Using Oracle Application Express and I want to display each duplicate entry in a table. I also want to create a column with a value of 1 for each instance of a duplicate.
So with a table:
Name
Chris
Sean
Chris
John
My query should return
Name Count
Chris 1
Chris 1
How would I do this?
You can do this using window/analytic functions:
select name, 1
from (select name, count(*) over (partition by name) as cnt
from table t
) t
where cnt > 1;
Related
I have a table in oracle that I'm trying to write a query for but having a problem writing it correctly. The data of the table looks like this:
Name
ID
DATE
Shane
1
01JAN2023
Angie
2
02JAN2023
Shane
1
02JAN2023
Austin
3
03JAN2023
Shane
1
03JAN2023
Angie
2
03JAN2023
Tony
4
05JAN2023
What I was trying to come up with was a way to iterate over each day, look at all the records for that day and compare with the rest of the records in the table that came before it and only pull back the first instance of the record based on the ID & Date. The expected output would be:
Name
ID
DATE
Shane
1
01JAN2023
Angie
2
02JAN2023
Austin
3
03JAN2023
Tony
4
05JAN2023
Can anyone tell me what the query should be to accomplish this?
Thank you in advance.
You'll need to convert your date field to a real date so it orders correctly
SELECT name,id,MIN(TO_DATE(date,'DDMONYYYY')) date
FROM table
GROUP BY name,id
Isn't that just
select name, id, min(date_column)
from your_table
group by name, id;
If you don't want to use aggregation, you can use FETCH NEXT ROWS WITH TIES:
SELECT tab.*
FROM tab
ORDER BY ROW_NUMBER() OVER(PARTITION BY Name, Id ORDER BY DATE_)
FETCH NEXT 1 ROWS WITH TIES
Output:
NAME
ID
DATE_
Angie
2
02-JAN-23
Austin
3
03-JAN-23
Shane
1
01-JAN-23
Tony
4
05-JAN-23
Check the demo here.
Apologies if this seems simple to some, I am still in the (very) early stages of learning!
Basically I've got a table database that has multiple users (Users_ID), each with a corresponding access name(NAME). The problem is, some Users have multiple access names, meaning when the data is pulled, there is duplicates in the User_ID column.
I need to remove the duplicates in the User column and join their corresponding access names in the NAME column, so it only takes up 1 row and no data is lost.
The current SQL query I'm using is :
select Table1_user_id, Table2.name,
from Table1
inner join Table2
on Table1.role_id = Table2.role_id
An example of what this would return:
USER_ID | NAME
------- --------------
Tim Level_1 Access
John Level 2 Access
Tim Level 2 Access
Mark Level 3 Access
Tim Level 3 Access
Ideally, I would remove the duplicates for Tim and display as following:
USER_ID | NAME
------- ----------------------------------------------
Tim Level_1 Access, Level 2 Access, Level 3 Access
John Level 2 Access
Mark Level 3 Access
Thanks in advance for any help regarding this and sorry if something similar has been asked before!
Use GROUP_CONCAT with SEPARATOR :
SELECT Table1.user_id, GROUP_CONCAT(Table2.name SEPARATOR ',') AS Ename
FROM Table1
INNER JOIN Table2 ON Table1.role_id = Table2.role_id
GROUP BY Table1.user_id
select Table1_user_id, LISTAGG(Table2.name,', ') WITHIN GROUP (ORDER BY Table2.name) as Name
from Table1
inner join Table2
on Table1.role_id = Table2.role_id
I have sample Data like:
Table empdata:
Name Desig Sal
-------------------------
john staff 26000
sen owner 50000
smith assistant 10000
i want to print each of the columns like
Current field value is : John
Current field value is : staff
Current field value is : 26000
Current field value is : sen
Current field value is : owner
Current field value is : 50000.. and so on
I am able to use cursor to fetch the emp data:
cursor c1 is
select name, desig, sal from empdata;
but i want to iterate over the columns too. I have shown 3 columns here, but there are atleast 30 columns in actual data, and i would like to print each of the field.
Please help.
Hi you can use this kind basic code.
begin
for i in (select * from emp where rownum < 5)
Loop
dbms_output.put_line('Current field value is: '||i.Emp_id);
dbms_output.put_line('Current field value is: '||i.emp_name);
end loop;
end;
If I understand you correctly, I think you're after something like:
select name,
desig,
sal,
(select approved from approval_table apv1 where apv1.data = emp.name) name_aprvd,
(select approved from approval_table apv2 where apv2.data = emp.desig) desig_aprvd,
(select approved from approval_table apv3 where apv3.data = emp.sal) sal_aprvd
from empdata emp;
Quite what you expect to do with the information once you've got it, I'm not sure. Maybe you return this as a cursor? Maybe you pass it into a procedure? I'm not sure, but hopefully you have enough information to sort out your requirement?
I am trying to create a view that displays size (char) of LastName and the total number of records whose last name has that size. So far I have:
SELECT LENGTH(LastName) AS Name_Size
FROM Table
ORDER BY Name_Size;
I need to add something like
COUNT(LENGTH(LastName)) AS Students
This is giving me an error. Do I need to add a GROUP BY command? I need the view:
Name_Size Students
3 11
4 24
5 42
SELECT LENGTH(LastName) as Name_Size, COUNT(*) as Students
FROM Table
GROUP BY Name_Size
ORDER BY Name_Size;
You may have to change the group by and order by to LENGTH(LastName) as not all SQL engines let you reference an alias from the select statement in a clause on that same statement.
HTH,
Eric
Let's say I have table data similar to the following:
123456 John Doe 1 Green 2001
234567 Jane Doe 1 Yellow 2001
234567 Jane Doe 2 Red 2001
345678 Jim Doe 1 Red 2001
What I am attempting to do is only isolate the records for Jane Doe based upon the fact that she has more than one row in this table. (More that one sequence number)
I cannot isolate based upon ID, names, colors, years, etc...
The number 1 in the sequence tells me that is the first record and I need to be able to display that record, as well as the number 2 record -- The change record.
If the table is called users, and the fields called ID, fname, lname, seq_no, color, date. How would I write the code to select only records that have more than one row in this table? For Example:
I want the query to display this only based upon the existence of the multiple rows:
234567 Jane Doe 1 Yellow 2001
234567 Jane Doe 2 Red 2001
In PL/SQL
First, to find the IDs for records with multiple rows you would use:
SELECT ID FROM table GROUP BY ID HAVING COUNT(*) > 1
So you could get all the records for all those people with
SELECT * FROM table WHERE ID IN (SELECT ID FROM table GROUP BY ID HAVING COUNT(*) > 1)
If you know that the second sequence ID will always be "2" and that the "2" record will never be deleted, you might find something like:
SELECT * FROM table WHERE ID IN (SELECT ID FROM table WHERE SequenceID = 2)
to be faster, but you better be sure the requirements are guaranteed to be met in your database (and you would want a compound index on (SequenceID, ID)).
Try something like the following. It's a single tablescan, as opposed to 2 like the others.
SELECT * FROM (
SELECT t1.*, COUNT(name) OVER (PARTITION BY name) mycount FROM TABLE t1
)
WHERE mycount >1;
INNER JOIN
JOIN:
SELECT u1.ID, u1.fname, u1.lname, u1.seq_no, u1.color, u1.date
FROM users u1 JOIN users u2 ON (u1.ID = u2.ID and u2.seq_no = 2)
WHERE:
SELECT u1.ID, u1.fname, u1.lname, u1.seq_no, u1.color, u1.date
FROM users u1, thetable u2
WHERE
u1.ID = u2.ID AND
u2.seq_no = 2
Check out the HAVING clause for a summary query. You can specify stuff like
HAVING COUNT(*) >= 2
and so forth.