AWK int comparison statements not working - bash

Question

I am using Hacker Rank challenges to teach myself BASH, and I'm in need of some advice.
I'm specifically trying to solve this challenge: Apple and Oranges by nabila_ahmed
I need to read in multiple lines of ints separated by spaces, on multiple lines. I decided to use awk to do this because it seems a lot more efficient in memory storage than using read. (I tried a couple of solutions using read and they timed out, because the test cases are really big.)
Example input:
7 11
5 15
3 2
-2 2 1
5 -6
This is my first attempt in bash and it timed out:
row=0
while read line || [[ -n $line ]]; do
if [ "$row" -eq 0 ]
then
column=0
for n in $line; do
if [ "$column" -eq 0 ]
then
housePos1=$n
elif [ "$column" -eq 1 ]
then
housePos2=$n
fi
((column++))
done
# Calculate house min and max
if [ "$housePos1" -gt "$housePos2" ]
then
minHousePos=$housePos2
maxHousePos=$housePos1
else
minHousePos=$housePos1
maxHousePos=$housePos2
fi
elif [ "$row" -eq 1 ]
then
column=0
for n in $line; do
if [ "$column" -eq 0 ]
then
appleTreePos=$n
elif [ "$column" -eq 1 ]
then
orangeTreePos=$n
fi
((column++))
done
elif [ "$row" -eq 3 ]
then
applesInHouse=0
for n in $line; do
# Calculate the apple's position
let applePos=$((appleTreePos + n))
# If the apple's position is within the houses position, count it
if [ "$applePos" -ge "$minHousePos" ] && [ "$applePos" -le "$maxHousePos" ]
then
((applesInHouse++))
fi
done
elif [ "$row" -eq 4 ]
then
orangesInHouse=0
for n in $line; do
# Calculate the apple's position
let orangePos=$((orangeTreePos + n))
# If the apple's position is within the houses position, count it
if [ "$orangePos" -ge "$minHousePos" ] && [ "$orangePos" -le "$maxHousePos" ]
then
((orangesInHouse++))
fi
done
fi
((row++))
done
echo "$applesInHouse"
echo "$orangesInHouse"
Here is my second attempt in bash, even more of the solutions timed out:
x=0;y=0;read -r s t;read -r a b;read -r m n;
for i in `seq 1 $m`; do
if [ "$i" -lt "$m" ]
then
read -d\ z
else
read -r z
fi
if [ "$((a+z))" -ge "$s" ] && \
[ "$((a+z))" -le "$t" ]
then
((x++))
fi
done
for i in `seq 1 $n`; do
if [ "$i" -lt "$n" ]
then
read -d\ z
else
read -r z
fi
if [ "$((b+z))" -ge "$s" ] && \
[ "$((b+z))" -le "$t" ]
then
((y++))
fi
done
echo $x; echo $y
Here's where I am at in debugging my solution using awk...
awk -v RS='[-]?[0-9]+' \
'{
if(word==$1) {
counter++
if(counter==1){
s=RT
}else if(counter==2){
t=RT
}else if(counter==3){
a=RT
}else if(counter==4){
b=RT
}else if(counter==5){
m=RT
}else if(counter==6){
n=RT
}else{
counter2++
if(counter2<=m){
print "Apples:"
print a+RT
print a+RT>=s
print a+RT<=t
applecount++
}
if(counter2>m && counter2<=m+n){
print "Oranges:"
print b+RT
print b+RT>=s
print b+RT<=t
orangecount++
}
}
}else{
counter=1
word=$1
}
}
END {
print "Total Counts:"
print applecount
print orangecount
}
'
Here is the output from that script when using the sample input
Apples:
3
0
0
Apples:
7
1
0 <-- This is the problem! (7 is less than or equal to 11)
Apples:
6
0
0
Oranges:
20
0
0
Oranges:
9
1
0 <-- This is also a problem! (9 is less than or equal to 11)
Total Counts:
3
2
As you can see, I'm getting some of the wrong comparisons...
ANSWER
(mostly courtesy of #glenn-jackman)
apples_oranges() {
local s t a b m n d
local -a apples oranges
local na=0 nb=0
{
read s t
read a b
read m n
read -a apples
read -a oranges
} < "$1"
for d in "${apples[#]}"; do
(( s <= a+d && a+d <= t )) && ((na++))
done
echo $na
for d in "${oranges[#]}"; do
(( s <= b+d && b+d <= t )) && ((nb++))
done
echo $nb
}
apples_oranges /dev/stdin

Answer 1

I'd do this with bash
apples_oranges() {
local s t a b m n d
local -a apples oranges
local na=0 nb=0
{
read s t
read a b
read m n # unused
read -a apples
read -a oranges
} < "$1"
for d in "${apples[#]}"; do
(( a+d >= s )) && ((na++))
done
echo $na
for d in "${oranges[#]}"; do
(( b-d <= t )) && ((nb++))
done
echo $nb
}
apples_oranges input.txt

Answer 2

this may get you started...
$ awk '
NR==1{split($0,house)}
NR==2{split($0,trees)}
NR==3{split($0,counts)}
NR==4{split($0,apples)}
NR==5{split($0,oranges)}
END{for(i in apples)
if(trees[1]+apples[i]>=house[1] && trees[1]+apples[i]<=house[2]) a++; print a}' file