I wanna catch the date in my table which is written like this "20140205101309" I tried to get by many ways, but i was not able to catch it so how to modifiy my query to catch it ?
select * from my.DETAIL a where A.DATE
between to_DATE('YYYYMMDD hh24:mi:ss','28-dec-2013 12:00:00')
and to_date ('YYYYMMDD hh24:mi:ss','2-feb-2014 00:00:00');
thank you in advance
Make a.call_date a date before comparing:
select *
from operation.reject_detail a
where to_date(a.call_date, 'YYYYMMDDHHMISS') between
to_date('28-12-2013 12:00:00','DD-MM-YYYY HH24:MI:SS') and
to_date('02-02-2014 00:00:00','DD-MM-YYYY HH24:MI:SS' );
Assuming 20140205101309 is: 2014, februari, 5 10:13:09
If you are not interested in the time part do this:
select *
from operation.reject_detail a
where to_date(substr(a.call_date,1,8), 'YYYYMMDD') between
to_date('28-12-2013','DD-MM-YYYY') and
to_date('02-02-2014','DD-MM-YYYY');
Storing dates as strings is bad practice, but since that is what you have and it's in a relatively sensible format, you can just compare it as a string:
select * from my.DETAIL a
where A.DATE between '20131228120000' and '20140202000000'
Or to ignore the time part on the table and include the full second date:
select * from my.DETAIL a
where A.DATE between '20131228000000' and '20140202235959'
There doesn't seem to be much point converting everything to DATE types, particularly if your column is indexed. If it isn't indexed than you could just look at the date part:
where substr(A.DATE, 1, 8) between '20131228' and '20140202'
Related
I am trying to separate the time and date in one column to be independent off each other. I am new at writing scripts
this is my query:
select
*
from
[tablename]
where
to_date([column_name]) in ( '15-Jun-2021', '16-Jun-2021' )
and
to_char([column_name],'dd-Mon-yyyy HH:MM:ss') < '15-Jun-2021 19:54:30'
The way you put it, it would be
select *
from your_table
where date_column >= date '2021-06-15'
and date_column < to_date('15.06.2021 19:54:30', 'dd.mm.yyyy hh24:mi:ss')
because
date_column should be of date datatype. If it isn't, you'll have problems of many kinds in the future. Therefore,
don't to_date it, it is already a date
don't to_char it either, because you'd be comparing strings and get unexpected result. Use that function when you want to nicely display the result
the second condition you wrote makes the first one questionable. If date_column is less than value you wrote, then you can omit date '2021-06-16' from the first condition because you won't get any rows for that date anyway
date literal (date '2021-06-15') sets time to midnight, so condition I wrote should return rows you want
SQL> select date '2021-06-15' first,
2 to_date('15.06.2021 19:54:30', 'dd.mm.yyyy hh24:mi:ss') second
3 from dual;
FIRST SECOND
------------------- -------------------
15.06.2021 00:00:00 15.06.2021 19:54:30
SQL>
I ran these two scripts below and they give two different results. The first did not include data for the 30th of April but the latter does. I am using oracle sql. Could someone assist?
select distinct * from a where (m_date between'01-MAY-17' AND '30-MAY-17');
select distinct * from a where m_date like '%-MAY-17';
I used the to_date function and it worked:
select distinct * from a where to_date (m_date) between'01-MAY-17' AND '30-MAY-17'
This produced the same results as with the like clause:
select distinct * from a where m_date like '%-MAY-17'
Your between clause
select distinct * from a where to_date (m_date) between'01-MAY-17' AND '30-MAY-17'
is the same as saying (pseudo-code)
...where to_date (m_date) between '01-may-17 00:00:00' AND '30-may-17 00:00:00'...
which excludes and date values on 5/30 where there is any time element other than 12AM in the morning. (Also, May does have 31 days).
It would be more correct to do the following, assuming m_date is a date data type and assuming you want all values during the month of may.
... where m_date >= to_date('01-may-17') and m_date < to_date('01-jun-17')...
I am using Oracle XE on my machine.
Defined a table as :
Name Type
ENAME VARCHAR2(20)
DOJ DATE
Firing a simple select:
select * from test1.tasty1;
ENAME DOJ
sat 08-DEC-16
So ok - I am aware that DATE field has time component in it.
The following query using TRUNC works fine:
select * from test1.tasty1 where trunc(DOJ) = '08-DEC-16';
Now I wanted to test the 'to_date' function - but none of the below queries worked - wonder why ?
select * from test1.tasty1 where DOJ =
to_date('08-12-2016','DD-MM-YYYY');
select * from test1.tasty1 where
DOJ = to_date('08-DEC-2016','DD-MON-YYYY');
select * from
test1.tasty1 where DOJ = to_date('08-DEC-16','DD-MON-YY');
select
* from test1.tasty1 where DOJ = to_date('08-DEC-16','dd-mon-RR');
Had taken a look at the following on SO:
Oracle TO_DATE not working
so not sure what is wrong here ?
From your question and comments, it appears that this is the sequence of events which happened.
You did the following INSERT into your table:
INSERT INTO test1.tasty1 VALUES ('sat', SYSDATE)
Keep in mind that dates in Oracle have both a date and a time component. So even though you did insert the date '2016-12-08' you also inserted a time component. As a result, the following query is not returning any records:
SELECT * FROM test1.tasty1 WHERE DOJ = '2016-08-12'
This is probably because you never specified the time component, and therefore the record you inserted earlier is not matching. If you want to compare only the date portion, you can use TRUNC as follows:
SELECT * FROM test1.tasty1 WHERE TRUNC(DOJ) = '2016-08-12'
The solution to your problem moving forward would be to wrap SYSDATE with TRUNC during the insert, if you really only want to deal with the date components.
By the way, the format '08-DEC-16' used as a literal will not be recognized by Oracle as a valid date. Instead, use '2016-12-08'.
Have you tried like this as comparison of date with date is correct:
select * from test1.tasty1 where to_date(DOJ,'DD-MM-YYYY') = to_date('08-12-2016','DD-MM-YYYY');
Compare apples with apples and not with mangoes.
What it worked from is instead of make a date to compare, change the date column to char with to_char(datecol, 'DD-MM-YYYY') = '01-01-2022'
Sory, I have Question ? Why not show up when I execute some of its field content.
Please help me to fix it. Thank U
SELECT * FROM T_TRANS WHERE TIME_START = to_date('01-09-2014', 'DD-MM-YY');
Oracle is being a bit lenient with you with the date format mask, but you should use YYYY to make it clearer. But you're still providing a single point in time as midnight on that date:
select to_char(to_date('01-09-2014', 'DD-MM-YY'), 'YYYY-MM-DD HH24:MI:SS') as two_digit,
to_char(to_date('01-09-2014', 'DD-MM-YYYY'), 'YYYY-MM-DD HH24:MI:SS') as four_digit
from dual;
TWO_DIGIT FOUR_DIGIT
------------------- -------------------
2014-09-01 00:00:00 2014-09-01 00:00:00
Given the name of the column it's reasonable to assume you have other times, and your query won't match anything except exactly midnight. To find all records on that day, you need to provide a range:
SELECT * FROM T_TRANS
WHERE TIME_START >= to_date('01-09-2014', 'DD-MM-YYYY');
AND TIME_START < to_date('02-09-2014', 'DD-MM-YYYY');
... though I prefer the ANSI date notation for this sort of this:
WHERE TIME_START >= DATE '2014-09-01'
AND TIME_START < DATE '2014-09-02'
You could specify 23:59:59 on the same date, but that will break subtly when you use a timestamp field rather than a date field.
You could also truncate the value from the table (as #San said in a comment), or convert to a string for comparison (as #yammy showed in an answer), but either of those will prevent any index on the time_start column being used, affecting performance.
After reading Alex Poole suggestion, you should try:
SELECT * FROM T_TRANS WHERE to_char(TIME_START, 'DD-MM-YYYY') = '01-09-2014';
Shouldn't the format mask be "DD-MM-YYYY"?
I have a query in PL/SQL on Oracle 10g that isn't behaving as I thought. I'm 100% sure I am doing something silly so I'm sorry.. Here goes:
I have some data in a table that looks like this:
I then went to query but using the time element, like this:
select * from dw_time
where createdtime > to_date('2012/04/12 03:06:00', 'yyyy/mm/dd hh24:mi:ss')
When this is executed we get records returned that include the rows in the image 03:05AM. So thinking it was the to_date function I checked that:
select to_date('2012/04/12 10:24:00', 'yyyy/mm/dd hh:mi:ss')
from dual;
Now I was totally confused as it clearly know that as a time. So I tried it again:
select * from dw_time
where createdtime > to_date('2012/04/12 03:06:00', 'yyyy/mm/dd hh24:mi:ss')
As you can see it is totally ignoring the time component! At this point I thought it was time to ask the gurus on here!
Many thanks
Mike
Is it possible that in your table '12/4/2012' means 4 Dec 2012 and query outputs it in MM/DD/YYYY format?
Look at DB output date format - it's MM/DD/YYYY - you can see it on output of:
select to_date('2012/04/12 10:24:00', 'yyyy/mm/dd hh:mi:ss') from dual;
So change your select to:
select * from dw_time where createdtime > to_date('2012/12/04 03:06:00', 'yyyy/mm/dd hh24:mi:ss')
You can see date output format by this query:
select * from nls_session_parameters where parameter = 'NLS_DATE_FORMAT';
And you can change date output format by this:
alter session set NLS_DATE_FORMAT='DD/MM/YYYY HH24:MI:SS';