Disable MDI child Form buttons - vb6

Is there possible to disable child's form buttons from parent form?
For example, I have 2 radio-buttons in parent form, one is True second False, when I choose one of them fires radiobutton.CheckedChanged event and there I have code what goes like this, but it's not working:
ChildForm.Button1.Enabled = False
where seems to be the problem? Can anyone help with this?

You would need to create an instance of the childform.
So...
ChildForm cf = new ChildForm();
cf.Button1.Enabled = false;
You have to keep in mind though, it could be a different instance than the child form that is currently being shown.
To be sure, depending on your code (which I can't see) and how your program is laid out I would probably do something like this...
ChildForm cf = new ChildForm();
cf.show();
cf.Button1.Enabled = false;
so here I know that the ChildForm that is showing is the one that has the button disabled.

In VB6 the following project works:
1 MDI form:
Option Explicit
Private Sub MDIForm_Click()
Form1.Option1.Enabled = False
End Sub
Private Sub MDIForm_Load()
Form1.Show
End Sub
Form1 is a MDI child form with 2 radio buttons on it

Related

Delphi form menus

So I have two menu's. When I click a button on menu 1, it creates menu 2, then menu 1 hides itself. After that I want to go back to menu 1 and hide menu 2.
How do I keep a reference to menu 1 in menu 2? Then if I want to go back to menu 2 I don't want to create a new instance, I want to use the already created one. How do I do that?
I know this may be easy but I find Delphi extremley confusing and can't seem to find a way out of it.
Thanks!
If you mean Main menu when you say "form menu" then you can have only one actual TMainMenu component on a form.
Dynamically creating a new TMainMenu is doable, but involves message handling to postpone the deletion of the exisiting TMainMenu to then be able to create a new one. The reason is that you can not delete a menu in the OnClick handler of one of the menu's items.
Let me suggest an easier way to achieve something similar by hiding / showing branches of a single TMainMenu as follows:
Drop a TMainMenu on the form and write menu items as usual. In my example I created two branches, one named MenuA and the other MenuB. Under these I added menu items, of which the first one (you are free to choose which one you use) activates the other menu branch and hides it's own branch. And visa versa for the other one.
Here's the menu part of the form in text view:
object MainMenu1: TMainMenu
Left = 112
Top = 48
object MenuA: TMenuItem
Caption = 'MenuA'
object Item11: TMenuItem
Caption = 'MenuB'
OnClick = Item11Click
end
object Item12: TMenuItem
Caption = 'Item12'
end
end
object MenuB: TMenuItem
Caption = 'MenuB'
object Item21: TMenuItem
Caption = 'MenuA'
OnClick = Item21Click
end
object Item22: TMenuItem
Caption = 'Item22'
end
object Item23: TMenuItem
Caption = 'Item23'
end
end
end
And here is the code for the menu clicks. Note that I make the second menu branch hidden in the forms OnCreate even. Instead, you can of course set the Visible property to False at design time, in the Object Inspector.
procedure TForm9.FormCreate(Sender: TObject);
begin
MenuB.Visible := False;
end;
procedure TForm9.Item11Click(Sender: TObject);
begin
MenuB.Visible := True;
MenuA.Visible := False;
end;
procedure TForm9.Item21Click(Sender: TObject);
begin
MenuB.Visible := False;
MenuA.Visible := True;
end;

vb2013 exit from local sub closes form

I have a local sub that allows the user to move a row of a datagridview, triggered by a button click. The sub works fine in debugger but when it exits control is transfered to the calling form, i.e. the current form is closed. This also happens when no row is moved, i.e. when one of the abort conditions on entrance are met. Simply: exiting this sub will close the form!?!
Private Sub btnMove_Click(sender As Object, e As EventArgs) Handles btnMove.Click
Dim rowToGo As DataGridViewRow
Dim rtgIndex As Integer = 0
If (dgvAuftrag.RowCount <= 1) or (dgvAuftrag.CurrentRow Is Nothing) Then
Beep()
Exit Sub
End If
rowToGo = dgvAuftrag.CurrentRow
rtgIndex = rowToGo.Index + 1
If (rtgIndex >= dgvAuftrag.RowCount) Then rtgIndex = 0
Try
dgvAuftrag.Rows.Remove(rowToGo)
dgvAuftrag.Rows.Insert(rtgIndex, rowToGo)
Catch ex As Exception
IssueErrorMessage(ex)
End Try
End Sub
All other local subs and functions work normal, just this one behaves strange. Any ideas how to fix/avoid this bug?
This is not a solution of the problem but a functioning workaround based on the sugestion of Hans. I have introduced a global boolean var named OKtoExit which is intialized to false.
private OKtoExit as boolean = false
Then I have a new FormClose event handler that checks that var. If OKtoExit is false then e.Cancel = true and the handler exits. The regular Exit functions (Save and Quit) set OKtoExit to true, any other code leaves the values unchanged.
Private Sub Current_FormClosing(sender As Object, e As FormClosingEventArgs) Handles MyBase.FormClosing
If Not exitOK Then
e.Cancel = True
Exit Sub
End If
End Sub
As I said, this is just a workaround that has the same effect as a normal functioning VB-Code. I would appreciate if somebody could present a real solution!
After many months I discovered the true reason for the problem and I must give all credits to Hans Passant: I had a button on one of the first forms that had the Dialog Result property set to Cancel. This was a really beautyful button so many other buttons in the appliaction were a copy of this first button where I just modified the label. Thus they all led to the unwanted behavior that a form was closed as soon as a user clicked one of them no matter what the label said... After months I discovered that just by chance. Thanks to Hans again, I obviously overlooked his last hint "And look at the button's DialogResult property."!

Outlook 2013 Addin: Change Ribbon Button Image on click of button using c#

I have created Ribbon button for Outlook 2013 using c#.
And i have also set image for the ribbon.
Now on click of Ribbon button i want to change Ribbon Image.
Is it possible to achieve this using c#.?
Not sure how exactly you want it to work, but this could do the trick.
bool callback {get;set}
public Bitmap GetImage(IRibbonControl control)
{
switch (control.Id)
{
case "FooButtonId":
{
if(callback== true){
callback = false;
return new Bitmap(Properties.Resources.someimage1);
}else
callback =true;
return new Bitmap(Properties.Resources.someimage2);
}
}
}
}
This question is 3 yo but helped me to go further and I want to share this with you.
First, I accomplished this in VB.net so my code will be in VB.net. There are some online tools to convert the code into C#.
Second, I used a Toggle button instead of a Simple button.
Third, I used OnOff as a project setting in order to save the state of the Toggle button.
Step 1: Ribbon.xml file, code to place the toggle button on the ribbon.
Assuming you already have set up the tab and group tags in the file.
<toggleButton id="onoffTBTN" label="ON/OFF" showImage="true" onAction="OnOffToggle" getImage="OnOffImage"/>
Step 2: Ribbon.vb file, code to change the OnOff setting based on the Toggle button status(pressed or not) and forces to invalidate the custom control
Public Sub OnOffToggle(ByVal control As Office.IRibbonControl, ByVal pressed As Boolean)
My.Settings.OnOff = pressed
My.Settings.Save()
myRibbon.InvalidateControl("onoffTBTN")
End Sub
Step 3: Ribbon.vb file, reads the OnOff setting and changes the image accordingly. Have in mind that your images must have been added to your project resources in order to use them at My.Resources.*. I used png files that support transparent pixels. This function is called in two occasions, first when the Outlook starts and second when the toggle button is pressed and specifically with the command myRibbon.InvalidateControl("onoffTBTN").
Public Function OnOffImage(ByVal control As Office.IRibbonControl) As Drawing.Bitmap
Dim onoff As Boolean = My.Settings.OnOff
Select Case control.Id
Case "onoffTBTN"
If onoff = True Then
Return New Drawing.Bitmap(My.Resources._on)
Else
Return New Drawing.Bitmap(My.Resources.off)
End If
End Select
End Function
The only weird behaviour is when the OnOff setting has been set to TRUE. The correct image is displayed but the Toggle button looks unpressed. You have to click twice in order to set the OnOff setting to False.

Click and CheckStateChanged VB6

According to Microsoft:
"In Visual Basic 6.0, the Click event is raised when the CheckBox state is changed programmatically. "
and this is exactly what i do not want.
I want click event only raise when i click on the checkbox and not when the state is changed.
Any idea how to do it ?
Thank you
you can set a flag when you are populating the form from code to ignore changes. This can get messy if the code is not organized well.
Form Level:
Public IgnoreChange As Boolean
Form Load:
IgnoreChange = False
Event:
If IgnoreChange Then Exit Sub
Your code:
frmReference.IgnoreChange = True
frmReference.Checkbox1.Checked = True
frmReference.IgnoreChange = False
Code should only respond to user actions
Not sure if it's the best way, but one way would be to have a variable called something like IgnoreEvents and set that to true right before changed the state programmatically.
Then in the event handler if that variable is true, you just exit the event handler without doing anything.
Put your Click event code in the MouseDown event instead. You'll have to manually set the checkstate though:
Private Sub Check1_MouseDown(Button As Integer, Shift As Integer, X As Single, Y As Single)
Check1.Value = IIf(Check1.Value = vbChecked, vbUnchecked, vbChecked)
' run other necessary code here
End Sub

get cursor position another form in windows application

I have two form in my application i am calling two form together from master page.i wrote code in my master page
in top i declared like this
Dim form As New FrmDelivary
Dim frm1 As New FrmrecievedDelivaryRequest
in toolstrip menu event like this:
Dim frm1 As New FrmrecievedDelivaryRequest
frm1.Location = New Point(625, 225)
frm1.MdiParent = Me
frm1.Show()
Dim frm2 As New FrmDelivary
frm2.Location = New Point(965, 0)
frm2.MdiParent = Me
frm.show()
if i press R i want to go my cursor the particular textbox of FrmrecievedDelivaryRequest
if i press D i want to go my cursor the particular textbox of FrmDelivary
How can I do this? i trey something like this in frmMaster_KeyDown event: but same page is showing again. I have already open instance of FrmDelivary, so I don't want to show same page again. I want to just get cursor position to particular textbox of this form
If e.KeyCode = Keys.A Then
form.Show()
form.txtTicket.Focus()
Cursor.Position = form.txtTicket.Location
end if
I am working on vb.net windows application
After
frm1.Show()
place
frm1.txtTicket.Focus()
I don't think you need the Cursor.Position call
Set your frm1 and frm2 variables at the top of the code window so they are accessible from all of the Subs. In your KeyDown event, put
If e.KeyCode = Keys.A Then
frm1.Show()
frm1.txtTicket.Focus()
Cursor.Position = frm1.txtTicket.Location
end if
The problem is that you are instantiating a new copy of the form with the "AS NEW frmDelivery" statement.

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