IF Condition for intervals made by real numbers in bash - bash

Question

This is a bash routine to compare two numbers with some defined intervals given by integers numbers:
#!/bin/bash
# The comparing function
function compareInterval {
t1=$1
t2=$2
shift 2
while (( "$2" )); do
if (( $t1 >= $1 && $t2 <= $2 )); then
# got match
return 0
fi
shift 2
done
return 1
}
# sample values
t_initial=2
t_final=4
# Invocation. Compares against 1-3, 3-5, 2-5
if compareInterval $t_initial $t_final 1 3 3 5 2 5; then
echo Got match
fi
If the intervals are given by real numbers, i.e., 1.234, how does the condition in the function change?

Answer 1

Here's a new version of the code:
#!/bin/bash
function compareInterval {
t1=$1
t2=$2
shift 2
while (( $(awk -v var="$2" 'BEGIN{ if (var=="") print 0; else print 1; }') )); do
var1=$(awk -v t1="$t1" -v t2="$1" 'BEGIN{ print (t1 >= t2) }')
var2=$(awk -v t3="$t2" -v t4="$2" 'BEGIN{ print (t3 <= t4) }')
if [[ "$var1" -eq "1" && "$var2" -eq "1" ]]; then
# got match
return 0
fi
shift 2
done
return 1
}
t_initial=4399.75148230007220954256
t_final=4399.75172111932808454256
if compareInterval $t_initial $t_final 4399.48390124308 4400.47652912846 3 5 2 5; then
echo Got match
fi

Answer 2

Just another pure bash solution:
#!/bin/bash
function compareInterval {
t1=$1 t2=$2
shift 2
while [[ $# -ge 2 ]]; do
is_ge "$t1" "$1" && is_le "$t2" "$2" && return 0 ## Got match.
shift 2
done
return 1
}
function is_ge {
local A1 A2 B1 B2
if [[ $1 == *.* ]]; then
A1=${1%%.*}
A2=${1##*.}
else
A1=$1
A2=0
fi
if [[ $2 == *.* ]]; then
B1=${2%%.*}
B2=${2##*.}
else
B1=$2
B2=0
fi
(( L = ${#A2} > ${#B2} ? ${#A2} : ${#B2} ))
A2=$A2'00000000000000000000'; A2=1${A2:0:L}
B2=$B2'00000000000000000000'; B2=1${B2:0:L}
(( A1 == B1 ? A2 >= B2 : A1 > B1 ))
}
function is_le {
local A1 A2 B1 B2
if [[ $1 == *.* ]]; then
A1=${1%%.*}
A2=${1##*.}
else
A1=$1
A2=0
fi
if [[ $2 == *.* ]]; then
B1=${2%%.*}
B2=${2##*.}
else
B1=$2
B2=0
fi
(( L = ${#A2} > ${#B2} ? ${#A2} : ${#B2} ))
A2=$A2'00000000000000000000'; A2=1${A2:0:L}
B2=$B2'00000000000000000000'; B2=1${B2:0:L}
(( A1 == B1 ? A2 <= B2 : A1 < B1 ))
}
t_initial=2.4
t_final=4.5
if compareInterval "$t_initial" "$t_final" 1 3 3 5 2 5; then
echo 'Got match.'
fi
Note: Of course sanity checks can be added but I find that not too necessary for now.