using awk and printf in for loop bash - bash

Question

How can I use awk and printf in for loop?
Here is my code
for fileName in /home/BamFiles/sample*
do
sampleIds=${fileName##*/}
for Bam in /home/BamFiles/sample*/*.bam
do
samtools idxstats $Bam | awk '{i+=$3+$4} END {printf("%s\t%d",$sampleIds Bam)}'
done
done
I get the the following error
awk: fatal: not enough arguments to satisfy format string
`%d %s'
^ ran out for this one
Expected output is
sample1 52432
sample2 32909
sample3 54000
sample5 45890
Thanks

Answer 1

Awk can never be able to expand a shell variable. You are also trying to pass only a single argument to printf (nothing is passed for %d.
Perhaps you want it this way:
samtools idxstats "$Bam" | awk -v "file=$fileName" '{i+=$3+$4} END {printf("%s\t%d\n", file, i)}'
Note that embedding a variable's value directly to awk's code may be possible by using double-quotes but is not recommended:
samtools idxstats "$Bam" | awk "{i+=\$3+\$4} END {printf(\"%s\\t%d\", $file, i)}"
Suggestion:
shopt -s nullglob
for sample in /home/BamFiles/sample*; do
for bam in "$sample"/*.bam; do
samtools idxstats "$bam"
done | awk -v sample="${sample##*/}" '{ i += $3 + $4 } END { printf("%s\t%d\n", sample, i) }'
done
Or
shopt -s nullglob
for sample in /home/BamFiles/sample*; do
for bam in "$sample"/*.bam; do
samtools idxstats "$bam" | \
awk -v sample="${sample##*/}" -v bam="${bam##*/}" \
'{ i += $3 + $4 } END { printf("%s\t%s\t%d\n", sample, bam, i) }'
done
done