I have this until now:
if [[ $1 = "-s" ]] && [[ $2 =~ ^[0-9]+$ ]]
echo "ok"
for $2 = 1 awk {print $1} something.txt
fi
What I want is, for example, when I enter -s 2, to list the second word of every line first!
I already know the for part is wrong.
Replace
for $2 = 1 awk {print $1} something.txt
by
awk -v var="$2" '{print $var}' something.txt
Related
This is a part of my shell script.
for line in `cat $1`
do
startNum=`echo $line | awk -F "," '{print $1}'`
endNum=`echo $line | awk -F "," '{print $2}'`
operator=`echo $line | awk -F "," '{print $3}'`
termPrefix=`echo $line | awk -F "," '{print $4}'`
if [[ "$endNum" == 81* ]] || [[ "$endNum" == 33* ]] || [[ "$endNum" == 55* ]]
then
areaCode="${endNum:0:2}"
series="${endNum:2:4}"
startCLI="${startNum:6:4}"
endCLI="${endNum:6:4}"
else
areaCode="${endNum:0:3}"
series="${endNum:3:3}"
startCLI="${startNum:6:4}"
endCLI="${endNum:6:4}"
fi
echo "Add,${areaCode},${series},${startCLI},${endCLI},${termPrefix},"
#>> ${File}
done
input is csv contains below many rows :
5557017101,5557017101,102,1694
5515585614,5515585614,102,084
Output od shell script :
,dd,55,5701,7101,7101,1694
,dd,55,1558,5614,5614,0848
Not sure why comma is coming in startign of output, instead as per shell script it should come in the end.
please help
Here is a suggested awk command that should replace all of your shell+awk code. This awk also takes care of trailing \r:
awk -v RS=$'\r' 'BEGIN{FS=OFS=","} NF>3{
startNum=$1; endNum=$2; termPrefix=$4;
if (endNum ~ /^(81|33|55)/) {
areaCode=substr(endNum,1,2); series=substr(endNum,3,4)
}
else {
areaCode=substr(endNum,1,3); series=substr(endNum,4,3)
}
startCLI=substr(startNum,7,4); endCLI=substr(endNum,7,4);
print "Add", areaCode, series, startCLI, endCLI, termPrefix
}' file
Add,55,5701,7101,7101,1694
Add,55,1558,8561,5614,084
Say i have:
> id|lastName|firstName|gender|birthday|creationDate|locationIP|browserUsed
>
> 13194139534963|Berty|Jean|male|1988-08-02|2012-04-02T08:33:15.012+0000|41.216.190.153|Google
> Chrome
>
> 13194139535544|Oliveira|Manuel|male|1984-10-31|2012-03-14T16:00:12.287+0000|109.71.166.230|Internet
> Explorer
>
> 13194139537327|Wei|Lei|male|1987-01-06|2012-03-13T03:07:51.899+0000|27.99.188.150|Internet
> Explorer
>
> 13194139539118|Alvarez|Monica|male|1989-10-17|2012-02-25T19:18:54.137+0000|190.169.213.242|Internet
> Explorer
>
> 13194139539746|Xu|Wei|female|1986-11-30|2012-03-19T23:16:12.495+0000|27.103.77.193|Firefox
I want to make a command with those parameters : ./tool.sh --born-since dateA --born-until dateB -f file
1)If born-since and born-until dates are given i want to print all those born(the whole line)between two specific dates ( Year-Month-Date )
Example
./tool.sh --born-since 1988-08-02 --born-until 2012-09-13 -f file
Output:
13194139534963|Berty|Jean|male|1988-08-02|2012-04-02T08:33:15.012+0000|41.216.190.153|Google
13194139539118|Alvarez|Monica|male|1989-10-17|2012-02-25T19:18:54.137+0000|190.169.213.242|Internet
Explorer
2)If only born-since date is given i want to list all the people(whole line) with born dates of that and after.
Example:
./tool.sh --born-since 1988-08-02 -f file
Output:
Same as 1)
3)If only born-until date is given i want to list all the people born until that date(again the whole line about them).
./tool.sh --born-until 1988-08-02 -f file
Output:
13194139535544|Oliveira|Manuel|male|1984-10-31|2012-03-14T16:00:12.287+0000|109.71.166.230|Internet Explorer
13194139537327|Wei|Lei|male|1987-01-06|2012-03-13T03:07:51.899+0000|27.99.188.150|Internet Explorer
13194139539746|Xu|Wei|female|1986-11-30|2012-03-19T23:16:12.495+0000|27.103.77.193|Firefox
My code is :
while [ $# -gt 0 ];do #Get and store Dates (Since-Until)
if [ "$1" = --born-since ];then
if [[ "$2" =~ $re ]];then #re='[0-9]-*' # Check if $2 is number
BSDate=$2
BSYear=$(echo "$BSDate" | awk -F '-' '{print $1}') # Get BSYear
BSMonth=$(echo "$BSDate" | awk -F '-' '{print $2}') # Get BSMonth
BSDay=$(echo "$BSDate" | awk -F '-' '{print $3}') # Get BSDay
fi
elif [ "$1" = --born-until ];then
if [[ "$2" =~ $re ]];then
BUDate=$2
BUYear=$(echo "$BUDate" | awk -F '-' '{print $1}') # Get BUYear
BUMonth=$(echo "$BUDate" | awk -F '-' '{print $2}') # Get BUMonth
BUDay=$(echo "$BUDate" | awk -F '-' '{print $3}') # Get BUDay
fi
fi
shift
done
if [ "$BSDate" ] && [ "$BUDate" ];then #If both date arguments exist
elif [ "$BSDate" ];then
elif [ "$BUDate" ];then
fi
If i enter --born-since 1998-10-30 the arguments get passed correctly for evaluation in awk , 1998 = BSYear , 10 = BSMonth , 30 = BSDay. Can someone help me implement the awk part ?
For the awk part :
cat ./tool.sh
awk -F'|' -vs="$1" -ve="$2" '
BEGIN{if(!s)s="0000-00-00";if(!e)e="9999-99-99"}
NR>1 && $5>=s && $5<=e' infile
And you call it like that
./tool.sh '1987-01-06' '1988-08-02'
or
./tool.sh '' '1988-08-02'
or
./tool.sh '1987-01-06' ''
I fixed it with : awk -F'|' '{if ($5 >= "'$BSDate'" && $5 <= "'$BUDate'")
i am new to bash script. so,i need help. Below command print out USB serial number. But i don't how to store it in a string. Because i want to compare with other string to see if they are match.The other string can be any string. so, if someone can help me write the code,i would very much appreciate. Thanks in Advanced.
lsusb -v | awk '/iSerial/ {if ($2 == "3" || $2 == "2") {print $3}}'
anubhava, would this be right if i want to compare two strings.
#!/bin/sh
string="asd11ds"
output=$(lsusb -v | awk '/iSerial/ && ($2 == "3" || $2 == "2")) {print $3}')
echo $output
if [[$output==$string]];then
echo"the two string are the same/are different"
fi
You use $(...) notation (command substitution) to store a command's output.
You awk can also be shortened:
output=$(lsusb -v | awk '/iSerial/ && ($2 == "3" || $2 == "2")) {print $3}')
since your question tag is bash, I provide bash script
#!/usr/bin/env bash
string="asd11ds"
output=$(lsusb -v | awk '/iSerial/ && ($2 == "3" || $2 == "2")) {print $3}')
echo $output
if [[ "$output" == "$string" ]]; then
echo "the two strings are same"
else
echo "the two strings are different"
fi
Good day,
I was wondering how to pass the filename to awk as variable, in order to awk read it.
So far I have done:
echo file1 > Aenumerar
echo file2 >> Aenumerar
echo file3 >> Aenumerar
AE=`grep -c '' Aenumerar`
r=1
while [ $r -le $AE ]; do
lista=`awk "NR==$r {print $0}" Aenumerar`
AEList=`grep -c '' $lista`
s=1
while [ $s -le $AEList ]; do
word=`awk -v var=$s 'NR==var {print $1}' $lista`
echo $word
let "s = s + 1"
done
let "r = r + 1"
done
Thanks so much in advance for any clue or other simple way to do it with bash command line
Instead of:
awk "NR==$r {print $0}" Aenumerar
You need to use:
awk -v r="$r" 'NR==r' Aenumerar
Judging by what you've posted, you don't actually need all the NR stuff; you can replace your whole script with this:
while IFS= read -r lista ; do
awk '{print $1}' "$lista"
done < Aenumerar
(This will print the first field of each line in each of file1, file2, file3. I think that's what you're trying to do?)
I need to look at a line, and perform a quick if/then->echo on it depending on the content of column 3.
The file looks like this:
name network subnetmask
net_A 192.168.0.0 24
net_b 10.10.0.0 16
Some columns also have a blank 3rd column, and I need to have an if/then for those as well.
Psuedo-code should look like this in my mind:
snet_mask=`cat $filename | grep -i net | awk '{print $3}`
if [ $snet_mask = 24 ]
then
awk '{print "something"$1,"something else"}'
fi
if [ $snet_mask = 23 ]
then
awk '{print "something"$1,"something else"}'
fi
etc
That just doesn't work it seems, since $snet_mask becomes the value of "all" of $3, so I think I need a for loop based on grep -i net, however I don't really know.
What's the right answer? :)
Try this one-liner :
awk '$1 ~ "^net" && $3==24{print "something", $3, "something else"} $1 ~ "^net" $3==23{print "something", $3, "something else"}' file.txt
Or on multi-lines (easier to read) :
awk '
$1 ~ "^net" && $3==24{print "something", $3, "something else"}
$1 ~ "^net" && $3==23{print "something", $3, "something else"}
' file.txt
We can do it simply like this too (depends of your needs) :
awk '
$1 ~ "^net" && ($3==24 || $3==23) {print "something", $3, "something else"}
' file.txt
Or even simpler & shortest with a regex :
awk '
$1 ~ "net" && $3 ~ "^2[34]$" {print "something", $3, "something else"}
' file.txt
you could accomplish what you need in an awk statement, since you're already using awk
cat $filename | grep -i net | awk '{if($3==24) print $1; else print $0;}'
In the if statement (if 3rd col is 23), I'm printing just the first column, otherwise I'm printing everything. Obviously you can expand this to work with all of your cases
Staying in bash without external tools, you could do something like this:
while read name network netmask ; do
if [[ "$name" == net* ]] ; then
case "$netmask" in
"") echo "It's empty" ;;
24) echo "It's 24" ;;
23) echo "It's 23" ;;
*) echo "None of the above" ;;
esac
fi
done < "$filename"