Heading image or string? - image

Question

I just created a page which the user can choose the mode to show, such as icon (image) or just temperature (text). Those are my code:
<?lc
#tell the browser that we will send binary data (png)
put header("Content-type:image/png")
#get ip address
if $_GET["ip"] = "" then
put $_SERVER["REMOTE_ADDR"] into ipAddress
else
put $_GET["ip"] into ipAddress
end if
#get the mode
put $_GET["mode"] into mode
#get longtitude and latitude data
put url ("http://vo.afteroffice.com/r/v/public/pub/geoloc?ip=" & ipAddress) into geoInfo
split geoInfo by cr and ":"
#input lon and lat data into url
put url ("http://api.yr.no/weatherapi/locationforecast/1.8/?lat=" & geoInfo["latitude"] & ";lon=" & geoInfo["longtitude"]) into weatherDetail
#create tree from XML data
put revCreateXMLTree(weatherDetail, false, true, false) into tLocation
#get data about temperature and clouds
put revXMLAttribute(tLocation,"weatherdata/product/time/location/temperature", "value") into temperature
#create the output
if mode = "temperature" then
put "The temperature is " & temperature
else if mode = "icon" then
put URL("binfile:icon/hot01.png")
else if mode = "" then
put "Oke"
end if
?>
My image & text problems are:
If I don't put put header("Content-type:image/png") in my code and I call mode=icon, the result will be "‰PNG IHDRPPŽò­tEXtSoftwareAdobe ImageReadyqÉe
If I put put header("Content-type:image/png") in my code and I call mode=temperature, the result will be "Te image cannot displayed, cause it contains error"
Could you help me? Thank you.

Answer 1

And how about adding something like
if mode = "temperature" then
# do not put header
else if mode = "icon" then
put header("Content-type:image/png")
end if
at the position where you have your content type header now?
You just have to add the definition of mode at the beginning instead of the middle of your script