I am trying to separate the time and date in one column to be independent off each other. I am new at writing scripts
this is my query:
select
*
from
[tablename]
where
to_date([column_name]) in ( '15-Jun-2021', '16-Jun-2021' )
and
to_char([column_name],'dd-Mon-yyyy HH:MM:ss') < '15-Jun-2021 19:54:30'
The way you put it, it would be
select *
from your_table
where date_column >= date '2021-06-15'
and date_column < to_date('15.06.2021 19:54:30', 'dd.mm.yyyy hh24:mi:ss')
because
date_column should be of date datatype. If it isn't, you'll have problems of many kinds in the future. Therefore,
don't to_date it, it is already a date
don't to_char it either, because you'd be comparing strings and get unexpected result. Use that function when you want to nicely display the result
the second condition you wrote makes the first one questionable. If date_column is less than value you wrote, then you can omit date '2021-06-16' from the first condition because you won't get any rows for that date anyway
date literal (date '2021-06-15') sets time to midnight, so condition I wrote should return rows you want
SQL> select date '2021-06-15' first,
2 to_date('15.06.2021 19:54:30', 'dd.mm.yyyy hh24:mi:ss') second
3 from dual;
FIRST SECOND
------------------- -------------------
15.06.2021 00:00:00 15.06.2021 19:54:30
SQL>
Related
In Oracle SQL Developer, I have a table called t1 who have two columns col1 defined as NUMBER(19,0) and col2 defined as TIMESTAMP(3).
I have these rows
col1 col2
1 03/01/22 12:00:00,000000000
2 03/01/22 13:00:00,000000000
3 26/11/21 10:27:11,750000000
4 26/11/21 10:27:59,606000000
5 16/12/21 11:47:04,105000000
6 16/12/21 12:29:27,101000000
My sysdate looks like this:
select sysdate from dual;
SYSDATE
03/03/22
I want to create a stored procedure (SP) which will delete rows older than 2 months and displayed message n rows are deleted
But when i execute this statement
select * from t1 where to_date(TRUNC(col2), 'DD/MM/YY') < add_months(sysdate, -2);
I don't get the first 2 rows of my t1 table. I get more than 2 rows
1 03/01/22 12:00:00,000000000
2 03/01/22 13:00:00,000000000
How can i get these rows and deleted it please ?
In Oracle, a DATE data type is a binary data type consisting of 7 bytes (century, year-of-century, month, day, hour, minute and second). It ALWAYS has all of those components and it is NEVER stored with a particular formatting (such as DD/MM/RR).
Your client application (i.e. SQL Developer) may choose to DISPLAY the binary DATE value in a human readable manner by formatting it as DD/MM/RR but that is a function of the client application you are using and not the database.
When you show the entire value:
SELECT TO_CHAR(ADD_MONTHS(sysdate, -2), 'YYYY-MM-DD HH24:MI:SS') AS dt FROM DUAL;
Then it outputs (depending on time zone):
DT
2022-01-03 10:11:28
If you compare that to your values then you can see that 2022-01-03 12:00:00 is not "more than 2 months ago" so it will not be matched.
What you appear to want is not "more than 2 months ago" but "equal to or more than 2 months, ignoring the time component, ago"; which you can get using:
SELECT *
FROM t1
WHERE col2 < add_months(TRUNC(sysdate), -2) + INTERVAL '1' DAY;
or
SELECT *
FROM t1
WHERE TRUNC(col2) <= add_months(TRUNC(sysdate), -2);
(Note: the first query would use an index on col2 but the second query would not; it would require a function-based index on TRUNC(col2) instead.)
Also, don't use TO_DATE on a column that is already a DATE or TIMESTAMP data type. TO_DATE takes a string as the first argument and not a DATE or TIMESTAMP so Oracle will perform an implicit conversion using TO_CHAR and if the format models do not match then you will introduce errors (and since any user can set their own date format in their session parameters at any time then you may get errors for one user that are not present for other users and is very hard to debug).
db<>fiddle here
Perhaps just:
select *
from t1
where col2 < add_months(sysdate, -2);
i have a problem with a date parameter query using 'between' operator in oracle view, when i do this query :
SELECT *
FROM MY_VIEW
WHERE STATUS = 'Active'
AND CHECKER_DATE BETWEEN to_date(sysdate - 1, 'DD-MON-YY') AND to_date(sysdate, 'DD-MON-YY');
it does not give me the records (actualy i have any record on that date).
I try using 'in' operator, but still not give me the records.
Please throw some information for this.
*checker_date defined as date
Your first error is to call to_date() on a value that is already a DATE. to_date() expects a VARCHAR value, so sysdate will be first converted to VARCHAR and will then immediately be converted back to a DATE value which it was to begin with.
You probably want
AND CHECKER_DATE BETWEEN trunc(sysdate) - 1 AND trunc(sysdate)
Most probably this will still not give you want you want as that would not include rows from "today". trunc(sysdate) means "today at midnight" and any row that was created today after midnight will not be included. With date/time values (and Oracle's DATE type does contain a time, despite the name) it's better to not use BETWEEN, but explicit range operators instead:
AND CHECKER_DATE >= trunc(sysdate) - 1
AND CHECKER_DATE < trunc(sysdate) + 1
trunc(sysdate) + 1 is tomorrow at midnight, so any value that is (strictly) smaller than that is "today".
All the above assumes that CHECKER_DATE is defined as DATE or TIMESTAMP
You can try:
SELECT *
FROM MY_VIEW
WHERE STATUS = 'Active'
AND CHECKER_DATE BETWEEN trunc(sysdate - 1) AND trunc(sysdate);
Oracle advises against using to_date for date. Also trunc is here because Trunc removes the time component.
may be records are not 'Active' or 'Active' a not-existing value in one of the reference tables if any and trunc(sysdate -1) and trunc(sysdate) would help
I need to query 2 tables, one contains a TIMESTAMP(6) column, other contains a DATE column. I want to write a select statement that prints both values and diff between these two in third column.
SB_BATCH.B_CREATE_DT - timestamp
SB_MESSAGE.M_START_TIME - date
SELECT SB_BATCH.B_UID, SB_BATCH.B_CREATE_DT, SB_MESSAGE.M_START_TIME,
to_date(to_char(SB_BATCH.B_CREATE_DT), 'DD-MON-RR HH24:MI:SS') as time_in_minutes
FROM SB_BATCH, SB_MESSAGE
WHERE
SB_BATCH.B_UID = SB_MESSAGE.M_B_UID;
Result:
Error report -
SQL Error: ORA-01830: date format picture ends before converting entire input string
01830. 00000 - "date format picture ends before converting entire input string"
You can subtract two timestamps to get an INTERVAL DAY TO SECOND, from which you calculate how many minutes elapsed between the two timestamps. In order to convert SB_MESSAGE.M_START_TIME to a timestamp you can use CAST.
Note that I have also removed your implicit table join with an explicit INNER JOIN, moving the join condition to the ON clause.
SELECT t.B_UID,
t.B_CREATE_DT,
t.M_START_TIME,
EXTRACT(DAY FROM t.diff)*24*60 +
EXTRACT(HOUR FROM t.diff)*60 +
EXTRACT(MINUTE FROM t.diff) +
ROUND(EXTRACT(SECOND FROM t.diff) / 60.0) AS diff_in_minutes
FROM
(
SELECT SB_BATCH.B_UID,
SB_BATCH.B_CREATE_DT,
SB_MESSAGE.M_START_TIME,
SB_BATCH.B_CREATE_DT - CAST(SB_MESSAGE.M_START_TIME AS TIMESTAMP) AS diff
FROM SB_BATCH
INNER JOIN SB_MESSAGE
ON SB_BATCH.B_UID = SB_MESSAGE.M_B_UID
) t
Convert the timestamp to a date using cast(... as date). Then take the difference between the dates, which is a number - expressed in days, so if you want it in minutes, multiply by 24*60. Then round the result as needed. I made up a small example below to isolate just the steps needed to answer your question. (Note that your query has many other problems, for example you didn't actually take a difference of anything anywhere. If you need help with your query in general, please post it as a separate question.)
select ts, dt, round( (sysdate - cast(ts as date))*24*60, 2) as time_diff_in_minutes
from (select to_timestamp('2016-08-23 03:22:44.734000', 'yyyy-mm-dd hh24:mi:ss.ff') as ts,
sysdate as dt from dual )
;
TS DT TIME_DIFF_IN_MINUTES
-------------------------------- ------------------- --------------------
2016-08-23 03:22:44.734000000 2016-08-23 08:09:15 286.52
I've got two sets of dates being passed into a query and I would like to find all the months/years between both sets of dates.
When I try this:
WITH CTE_Dates (cte_date) AS (
SELECT cast(date '2014-01-27' as date) from dual
UNION ALL
SELECT cast(ADD_MONTHS(TRUNC(cte_date, 'MONTH'),1) as date)
FROM CTE_Dates
WHERE ( TO_DATE(ADD_MONTHS(TRUNC(cte_date, 'MONTH'), 1)) BETWEEN TO_DATE ('27-01-2014','DD-MM-YYYY') AND TO_DATE ('27-04-2014','DD-MM-YYYY'))
OR
( TO_DATE(ADD_MONTHS(TRUNC(cte_date, 'MONTH'), 1)) BETWEEN TRUNC(TO_DATE('27-11-2014','DD-MM-YYYY'), 'MONTH') AND TO_DATE ('27-01-2015','DD-MM-YYYY'))
)
SELECT * from CTE_Dates
I get:
27-JAN-14
01-FEB-14
01-MAR-14
01-APR-14
I would also want to get:
01-NOV-14
01-DEC-14
01-JAN-15
It looks like the OR portion of the WHERE clause gets ignored.
Suggestions on how to create this query?
Thanks
Cory
The problem with what you have now (aside from extra cast() and to_date() calls) is that on the fourth iteration both the conditions are false so the recursion stops; there's nothing to make it skip a bit and pick up again, otherwise it would continue forever. I don't think you can achieve both ranges within the recursion.
You can put the latest date you want inside the recursive part, and then filter the two ranges you want afterwards:
WITH CTE_Dates (cte_date) AS (
SELECT date '2014-01-27' from dual
UNION ALL
SELECT ADD_MONTHS(TRUNC(cte_date, 'MONTH'), 1)
FROM CTE_Dates
WHERE ADD_MONTHS(TRUNC(cte_date, 'MONTH'), 1) <= date '2015-01-27'
)
SELECT * from CTE_Dates
WHERE cte_date BETWEEN date '2014-01-27' AND date '2014-04-27'
OR cte_date BETWEEN date '2014-11-27' AND date '2015-01-27';
CTE_DATE
---------
27-JAN-14
01-FEB-14
01-MAR-14
01-APR-14
01-DEC-14
01-JAN-15
6 rows selected
You can replace the hard-coded values with your pairs of start and end dates. If the ranges might overlap or the second range could be (or end) before the first one, you could pick the higher date:
WHERE ADD_MONTHS(TRUNC(cte_date, 'MONTH'), 1)
<= greatest(date '2015-01-27', date '2014-04-27')
... though that only makes sense with variables, not fixed values.
Sory, I have Question ? Why not show up when I execute some of its field content.
Please help me to fix it. Thank U
SELECT * FROM T_TRANS WHERE TIME_START = to_date('01-09-2014', 'DD-MM-YY');
Oracle is being a bit lenient with you with the date format mask, but you should use YYYY to make it clearer. But you're still providing a single point in time as midnight on that date:
select to_char(to_date('01-09-2014', 'DD-MM-YY'), 'YYYY-MM-DD HH24:MI:SS') as two_digit,
to_char(to_date('01-09-2014', 'DD-MM-YYYY'), 'YYYY-MM-DD HH24:MI:SS') as four_digit
from dual;
TWO_DIGIT FOUR_DIGIT
------------------- -------------------
2014-09-01 00:00:00 2014-09-01 00:00:00
Given the name of the column it's reasonable to assume you have other times, and your query won't match anything except exactly midnight. To find all records on that day, you need to provide a range:
SELECT * FROM T_TRANS
WHERE TIME_START >= to_date('01-09-2014', 'DD-MM-YYYY');
AND TIME_START < to_date('02-09-2014', 'DD-MM-YYYY');
... though I prefer the ANSI date notation for this sort of this:
WHERE TIME_START >= DATE '2014-09-01'
AND TIME_START < DATE '2014-09-02'
You could specify 23:59:59 on the same date, but that will break subtly when you use a timestamp field rather than a date field.
You could also truncate the value from the table (as #San said in a comment), or convert to a string for comparison (as #yammy showed in an answer), but either of those will prevent any index on the time_start column being used, affecting performance.
After reading Alex Poole suggestion, you should try:
SELECT * FROM T_TRANS WHERE to_char(TIME_START, 'DD-MM-YYYY') = '01-09-2014';
Shouldn't the format mask be "DD-MM-YYYY"?