Verilog multiple simultaneous independant signal assignments in testbench - vhdl

In VHDL I can write this in my testbench:
signal clk : std_logic := '0';
signal count_in : std_logic_vector(3 downto 0) := "0000";
signal load : std_logic := '0';
signal reset : std_logic := '0';
signal count_out : std_logic_vector(3 downto 0) := "0000";
...
clk <= not clk after 50 ns;
reset <= '1' after 1400 ns, '0' after 1900 ns;
count_in <= "1010" after 2500 ns;
load <= '1' after 2700 ns, '0' after 3000 ns;
The signal declarations are before the "begin" of the testbench architecture while the portion after the elipse is in the body of the testbench architecture. A much better way is to use a process which ends with "wait" statement when writing testbenches. I understand how to do this in verilog as well as VHDL.
In verilog we can have an initial block that assigns value once. It is also possible to have multiple initial blocks. I have not tried this, but I don't think that it is wise to drive the same signal from multiple initial blocks.
Now my question is, how do I translate the above code for the DUT stimulus into Verilog? I expect that I shall use an assign statement with multiple #delay values. Is that correct? How do I do it?

In Verilog 2001 and above, you can initialize variables upon declaration, like VHDL. Another interesting, but perhaps less common way to do this is to use use a fork-join block with blocking assignments. In the following code, each line in the fork-join block is executed independently and concurrently.
module test;
reg clk, load, reset;
reg [3:0] count_in, count_out;
initial
begin
fork
begin clk = 0; while (1) #50 clk = ~clk; end
begin count_in = 0; #2500 ; count_in = 4'b1010; end
begin load = 0; #2700 ; load = 1 ; #3000; load = 0; end
begin reset = 0; #1400 ; reset = 1; #1900; reset = 1; end
count_out = 0;
join
end
endmodule
Working example on edaplayground.
Also, notice that the clk signal in your code only toggles once. I slightly modified it so that the clock is running endlessly.

I'm not too familiar with VHDL, but this looks like a test bench stimulus. I generated the runnable testcase for comparison here.
The Verilog equivalent would look something like:
reg clk = 1'b0;
reg [3:0] count_in = 4'b0000;
reg load = 1'b0;
reg reset = 1'b0;
wire [3:0] count_out; // test bench is not driving this
...
initial begin
clk <= #50 !clk;
reset <= #1400 1'b1;
reset <= #1900 1'b0;
count_in <= #2500 4'b1010;
load <= #2700 1'b1;
load <= #3000 1'b0;
end
This will generate the same waveform, except count_out is floating instead of all zeros. By the naming convention I consider count_out should be driven by the device-under-test, which needs to be a wire type.
A SystemVerilog may look something like:
/* Note: bit cannot be X or Z
* initializes equivalent to 'logic clk = 1'b0;' or 'reg clk = 1'b0;'
*/
bit clk;
bit [3:0] count_in;
bit load;
bit reset;
wire [3:0] count_out; // logic type is also okay
...
initial begin
clk <= #50ns !clk;
reset <= #1400ns 1'b1;
reset <= #1900ns 1'b0;
count_in <= #2500ns 4'b1010;
load <= #2700ns 1'b1;
load <= #3000ns 1'b0;
end
Working example of Verilog and System Verilog here

Related

Would like someone to double check code for 8bit up counter with enable

I am a novice coder and don't know if what I did was correct so I would appreciate if someone could double check it for me.
So im trying to make an 8-bit up counter with an active-low count enable control signal. The counter should advance to the next count if cten = 0 and stops at the current count if cten = 1. The counter resets into a state that outputs binary 0 and progresses upward on each clock edge when counting is enabled until it reaches 255. It locks in the state producing output 255. I also tried to change the clock to 1Hz clock from a 50MHz clock the is on a FPGA board that will be used to run some instructions (with there being no more than 255 instructions, hence wanting to lock at that number) based off the count value of int_q.
library ieee;
use ieee.std_logic_1164.all;
use ieee.std_logic_unsigned.all;
use ieee.numeric_std.all;
entity counter is
port(
clk, rst, cten: in std_logic;
q: out std_logic_vector(7 downto 0)
);
end entity counter;
architecture moore of counter is
signal d,int_q: std_logic_vector(7 downto 0);
signal cnt: integer range 0 to 25000;
signal clk1Hz: std_logic;
begin
-- drive internal Q signal to output signal
q <= int_q;
-- next-state logic: add 1 unless 255, lock at 255
d <= int_q+1 when int_q < 255;
d <= int_q when int_q = 255;
process(clk)
begin
if rising_edge(clk) then
cnt <= cnt+1;
if cnt = 25000 then
clk1Hz <= not clk1Hz;
cnt <= 0;
end if;
end if;
end process;
-- register process
process(all)
begin
if rising_edge(clk1Hz) then
if rst ='1' then int_q <= "00000000";
elsif cten = '0' then int_q <= int_q+1;
else int_q <= int_q;
end if;
end if;
end process;
end architecture moore;
Several issues:
If rst is unasserted on the rising edge of clk1Hz, then int_q will remain in an unknown state.
clk1Hz is never initialized, so the not operation does nothing.
cnt is never initialized, so incrementing it does nothing.
int_q is being driven in 2 places: both inside and outside a process.
signal d is unused, did you want to connect it to q?
You're only counting to 25_000, but if your source clock is 50 MHz, you need to count to 25_000_000.
If you want a synchronous reset, (which given the name "Moore", I bet this is homework), it's good practice to create a new process specifically to internally synchronize that async reset signal to the system clock, maybe through a 2FF synchronizer for one idea.
If I understood the question correctly, this should get you in the ballpark:
library ieee;
use ieee.std_logic_1164.all;
use ieee.std_logic_unsigned.all;
use ieee.numeric_std.all;
entity counter is
port(
clk, rst, cten: in std_logic;
q: out std_logic_vector(7 downto 0)
);
end entity counter;
architecture moore of counter is
signal int_q: std_logic_vector(7 downto 0);
signal cnt: integer range 0 to 25_000_000;
signal clk1Hz: std_logic;
begin
-- indicate when at 255
q <= '1' when int_q = 255 else '0';
process(rst, clk)
begin
if rst = '1' then
-- need to assign initial values
clk1Hz <= '0';
cnt <= 0;
elsif rising_edge(clk) then
if cnt = 25_000_000 then
clk1Hz <= not clk1Hz;
cnt <= 0;
else
cnt <= cnt+1;
end if;
end if;
end process;
-- register process
process(rst, clk1Hz)
begin
if rst = '1' then
int_q <= (others => '0');
elsif rising_edge(clk1Hz) then
if cten = '0' then
int_q <= int_q+1; -- rolls over
end if;
end if;
end process;
end architecture moore;
If you want to map this in an FPGA you cannot generate a clock like you do. Clocks are very special signals with strict electrical requirements. If you need a 1Hz frequency clock and the frequency of your master clock is 50MHz there are basically two options:
Use a clock manager/generator hard macro of your FPGA if it has some, and configure it to generate a 1Hz clock from your master clock. Explicitly pass the output through a clock buffer if your tools don't do it automatically.
Do not generate a 1Hz clock, use an enable signal that you assert high once every 50M clock periods. Or use a rescaler and increment your counter only when the rescaler reaches a predefined value.
As the first option depends on your FPGA, your tools, etc. let's investigate the second:
library ieee;
use ieee.std_logic_1164.all;
use ieee.numeric_std.all;
entity counter is
generic(freqHz: positive := 50000000);
port(clk, rst, cten: in std_ulogic;
q: out std_ulogic_vector(7 downto 0));
end entity counter;
architecture moore of counter is
signal rescaler: integer range 0 to freqHz - 1;
signal cnt: integer range 0 to 255;
begin
q <= std_ulogic_vector(to_unsigned(cnt, 8));
process(clk)
begin
if rising_edge(clk) then
if rst = '1' then
rescaler <= freqHz - 1;
cnt <= 0;
elsif cnt /= 255 then
if rescaler /= 0 then
rescaler <= rescaler - 1;
else
rescaler <= freqHz - 1;
cnt <= cnt + 1;
end if;
end if;
end if;
end process;
end architecture moore;
Remarks:
Use ieee.std_logic_unsigned or ieee.numeric_std but not both. And as noted by #JHBonarius, do not use ieee.std_logic_unsigned at all. It is not standard and deprecated. Use ieee.numeric_std_unsigned, instead.
I added a generic parameter (freqHz) with a default value such that you can easily adapt to different clock frequencies.
The 50Mhz to 1Hz rescaler is decremented instead of incremented because a hardware zero detector is frequently slightly smaller and faster than an arbitrary value detector.
If you do not know the difference between std_logic and std_ulogic, always use std_ulogic, never std_logic (and use std_ulogic_vector instead of std_logic_vector, u_unsigned instead of unsigned...) One day or another you will really need std_logic and this day you will understand the difference, and why you should (almost) never use it. And do not listen to people who tell you that std_logic is more standard or better supported by the tools or whatever. They are wrong. The only exception is your teacher or your boss: even if they are wrong, it might be better to obey.

VHDL state machine testbench - works when on board but not on simulation

I have the VHDL implementation that works on board, it detects the sequence 01110 and will raise a flag for 2 clock counts. It detects overlapping sequences as well where 011101110 would raise the flag twice.
I've checked my implementation with a logic analyzer on the board and am fairly confident that it works. I am feeding in a repetition sequence of 0111 at 10 kHz, on the board, it has a clock at 100 MHz where I scale it to 10 kHz with a prescaler.
My problem is, when trying to recreate a similar scenario using a simulation, I do not get any outputs as expected
Image from logic analyzer from board
Image from Test Bench
Test Bench Code
library IEEE;
use IEEE.STD_LOGIC_1164.ALL;
use IEEE.STD_LOGIC_ARITH.ALL;
use IEEE.STD_LOGIC_UNSIGNED.ALL;
entity test_FSM_prac4 is
-- Port ( );
end test_FSM_prac4;
architecture Behavioral of test_FSM_prac4 is
component FSM_prac4 is
port (
inputSignal : in STD_LOGIC;
pushButton : in STD_LOGIC;
clk100mhz : in STD_LOGIC;
logic_analyzer : out STD_LOGIC_VECTOR (7 downto 0);
LEDs: out STD_LOGIC
); end component;
signal inputSignal : std_logic := '0';
signal pushButton: std_logic := '0';
signal clk100mhz: std_logic := '0';
signal logic_analyzer: std_logic_vector(7 downto 0);
signal LEDs : std_logic;
begin
uut : FSM_prac4 port map(
inputSignal => inputSignal,
pushButton => pushButton,
clk100mhz => clk100mhz,
logic_analyzer => logic_analyzer,
LEDs => LEDs
);
--generate clock 100mhz
clock_tic: process begin
loop
clk100mhz <= '0';
wait for 5ns;
clk100mhz <= '1';
wait for 5ns;
end loop;
end process;
input_changes: process begin
loop
inputSignal <= '0';
wait for 100us;
inputSignal <= '1';
wait for 100us;
inputSignal <= '1';
wait for 100us;
inputSignal <= '1';
wait for 100us;
end loop;
end process;
end Behavioral;
To show the mapping for logic Analyzer
logic_analyzer(0) <= masterReset;
logic_analyzer(1) <= newClock -- 10Khz Clock;
logic_analyzer(2) <= outputZ;
--FSM States
logic_analyzer(3) <= '1' when y = A ELSE '0';
logic_analyzer(4) <= '1' when y = B ELSE '0';
logic_analyzer(5) <= '1' when y = C ELSE '0';
logic_analyzer(6) <= '1' when y = D ELSE '0';
logic_analyzer(7) <= '1' when y = E ELSE '0';
If anyone could direct to what I am doing wrong on the test bench and how to replicate to get similar results as the first image as it shows that in simulation, it always stays at state A and the new clock is not toggling meaning that clk100mhz is somehow not connected but I can't figure out why.
Any help is greatly appreciated, thanks guys
edit:
I wrote a simple program to test my scalar clock
library IEEE;
use IEEE.STD_LOGIC_1164.ALL;
use IEEE.STD_LOGIC_ARITH.ALL;
use IEEE.STD_LOGIC_UNSIGNED.ALL;
entity scaler_clk is
Port (
pushButton : in std_logic;
indicator : out std_logic;
clk100mhz : in STD_LOGIC;
clk10khz: out STD_LOGIC
);
end scaler_clk;
architecture Behavioral of scaler_clk is
signal clockScalers : std_logic_vector (12 downto 0):= (others => '0') ;
signal prescaler: std_logic_vector(12 downto 0) := "1001110001000";
signal newClock: std_logic := '0';
signal masterReset : std_logic;
begin
clk10khz <= newClock;
masterReset <= pushButton;
process (clk100mhz,masterReset) begin
if(masterReset <= '1') then <--- error occurs here
clockScalers <= "0000000000000";
newClock <= '0';
indicator <= '1';
elsif (clk100mhz'event and clk100mhz = '1')then
indicator <= '0';
clockScalers <= clockScalers + 1;
if(clockScalers > prescaler) then
newClock <= not newClock;
clockScalers <= (others => '0');
end if;
end if;
end process;
end Behavioral;
test bench code
library IEEE;
use IEEE.STD_LOGIC_1164.ALL;
entity test_scaler_clk is
-- Port ( );
end test_scaler_clk;
architecture Behavioral of test_scaler_clk is
component scaler_clk Port (
pushButton : in std_logic;
indicator : out std_logic;
--input clock
clk100mhz : in STD_LOGIC;
clk10khz: out STD_LOGIC
);end component;
signal clk100mhz: std_logic := '0';
signal clk10khz : std_logic;
signal pushButton: std_logic;
signal indicator : std_logic;
begin
uut: scaler_clk port map(
pushButton => pushButton,
indicator => indicator,
clk100mhz => clk100mhz,
clk10khz => clk10khz
);
pushButton <= '0';
clock_tic: process begin
loop
clk100mhz <= '0';
wait for 5ns;
clk100mhz <= '1';
wait for 5ns;
end loop;
end process;
end Behavioral;
Even though I set pushButton to '0', it is still triggering masterReset, anyone knows why, that's why the 10 kHz clock isn't working
There are several things that you could (should) improve in your code. As Brian already explained, in your Behavioral architecture of scaler_clk, you should have:
if(masterReset = '1') then
instead of:
if(masterReset <= '1') then
Now, let's start with the most likely cause of your initial problem: unbound components. Your test benches instantiate the design to validate as components. VHDL components are kind of prototypes of actual entities. Prototypes are enough to compile because the compiler can perform all necessary syntax and type checking. But they are not enough to simulate because the simulator also needs the implementation behind the prototype. Some tools have a default binding strategy for unbound components: if they find an entity with the same name and if it has only one architecture, they use that. Your simulator apparently does not use such strategy (at least not by default, there is maybe an option for that but it is disabled). Note that most simulators I know issue warnings when they find unbound components. You probably missed these warnings.
Anyway, your component instances are unbound (they have no associated entity/architecture) and the simulator considers them as black boxes. Their outputs are not driven, except by the initial values you declared (1).
How to fix this? Two options:
Use a configuration to specify which entity/architecture pair shall be used for each component instance:
for all: scaler_clk use entity work.scaler_clk(Behavioral);
Use entity instantiations instead of components:
uut: entity work.scaler_clk(Behavioral) port map...
Now, let's go through some other aspects of your code that could be improved:
You are using non-standard packages, that are frequently not even compatible: IEEE.STD_LOGIC_ARITH and IEEE.STD_LOGIC_UNSIGNED. As they are not standard they should not even be in the standard IEEE library. You should use IEEE.NUMERIC_STD instead, and only that one. It declares the SIGNED and UNSIGNED types (with the same declaration as STD_LOGIC_VECTOR) and overloads the arithmetic operators on them.
Your test benches generate the 100MHz clock with:
clock_tic: process begin
loop
clk100mhz <= '0';
wait for 5ns;
clk100mhz <= '1';
wait for 5ns;
end loop;
end process;
The infinite loop is useless: a process is already an infinite loop:
clock_tic: process
begin
clk100mhz <= '0';
wait for 5ns;
clk100mhz <= '1';
wait for 5ns;
end process clock_tic;
would do the same. Same remark for your input_changes process.
Your input_changes process uses wait for <duration> statements. This is not a good idea because you do not know when the inputSignal signal toggles, compared to the clock. Is it just before, just after or exactly at the same time as the rising edge of clk100mhz? And if it is exactly at the same time, what will happen? Of course, you can carefully chose the <durations> to avoid such ambiguities but it is error prone. You should use the wait for <duration> only in the clock generating process. Everywhere else, it is better to synchronize with the clock:
input_changes: process
begin
inputSignal <= '0';
for i in 1 to 10000 loop
wait until rising_edge(clk100mhz);
end loop;
inputSignal <= '1';
for i in 1 to 10000 loop
wait until rising_edge(clk100mhz);
end loop;
inputSignal <= '1';
for i in 1 to 10000 loop
wait until rising_edge(clk100mhz);
end loop;
inputSignal <= '1';
for i in 1 to 10000 loop
wait until rising_edge(clk100mhz);
end loop;
end process input_changes;
This guarantees that inputSignal changes just after the rising edge of the clock. And you could rewrite it in a bit more elegant way (and probably a bit easier to maintain):
input_changes: process
constant values: std_logic_vector(0 to 3) := "0111";
begin
for i in values'range loop
inputSignal <= values(i);
for i in 1 to 10000 loop
wait until rising_edge(clk100mhz);
end loop;
end loop;
end process input_changes;
You are using resolved types (STD_LOGIC and STD_LOGIC_VECTOR). These types allow multiple drive, that is, having a hardware wire (VHDL signal) that is driven by several devices (VHDL processes). Usually you do not want this. Usually you even want to avoid this like the plague because it can cause short-circuits. In most cases it is wiser to use non-resolved types (STD_ULOGIC and STD_ULOGIC_VECTOR) because the compiler and/or the simulator will raise errors if you accidentally create a short circuit in your design.
One last thing: if, as its name suggests, you intend to use the clk10khz signal as a real clock, you should reconsider this decision. It is a signal that you generate with your custom logic. Clocks have very specific electrical and timing constraints that cannot really be fulfilled by regular signals. Before using clk10khz as a clock you must deal with clock skew, clock buffering... Not impossible but tricky. If you did use it as a clock your synthesizer probably issued critical warnings that you also missed (have a look maybe at the timing report). Moreover, this is probably useless in your case: an enable signal generated from clk100mhz could probably be used instead, avoiding all these problems. Instead of:
process (clk100mhz,masterReset) begin
if(masterReset = '1') then
clockScalers <= "0000000000000";
newClock <= '0';
indicator <= '1';
elsif (clk100mhz'event and clk100mhz = '1')then
indicator <= '0';
clockScalers <= clockScalers + 1;
if(clockScalers > prescaler) then
newClock <= not newClock;
clockScalers <= (others => '0');
end if;
end if;
end process;
use:
signal tick10khz: std_ulogic;
...
process(clk100mhz, masterReset) begin
if masterReset = '1') then
clockScalers <= "0000000000000";
tick10khz <= '0';
elsif rising_edge(clk100mhz) then
clockScalers <= clockScalers + 1;
tick10khz <= '0'
if(clockScalers > prescaler) then
tick10khz <= '1';
clockScalers <= (others => '0');
end if;
end if;
end process;
And then, instead of:
process(clk10khz)
begin
if rising_edge(clk10khz) then
register <= register_input;
end if;
end process;
use:
process(clk100mhz)
begin
if rising_edge(clk100mhz) then
if tick10khz = '1' then
register <= register_input;
end if;
end if;
end process;
The result will be the same but with only one single 100MHz clock, which avoids clock skew, clock buffering and clock domain crossing problems.
(1) This illustrates why declaring variables and signals with initial values is usually not a good idea: it hides potential problems. Without this your signals would have been stuck at 'U' (uninitialized) and it would maybe have helped understanding where the problem comes from.

Quartus II : simple counter but weird behaviour

First of all I'm sorry to bother you guys with my very noob question, but I can't find any sense to what's happening with my (ModelSim simulated) circuit.
Here's my code, simple as can be :
LIBRARY ieee;
use ieee.std_logic_1164.all;
use ieee.numeric_std.all;
ENTITY Counter IS
PORT(
enable : in std_logic;
clk : in std_logic;
count : out integer range 0 to 255);
END Counter;
ARCHITECTURE LogicFunction OF Counter IS
signal count_i : integer range 0 to 255;
begin
cnt : process(clk, enable, count_i)
begin
count <= count_i;
if (enable = '0') then
count_i <= 0;
else
count_i <= count_i + 1;
end if;
end process;
end LogicFunction;
My problem is : when I perform a timing simulation with ModelSim, with a clock signal, "enabled" is first '0' and then '1', the output ("count") stays at zero all the time. I tried a lot of different things, like setting the "count" out as a vector, doing all sorts of casts, but it still stays the same.
The increment "count_i <= count_i + 1;" seems to be the problem : I tried to replace it with something like "count_i <= 55", and then the output changes (to "55" in the previous example).
I've seen the exact same increment in the code on that webpage for example :
http://surf-vhdl.com/how-to-connect-serial-adc-fpga/
I've created a project, simulated it and... it works ! I really don't get what the guy did that I didn't, excepted for a bunch of "if" that I don't need in my code.
Any help would be greatly appreciated, I've spent like 3 hours of trial and errors...
Thanx in advance !
In addition to not using a clock edge to increment i_count you're using enable as a clear because it's both in the sensitivity list and encountered first in an if statement condition.
library ieee;
use ieee.std_logic_1164.all;
-- use ieee.numeric_std.all;
entity counter is
port(
enable : in std_logic;
clk : in std_logic;
count : out integer range 0 to 255);
end counter;
architecture logicfunction of counter is
signal count_i : integer range 0 to 255;
begin
cnt : process (clk) -- (clk, enable, count_i)
begin
-- count <= count_i; -- MOVED
-- if (enable = '0') then -- REWRITTEN
-- count_i <= 0;
-- else
-- count_i <= count_i + 1;
-- end if;
if rising_edge(clk) then
if enable = '1' then
count_i <= count_i + 1;
end if;
end if;
end process;
count <= count_i; -- MOVED TO HERE
end architecture logicfunction;
Your code is modified to using the rising edge of clk and require enable = '1' before i_count increment. The superfluous use clause referencing package numeric_std has been commented out. The only numeric operation you're performing is on an integer and those operators are predefined in package standard.
Note the replacement if statement doesn't surround it's condition with parentheses. This isn't a programming language and they aren't needed.
The count assignment is moved to a concurrent signal assignment. This removes the need of having i_count in the sensitivity list just to update count.
Throw in a testbench to complete a Miminal Complete and Verifiable Example:
library ieee;
use ieee.std_logic_1164.all;
entity counter_tb is
end entity;
architecture foo of counter_tb is
signal enable: std_logic := '0';
signal clk: std_logic := '0';
signal count: integer range 0 to 255;
begin
DUT:
entity work.counter
port map (
enable => enable,
clk => clk,
count => count
);
CLOCK:
process
begin
wait for 5 ns; -- 1/2 clock period
clk <= not clk;
if now > 540 ns then
wait;
end if;
end process;
STIMULUS:
process
begin
wait for 30 ns;
enable <= '1';
wait for 60 ns;
enable <= '0';
wait for 30 ns;
enable <= '1';
wait;
end process;
end architecture;
And that gives:
Which shows that the counter doesn't counter when enable is '0' nor does enable = '0' reset the value of i_count.
The Quartus II Handbook Volume 1 Design and Synthesis doesn't give an example using a clock edge and an enable without an asynchronous clear or load signal.
The secret here is anything inside the if statement condition specified using a clock edge will be synchronous to the clock. Any condition outside will be asynchronous.
The form of synthesis eligible sequential logic is derived from the now withdrawn IEEE Std 1076.6-2004 IEEE Standard for VHDL Register
Transfer Level (RTL) Synthesis. Using those behavioral descriptions guarantees you can produce hardware through synthesis that matches simulation.

Gated Clock in Clock Divider for a Square Wave

I recently have been designing a clock divider for my system - which I redesigned, and now has an asynchronous reset, which generates a synchronous reset for the rest of the system. To do this, I followed the answers & advice to my own question and used a clock enable to toggle an output, thus generating clock with a 50% duty cycle (which is desired).
However, this has thrown up the error when generating the bitstream of
PhysDesignRules:372 - Gated clock. Clock net ... is sourced by a combinatorial pin. This is not good design practice. Use the CE pin to control the loading of data into the flip-flop.
Reading into this question about using the clock enable, it appears when creating a clock enable is correct, however, because I need a square wave (and not just a 1/200MHz pulse), and thus using the enable to toggle another signal, it appears in this question that this is an intentional gated clock.
So my questions are; is this gated clock warning significant? Both in simulation, and on an oscilloscope it appears to function correctly (so I'm inclined to ignore it), but am I storing problems for later? Is there a way of getting a very slow 50% duty cycle pulse without a gated clock?
I've put my code below!
Thanks very much (especially to the handful of people who have collectively given a lot of time to my recent non-stop questions)
David
library IEEE;
use IEEE.STD_LOGIC_1164.ALL;
use IEEE.NUMERIC_STD.ALL;
library UNISIM;
use UNISIM.VComponents.all;
ENTITY CLK_DIVIDER IS
GENERIC(INPUT_FREQ : INTEGER;
OUT1_FREQ : INTEGER;
OUT2_FREQ : INTEGER
);
PORT(SYSCLK : IN STD_LOGIC;
RESET_N : IN STD_LOGIC;
RESET_N_OUT : OUT STD_LOGIC;
OUT1 : OUT STD_LOGIC;
OUT2 : OUT STD_LOGIC);
END CLK_DIVIDER;
architecture Behavioral of Clk_Divider is
constant divider1 : integer := INPUT_FREQ / OUT1_FREQ / 2;
constant divider2 : integer := INPUT_FREQ / OUT2_FREQ / 2;
signal counter1 : integer := 0;
signal counter2 : integer := 0;
signal output1 : std_logic := '0';
signal output2 : std_logic := '0';
signal reset : boolean;
begin
reset_proc : process(RESET_N, SYSCLK)
variable cycles : integer := 0;
variable reset_counter : integer := 0;
begin
if rising_edge(SYSCLK) then
if cycles < 2 then
if reset_counter >= divider1 then
cycles := cycles + 1;
reset_counter := 0;
else
reset_counter := reset_counter + 1;
end if;
reset <= true;
else
reset <= false;
end if;
end if;
if RESET_N = '0' then
cycles := 0;
reset_counter := 0;
reset <= true;
end if;
end process;
output1_proc : process(SYSCLK)
begin
if rising_edge(SYSCLK) then
if counter1 >= divider1 - 1 then
output1 <= not output1;
counter1 <= 0;
else
counter1 <= counter1 + 1;
end if;
if RESET_N = '0' then
counter1 <= 0;
output1 <= '1';
end if;
end if;
end process;
output2_proc : process(SYSCLK)
begin
if rising_edge(SYSCLK) then
if counter2 >= divider2 - 1 then
output2 <= not output2;
counter2 <= 0;
else
counter2 <= counter2 + 1;
end if;
if RESET_N = '0' then
counter2 <= 0;
output2 <= '1';
end if;
end if;
end process;
OUT1 <= output1;
OUT2 <= output2;
RESET_N_OUT <= '0' when reset else '1';
end Behavioral;
The comments suggest, that the clock-divider is instantiated in a larger design.
If you want to use the generated clock there, you must add a BUFG between signal output2 and the output out2 like this:
out2_bufg : BUFG port map(I => output2, O => out2);
The component BUFG is defined in the library unisim.vcomponents. Same applies to output out1.
The BUFG ensures, that the generated clock is distributed using a clock-tree, so that the clock signal arrives at all destination flip-flops at the same time. This minimizes hold-time violations and gives more room for the setup of data signals.
If you still get the warning/error, then you combined the generated clock signal with another signal elsewhere in the larger design.
The reset_proc process is written with a elsif cycles > 1 then outside the clocked part, and with the condition derived from cycles which is also assigned as part of reset. It is unclear what hardware is actually described here, but it makes the synthesis tool unhappy.
If you want to use RESET_N as asynchronous reset, then just make a simple if RESET_N = '0' then ... end if;, and assign whatever signals or variables required to be reset. Other assignments should be moved to the clocked part.
NOTE: Code was changed after the above update... which may have removed the reason for the question.
Btw. RESET_N is used as asynchronous reset in the reset_proc, but as synchronous reset in the other processes, and this inconsistent use looks like there may be a potential problem with the reset scheme.

Uart Vhdl, simulation is ok but in fpga not work

I write simple vhdl code for Uart receiver.
Simulation (iSIM) is fine but when implemented I have wrong reading behavior.
When synthetized ISE tell me there are latches on state machine end on data_fill(x).
have you any suggestion.
thanks in advance
gian
here the code
library ieee;
use IEEE.STD_LOGIC_1164.all;
use IEEE.STD_LOGIC_UNSIGNED.all;
entity rx_uart is
port (
clk : in STD_LOGIC;
rst : in STD_LOGIC;
rx_data : in STD_LOGIC;
data_out: out STD_LOGIC_VECTOR(7 downto 0)
);
end rx_uart;
architecture fizzim of rx_uart is
-- state bits
subtype state_type is STD_LOGIC_VECTOR(2 downto 0);
constant idle: state_type:="000"; -- receive_en=0 load_en=0 cnt_en=0
constant receive: state_type:="101"; -- receive_en=1 load_en=0 cnt_en=1
constant stop_load: state_type:="010"; -- receive_en=0 load_en=1 cnt_en=0
signal state,nextstate: state_type;
signal cnt_en_internal: STD_LOGIC;
signal load_en_internal: STD_LOGIC;
signal receive_en_internal: STD_LOGIC;
signal count : integer range 0 to 54686:=0;
signal cnt_en : STD_LOGIC;
signal load_en : STD_LOGIC;
signal receive_en : STD_LOGIC;
signal data_fill : STD_LOGIC_VECTOR(9 downto 0);
-- comb always block
begin
COUNTER_EN : process(clk,rst,cnt_en) begin
if (rst ='1') then
count <= 0;
elsif rising_edge(clk) then
if (cnt_en ='1') then
count <= count+1;
else
count <= 0;
end if;
end if;
end process;
LOADER: process(clk,rst,load_en) begin
if (rst='1') then
data_out <= (others =>'0');
elsif (rising_edge(clk) and load_en='1')then
data_out <= data_fill(8 downto 1);
end if;
end process;
ASSIGNATION : process(clk,rst,receive_en) begin
if (rst ='1') then
data_fill <= (others =>'0');
elsif (receive_en='1') then
case count is
when 7812 =>
data_fill(1) <= rx_data;
when 13020 =>
data_fill(2) <= rx_data;
when 18228 =>
data_fill(3) <= rx_data;
when 23436 =>
data_fill(4) <= rx_data;
when 28664 =>
data_fill(5) <= rx_data;
when 33852 =>
data_fill(6) <= rx_data;
when 39060 =>
data_fill(7) <= rx_data;
when 44268 =>
data_fill(8) <= rx_data;
when 49476 =>
data_fill(9) <= rx_data;
when others =>
data_fill(0) <= '0';
end case;
end if;
end process;
COMB: process(state,clk,count,rst,rx_data) begin
case state is
when idle =>
if (rx_data='0') then
nextstate <= receive;
elsif (rx_data='1') then
nextstate <= idle;
end if;
when receive =>
if (count<=54685) then
nextstate <= receive;
elsif (count>54685) then
nextstate <= stop_load;
end if;
when stop_load =>
nextstate <= idle;
when others =>
end case;
end process;
-- Assign reg'd outputs to state bits
cnt_en_internal <= state(0);
load_en_internal <= state(1);
receive_en_internal <= state(2);
-- Port renames for vhdl
cnt_en <= cnt_en_internal;
load_en <= load_en_internal;
receive_en <= receive_en_internal;
-- sequential always block
FF: process(clk,rst,nextstate) begin
if (rst='1') then
state <= idle;
elsif (rising_edge(clk)) then
state <= nextstate;
end if;
end process;
end fizzim;
You need to understand when latches are generated. Latches are generated when you have an incomplete assignment in combinational logic. Your case statements are combinational. You do not completely assign all possibilities of your data signal and your state machine. When you have an incomplete assignment in a combinational process you will always generate a latch. Latches are bad!
Use your when others properly to assign all of your signals under all conditions. Your data_fill signal will always generate a latch because you don't handle all conditions for data 0:9 on all cases.
Read more about how to avoid latches in VHDL
Edit: It seems too that you don't consistently create sequential logic in VHDL. You need to be creating a clocked process or remove clk from your sensitivity list in a combinational process.
your design has several bad code sites besides your latch problem. I'll number them for better reference.
(1)
Xilinx XST won't recognize the implemented state machine as a FSM. See your XST report or the *.syr file. There won't be a FSM section. If XST finds no FSM it's not able to choose "the best" state encoding and optimize your FSM.
You should use an enum as a state-type and also initialize your state signal:
type t_state is (st_idle, st_receive, st_stop);
signal state : t_state := st_idle;
signal nextstate : t_state;
Your FSM process also needs default assignments (see Russell's explanation) like
nextstate <= state;
(2)
asynchronous resets are no good design practice and complicate timing closure calculations.
(3)
you are handling raw input signals from outside you FPGA without any timing information. to prevent meta stability problems place two D-flip-flops on the rx_data path. you should also add the async-reg and no-srl-extract attribute to these 2 registers to prevent XST optimizations
SIGNAL I_async : STD_LOGIC := '0';
SIGNAL I_sync : STD_LOGIC := '0';
-- Mark register "I_async" as asynchronous
ATTRIBUTE ASYNC_REG OF I_async : SIGNAL IS "TRUE";
-- Prevent XST from translating two FFs into SRL plus FF
ATTRIBUTE SHREG_EXTRACT OF I_async : SIGNAL IS "NO";
ATTRIBUTE SHREG_EXTRACT OF I_sync : SIGNAL IS "NO";
[...]
BEGIN
[...]
I_async <= In WHEN rising_edge(Clock);
I_sync <= I_async WHEN rising_edge(Clock);
Let 'In' be your asynchronous input. Now you can use I_sync in your clock domain. I choose to describe these 2 registers in a one-liner, you can also use a classic process :) The suffix '_async' allows you to define a matching timing rule in your *.xcf and *.ucf files.

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