to make it cleaner.
Yesterday, late at night, I dreamed of a makefile like this...
#makefile
# ...
my_complete_doc.%.html: my_trans_exe header.%.html $(wildcard source/*.%.html)
$< --language $(variable_for_%) > $#
(?) Does it replace % by all the languages which have their own header.language.html files. And does the file my_completed_doc.language.html get changed as soon as one of the source/*.language.html get changed?
(?) How to get the % replaced in several prerequisites, possibly into the wildcard and necessarily in the recipe?
First, the easy problem: you wish to use the '%' variable in the recipe. The answer is to use the '$*' automatic variable:
my_complete_doc.%.html: my_trans_exe ...
$< --language $* > $#
Then the easy question: yes, the header.%.html prerequisite is correct. When you try to build my_complete_doc.dutch.html then Make will evaluate it as header.dutch.html, when you try to build my_complete_doc.french.html, Make will evaluate it as header.french.html.
Now the tricky problem: the prerequisite $(wildcard source/*.%.html). Ordinarily, Make expands $(wildcard ...) statements before executing any rule, or deciding which targets to build. So it searches for any files such as source/foo.%.html or source/bar.%.html (that is, files whose names contain the character '%'), finds none, and evaluates the statement as an empty string. But Make will defer this evaluation until it has chosen the rule, if you use SECONDEXPANSION:
.SECONDEXPANSION:
my_complete_doc.%.html: my_trans_exe header.%.html $$(wildcard source/*.%.html)
$< --language $* > $#
(Note the '$$'. In the first -- ordinary -- expansion, Make reduces "$$(...)" to "$(...)", and in the second -- when '%' has a value -- it expands "$(...)".) Now if you modify any file such as source/foo.german.html, Make will consider the file my_complete_doc.german.html out of date and in need of rebuilding.

Passing additional variables from command line to make

Can I pass variables to a GNU Makefile as command line arguments? In other words, I want to pass some arguments which will eventually become variables in the Makefile.
You have several options to set up variables from outside your makefile:
From environment - each environment variable is transformed into a makefile variable with the same name and value.
You may also want to set -e option (aka --environments-override) on, and your environment variables will override assignments made into makefile (unless these assignments themselves use the override directive . However, it's not recommended, and it's much better and flexible to use ?= assignment (the conditional variable assignment operator, it only has an effect if the variable is not yet defined):
FOO?=default_value_if_not_set_in_environment
Note that certain variables are not inherited from environment:
MAKE is gotten from name of the script
SHELL is either set within a makefile, or defaults to /bin/sh (rationale: commands are specified within the makefile, and they're shell-specific).
From command line - make can take variable assignments as part of his command line, mingled with targets:
make target FOO=bar
But then all assignments to FOO variable within the makefile will be ignored unless you use the override directive in assignment. (The effect is the same as with -e option for environment variables).
Exporting from the parent Make - if you call Make from a Makefile, you usually shouldn't explicitly write variable assignments like this:
# Don't do this!
target:
$(MAKE) -C target CC=$(CC) CFLAGS=$(CFLAGS)
Instead, better solution might be to export these variables. Exporting a variable makes it into the environment of every shell invocation, and Make calls from these commands pick these environment variable as specified above.
# Do like this
CFLAGS=-g
export CFLAGS
target:
$(MAKE) -C target
You can also export all variables by using export without arguments.
The simplest way is:
make foo=bar target
Then in your makefile you can refer to $(foo). Note that this won't propagate to sub-makes automatically.
If you are using sub-makes, see this article: Communicating Variables to a Sub-make
Say you have a makefile like this:
action:
echo argument is $(argument)
You would then call it make action argument=something
From the manual:
Variables in make can come from the environment in which make is run. Every environment variable that make sees when it starts up is transformed into a make variable with the same name and value. However, an explicit assignment in the makefile, or with a command argument, overrides the environment.
So you can do (from bash):
FOOBAR=1 make
resulting in a variable FOOBAR in your Makefile.
It seems command args overwrite environment variable.
Makefile:
send:
echo $(MESSAGE1) $(MESSAGE2)
Example run:
$ MESSAGE1=YES MESSAGE2=NG make send MESSAGE2=OK
echo YES OK
YES OK
There's another option not cited here which is included in the GNU Make book by Stallman and McGrath (see http://www.chemie.fu-berlin.de/chemnet/use/info/make/make_7.html). It provides the example:
archive.a: ...
ifneq (,$(findstring t,$(MAKEFLAGS)))
+touch archive.a
+ranlib -t archive.a
else
ranlib archive.a
endif
It involves verifying if a given parameter appears in MAKEFLAGS. For example .. suppose that you're studying about threads in c++11 and you've divided your study across multiple files (class01, ... , classNM) and you want to: compile then all and run individually or compile one at a time and run it if a flag is specified (-r, for instance). So, you could come up with the following Makefile:
CXX=clang++-3.5
CXXFLAGS = -Wall -Werror -std=c++11
LDLIBS = -lpthread
SOURCES = class01 class02 class03
%: %.cxx
$(CXX) $(CXXFLAGS) -o $#.out $^ $(LDLIBS)
ifneq (,$(findstring r, $(MAKEFLAGS)))
./$#.out
endif
all: $(SOURCES)
.PHONY: clean
clean:
find . -name "*.out" -delete
Having that, you'd:
build and run a file w/ make -r class02;
build all w/ make or make all;
build and run all w/ make -r (suppose that all of them contain some certain kind of assert stuff and you just want to test them all)
If you make a file called Makefile and add a variable like this $(unittest)
then you will be able to use this variable inside the Makefile even with wildcards
example :
make unittest=*
I use BOOST_TEST and by giving a wildcard to parameter --run_test=$(unittest)
then I will be able to use regular expression to filter out the test I want my Makefile
to run
export ROOT_DIR=<path/value>
Then use the variable, $(ROOT_DIR) in the Makefile.

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