spring mongo creating like query - spring

I can match starting of string i.e clo with keywords and it gives me correct result db.post.find({"keywords":"/^clo/"}).pretty() When I tried to write same query using spring mongo.It not working properly. It gives result as % string %. i.e. matches anywhere in string. I am trying to match only at starting . my code is
String pattern = "/^" + keyword + "/";
Criteria criteria2 = Criteria.where("keywords").is(keyword).regex(pattern);
Where I am missing ?

You can do it like this:
Query.query(Criteria.where("keywords").regex("^clo"))
Or use it as native query:
new BasicQuery("{'keywords' : '/^clo/'}")
Method is() provides the full equals, regex() has to be without / wrappers.
That's is your issue.

Related

Search Query Parameter

I want to search email which contains '+' in it. for example
something like this myemail.subdomain+1#domain.com.
URL - https://example.com?searchKey=myemail.subdomain+1#
I am using Laravel, this parameter is fetched from route using
$request->get('searchKey');
but it's converting '+' to ' ' ,
as a result i am getting
searchKey as myemail.subdomain 1#
which leads to improper result.
Any help?
PHP assumes that + from GET request is a space. Right encoded plus symbol is %2B.
You have to just prepare string from request to save plus symbol:
$searchKey= urlencode(request()->get('searchKey'));
In your case you'll get # as %40. Then you can replace plus with correct code and decode it. But then be careful with usual spaces!
$searchKey = urlencode(request()->get('searchKey'));
$searchKey = urldecode(str_replace('+', '%2B', $searchKey));
https://www.php.net/manual/en/function.urlencode.php
https://www.php.net/manual/en/function.urldecode.php
P.S. I suppose it is not the best soulution, but it should work.
P.P.S. Or, if you can prepare plus as a %2B before it will be at search parameter, do it

Passing parameter to Match query in Neo4j using Spring

I am trying to compare node name from Neo4j database with given technology name. I am doing using Spring Application.
#Query("MATCH (n) WHERE n.name =~ '(?i){0}' RETURN n.name")
String getTechnology(String technologyname);
Request is like
MATCH (n)
WHERE n.name =~ '(?i){0}'
RETURN n.name
with params {0=AVM}.
But it's returning null. However, if I do it actual technology name it's working fine.
Pass the parameter as WHERE n.name =~ {0}. What's happening is that the parameter isn't substituted from within the string, so the parameter has no binding in the query, and instead you're searching for the string literal "{0}" which always fails.
If you want to pass a regex as a parameter, you'll need to put the "(?i)" part in the string getting passed, effectively letting your code decide the regex, not just a string inside of it.
You need to separate the regular expression part from the parameter part like this:
#Query("MATCH (n) WHERE n.name =~ '(?i)' + {0} RETURN n.name")
String getTechnology(String technologyname);
As You'd concatenate in Neo4j.

Jackrabbit XPath Query: UUID with leading number in path

I have what I think is an interesting problem executing queries in Jackrabbit when a node in the query path is a UUID that start with a number.
For example, this query work fine as the second node starts with a letter, 'f':
/*/JCP/feeadeaf-1dae-427f-bf4e-842b07965a93/label//*[#sequence]
This query however does not, if the first 'f' is replaced with '2':
/*/JCP/2eeadeaf-1dae-427f-bf4e-842b07965a93/label//*[#sequence]
The exception:
Encountered "-" at line 1, column 26.
Was expecting one of:
<IntegerLiteral> ...
<DecimalLiteral> ...
<DoubleLiteral> ...
<StringLiteral> ...
... rest omitted for brevity ...
for statement: for $v in /*/JCP/2eeadeaf-1dae-427f-bf4e-842b07965a93/label//*[#sequence] return $v
My code in general
def queryString = queryFor path
def queryManager = session.workspace.queryManager
def query = queryManager.createQuery queryString, Query.XPATH // fails here
query.execute().nodes
I'm aware my query, with the leading asterisk, may not be the best, but I'm just starting out with querying in general. Maybe using another language other than XPATH might work.
I tried the advice in this post, adding a save before creating the query, but no luck
Jackrabbit Running Queries against UUID
Thanks in advance for any input!
A solution that worked was to try and properly escape parts of the query path, namely the individual steps used to build up the path into the repository. The exception message was somewhat misleading, at least to me, as in made me think that the hyphens were part of the root cause. The root problem was that the leading number in the node name created an illegal XPATH query as suggested above.
A solution in this case is to encode the individual steps into the path and build the rest of the query. Resulting in the leading number only being escaped:
/*/JCP/_x0032_eeadeaf-1dae-427f-bf4e-842b07965a93//*[#sequence]
Code that represents a list of steps or a path into the Jackrabbit repository:
import org.apache.commons.lang3.StringUtils;
import org.apache.jackrabbit.util.ISO9075;
class Path {
List<String> steps; //...
public String asQuery() {
return steps.size() > 0 ? "/*" + asPathString(encodedSteps()) + "//*" : "//*";
}
private String asPathString(List<String> steps) {
return '/' + StringUtils.join(steps, '/');
}
private List<String> encodedSteps() {
List<String> encodedSteps = new ArrayList<>();
for (String step : steps) {
encodedSteps.add(ISO9075.encode(step));
}
return encodedSteps;
}
}
Some more notes:
If we escape more of the query string as in:
/_x002a_/JCP/_x0032_eeadeaf-1dae-427f-bf4e-842b07965a93//_x002a_[#sequence]
Or the original path encoded as a whole as in:
_x002f_a_x002f_fffe4dcf0-360c-11e4-ad80-14feb59d0ab5_x002f_2cbae0dc-35e2-11e4-b5d6-14feb59d0ab5_x002f_c
The queries do not produce the wanted results.
Thanks to #matthias_h and #LarsH
An XML element name cannot start with a digit. See the XML spec's rules for STag, Name, and NameStartChar. Therefore, the "XPath expression"
/*/JCP/2eeadeaf-1dae-427f-bf4e-842b07965a93/label//*[#sequence]
is illegal, because the name test 2eead... isn't a legal XML name.
As such, you can't just use any old UUID as an XML element name nor as a name test in XPath. However if you put a legal NameStartChar on the front (such as _), you can probably use any UUID.
I'm not clear on whether you think you already have XML data with an element named <2eead...> (and are trying to query that element's descendants); if so, whatever tool produced it is broken, as it emits illegal XML. On the other hand if the <2eead...> is something that you yourself are creating, then presumably you have the option of modifying the element name to be a legal XML name.

urlrewriting tuckey using Tuckey

My project (we have Spring 3) needs to rewrite URLs from the form
localhost:8888/testing/test.htm?param1=val1&paramN=valN
to
localhost:8888/nottestinganymore/test.htm?param1=val1&paramN=valN
My current rule looks like:
<from>^/testing/(.*/)?([a-z0-9]*.htm.*)$</from>
<to type="passthrough">/nottestinganymore/$2</to>
But my query parameters are being doubled, so I am getting param1=val1,val1 and paramN=valN,valN...please help! This stuff is a huge pain.
To edit/add, we have use-query-string=true on the project and I doubt I can change that.
The regular expression needs some tweaking. Tuckey uses the java regular expression engine unless specified otherwise. Hence the best way to deal with this is to write a small test case that will confirm if your regular expression is correct. For e.g. a slightly tweaked example of your regular expression with a test case is below.
#Test public void testRegularExpression()
{
String regexp = "/testing/(.*)([a-z0-9]*.htm.*)$";
String url = "localhost:8888/testing/test.htm?param1=val1&paramN=valN";
Pattern pattern = Pattern.compile(regexp);
Matcher matcher = pattern.matcher(url);
if (matcher.find())
{
System.out.println("$1 : " + matcher.group(1) );
System.out.println("$2 : " + matcher.group(2) );
}
}
The above will print the output as follows :
$1 : test
$2 : .htm?param1=val1&paramN=valN
You can modify the expression now to see what "groups" you want to extract from URL and then form the target URL.

How to query a Mongoid Regexp Field?

I want to create a regex field in my Mongoid document so that I can have a behavior something like this:
MagicalDoc.create(myregex: /abc\d+xyz/)
MagicalDoc.where(myregex: 'abc123xyz')
I'm not sure if this is possible and what kind of affect it would have. How can I achieve this sort of functionality?
Update: I've learned from the documentation that Mongoid supports Regexp fields but it does not provide an example of how to query for them.
class MagicalDoc
include Mongoid::Document
field :myregex, type: Regexp
end
I would also accept a pure MongoDB answer. I can find a way to convert it to Mongoid syntax.
Update: Thanks to SuperAce99 for helping find this solution. Pass a string to a Mongoid where function and it will create a javascript function:
search_string = 'abc123xyz'
MagicalDoc.where(%Q{ return this.myregex.test("#{search_string}") })
The %Q is a Ruby method that helps to escape quotes.
regexp is not a valid BSON type, so you'll have to figure out how Mongoid represents it to devise a proper query.
Query String using Regex
If you want to send MongoDB a regular expression and return documents MongoDB provides the $regex query operator, which allows you to return documents where a string matches your regular expression.
Query Regex using String
If you want to sent Mongo a string and return all documents that have a regular expression that matches the provided string, you'll probably need the $where operator. This allows you to run a Javascript command on each document:
db.myCollection.find( { $where: function() { return (this.credits == this.debits) } } )
You can define a function which returns True when the provided string matches the Regex stored in the document. Obviously this can't use an Index because it has to execute code for every document in the collection. These queries will be very slow.

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