So I have two menu's. When I click a button on menu 1, it creates menu 2, then menu 1 hides itself. After that I want to go back to menu 1 and hide menu 2.
How do I keep a reference to menu 1 in menu 2? Then if I want to go back to menu 2 I don't want to create a new instance, I want to use the already created one. How do I do that?
I know this may be easy but I find Delphi extremley confusing and can't seem to find a way out of it.
Thanks!
If you mean Main menu when you say "form menu" then you can have only one actual TMainMenu component on a form.
Dynamically creating a new TMainMenu is doable, but involves message handling to postpone the deletion of the exisiting TMainMenu to then be able to create a new one. The reason is that you can not delete a menu in the OnClick handler of one of the menu's items.
Let me suggest an easier way to achieve something similar by hiding / showing branches of a single TMainMenu as follows:
Drop a TMainMenu on the form and write menu items as usual. In my example I created two branches, one named MenuA and the other MenuB. Under these I added menu items, of which the first one (you are free to choose which one you use) activates the other menu branch and hides it's own branch. And visa versa for the other one.
Here's the menu part of the form in text view:
object MainMenu1: TMainMenu
Left = 112
Top = 48
object MenuA: TMenuItem
Caption = 'MenuA'
object Item11: TMenuItem
Caption = 'MenuB'
OnClick = Item11Click
end
object Item12: TMenuItem
Caption = 'Item12'
end
end
object MenuB: TMenuItem
Caption = 'MenuB'
object Item21: TMenuItem
Caption = 'MenuA'
OnClick = Item21Click
end
object Item22: TMenuItem
Caption = 'Item22'
end
object Item23: TMenuItem
Caption = 'Item23'
end
end
end
And here is the code for the menu clicks. Note that I make the second menu branch hidden in the forms OnCreate even. Instead, you can of course set the Visible property to False at design time, in the Object Inspector.
procedure TForm9.FormCreate(Sender: TObject);
begin
MenuB.Visible := False;
end;
procedure TForm9.Item11Click(Sender: TObject);
begin
MenuB.Visible := True;
MenuA.Visible := False;
end;
procedure TForm9.Item21Click(Sender: TObject);
begin
MenuB.Visible := False;
MenuA.Visible := True;
end;
Related
I have a listbox (ListBox1) and a button (Button1). When I click on the button, a new item is added to the listbox. If I click on the newly added item, it is highlighted. If I add another item to the listbox, the previously selected item is still highlighted. I want it so that the item that I add gets highlighted (selected) automatically.
How do I do this?
Thanks in advance.
Assign the ItemIndex property of the list box. For example...
ListBox1.ItemIndex := ListBox1.Items.Count-1;
The -1 is because lists are 0 based.
Alternatively, you can obtain the index of the new item directly when you call Add(), so...
var
I: Integer;
begin
I:= ListBox1.Items.Add('Some Value');
ListBox1.ItemIndex := I;
end;
Or even more simple:
ListBox1.ItemIndex := ListBox1.Items.Add('Some Value');
In Eclipse E4 (Luna), using the application model to create parts, handlers, commands, handled menu items etc, (these are not created programatically). I have a toolbar. This contains a sub-Menu item called "Filter" that contains another sub-menu of two filters. The two filters are two Handled Menu Items which are set up as "Radio" Buttons.
When I select the appropriate in the UI of my running app from the selection, the Radio button switches just fine to the selected Item. However I would like this selection to update (deselecting one Radio button and selecting the appropriate radio button of the handled menu item) when my ViewPart changes through other UI selection. Currently my ViewPart updates, but the Radio buttons are on the same previous selection through the UI.
Is there a way in which I get access both Handled Menu Item's IDs and set the selection (one to false, the other to true) when the viewer is updated.
Image of design is attached below:
Hierarchy of the application model is as follows:
Thanks in advance,
Marv
You can use the model service to find menu items. Use something like:
#Inject
EModelService modelService;
#Inject
MApplication app;
List<MMenuItem> items = modelService.findElements(app, "menu item id", MMenuItem.class, Collections.emptyList(), EModelService.IN_MAIN_MENU);
Once you have the MMenuItem you can call the setSelected(boolean) method to change the selection.
To find a menu item which is in a Part menu use:
modelService.findElements(app, "menu item id", MMenuItem.class, Collections.emptyList(), EModelService.IN_PART);
(IN_PART argument instead of IN_MAIN_MENU).
You could also specify the MPart rather than the Application as the first argument to findElements which may speed up the search.
For menus as a child of a Tool Bar Item it appears that the model services cannot find these directly. However you can find the Tool Bar Item and look at the menu yourself:
List<MToolItem> items = modelService.findElements(app, "tool bar item id", MToolItem.class, Collections.emptyList(), EModelService.IN_PART);
MToolItem item = items.get(0);
MMenu menu = item.getMenu();
List<MMenuElement> children = menu.getChildren();
... search menu elements
I solved this by starting with MPart PartID and drilling down to the HandledMenuItems on which I wanted to set the Radio Button selections, then setting the selection property for each individual HandledMenuItem.
This can probably be refactored to be more concise, but I've left the code with each step to have the solution easier to read.
BTW, in every instance / combination of the EModelService methods, the list returned a size of 0. So I'm not certain if that will work for what I'm trying to achieve. The following does work, although I'm not certain it is the most efficient means.
I hope this helps others.
// Get view part
MPart viewPart = _partService.findPart("part_id");
// get list of all menu items from the Part
List<MMenu> viewPartMenu = viewPart.getMenus();
// Get list of ViewMenus from viewPartMenu there is only one View Menu so it will be index 0
MMenu viewMenu = viewPartMenu .get(0);
// Get list of MMenuElements from the viewMenu - the children in the view menu
List<MMenuElement> viewMenuElements = viewMenu.getChildren();
// This gets me to the 2 HandledMenuItems
// Upper Most HandledMenuItem Radio Button is at viewMenuElements index 0. This is cast to MHandledMenuItem
MHandledMenuItem upperHandledMenuItem = (MHandledMenuItem) viewMenuElements.get(0);
// Set Selection
upperHandledMenuItem.setSelected(false);
// Lower Most HandledMenuItem Radio Button is at viewMenuElements index 1. This is cast to MHandledMenuItem
MHandledMenuItem lowerHandledMenuItem = (MHandledMenuItem) viewMenuElements.get(1);
// Set selection
lowerHandledMenuItem.setSelected(true);
I'm building multiplatform( iOS, Android, OSX, Windows APP) in Firemonkey. One of the things I'm trying to do is create a custom listbox item( with more data elements) that will work on all these platforms:
will give you ability to select item(s), display properly.
According to research I did, probably the best way for this is to create custom style for list box item and define data elements there. That's what I did.
I'm creating items from client dataset in this procedure:
procedure TMasterDetailForm.LoadAvailable;
var i: Integer;
Item: TListBoxItem;
begin
lstAvailable.Clear;
//Add Header
lstAvailable.BeginUpdate;
Item := TListBoxItem.Create( lstAvailable );
Item.Parent := lstAvailable;
Item.Height := 70;
//Item.OnApplyStyleLookup := ListItemApplyStyleLookupHandler;
Item.StyleLookup := AvailableListHeaderStyle;
//Add Details
cdsAvailable.First;
for I := 1 to cdsAvailable.RecordCount do
begin
Item := TListBoxItem.Create( lstAvailable );
Item.Parent := lstAvailable;
Item.Height := 50;
//Item.Selectable := True;
//Item.OnApplyStyleLookup := ListItemApplyStyleLookupHandler;
Item.StyleLookup := AvailableListItemStyle;
//Item.StyleLookup := 'ListboxItem1Style1';
Item.StylesData[ txtWoNum ] := cdsAvailable.FieldByName( 'work package' ).AsString;
Item.StylesData[ txtAircraft ] := cdsAvailable.FieldByName('aircraft').AsString;
Item.StylesData[ txtTaskDescription ] := cdsAvailable.FieldByName('task').AsString;
cdsAvailable.Next;
end;
lstAvailable.EndUpdate;
end;
Everything gets styled properly on all platforms, except that tapping(clicking) on ListBoxItem on Android or iOS, doesn't highlight the ListBoxItem. If I unissign style then selecting items also works.I can't figure out how to fix this.
Btw, onclick event on ListBox seems to work properly( itemindex changes).
Any input will be greatly appreciated.
Edit( 12/12/2014) : I tried simplifying the example by adding items manually in the ListBox editor and discarding this code here, and I found out that animation for selecting the listbox item changes. So, I customized the listbox item and only changed TextColor to blue. In runtime on Android when you select the listbox item it just changes the color of the text to black instead of painting the whole row. Any ideas how to have listbox behave in similar way like when there is no style attached to it?
Sorry my english is bad.
I have a solution (tested in XE7):
Open a form
Change the IDE Style to "iOS"
Select the TListBox an open a context menu and select "Edit Default
Style": the StyleBook2 is created.
Add a TRectangle component in the style "listboxstyle/background"
with the name "selection". This is the magic!
Now, Firemonkey found the 'selection' component and work fine!
If you already have StyleBook2 component before these steps, you may need to delete it, be careful!
Is there possible to disable child's form buttons from parent form?
For example, I have 2 radio-buttons in parent form, one is True second False, when I choose one of them fires radiobutton.CheckedChanged event and there I have code what goes like this, but it's not working:
ChildForm.Button1.Enabled = False
where seems to be the problem? Can anyone help with this?
You would need to create an instance of the childform.
So...
ChildForm cf = new ChildForm();
cf.Button1.Enabled = false;
You have to keep in mind though, it could be a different instance than the child form that is currently being shown.
To be sure, depending on your code (which I can't see) and how your program is laid out I would probably do something like this...
ChildForm cf = new ChildForm();
cf.show();
cf.Button1.Enabled = false;
so here I know that the ChildForm that is showing is the one that has the button disabled.
In VB6 the following project works:
1 MDI form:
Option Explicit
Private Sub MDIForm_Click()
Form1.Option1.Enabled = False
End Sub
Private Sub MDIForm_Load()
Form1.Show
End Sub
Form1 is a MDI child form with 2 radio buttons on it
I have two form in my application i am calling two form together from master page.i wrote code in my master page
in top i declared like this
Dim form As New FrmDelivary
Dim frm1 As New FrmrecievedDelivaryRequest
in toolstrip menu event like this:
Dim frm1 As New FrmrecievedDelivaryRequest
frm1.Location = New Point(625, 225)
frm1.MdiParent = Me
frm1.Show()
Dim frm2 As New FrmDelivary
frm2.Location = New Point(965, 0)
frm2.MdiParent = Me
frm.show()
if i press R i want to go my cursor the particular textbox of FrmrecievedDelivaryRequest
if i press D i want to go my cursor the particular textbox of FrmDelivary
How can I do this? i trey something like this in frmMaster_KeyDown event: but same page is showing again. I have already open instance of FrmDelivary, so I don't want to show same page again. I want to just get cursor position to particular textbox of this form
If e.KeyCode = Keys.A Then
form.Show()
form.txtTicket.Focus()
Cursor.Position = form.txtTicket.Location
end if
I am working on vb.net windows application
After
frm1.Show()
place
frm1.txtTicket.Focus()
I don't think you need the Cursor.Position call
Set your frm1 and frm2 variables at the top of the code window so they are accessible from all of the Subs. In your KeyDown event, put
If e.KeyCode = Keys.A Then
frm1.Show()
frm1.txtTicket.Focus()
Cursor.Position = frm1.txtTicket.Location
end if
The problem is that you are instantiating a new copy of the form with the "AS NEW frmDelivery" statement.