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Using only five 3s and valid mathematical operations, how to get answer 31? Only digit 3 should be there and you can use 5 times (no more or less) to get the answer.
Would this work?
33 - 3 + 3/3
You can get to 31 with…
(3**3+(3/3))+3
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Excerpts can be found on https://www.kimbalite.com
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I've tried applying Kondu's algorithmic formulas, but it's just not working.
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How to do 50% of 120 in scala code..need proper syntax ,& runnable code for same.
Eg :
int k = (int)(120*(50.0f/100.0f));
This is in java need scala code for same.
The answer would be:
(120*(50.0f/100.0f)).toInt
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How I can get always round number from Ruby rand method between the interval rand(1..99999999).
For Example I want to get as a result for example 1000 or 100000
Randomize the power of 10:
10 ** rand(1..9)
Why not this:
('1' + '0' * (0..10).sample).to_i
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develop an ASM program to get the sum of integers 1 to 10 in R16..
hope someone can help total newbie
since the task does not require to actual calculate the sum the answer may be pretty easy:
LDI R16, 55
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I want to know the possible root causes which makes the problem "R6016 - not enough space for thread data" for the application(COM .exe) which i created.