In below example (which I got it from PagerDuty webpage):
machine="hi"
curl -H "Content-type: application/json" -X POST \
-d "{ \"service_key\": \"e93facc04764012d7bfb002500d5d1a6\", \"description\": \"FAILURE for production/HTTP on machine $machine\" }" \
"https://events.pagerduty.com/generic/2010-04-15/create_event.json"
I want to use variables in description like:
"description": "FAILURE for $machine",
However it does not work and it only shows me the "FAILURE for $machine",
I tried "FAILURE for ${machine}", but it does not work too. Do you know how to solve it?
The problem is that use use single quotes. You need to use double quotes and escape and double quote in the string:
curl -H "Content-type: application/json" -X POST \
-d "{
\"service_key\": \"e93facc04764012d7bfb002500d5d1a6\",
...
\"description\": \"FAILURE for production/HTTP on machine $machine\"
}" \
"https://events.pagerduty.com/generic/2010-04-15/create_event.json"
Quite tedious, but it will do the job.
Related
I am trying to run a bash script, where I would like to make POST calls in a for loop as follows:
for depId in "${depIds[#]}"
do
echo "$depId" <--------------------------------- THIS IS PRINTING PROPER VALUE
curl 'https://student.service.com/api/student' \
-H 'Accept: application/json' \
-H 'Content-Type: application/json' \
-H 'Cookie: UISESSION=abcd' \
--data-raw '{"name":"Student Name","description":"Dummy","depId":$depId}' \ <---- HERE I CANNOT GET THE VALUE OF THE VARIABLE
--compressed
echo "$content"
done
As mentioned above, I cannot get the value of the department id in the URL, with the above form, I am getting a Request Malformed exception. I have even tried with ${depId}, but no luck.
Could anyone please help here ?
Try flipping your quotes around the variable.
--data-raw '{"name":"Student Name","description":"Dummy","depId":'"$depId"'}' \
#!/bin/bash
curl -v \
--request PATCH \
--data "$(
printf '{"files": {"somefile.json": {"content": " {"field": "value"} "}}}' \
)" \
--user x:x \
https://api.github.com/gists/x
Tried adding --header "Content-Type: application/json", no luck.
I'm using this because the content is actually a command output but right now I'm testing the basics because this is not workig.
I believe is somethig related to double quote escaping in bash, tried for a couple of hours with no luck. This is a nightmare.
Any tip is welcomed. Thanks.
It looks like you have too many quotation marks. If you want the value of the "content" element to be an object, then instead of this:
"content": " {"field": "value"} "
try this:
"content": {"field": "value"}
On the off chance that you want it to be a string, then try this:
"content": " {\"field\": \"value\"} "
Instead of fighting against quote escaping, you could write your payload to a file and tell curl to use that file as data like so:
curl -v \
--request PATCH \
--data #/tmp/some/file \
--user x:x \
https://api.github.com/gists/x
Note the # sign in the --data argument, which tells curl that the rest of the argument is a file name to read data from.
Depending on how you create your payload, you could also pipe it to curl using - as filename (echo payload | curl --data #- ...)
I'm currently trying to make a DDNS script that interacts with the Cloudflare API to catch changes in my ip address and automatically fix the ip address change for my web server. Everything is working correctly so far except I can't get $IP to be put properly in the curl statement. I first run a python script from within the bash script to get the ip address, then run the curl statement in the bash script. Here's what the python script looks like (it returns an ip address like "1.1.1.1" with quotations included because the curl command requires the quotations)
#!/usr/bin/python3
import subprocess as sp
def main():
command = "dig +short myip.opendns.com #resolver1.opendns.com";
ip = sp.check_output(command, shell=True).decode('utf-8').strip('\n');
ip_tmp = ip;
ip_tmp = '"' + ip + '"';
ip = ip_tmp;
print(ip);
if __name__ == "__main__":
main();
And the bash script looks like this:
#!/bin/bash
IP=$("./getIP.py")
curl -X PUT "https://api.cloudflare.com/client/v4/zones/zone_id/dns_records/dns_id" \
-H "X-Auth-Email: example.com" \
-H "X-Auth-Key: authkey" \
-H "Content-Type: application/json" \
--data '{"type":"A","name":"example.com","content":$IP,"ttl":120,"proxied":true}'
I've tried to have the python script only return numbers and then added the quotations in the bash script and now vice versa and I can't seem to get it to work. The last line should end up looking like this once the variable replaces with quotations around the ip address:
'{"type":"A","name":"example.com","content":"127.0.0.1","ttl":120,"proxied":true}'
The single quotes around your json structure prevent the variable from expanding.
You have a few options that are readily available.
Ugly quote escaping inside/around your json.
"{\"type\":\"A\",\"name\":\"example.com\",\"content\":$IP,\"ttl\":120,\"proxied\":true}"
Having the python write this data to a file and telling curl to use that file for the source of the post data.
curl -X PUT "https://api.cloudflare.com/client/v4/zones/zone_id/dns_records/dns_id" \
-H "X-Auth-Email: example.com" \
-H "X-Auth-Key: authkey" \
-H "Content-Type: application/json" \
--data #file_you_wrote_your_json_to.json
Using the python requests or urllib modules to issue the request to cloud flare.
Update your main() function to return the IP instead of print it.
my_ip = main()
url = "https://api.cloudflare.com/client/v4/zones/zone_id/dns_records/dns_id"
myheaders = {
"X-Auth-Email": "example.com",
"X-Auth-Key": "authkey",
"Content-Type": "application/json"
}
myjson = {
"type":"A",
"name":"example.com",
"content":my_ip,
"ttl":120,
"proxied":true
}
requests.put(url, headers=myheaders, data=myjson)
Better yet, just do it in bash. Cloudflare DDNS on github.
One shot to fetch the dynamic A-record ID:
curl -X GET "https://api.cloudflare.com/client/v4/zones/**Zone ID** \
/dns_records?type=A&name=dynamic" \
-H "Host: api.cloudflare.com" \
-H "User-Agent: ddclient/3.9.0" \
-H "Connection: close" \
-H "X-Auth-Email: example#example.com" \
-H "X-Auth-Key: "**Authorization key**" \
-H "Content-Type: application/json"
Cron job (* * * * *) to set the dynamic A-record:
#/usr/bin/env sh
AUTH_EMAIL=example#example.com
AUTH_KEY=** CF Authorization key **
ZONE_ID=** CF Zone ID **
A_RECORD_NAME="dynamic"
A_RECORD_ID=** CF A-record ID from cloudflare-dns-id.sh **
IP_RECORD="/tmp/ip-record"
RECORDED_IP=`cat $IP_RECORD`
PUBLIC_IP=$(curl --silent https://api.ipify.org) || exit 1
if [ "$PUBLIC_IP" = "$RECORDED_IP" ]; then
exit 0
fi
echo $PUBLIC_IP > $IP_RECORD
RECORD=$(cat <<EOF
{ "type": "A",
"name": "$A_RECORD_NAME",
"content": "$PUBLIC_IP",
"ttl": 180,
"proxied": false }
EOF
)
curl "https://api.cloudflare.com/client/v4/zones/$ZONE_ID \
/dns_records/$A_RECORD_ID" \
-X PUT \
-H "Content-Type: application/json" \
-H "X-Auth-Email: $AUTH_EMAIL" \
-H "X-Auth-Key: $AUTH_KEY" \
-d "$RECORD"
I have a curl request in below format
curl -v -H "Content-Type:application/json" -H "x-user-id:xxx" -H "x-api-key:yyy" --data '{"logs":"'"${TEST_OUTPUT}"'","pass":"true | false"}' https://razeedash.one.qqq.cloud.com/api/v1/clusters/zzz/api/test_results
This works fine while I do from my MAC terminal. But the same command throws
13:49:26 {
13:49:26 "status": "error",
13:49:26 "message": "Invalid credentials"
13:49:26 }
I saw this post but not sure how else would I send a json body without curly braces. I know that we can save it as a file.json and use the file as body.But for some reasons that cannot be implemented in my scenario
In general, you should avoid trying to build JSON using string interpolation. Use a tool like jq to handle any necessary quoting.
jq -n --argson o "$TEST_OUTPUT" '{logs: $o, pass: "true | false"}' |
curl -v -H "Content-Type:application/json" \
-H "x-user-id:xxx" \
-H "x-api-key:yyy" \
--data #- \
https://razeedash.one.qqq.cloud.com/api/v1/clusters/zzz/api/test_results
However, if you can manage to correctly generate your JSON as you are now, you can just replace the jq command with echo:
echo '{"logs": ...' | curl ...
The #- argument to --data says to read from standard input.
I have a curl command:
curl -u ${USER_ID}:${PASSWORD} -X GET 'http://blah.gso.woo.com:8080/rest/job-execution/job-details/${job_id}'
The variable job_id has a value in it, say, 1160. When I execute the curl command in shell it gives me the following error:
{"message":"Sorry. An unexpected error occured.", "stacktrace":"Bad Request. The request could not be understood by the server due to malformed syntax."}
If I pass the number '1160' directly in the command, as shown below, the curl command works.
curl -u ${USER_ID}:${PASSWORD} -X GET 'http://blah.gso.woo.com:8080/rest/job-execution/job-details/1160'
I want to be able to pass the value of the variable in the curl command.
When using variables in shell, you can only use doubles quotes, not single quotes : the variables inside single quotes are not expanded.
Learn the difference between ' and " and `. See http://mywiki.wooledge.org/Quotes and http://wiki.bash-hackers.org/syntax/words
I ran into this problem with passing as well, it was solved by using ' " $1 " '
See connection.uri below
curl -X POST -H "Content-Type: application/json" --data '
{"name": "mysql-atlas-sink",
"config": {
"connector.class":"com.mongodb.kafka.connect.MongoSinkConnector",
"tasks.max":"1",
"topics":"mysqlstock.Stocks.StockData",
"connection.uri":"'"$1"'",
"database":"Stocks",
"collection":"StockData",
"key.converter":"io.confluent.connect.avro.AvroConverter",
"key.converter.schema.registry.url":"http://schema-registry:8081",
"value.converter":"io.confluent.connect.avro.AvroConverter",
"value.converter.schema.registry.url":"http://schema-registry:8081",
"transforms": "ExtractField",
"transforms.ExtractField.type":"org.apache.kafka.connect.transforms.ExtractField$Value",
"transforms.ExtractField.field":"after"
}}' http://localhost:8083/connectors -w "\n"
How to pass json to curl with shell variable(s):
myvar=foobar
curl -H "Content-Type: application/json" --data #/dev/stdin<<EOF
{ "xkey": "$myvar" }
EOF
With the switch -d or --data, the POST request is implicit
use variable in a double-quote single-quote "' $variable '"
#!/usr/bin/bash
token=xxxxxx
curl --location --request POST 'http://127.0.0.1:8009/submit/expense/' \
--form 'token="'$token'"' \
--form 'text="'$1'"' \
--form 'amount="'$2'"'
userdetails="$username:$apppassword"
base_url_part='https://api.XXX.org/2.0/repositories'
path="/$teamName/$repoName/downloads/$filename"
base_url="$base_url_part$path"**strong text**
curl -L -u "$userdetails" "$base_url" -o "$downloadfilename"