i am new to bash script. so,i need help. Below command print out USB serial number. But i don't how to store it in a string. Because i want to compare with other string to see if they are match.The other string can be any string. so, if someone can help me write the code,i would very much appreciate. Thanks in Advanced.
lsusb -v | awk '/iSerial/ {if ($2 == "3" || $2 == "2") {print $3}}'
anubhava, would this be right if i want to compare two strings.
#!/bin/sh
string="asd11ds"
output=$(lsusb -v | awk '/iSerial/ && ($2 == "3" || $2 == "2")) {print $3}')
echo $output
if [[$output==$string]];then
echo"the two string are the same/are different"
fi
You use $(...) notation (command substitution) to store a command's output.
You awk can also be shortened:
output=$(lsusb -v | awk '/iSerial/ && ($2 == "3" || $2 == "2")) {print $3}')
since your question tag is bash, I provide bash script
#!/usr/bin/env bash
string="asd11ds"
output=$(lsusb -v | awk '/iSerial/ && ($2 == "3" || $2 == "2")) {print $3}')
echo $output
if [[ "$output" == "$string" ]]; then
echo "the two strings are same"
else
echo "the two strings are different"
fi
Related
Would it be possible to print the filename used to redirect STDERR, given the sample command below:
command.sh 2>file.err
Code in command.sh:
#!/bin/sh
ls -l non_existing_file.txt
echo "STDERR file is: $stderrFilename" # variable should print file.err
It's a little risky, but you could try parsing AIX's procfiles output. It involves capturing the major and minor numbers of the stderr device, along with the inode number, then looking for the corresponding device, its mountpoint, and then using find to look for the file with the given inode number:
#!/bin/sh
dev=$(procfiles $$ | awk '$1 == "2:" { print substr($4, 5) }')
inode=$(procfiles $$ | awk '$1 == "2:" { print substr($5, 5) }')
major=${dev%%,*}
minor=${dev##*,}
if [ "$major}" -eq 0 ]
then
echo I give up, the major number is zero
exit 1
fi
for file in /dev/*
do
[ -b "$file" ] || continue
if istat "$file" | grep -q "^Major Device ${major}.*Minor Device ${minor}$"
then
break
fi
done
fs=$(mount | awk '$1 == "'"${file}"'" { print $2 }')
stderrFilename=$(find "$fs" -inum "$inode")
I made a solution using history. Not sure if there is an easier way to do this ( or a proper one).
#!/bin/sh
stderrfname=`history | tail -1 | awk '{ print $3 }' | sed "s/.*>//"`
echo "STDERR file is: $stderrfname"
This is a part of my shell script.
for line in `cat $1`
do
startNum=`echo $line | awk -F "," '{print $1}'`
endNum=`echo $line | awk -F "," '{print $2}'`
operator=`echo $line | awk -F "," '{print $3}'`
termPrefix=`echo $line | awk -F "," '{print $4}'`
if [[ "$endNum" == 81* ]] || [[ "$endNum" == 33* ]] || [[ "$endNum" == 55* ]]
then
areaCode="${endNum:0:2}"
series="${endNum:2:4}"
startCLI="${startNum:6:4}"
endCLI="${endNum:6:4}"
else
areaCode="${endNum:0:3}"
series="${endNum:3:3}"
startCLI="${startNum:6:4}"
endCLI="${endNum:6:4}"
fi
echo "Add,${areaCode},${series},${startCLI},${endCLI},${termPrefix},"
#>> ${File}
done
input is csv contains below many rows :
5557017101,5557017101,102,1694
5515585614,5515585614,102,084
Output od shell script :
,dd,55,5701,7101,7101,1694
,dd,55,1558,5614,5614,0848
Not sure why comma is coming in startign of output, instead as per shell script it should come in the end.
please help
Here is a suggested awk command that should replace all of your shell+awk code. This awk also takes care of trailing \r:
awk -v RS=$'\r' 'BEGIN{FS=OFS=","} NF>3{
startNum=$1; endNum=$2; termPrefix=$4;
if (endNum ~ /^(81|33|55)/) {
areaCode=substr(endNum,1,2); series=substr(endNum,3,4)
}
else {
areaCode=substr(endNum,1,3); series=substr(endNum,4,3)
}
startCLI=substr(startNum,7,4); endCLI=substr(endNum,7,4);
print "Add", areaCode, series, startCLI, endCLI, termPrefix
}' file
Add,55,5701,7101,7101,1694
Add,55,1558,8561,5614,084
I have this until now:
if [[ $1 = "-s" ]] && [[ $2 =~ ^[0-9]+$ ]]
echo "ok"
for $2 = 1 awk {print $1} something.txt
fi
What I want is, for example, when I enter -s 2, to list the second word of every line first!
I already know the for part is wrong.
Replace
for $2 = 1 awk {print $1} something.txt
by
awk -v var="$2" '{print $var}' something.txt
I need to look at a line, and perform a quick if/then->echo on it depending on the content of column 3.
The file looks like this:
name network subnetmask
net_A 192.168.0.0 24
net_b 10.10.0.0 16
Some columns also have a blank 3rd column, and I need to have an if/then for those as well.
Psuedo-code should look like this in my mind:
snet_mask=`cat $filename | grep -i net | awk '{print $3}`
if [ $snet_mask = 24 ]
then
awk '{print "something"$1,"something else"}'
fi
if [ $snet_mask = 23 ]
then
awk '{print "something"$1,"something else"}'
fi
etc
That just doesn't work it seems, since $snet_mask becomes the value of "all" of $3, so I think I need a for loop based on grep -i net, however I don't really know.
What's the right answer? :)
Try this one-liner :
awk '$1 ~ "^net" && $3==24{print "something", $3, "something else"} $1 ~ "^net" $3==23{print "something", $3, "something else"}' file.txt
Or on multi-lines (easier to read) :
awk '
$1 ~ "^net" && $3==24{print "something", $3, "something else"}
$1 ~ "^net" && $3==23{print "something", $3, "something else"}
' file.txt
We can do it simply like this too (depends of your needs) :
awk '
$1 ~ "^net" && ($3==24 || $3==23) {print "something", $3, "something else"}
' file.txt
Or even simpler & shortest with a regex :
awk '
$1 ~ "net" && $3 ~ "^2[34]$" {print "something", $3, "something else"}
' file.txt
you could accomplish what you need in an awk statement, since you're already using awk
cat $filename | grep -i net | awk '{if($3==24) print $1; else print $0;}'
In the if statement (if 3rd col is 23), I'm printing just the first column, otherwise I'm printing everything. Obviously you can expand this to work with all of your cases
Staying in bash without external tools, you could do something like this:
while read name network netmask ; do
if [[ "$name" == net* ]] ; then
case "$netmask" in
"") echo "It's empty" ;;
24) echo "It's 24" ;;
23) echo "It's 23" ;;
*) echo "None of the above" ;;
esac
fi
done < "$filename"
I am trying to extract the highest number from $countip and copy it to $totalip, the problem is that $totalip is allways returning 0. Can anybody help me please, i am new to bash script.
for srcip in `cat /var/log/messages | grep "WACSLAW1 CRITICAL INCOMING" | awk '{ print $14 }'|grep -v 192.168.1. |grep -v IN=eth1 |grep -v MAC`;do
if (! grep "$srcip" /var/wacstemp/ids.tmp > /dev/null) ; then
countip=0
echo $srcip >> /var/wacstemp/ids.tmp
else
countip=`expr $countip + 1`
if [ $countip -gt $totalip ];
then
# echo $countip
countip=$totalip
# echo $totalip
fi
fi
done
You must switch
countip=$totalip
to
totalip=$countip
otherwise totalip will never be updated.
OT: You could simplify the initial filter to
awk '/WACSLAW1 CRITICAL INCOMING/ && $14 !~ /192.168.1./ && $14 !~ /IN=eth1/ && $14 !~ /MAC/ { print $14 }' /var/log/messages