Default value for struct member in c++ - c++11

It seems that we can not give a default value for struct members in c++,but I find that code as below can compile and run, why? Am I missing something?
struct Type {
int i = 0xffff;
};
Program:
#include <iostream>
using namespace std;
struct Type {
int i = 0xffff;
};
int main() {
// your code goes here
Type val;
std::cout << val.i << std::endl;
return 0;
}

It is going to depend on the compiler you use.
For gcc and clang you need to pass the flag -std=c++11 to the compiler.
Support for member initializer and other c++11 features:
gcc since 4.7. See here.
clang since 3.0. See here.
Visual studio compiler in its 2013 version. See here.

This is correct and introduced in C++11 standard. This concept is known as in-class member initializer
You can check Stroustrup FAQ link on this concept:
http://www.stroustrup.com/C++11FAQ.html#member-init

Related

CUDA 8.0: Compile Error with Template Friend in Namespace

I noticed that the following code compiles with g++/clang++-3.8 but not with nvcc:
#include <tuple> // not used, just to make sure that we have c++11
#include <stdio.h>
namespace a {
template<class T>
class X {
friend T;
};
}
I get the following compile error:
/usr/local/cuda-8.0/bin/nvcc -std=c++11 minimum_cuda_test.cu
nvcc warning : The 'compute_20', 'sm_20', and 'sm_21' architectures are deprecated, and may be removed in a future release (Use -Wno-deprecated-gpu-targets to suppress warning).
minimum_cuda_test.cu:7:10: error: ‘T’ in namespace ‘::’ does not name a type
friend T;
Interestingly, this works with nvcc:
#include <tuple> // not used, just to make sure that we have c++11
#include <stdio.h>
template<class T>
class X {
friend T;
};
Is this a bug in the compiler? I thought nvcc would internally use g++ or clang as a compiler so I am confused why this would work with my local compiler but not with nvcc.
In both cases, the code is being compiled by g++. However, when you pass a .cu file to nvcc, it puts the code through the CUDA C++ front end before passing it to the host compiler. Looking at CUDA 8 with gcc 4.8, I see that the code has been transformed from
namespace a {
template<class T>
class X {
friend T;
};
}
to
namespace a {
template< class T>
class X {
friend ::T;
};
You can see that the front end has replaced the templated friend with an equivalent, but with a prepended anonymous namespace, which is breaking the compilation. I'm not a C++ language lawyer, but this would appear to me to be a bug in the CUDA front end. I would suggest reporting it to NVIDIA.

Clang compilation error: "variable 'array' with variably modified type cannot be captured in lambda expression

In the code listed below, "LambdaTest" fails with the following error on Clang only:
shared/LambdaTest.cpp:8:31: error: variable 'array' with variably
modified type cannot be captured in a lambda expression
auto myLambdaFunction = [&array]()
^
shared/LambdaTest.cpp:7:9: note: 'array' declared here
int array[length];
The function "LambdaTest2" which passes the array as a parameter instead of capturing compiles fine on G++/Clang.
// Compiles with G++ but fails in Clang
void LambdaTest(int length)
{
int array[length];
auto myLambdaFunction = [&array]()
{
array[0] = 2;
};
myLambdaFunction();
}
// Compiles OK with G++ and Clang
void LambdaTest2(int length)
{
int array[length];
auto myLambdaFunction = [](int* myarray)
{
myarray[0] = 2;
};
myLambdaFunction(array);
}
Two questions:
What does the compiler error message "variable 'array' with variably modified type cannot be captured in a lambda expression" mean?
Why does LambdaTest fail to compile on Clang and not G++?
Thanks in advance.
COMPILER VERSIONS:
*G++ version 4.6.3
*clang version 3.5.0.210790
int array[length]; is not allowed in Standard C++. The dimension of an array must be known at compile-time.
What you are seeing is typical for non-standard features: they conflict with standard features at some point. The reason this isn't standard is because nobody has been able to make a satisfactory proposal that resolves those conflicts. Instead, each compiler has done their own thing.
You will have to either stop using the non-standard feature, or live with what a compiler happens to do with it.
VLA (Variable-length array) is not officially supported in C++.
You can instead use std::vector like so:
void LambdaTest(int length)
{
std::vector<int> array(length);
auto myLambdaFunction = [&array]()
{
array[0] = 2;
};
myLambdaFunction();
}
Thanks to both answers above for pointing out that VLAs are non-standard. Now I know what to search for.
Here are more are related links to the subject.
Why aren't variable-length arrays part of the C++ standard?
Why no VLAS in C++

gcc "not inlined" warning

Does gcc's inline __attribute__((__always_inline__)) generate warning, when compiler can't inline function?
Because VS does http://msdn.microsoft.com/en-us/library/z8y1yy88.aspx:
If the compiler cannot inline a function declared with __forceinline,
it generates a level 1 warning.
You need -Winline to get warnings about non-inlined functions.
If you want to verify this you can try taking the address of an inline function (which prevents it from being inlined) and then you should see a warning.
#include <stdio.h>
static inline __attribute__ ((always_inline)) int add(int a, int b)
{
return a + b;
}
int main(void)
{
printf("%d\n", add(21, 21));
printf("%p\n", add);
return 0;
}
EDIT
I've been trying to produce a warning with the above code and other examples without success - it seems that the behaviour of current versions of gcc and clang may have changed in this area. I'll delete this answer if I can't code up with a better example that generates a warning.

struct keyword in gcc vs Borland C

I'm confused about the struct definitions below. Shouldn't be both correct? With Borland C both compile, but with gcc only the second one compiles. The error is "unknown type name _Node".
typedef struct _Node {
int item;
_Node* next;
} Node;
typedef struct _Node {
int item;
struct _Node* next;
} Node;
It depends on how the compiler handles forward references. The gcc compiler may do,this by default since it is also a C++ compiler.
No, in C only the second (explicitly including the struct specifier) is correct. While C++ allows the omission of struct, c does not, so this is a non-portable Borland extension. If you compile with g++, I imagine it should accept the first syntax as well.

How do I use boost library with WDK environment

I wanna to compile my c plus plus project that using boost library with WDK rather than VisualStudio.
My computer's OS is Windows7-64bit, the WDK version is 7.6 and boost library version is 1.51
Once I compile my source code project, the WDK compiler will occure an error:
e:\lib\boost_1_51_0\boost\array.hpp(72) : error C2039: 'ptrdiff_t' : is not a member of 'std' .
Whole project's file contents are as follow:
File sources:
TARGETTYPE=PROGRAM
TARGETNAME=helloworld
UMENTRY=main
USE_MSVCRT=1
USE_NATIVE_EH=1
#
# use iostream package and STL
#
USE_IOSTREAM=1
USE_STL=1
STL_VER=70
#
# my boost library root directory
#
BOOST_INC_PATH=E:\lib\boost_1_51_0
INCLUDES=$(BOOST_INC_PATH)
TARGETLIBS=$(SDK_LIB_PATH)\user32.lib
SOURCES=HelloWorld.cpp
UMTYPE=console
UMBASE=0x4000000
File HelloWorld.cpp:
#include <iostream>
#include <vector>
#include <string>
#include <boost/array.hpp>
void InvokeVector()
{
//invoke STL's vector
std::vector<std::string> vec;
vec.push_back("Entry ");
vec.push_back("of ");
vec.push_back("Vector");
vec.push_back("……\n");
//print vec
for (int i=0; i<vec.size(); i++) {
std::cout<<vec.at(i);
}
}
void InvokeBoost()
{
//invoke Boost's array<T, N>
boost::array<int, 3> arr = {1, 2, 3};
for (int i=0; i<arr.size(); i++) {
std::cout<<"arr["<<i<<"]"<<"is" <<arr[i]<<std::endl;
}
}
int main()
{
// InvokeVector(); //run normally
InvokeBoost(); //it will occure an error
return 0;
}
Could you please teach me how to solve this problem? Any help will be greatly appreciated!
Short answer: No.
But you can port some.
It's well explained here : The NT Insider:Guest Article: C++ in an NT Driver
One of the main problems with C++ in the
kernel is that most of the "nice" features of the language are not
directly available in that mode. Some are easy to recreate and we will
see how to do that. However, some features should be forgotten such as
C++ exceptions, which are not the same as kernel exceptions.
Such features have to be forgotten simply because there is no support
for them in kernel mode. Translation: does not compile. If you have
the time and energy you may attempt to port them to kernel mode, but
frankly, exceptions are too slow for kernel mode. This will have an
impact on your C++ coding style, which is something you should keep in
mind.
longer answer - yes
just add
typedef int ptrdiff_t;
before pulling in boost headers and all will be well for basic boostness

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