SELECT * FROM `movie_list`
WHERE `movie_id` IN
(SELECT DISTINCT movie_id FROM `movie_genre` where genre_id in (12,18,53))
AND rated IN
('Not Rated','N/A')
How can i convert the above to a query builder syntax:
$movies = DB::table('movie_list')
->whereIn('movie_id',function($query){
$query->select.....
})->get();
I have the inner one: it goes like this:
DB::table('movie_genre')
->whereIn('genre_id', array(12,18,53))
->distinct()
->get(array('movie_id'));
How do i use this result with the rest of my query?
You could do this alot smoother with Eloquent Models, but assuming you don't have your models setup, this should do the trick (untested)
$ids = DB::table('movie_genre')
->whereIn('genre_id', [12,18,33])
->distinct()
->get(['movie_id'])
->toArray();
$movies = DB::table('movie_list')
->whereIn('movie_id', array_values($ids))
->get();
Related
I have following temp tables I wanna join them In query builder but I am failing to do so. I wanna join these 2 tables so I can do i1.imp/i2.imp
$subQuery1 = MyModel::query()
->from("table as i1")
->select(
\DB::raw('sum(col) as col1'),
\DB::raw('co1')
)->where('stamp', '>=', '2022-03-01 14:25:00')
->where('stamp', '<', '2022-03-07 14:30:00')
->groupBy(
'co1'
);
$subQuery2 = MyModel::query()
->from("table as i2")
->select(
\DB::raw('sum(col) as col1'),
\DB::raw('co1')
)->where('stamp', '>=', '2022-03-01 14:20:00')
->where('stamp', '<', '2022-03-07 14:25:00')
->groupBy(
'co1'
);
You can use from, fromSub or table and pass in a subquery instead of a table.
You can do the same with joinSub for joins.
You need to provide an alias though.
For example, to use $subquery1 as the main table and join it with $subquery2, the resulting query could look like this:
$results = DB::query()
->select(.....)
->fromSub($subquery1, 'i1')
->joinSub($subquery2, 'i2', function ($join) {
$join->on('i1.col', '=', 'i2.col');
// ->orOn(....)
});
->where(....)
->get();
Laravel 9.x API - fromSub
Queries - Subquery Joins
I know that something similar was here some time ago,but it wasn't the same case and I can't just figure it out on myself.
I need to transform raw SQL query to Eloquent.
This query contains SELECT COUNT in WHERE clause, for simplicity I have this (may has not much sense) query :
SELECT u.column1, u.column2, u.column3, s.column1 FROM users u
LEFT JOIN salary s ON u.id = s.user_id
WHERE
(
SELECT count(cars_id) FROM cars WHERE cars.user_id = u.id
) = 0
AND u.city IN ("London","Paris")
I tried:
$columns = [
'users.column1',
'users.column2',
'users.column3',
'salary.column1'
];
$q = User::select($columns)
->leftJoin('salary', 'salary.user_id', '=', 'users.id')
->whereRaw(" (SELECT COUNT(cars_id) FROM cars WHERE cars.user_id = u.id) = 0 ")
->whereRaw("u.city IN ('London','Paris')")
->get();
But it doesn't return same results as raw SQL (SQL had 161 rows and Eloquent 154 rows).
Maybe you know how to transform this kind of query correctly to Eloquent?
Thanks
Based on your query I believe this should do it:
DB::table('users as u')
->select([ 'u.column1', 'u.column2', 'u.column3', 's.column1'])
->leftJoin('salary as s', 'u.id', '=', 's.user_id')
->leftJoin('cars as c', 'c.user_id', '=', 'u.id')
->whereIn('u.city', ['London', 'Paris'])
->havingRaw('count(c.id) = 0')
->get();
Please let me know.
I'm trying to make a query with eloquent, I try to get all the users who have one or more ads, taking into account that it is a one to many relationship (users to ads).
This query in general does what I want, but I do not know if it is well done and also how to pass it to Eloquent through the User model.
SELECT users.id, COUNT( anuncio.id ) AS 'total' FROM users
INNER JOIN anuncio ON users.id = anuncio.usuario_id WHERE
(SELECT COUNT( * ) FROM anuncio WHERE anuncio.usuario_id = users.id) >0
GROUP BY users.id ORDER BY total DESC
I have tried several ways that only return Builder to me.
For example:
$listas = new User;
$listas = $listas->join('anuncio','users.id','=','anuncio.usuario_id');
$listas = $listas->select(array('users.*', DB::raw('COUNT(anuncio.id) AS total')));
$listas = $listas->where(function($query) use ($listas){
$query->select(DB::raw('COUNT(anuncio.usuario_id)'))
->where('anuncio.usuario_id','=','users.id')
->groupBy('anuncio.usuario_id');
},'>','0');
$listas = $listas->orderBy('total','DESC')->paginate(48);
By any suggestion I will be very grateful.
Try with this
$listas = User::join('anuncio','users.id','=', 'anuncio.usuario_id')
->select('users.id',DB::raw("count(anuncio.id) as total"))
->groupby('users.id')
->having('total', '>', '0')
->orderby('total', 'desc')
->get();
Just use left join for this.
$users = DB::table('users')
->leftJoin('anuncio', 'users.id', '=', 'anuncio.usuario_id')
->get();
So Left Join will only select those result which has any match in anuncio table.
how select query like this in Laravel -
Select t.*, count(Select * from persons person
where person.user_id = t.id) from users t
try:
DB::table('users')
->selectRaw('*, count(SELECT * FROM persons WHERE persons.user_id = users.id)')
->get();
In my opinion to count data of other table, you can use join table combining with group. It's same as your query. You can do this:
$users = DB::table('users')
->join('persons', 'users.id', '=', 'persons.user_id')
->select('users.*', count(persons.user_id))
->groupBy('persons.user_id')
->get();
I hope this can help you.
I am trying to replicate the below SQL in Laravels Eloquent query builder.
select a.name, b.note from projects a
left join (select note, project_id from projectnotes order by created_at desc) as b on (b.project_id = a.id)
where projectphase_id = 10 group by a.id;
So far I have:
$projects = Project::leftjoin('projectnotes', function($join)
{
$join->on('projectnotes.project_id', '=', 'projects.id');
})
->where('projectphase_id', '=', '10')
->select(array('projects.*', 'projectnotes.note as note'))
->groupBy('projects.id')
->get()
which works for everything except getting the most recent projectnotes, it just returns the first one entered into the projectnotes table for each project.
I need to get the order by 'created_at' desc into the left join but I don't know how to achieve this.
Any help would be much appreciated.
Your subquery is unnecessary and is just making the entire thing inefficient. To be sure though, make sure this query returns the same results...
SELECT
projects.name,
notes.note
FROM
projects
LEFT JOIN
projectnotes notes on projects.id = notes.project_id
WHERE
projects.projectphase_id = 10
ORDER BY
notes.created_at desc
If it does, that query translated to the query builder looks like this...
$projects = DB::table('projects')
->select('projects.name', 'notes.note')
->join('projectnotes as notes', 'projects.id', '=', 'notes.project_id', 'left')
->where('projects.projectphase_id', '=', '10')
->orderBy('notes.created_at', 'desc')
->get();