I have a list of files like so :
10_I_am_here_001.jpg
20_I_am_here_003.jpg
30_I_am_here_008.jpg
40_I_am_here_004.jpg
50_I_am_here_009.jpg
60_I_am_here_002.jpg
70_I_am_here_005.jpg
80_I_am_here_006.jpg
How can I rename all the files in a directory, so that I can drop ^[0-9]+_ from the filename ?
Thank you
Using pure BASH:
s='10_I_am_here_001.jpg'
echo "${s#[0-9]*_}"
I_am_here_001.jpg
You can then write a simple for loop in that directory like this:
for s in *; do
f="${s#[0-9]*_}" && mv "$s" "$f"
done
Using rename :
rename 's/^[0-9]+_//' *
Here's another bash idea based on files ending .jpg as shown above or whatever>
VonBell
#!/bin/bash
ls *.jpg |\
while read FileName
do
NewName="`echo $FileName | cut -f2- -d "_"`"
mv $FileName $NewName
done
With bash extended globbing
shopt -s extglob
for f in *
do
[[ $f == +([0-9])_*.jpg ]] && mv "$f" "${f#+([0-9])_}"
done
Related
How does one rename
random_files.jpg
that\ may\ contain\ spaces.jpg
and_differ_in_extensions.mp4
to
PREFIX_1.jpg
PREFIX_2.jpg
PREFIX_3.mp4
via bash script? More formally, how do I rename all files in a directory into an ordered list of form PREFIX_N.ext where .ext is preserved from the original filename.
My attempt below
for f in *; do
[[ -f "$f" ]] && mv "$f" "PREFIX_$f"
done
changes only prefixes.
You can use this in a for loop using find:
while IFS= read -rd '' file; do
ext="${file##*.}"
echo mv "$file" "PREFIX_$((++i)).$ext"
done < <(find . -type f -name '*.*' -maxdepth 1 -print0)
Once satisfied with the output, remove echo before mv command.
You can loop over the files using *, and then access them with a quoted var to preserve all the special characters.
You can then use parameter expansion to remove the start of the file up to ., and append that to your new filename.
x=1;for i in *;do [[ -f "$i" ]] && mv "$i" "PREFIX_$((x++)).${i##*.}";done
If you know x isn't already set though you can remove the assignment at the start and change $((x++)) to $((++x))
Iam trying a shell script which will rename all the files in the current directory whose name contains upper-case characters into all lower case. For example, if the directory contains a file whose name is CoUnt.c, it should be renamed to count.c.
for f in *;
do
if [ -f "$f" ]; then
tr 'A-Z' 'a-z'
fi
done
but it is not working.
is there is any better solution for this?
You are not passing any data into the tr program, and you are not capturing any output either.
If you are using sh:
for f in *[A-Z]*
do
if [ -f "$f" ]; then
new_name=$(echo "$f"|tr 'A-Z' 'a-z')
mv "$f" "$new_name"
fi
done
Note the indentation - it makes code easier to read.
If you are using bash there is no need to use an external program like tr, you can use bash expansion:
for f in *[A-Z]*
do
if [[ -f $f ]]; then
new_name=${f,,*}
mv "$f" "$new_name"
fi
done
The problem is tr accepts values from stdin. So in order to translate upper to lower in each filename, you could do something like:
#!/bin/sh
for f in *
do
[ -f "$f" ] || continue
flc=$(echo "$f" | tr 'A-Z' 'a-z') ## form lower-case name
[ "$f" != "$flc" ] && echo mv "$f" "$flc"
done
(note: remove the echo before mv to actually move the files after you are satisfied with the operation)
Since I am unable to add comment posting here,
Used sed and it works for me
#!/bin/bash
for i in *
do
if [ -f $i ]
then
kar=$(echo "$i" | sed 's/.*/ \L&/')
mv "$i" "$kar"
done
The following code works fine.
for f in *
do
if [ -f $f ]; then
echo "$f" | tr 'A-Z' 'a-z' >/dev/null
fi
done
I would recommend rename because it is simple, efficient and also will check for clashes when two different files resolve to the same result:
You can use it with a Perl regex:
rename 'y/A-Z/a-z/' *
Documentation and examples available here.
I have a file input.txt that looks as follows.
abas_1.txt
abas_2.txt
abas_3.txt
1fgh.txt
3ghl_1.txt
3ghl_2.txt
I have a folder ff. The filenames of this folder are abas.txt, 1fgh.txt, 3ghl.txt. Based on the input file, I would like to create and rename the multiple copies in ff folder.
For example in the input file, abas has three copies. In the ff folder, I need to create the three copies of abas.txt and rename it as abas_1.txt, abas_2.txt, abas_3.txt. No need to copy and rename 1fgh.txt in ff folder.
Your valuable suggestions would be appreciated.
You can try something like this (to be run from within your folder ff):
#!/bin/bash
while IFS= read -r fn; do
[[ $fn =~ ^(.+)_[[:digit:]]+\.([^\.]+)$ ]] || continue
fn_orig=${BASH_REMATCH[1]}.${BASH_REMATCH[2]}
echo cp -nv -- "$fn_orig" "$fn"
done < input.txt
Remove the echo if you're happy with it.
If you don't want to run from within the folder ff, just replace the line
echo cp -nv -- "$fn_orig" "$fn"
with
echo cp -nv -- "ff/$fn_orig" "ff/$fn"
The -n option to cp so as to not overwrite existing files, and the -v option to be verbose. The -- tells cp that there are no more options beyond this point, so that it will not be confused if one of the files starts with a hyphen.
using for and grep :
#!/bin/bash
for i in $(ls)
do
x=$(echo $i | sed 's/^\(.*\)\..*/\1/')"_"
for j in $(grep $x in)
do
cp -n $i $j
done
done
Try this one
#!/bin/bash
while read newFileName;do
#split the string by _ delimiter
arr=(${newFileName//_/ })
extension="${newFileName##*.}"
fileToCopy="${arr[0]}.$extension"
#check for empty : '1fgh.txt' case
if [ -n "${arr[1]}" ]; then
#check if file exists
if [ -f $fileToCopy ];then
echo "copying $fileToCopy -> $newFileName"
cp "$fileToCopy" "$newFileName"
#else
# echo "File $fileToCopy does not exist, so it can't be copied"
fi
fi
done
You can call your script like this:
cat input.txt | ./script.sh
If you could change the format of input.txt, I suggest you adjust it in order to make your task easier. If not, here is my solution:
#!/bin/bash
SRC_DIR=/path/to/ff
INPUT=/path/to/input.txt
BACKUP_DIR=/path/to/backup
for cand in `ls $SRC_DIR`; do
grep "^${cand%.*}_" $INPUT | while read new
do
cp -fv $SRC_DIR/$cand $BACKUP_DIR/$new
done
done
I'm trying to recursively iterate over all my .html files in a directory and convert them to .jade using a bash script.
#!/bin/bash
for f in ./*.html ./**/*.html ; do
cat $f | html2jade -d > $f + '.jade';
done;
Naturally the $f + '.html' bit isn't correct. How might I fix this?
#!/bin/bash
shopt -s globstar
for f in **/*.html; do
html2jade -d < "$f" > "${f%.html}.jade"
done
Concatenation is the default for most cases.
... > "$f.jade"
Also:
html2jade ... < "$f"
And:
... > "${f%.html}.jade"
I got this
for file in *; do
any command
done
What I want to do is add an exception to the "for file in *; do".
Any ideas?
If you wanted to skip files with a particular extension, for example, ".pl", you could do:
for file in *
do
[ "${file##*.}" != "pl" ] && echo $file
done
One way to do what I think you are asking is to loop through and check a file name with a if statement (or just grep -v the ls cmd):
for file in `ls`; do
if [ "$file" == "something" ]; then
# do something
else
# something else
fi
done
For example, you have files
$ ls -1 ./
./M2U0001.MPG
./M2U0180.MPG
./text
Exception file is M2U0180.MPG
$> filename="M2U0180.MPG"
And
$> for file in $(ls -1 ./* | grep --invert-match "${filename}" ); do echo $file; done
./M2U0001.MPG
./text
Weird solution done :)
use bash's extended globbing
shopt -s extglob
for f in !(excluded-file); do echo "$f"; done
A simple solution :
The following code snippet will print all the files in the pwd , that have a .py extension
for i in * ;do
if [[ $i == *.py ]];then
echo "$i"
fi
done