In a PDF, I can set up a button to
Submit the FDF data to my RestAPI
Redirect to a webpage (to tell user 'Thanks') and that works perfectly.
But I need to do this using code... I am using iTextSharp in the following way:
pb is my pushbutton...
sURL is the URL I need the data to go to...
This is my code:
PdfFormField pff = pb.Field;
pff.SetAdditionalActions(PdfName.A, PdfAction.CreateSubmitForm(sURL, null, PdfAction.SUBMIT_XFDF));
af.ReplacePushbuttonField("submit", pff);
This does replace the button with the submit action. How do I keep the page redirect or how do I set it in code?
I have also tried PdfName.AA and PdfName.U based on examples and I am not certain what the different names are for. But nothing works. :-/
Apparently, the SetAdditionalActions() replaces the existing actions.
I have also tried using annotations and just adding a button that doesn't exist.
You are looking for a concept called chained actions as demonstrated in the PrintTimeTable example:
Chunk chunk = new Chunk("print this page");
PdfAction action = PdfAction.javaScript(
"app.alert('Think before you print!');", stamper.getWriter());
action.next(PdfAction.javaScript(
"printCurrentPage(this.pageNum);", stamper.getWriter()));
action.next(new PdfAction("http://www.panda.org/savepaper/"));
chunk.setAction(action);
In this case, we have an action that shows an alert, prints a page and redirects to an URL. These actions are chained to each other using the next() method.
In C#, this would be:
Chunk chunk = new Chunk("print this page");
PdfAction action = PdfAction.JavaScript("app.alert('Think before you print!');", stamper.Writer);
action.Next(PdfAction.JavaScript("printCurrentPage(this.pageNum);", stamper.Writer));
action.Next(new PdfAction("http://www.panda.org/savepaper/"));
chunk.SetAction(action);
See also the C# port of the book examples.
Related
I am working on xamarin.forms. I have a content page which contains one webview which load 3rd party url(www.xyz.com) site and one button in shell.
On button click event I am trying to get user input data using
webview.eval(javascript: var data = document.getElementById('first-name').value;alert(data)).
It works fine but due to void return type I could not store data in local variable and I have a customrender(webviewrender) but don't know on shell button click event how can I get userinput data from webview
Please suggest me how do I achieve this functionality.I do not want XLab-Hybridwebview.
You'll probably need to have the JavaScript code call out to the external code when the result is available. You could then wrap that whole process in a TaskCompletionSource to make everything nice and easy to use.
I'm creating my first app in rails.
Basically, I have a new customer form, normally when you enter a new customer you are redirected to the record you created.
However as I am loading all my pages via ajax I want to load the new record in rather than re-direct to it.
I already have the form firing via ajax, I just need to know how I can access the new record URL to load it into my container.
Hope that makes sense. Thanks in advance!
You can add an option :remote => true to your form_for helper method, so that instead of page redirect the form gets posted via ajax.
For Ex :
<%= form_for(#post, :remote => true) do |f| %>
...
<% end %>
Then create a new template named create.js.erb which will get rendered after create method has been executed.
In this template, you can display the details of the new record you created.
For Ex :
$('some_element').replaceWith('<%=#posts.name %>');
Edit: You mentioned using load in your javascript. I would generally avoid this as you're making two round trips to the server. 1) Create 2) Get html to load into a div. Additionally, if there is an error that happens, it will be more difficult to catch and do the "good thing", whatever that might be.
Once you've added the remote: true option to your form, you need to deal with what happens on the server side of things.
Assuming your using REST, you'll have a controller with a create action in it. Normally, this method is creating the item and then subsequently returning the HTML for the create page. Instead of this, we need to create a javascript view for the action. This will tell the calling page what to when this action is hit.
Let's assume your form has a div called "new_record_form" and that you have another div called "new_records". You'll want to blank out the form elements in the form, effectively resetting it. You'll also want to add the new record to the "new_records" div.
To add the record to the new records div, you might do something like this.
$("#new_records").append("#{#new_record.name}");
When you submit the form, you should see this added. One great way to debug issues is to use the inspector. If you're in chrome, right click anywhere, inspect element and select network. Do this prior to form submission. You'll be able to see the ajax call and the response. Your logs will also be helpful.
Don't forget to blank out the form as well.
Note: You mentioned all your pages are ajax, but I highly suggest you evaluate if this makes 100% sense due to the various issues that result. Not saying this is the best article on the subject but might be worth a read.
I am using HtmlUnit to navigate through the Web of knowledge web page. I am using the code below to set an option button so that results on the page would be sorted appropriately. Unfortunately, nothing happens when I execute the code. Results on the page remains sorted in the same way as they ware before.
HtmlSelect ssort = (HtmlSelect) pageX.getFirstByXPath("//*[#id=\'topNavBar\']/tbody/tr/td[3]/form/select");
HtmlOption optionA = ssort.getOptionByValue("LC.D;PY.D;AU.A;SO.A;VL.D;PG.A");
ssort.setSelectedAttribute(optionA, true);
ssort.click();
I debuged the code and there is no errors. Do you have any idea what am I doing wrong?
As a general rule, functions like the .click() and .setSelectedAttribute(HTMLOption, boolean)(See JavaDoc) will return a HTMLPage that in most cases is the same as the current one, however in your case it will return a different HTMLPage. So to capture the new page you just need to assign the return value to a HTMLPage.
N.B: You could also use getCurrentWindow() on the WebClient instance.
From my view I am sending via $.ajax a JSON object to my controller to save it in the database.
If all succeeded i want to redirect to another action which will show a diferent view.
If i use this code:
return RedirectToAction("CreatePage", "Survey", new {id = question.PageId});
The execution goes to the Survey controller which returns a view but it is not shown.
I have read some post which said that it is not posible to redirect via ajax.
The solution I use so far is to redirect via javascript like this:
success: function (ret) {
window.location.href = "/Survey/CreatePage/" + $("#PageId").val();
}
Although this always works, sometimes i need to refresh the CreatePage view to show the last changes made.
Any idea of how to solve this problem better?
Thanks in advance
As mccow002 suggested, I wasn't really needing to make the call via AJAX for that part. After studying the solutions suggested, i realized that i could simple submit it in a form. My confusion came because I have a save and continue editing and a save. For the save and continue I use the AJAX call, but for the save option with the form being submitted is ok.
Thanks very much for your help.
Instead of redirecting to a new page, you can send a rendered html from .net code back to client and load that html in page, like this $("#main").load(renderedHtml).
But for refreshing the page you can write a simple script that run at specified intervals and refresh the page contens.
You could use [OutputCache] on the CreatePage action so that it doesn't cache the page or only caches for so long.
output caching
I am trying to use CodeIgniter and jQuery-ui dialog to create a modal window with form to update user information.
The process should be like:
1. Press a button on a view page.
2. A modal window pops up.
3. Inside the window is a form that a user can fill.
4. If the user filled something before, the information should be shown in corresponding field
5. Click the update button on the modal window to save the changes to database.
Can anyone provide a good sample of this process?
I used ajax to pass the data but it didn't work when I was trying to update the data to the database. It would be nice if an example of how to pass data from ajax to php and how php handle that.
Thanks,
Milo
well the jquery bit for post(), get(), ajax() works the same in any measure you would normally use it.. key difference here is with CI you can't post directly to a file-name file-location due to how it handles the URI requests. That said your post URL would be the similar to how you would access a view file normally otherwise
ie: /viewName/functionName (how you've done it with controllers to view all along. post, get, ajax doesnt have to end in a extension. I wish I had a better example then this but I can't seem to find one at the moment..
url = '/home/specialFunction';
jQuery.get(url, function(data) {
jQuery("#div2display").html(data);
});
in the case of the above you notice despite it not being a great example that. you have the url with 2 parameters home and specialFunction
home in this case is the controller file for home in the control folder for the home file in views the specialFunction is a "public function" within the class that makes the home controller file. similar to that of index() but a separate function all together. Best way I have found to handle it is through .post() and a callback output expected in JSON cause you can form an array of data on the php side json_encode it and echo out that json_encode and then work with that like you would any JSON output. or if your just expecting a sinlge output and not multiples echoing it out is fine but enough of the end run output thats for you to decide with what your comfortable doing currently. Hopefully all around though this gives you some clairity and hopefully it works out for you.