I have a filename stored in $file.
I need to delete some contents from that file for some calculation. But the original file should not be modified. So I am looking for a way to create a duplicate copy of that file to modify, and then delete it later. Is there a way to create a file with command like "$filename+2" or something like that? How do I go about doing this?
Use cp as already mentioned but consider using mktemp to create the temp filename.
Related
Basically I have .bz2.gz.bz2 file which on extraction gives a .bz2.gz file and on again extraction gives .bz2 file. In this .bz2 file, is my txt file which I want to search on using grep command. I have searched for this but I got bzgrep command which will only search in bz2 file and not the corresponding .gz.bz2 file and give me no results.
Is there a command in unix system which will recursively search in a zipped archive for zipped archive and return results only when it finds the txt file inside it?
P.S: the txt file may be deep in the archive to level 10 max. I want the command to recursively find the txt file and search for the required string. And there will be no other than an archive inside the archive until the txt file level.
I'm not sure I fully understand but maybe this will help:
for i in /path/to/each/*.tar.bz2; do
tar -xvjf "$i" -C /path/to/save/in
rm $i
done
extract all `tar.bz2` and save them in directory then remove the `.bz2`
Thnx for sharing your question.
There are a couple of strange things with it though:
It makes no sense to have a .bz2.gz.bz2 file, so have you created this file yourself? If so, I'd advise you to reconsider doing so in that manner.
Also, you mention there is a .bz2 that would apparently contain different archives, but a .bz2 can only contain one single file by design. So if it contains archives it is probably a .tar.bz2 file in which the tar-file holds the actual archives.
In answer to your question, why can't you write a simple shell script that will unpack your .bz2.gz.bz2 into a .bz2.gz and then into a .bz2 file and then execute your bzgrep command on that file?
I do not understand where it is exactly that you seem to get stuck..
I have to do some things in some files from a directory in solaris. In that directory, I have thousands of files. Some of them, begin with FAC_. I need to make an array variable with those names of files (which four first letters name are FAC_), and then go over the array to do some task to each file.
How can I accomplish that?
Thanks
I think the simplest approach would be something like this:
files="FAC_*"
for file in $files; do
echo "$file"
done
If the files aren't in the same directory as the script you can use the following line to retrieve them.
files="$path/FAC_*"
I have several text docs that are created each day from templates. This process I've achieved successfully albeit probably in a Cro-Magnon way. I want these newly created text files to be filed within a newly created dated folder.
The script creates the file docs from the templates successfully and also creates the newly dated directory. I don't really want to create these text files somewhere else and then move them to the newly created directory. Rather that they be created directly within it. All my research tends to involve directories that already exist rather than one created from a var.
I've included just one file creation example below.
Hope you can help. TIA
today=`date '+%y%m%d'`;
today_Folder=~/Desktop/test/"${today}"
if [[ ! -d $today_Folder ]]
then
mkdir "${today_Folder} `(date '+%A')`"
fi
cat ~/Desktop/test/template.txt >> ~/Desktop/test/dest.txt
P.S. I've tried to make the cat command regarding the text files clearer - it simply creates files. I'm NOT trying to create a tree of directories. Simply ONE newly created directory that could be in test along with the text files.
Your question is how to dynamically create a file, also creating all the path to contain that file? That's not possible in any intuitive/portable way, and it's not typically programs always have to create the directory before the file. What you can do is pass the -p flag to mkdir. On Linux systems (this may also not be portable), this flag means "create all the directories necessary for this path". Zero directories is okay, so you don't need to check whether the directory already exists. So change the whole if block to just this:
mkdir -p "${today_Folder} `(date '+%A')`"
Also, it's kind of smelly the way you want a string (the path) and you're using three operations to create it. Could it be simpler? You want more statements when they add clarity, but in this case the steps are so simple that the only thing accomplished is to make your colleagues go up and read what you wrote more than once. It might suit to change it to:
dir_path=...
mkdir -p "${dir_path}"
To accomplish this, keep in mind that instead of backticks, you can add command substitution with $(). It helps since backticks can't be nested--it makes the line more readable, since you clearly see the command's start/end.
I have been stuck with a task where I need to rename a file with a substring from another filename and then move it to a directory.
What I want to achieve here is as below
I have a file named dummy.txt and another file named 20150416demo.xml
What I want is the file abc.txt to be renamed with the date from the xml file i.e. dummy20150416.txt
The final step is to move it to a different location. Appreciate you responses
Thanks
To rename/concatenate and move according to what you want you can use this script:
#!/bin/bash
file="20150416demo.xml"
date=${file:0:8}
mv abc.txt /destination/path/dummy$date.txt
I have a requirement where I need to copy some files from one location to other (Where the file may exist). While doing so,
I need to take a backup if the file already exists.
Copy the new file to the same location
I am facing problem in point 2. While I am trying to get the destination path for copying files, I am unable to extract the directory of the file. I tried using various options of find command, but was unable to crack it.
I need to trim the file name from the full file path so that it can be used in cp command. I am new to shell scripting. Any pointers are appreciated.
You can use
cp --backup
-b'--backup[=METHOD]'
*Note Backup options::. Make a backup of each file that would
otherwise be overwritten or removed. As a special case, `cp'
makes a backup of SOURCE when the force and backup options are
given and SOURCE and DEST are the same name for an existing,
regular file. One useful application of this combination of
options is this tiny Bourne shell script:
#!/bin/sh
# Usage: backup FILE...
# Create a GNU-style backup of each listed FILE.
for i; do
cp --backup --force -- "$i" "$i"
done
If you need only the filename, why not do a
basename /root/wkdir/index.txt
and assign it to a variable which would return only the filename?