Kendo Grid columns Hide/Show, Enable/Disable - kendo-ui

How to hide/show and Enable/Disable columns in kendo grid on condition or event.
I could only find option of enable/disable kendogrid column in .model
Any help is appreciated.
Thank you in advance!

You showing/hiding columns in KendoUI Grid you should use showColumn and hideColumnand use as argument a number (the index of the column that you want to show/hide) or a string (the name of the field associated in that column).
Example:
var grid = $("#grid").kendoGrid({
dataSource: ds,
editable : false,
pageable : true,
columns :
[
{ field: "FirstName", width: 90, title: "First Name" },
{ field: "LastName", width: 90, title: "Last Name" },
{ field: "City", width: 100 }
]
}).data("kendoGrid");
$("#show_col1").on("click", function() {
// Use the index of the column to show
grid.showColumn(0);
});
$("#hide_col1").on("click", function() {
// Use the name of the field to hide it
grid.hideColumn("FirstName");
});
You can control if the column should be initially hidden by setting hidden in the column initialization.
See an example here : http://jsfiddle.net/OnaBai/XNcmt

The Kendo grid contains a showColumn method that will take either an index or the column name string. To enable hiding/displaying columns, you'll initialize the grid columnX as a normal column, and mark it hidden (in MVC this is the .Hidden() method when binding the column). Then based on a page event, you can simply call showColumn (and then hideColumn to reverse the operation).

For Kendo Grid that has already been created, you can show/hide make all columns editable/uneditable by:
var allowEdit = false;
var grid = $("#sampleGrid").data("kendoGrid");
grid.showColumn(0);
grid.showColumn(1);
if (!allowEdit) {
grid.hideColumn(0);
grid.hideColumn(1);
}
var len = $("#sampleGrid").find("tbody tr").length;
for (var i = 0; i <= len ; i++) {
var model = $("#sampleGrid").data("kendoGrid").dataSource.at(i);
if (model) {
for (i = 0; i <= (grid.columns.length - 1) ; i++) {
var column = grid.columns[i];
model.fields[column.field].editable = allowEdit;
}
}
}

Related

Kendo UI Grid - Excel Export with hidden columns and custom formatting

I'm attempting to use the Grid component's built-in support for exporting to excel, applying custom cell formatting as shown in these Telerik docs:
http://docs.telerik.com/kendo-ui/controls/data-management/grid/how-to/excel/cell-format
The approach using hard-coded row / cell indexes in the export comes with a rather obvious issue when exporting a grid with a prior hidden column displayed - best way to reproduce is to refer to this jsfiddle:
https://jsfiddle.net/3anqpnqt/1/
Run fiddle
Click export to excel - observe custom number formatting
Unhide subcategory column (using column menu)
Click export to excel - observe custom number formatting on column 2 which is now 'subcategory'
With reference to this code in the fiddle:
$("#grid").kendoGrid({
toolbar: ["excel"],
excel: {
fileName: "Grid.xlsx",
filterable: true
},
columns: [
{ field: "productName" },
{ field: "category" },
{ field: "subcategory", hidden: true },
{ field: "unitPrice"}
],
dataSource: [
{ productName: "Tea", category: "Beverages", subcategory: "Bev1", unitPrice: 1.5 },
{ productName: "Coffee", category: "Beverages", subcategory: "Bev2", unitPrice: 5.332 },
{ productName: "Ham", category: "Food", subcategory: "Food1", unitPrice: -2.3455 },
{ productName: "Bread", category: "Food", subcategory: "Food2", unitPrice: 6 }
],
columnMenu: true,
excelExport: function(e) {
var sheet = e.workbook.sheets[0];
for (var rowIndex = 0; rowIndex < sheet.rows.length; rowIndex++) {
var row = sheet.rows[rowIndex];
var numericFormat = "#,##0.00;[Red](#,##0.00);-";
for (var cellIndex = 0; cellIndex < row.cells.length; cellIndex++) {
var cell = row.cells[cellIndex];
if (row.type === "data") {
if (cellIndex == 2) { // how are we able to identify the column without using indexes?
cell.format = numericFormat;
cell.hAlign = "right";
}
}
}
}
}
});
What I need to be able to do is identify the cell as the 'unitPrice' and apply the format, but inspection of the object model within the excelExport handler doesn't give me any way to make this link. In my real application, I have several custom formats to apply (percentages, n0, n2 etc) so it's not as simple as going $.isNumeric(cell.value) or otherwise.
Update
I also need the solution to work with column / row groups, which generate additional header rows / columns in the Excel model.
It looks like row[0] is the header row, so you could try changing
if (cellIndex == 2) {
to
if (sheet.rows[0].cells[cellIndex].value == "unitPrice") {
EDIT:
Seems to work with column group: https://jsfiddle.net/dwosrs0x/
Update:
The object model for worksheet is not the most clear. The first row does seem to be a "master" header row in the various scenarios that I looked at. Here is something that seems to work if unitPrice is not in a grouping. If unitPrice is in a grouping, then something more complicated involving the group header (row[1]) might be possible. The puzzle is to find out what position the desired column will eventually occupy.
var header = sheet.rows[0];
var upIndex = -1;
var upFound = false;
for (var cellIndex = 0; cellIndex < header.cells.length; cellIndex++) {
if ('colSpan' in header.cells[cellIndex])
upIndex = upIndex + header.cells[cellIndex].colSpan;
else
upIndex = upIndex + 1;
if (header.cells[cellIndex].value == "unitPrice") { // wot we want
upFound = true;
break;
}
}
for (var rowIndex = 0; rowIndex < sheet.rows.length; rowIndex++) {
var row = sheet.rows[rowIndex];
if (row.type === "data" && upFound) {
var cell = row.cells[upIndex];
cell.format = numericFormat;
cell.hAlign = "right";
}
}
fiddle with groups - https://jsfiddle.net/dwosrs0x/4/
fiddle with straightforward grid (to prove it still works) - https://jsfiddle.net/gde4nr0y/1/
This definitely has the whiff of "bodge" about it.

Summing a calculated unbound column in KendoUI Grid MVC

I have a KendoUI Grid where I need to display a sum of several of the columns in the footer.
As the Items column is bound this seems to be working perfectly.
I also have a Total Net £s for Items column which is calculated but I cannot get the aggregate function to work. Is it possible to sum a calculated column?
columns.Bound(m => m.Items).Format("{0:n2}")
.HtmlAttributes(new { #class = "items" }).Title("Units")
.ClientFooterTemplate("#= kendo.format('{0:n2}', sum) #");
columns.Template(p => { })
.ClientTemplate("#= kendo.toString((Items * 12) * NetPoundsPerItem, 'n2') #")
.Title("Total Net £s for Items")
.FooterTemplate("#= kendo.tostring(sum, \"n2\") #");
because this is a unbound column you will need to keep track of your numbers manually and then put your sum in your aggregate column. Use a footer template
columns: [
{ field: "Cost", width: 120 }, footertemplate: "<div id='total'> Total : $0.00 </div> },
{ field: "Quanity", title: "Quanity", width: 40}]
Use javascript to calculate the sum and then use jquery to set it.
//get the correct grid Kendo Grid
var grid = $("#grid").data("kendoGrid");
//get the data
var data = grid.dataSource.view();
var FinalTotal = 0;
// now iterate through each cell
data.forEach(function (entry) {
FinalTotal += entry["Quanitiy"] * entry["Price"];
}
// set the aggregate template div
$('#total').text("Total: " + kendo.toString(FinalTotal, 'C'));

Kendo grid resizable column width

The grid columns may be resizable. I want to store user-adjusted columns width and restore them when the next session starts.
The best way to store columns width I've found is the following:
var element = $('#grid').kendoGrid({
...
resizable: true,
columnResize: function(e) {
var state = {};
this.columns.every(function(c,i) {
state[c.field] = c.width;
return true;
});
var state_txt = JSON.stringify(state);
localStorage['profile_userprofile_grid_column_width'] = state_txt;
}
}
Now I want to restore column width saved in the previous user session. I can read columns width from the storage:
var state = JSON.parse(localStorage['profile_userprofile_grid_column_width']);
Does somebody know some elegant way to apply these values back to the grid if it is already created at this time? The resize handle does it internally, so it is possible, but the code doing it in the grid source is ugly.
You can trigger the columnResize event post initilisation as shown below
function grid_columnResize(e) {
// Put your code in here
console.log(e.column.field, e.newWidth, e.oldWidth);
}
$("#grid").kendoGrid({
columns: [
{ field: "name" },
{ field: "age" }
],
dataSource: [
{ name: "Jane Doe", age: 30 },
{ name: "John Doe", age: 33 }
],
resizable: true
});
var grid = $("#grid").data("kendoGrid");
grid.bind("columnResize", grid_columnResize);
Documentation
This is an old question, but here is what we have. Function handles column widths and groups.
var _updateResultsGridColumns = function(columns, groups) {
var kendoGrid = $resultsGrid.data("kendoGrid");
if (kendoGrid) {
kendoGrid.setOptions({
columns: columns,
});
var dataSource = kendoGrid.dataSource;
dataSource.group(groups);
kendoGrid.setDataSource(dataSource);
}
}

Highlight the sorted column

I'm firing the databound event but I'm not sure what do do from there.
The links here lead to generic docs:
http://www.kendoui.com/forums/ui/grid/highlight-sorted-column.aspx
Does anyone have a simple example of highlighting the current sorted column?
The idea is as follows:
Handle the dataBound event of the grid.
Get the current sort expression of the data source using its sort method.
Find the grid column which is bound to the sorted field. Iterate over the grid columns field.
Highlight the table cells which correspond to the column index. Use the tbody field of the grid.
Here is a sample implementation:
<div id="grid"></div>
<script>
$("#grid").kendoGrid({
dataSource: [
{ name: "Jane Doe", age: 30 },
{ name: "Jane Doe", age: 33 }
],
sortable: true,
dataBound: function() {
var columns = this.columns;
var sort = this.dataSource.sort()[0];
var sortedIndex = -1;
if (sort) {
for (var i = 0; i < columns.length; i++) {
if (columns[i].field == sort.field) {
sortedIndex = i;
break;
}
}
}
if (sortedIndex >= 0) {
this.tbody
.find("tr")
.find("td:eq(" + sortedIndex + ")")
.css( { background: "#a0b0c0" } );
}
}
});
</script>
And a live demo: http://jsbin.com/ixahid/1/edit

jqgrid: several questions - matrix display

I have data of matrix stored in table as below tables:
MatrixDimensions - MatrixId, NoOfRows, NoOfCol
MatrixValues - MatrixId, RowNo, ColNo, Value
How can I make jqGrid to take no. of rows & columns dynamically
and also display the serialized data in matrix? Is there a direct way or will I have to implement for loops to upload the data in matrix?
Can I display rows as columns and columns as rows (so having column headers vertically aligned)?
Can I enable only inline editing and disable form based editing?
I just wrote the answer to another question where I described how to create the grid with dynamic number of columns (number of rows is always dynamic in jqGrid). It seems to me this way you can display any matrix. In you case you can probably make the code simpler because you can use generic column names like "1", "2", etc. (or "Col. 1", "Col. 2", etc.) and so on.
I modified the code so that it uses array of arrays (matrix) instead of the array on objects with named properties. So jqGrid will looks like this:
or this:
depending on the input JSON data.
The full demo can be found here. The full JavaScript code of the demo you can find below:
var mygrid=jQuery("#list"),
cmTxtTemplate = {
width:40,
align:"center",
sortable:false,
hidden:true
}, currentTemplate = cmTxtTemplate, i,
cm = [], maxCol = 30, dummyColumnNamePrefix = "", //"Col. ",
clearShrinkToFit = function() {
// save the original value of shrinkToFit
var orgShrinkToFit = mygrid.jqGrid('getGridParam','shrinkToFit');
// set shrinkToFit:false to prevent shrinking
// the grid columns after its showing or hiding
mygrid.jqGrid('setGridParam',{shrinkToFit:false});
return orgShrinkToFit;
},
setGridWidthAndRestoreShrinkToFit = function(orgShrinkToFit,width) {
// restore the original value of shrinkToFit
mygrid.jqGrid('setGridParam',{shrinkToFit:orgShrinkToFit});
mygrid.jqGrid('setGridWidth',width);
},
dummyTestRegex = new RegExp(dummyColumnNamePrefix+"(\\d)+"),
counter = 1;
// Add dummy hidden columns. All the columns has the same template
for (i=0;i<maxCol;i++) {
cm.push({name:dummyColumnNamePrefix+(i+1),template:currentTemplate});
}
mygrid.jqGrid({
url:'Matrix1.json',
datatype: "json",
// colNames will be set based on the properties for JSON input
colModel:cm,
height:"auto",
rownumbers:true,
loadonce:true,
gridview: true,
rowNum: 1000,
sortname:"",
jsonReader: {
cell: "",
id: function (obj) {
return "id"+counter++;
},
page: function (obj) {
var rows = obj.rows, colModel = mygrid[0].p.colModel,
cmi, width = 0, iFirstDummy, cols, orgShrinkToFit,
showColNames = [], hideColNames = [];
if (typeof(rows) === "undefined" || !(rows.length>0)) {
// something wrong need return
return obj.page;
}
// find the index of the first dummy column
// in the colModel. If we use rownumbers:true,
// multiselect:true or subGrid:true additional
// columns will be inserted at the begining
// of the colModel
iFirstDummy = -1;
for(i=0;i<colModel.length;i++) {
cmi = colModel[i];
if (dummyTestRegex.test(cmi.name)) {
iFirstDummy = i;
break;
}
}
if (iFirstDummy === -1) {
// something wrong need return
return obj.page;
}
orgShrinkToFit = clearShrinkToFit();
// we get the first row of the JSON data
cols = rows[0].length;
// fill the list of unused columns
for(i=0;i<colModel.length;i++) {
cmi = colModel[i];
if (i<iFirstDummy+cols) {
cmi.width = currentTemplate.width;
showColNames.push(cmi.name);
} else {
hideColNames.push(cmi.name);
}
}
mygrid.jqGrid('showCol',showColNames);
mygrid.jqGrid('hideCol',hideColNames);
setGridWidthAndRestoreShrinkToFit(orgShrinkToFit,
cols*currentTemplate.width);
return obj.page;
}
}
});
$("#readJson1").click(function() {
mygrid.jqGrid('setGridParam',
{datatype:'json',page:1,url:'Matrix1.json'})
.trigger('reloadGrid');
});
$("#readJson2").click(function() {
mygrid.jqGrid('setGridParam',
{datatype:'json',page:1,url:'Matrix2.json'})
.trigger('reloadGrid');
});
The simplest way to transpose the matrix (reflect it over its main diagonal) is on the server. If you can't do this, you can create and fill the transposed matrix inside of page function (see my code above) and just replace the row part of the obj with the transposed matrix.

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