I'm attempting to generate a url using a bunch of different variables however when I follow a variable with an underscore the variable after the underscore does not show up. However, if I put a space before the underscore then there is a space in the generated URL. So my question is, is there an escape character for doing the sort of thing I have described?
Also code:
URL="$baseURL$BUILD/TorBrowserBundle-$BUILD-$OS$BIT _$LANG.zip"
The issue occurs in between $BIT and $LANG.
you can use ${}
so something like
URL="${baseURL}${BUILD}/TorBrowserBundle-${BUILD}-${OS}${BIT}_${LANG}.zip"
Related
This is what happens when I try to use a colon in th:text:
and a backslash doesn't seem to fix it:
How can I use the colon symbol in th:text?
If you want to place a literal into th:text, you have to use single quotes: th:text="'7:00AM'". See documentation here.
(By contrast, something like this th:text="7_00AM" is valid - because it is a literal token. Such strings can only use a subset of characters, but do not need enclosing 's.)
For a gradle script, I am composing strings that will be used as command line for a subsequent gradle Test-task. One of the strings is the user's password, which eventually will be passed to the called (exec'ed) "java ..." call using the JVM's -D option, e.g. -Dpassword=foobar.
What complicates things here is, that this password can/should of course contain special characters, that may interfere with the use of the string as command line. In other words: I need to escape special characters (which is OS-specific). :-(
Now to my actual question:
I want to use the String.replaceAll method, i.e. replaceAll(list_of_special characters, EscapeCharacter + Ref_to_matched_character),
e.g. simplified something like replaceAll("[#$%^&]", "^$1")
'^' meaning the escape character and '$1' meaning the matched character here.
Is that possible, i.e. can one refer to the matched pattern in the second argument of replaceAll?
Is that possible, i.e. can one refer to the matched pattern in the second argument of replaceAll?
yes, it's possible
'a#b$c'.replaceAll('([#$%^&])', '^$1')
returns
a^#b^$c
Thanks for the responses and the reviews improving readability. Meanwhile I got my expression working. For those interested:
// handles gthe following: `~!##$%^&*()_+-={}|[]\:;"'<>?,./
escaped = original.replaceAll('[~!##\\$\\%\\^\\&\\*\\(\\)_\\+-={}\\|\\[\\]\\\\:;\"\\\'<>\\?,\\./]', '^$0') // for Windows - cmd.exe
I am trying to read a CSV file which contains escaped quote values such as:
"1","unquoted text","\"quoted text\""
It seems that SuperCSV wants quotes to be quoted as
"1","unquoted text","""quoted text"""
Is there a way to change the escape character to a backslash? I've looked at the docs and not seen anything.
Just found a link to an issue logged in github: https://github.com/super-csv/super-csv/issues/14
Seems like a different CSV handler is in order.
I'm looking over a script (which has been used successfully in the past) which contains the following:
node=1
while :
do
userKey=WEB_${node}_USER
userVal=`echo ${!userKey}`
I have not been able to figure out why an exclamation point would be added to a variable reference like this. What purpose does "!" serve in this context?
It's rare for me to do much scripting so if I am missing any details please let me know and I will try to provide more information. I have not been able to find this answer elsewhere.
Thanks in advance!
It's called indirect parameter expansion. Where $userKey expands to the value of the variable userKey, ${!userKey} expands to the value of the variable whose name is the value of userKey. Since usrKey has the value WEB_1_USER (given the current value of $node, ${!userKey} expands to the same result as $WEB_1_USER.
Its use is somewhat rare, since in many cases (including, it appears, here) an array WEB_USER of user names would be clearer than a set of numbered variables.
WEB_USER=(alice bob charlie)
node=1
while :
do
userVal=${WEB_USER[node]}
In bash, I thought that the only characters that retained their meta-character status inside double quotes were the dollar sign ($), the back-tick (`) and the backslash (\).
I am trying to add 2 variable together inside of an assign. When reading the Smarty Assign Documentation it says:
This complex example must have the variables in backticks, what does this mean?
It is the following sign `
So you have
assign variable = `value`
According to the official Smarty documentation,
Smarty will recognize assigned variables embedded in "double quotes" so long as the variable name contains only numbers, letters, under_scores and brackets[].
With any other characters, for example a .period or $object->reference, then the variable must be surrounded by `backticks`.
In particular, if you are doing maths in, say, an assign, you need to use backticks for it to work.
backticks are only necessary when inside quotes, and when you have variables with characters such as . -> example:
{assign var="foo" value="myval is `$smarty.request.myval`"}