I am developing a search tool for my project,
My desired output is to get the common value from the different tables. eg) SKR0BP100
How to get this value ??
As i am running the program in for-loop and fetching the values from while-loop, now how to use array_intersect() function? Because for array intersect function, minimum 2 arrays are needed, but i get only one array at a time, as it runs on for-loop. So what should i do ?? Please Help me!
$result = array_intersect($arr1, $arr2);
But i have only one $array (ie, $sid[$i] at a time, as it runs in for-loop.
My program
for($i=0;$i<$cc;$i++)
{
$m1="select * from $u$sc where $b[$i]='$a[$i]' ";
$m2=mysql_query($m1);
echo"$m1<br><br>";
while($we=mysql_fetch_array($m2))
{
$sid[$i]=$we['SI'];
echo"$sid[$i]<br><br>";
}
}
Desired Output = SKR0BP100
// How to get this??
Present output
select * from Studentsc where Zone='East'
SKR0BP100
SKR0BP12
select * from Studentsc where Area='Rural'
SKR0BP129
SKR0BP13
SKR0BP100
select * from Studentsc where Class='12'
SKR0BP100
SKR0BP101
So if you want to create query then try this
$where = array();
for($i=0;$i<$cc;$i++)
{
$where[] = $b[$i]."='".$a[$i]."'";
}
$m1="select * from $u$sc where ".implode(" and ",$where); //If you are sure that atleast one value vomes
Related
This is for a search query based on many input fields, i'm doing if statements inside the query based on the inputs, for example :
$query = Model::all();
if($field = Input::get('field'))
$query->where('column_name', $field);
but what i want to do also is a condition to skip a row if there is no image with a name of that row id, like so :
if( file_exists('/img/'.$this_query->id) )
$query->skip();
Option 1: would be to make an array of the filenames, then utilize the whereIn query builder method, which checks for the occurrence of a column value in an array.
$query = Model::query();
$filenames = scandir('/img');
// the following excludes any id's not in the $filenames array
$query = $query->whereIn('id', $filenames);
Option 2: Run the query and then filter the resulting Collection in Laravel.
$query = Model::query();
// ... then build up your query
// the following gets the query results and then filters them out
$collection = $query->get()->filter( function($item) {
return file_exists('/img/'.$item->id);
}
Rationale: the database cannot check the filesystem during it's processing; so you either need to (Option 1) provide it a list from which to check, or (Option 2) do the checking after you get() the results back from the query.
I'm trying to merge multiple objects (like Receipts, Reports, etc) with Collection->merge().
This is the code I used:
$receipts = Receipt::all();
$reports = Report::all();
$collection = $receipts->merge($reports);
This is the result:
The above screenshot shows two elements, but the third element is missing because it has the same id (id: "1") as the first one. What I'm trying to achieve is to display all three of them as a collection.
EDIT:
I need the result to be objects (collection) because I also use the code on my view, where I check the class to determine what to display. Also, I use this function to sort the objects in the collection.
$collection->sort(function($a, $b)
{
$a = $a->created_at;
$b = $b->created_at;
if ($a === $b) {
return 0;
}
return ($a > $b) ? 1 : -1;
});
I know that this is an old question, but I will still provide the answer just in case someone comes here from the search like I did.
If you try to merge two different eloquent collections into one and some objects happen to have the same id, one will overwrite the other. I dunno why it does that and if that's a bug or a feature - more research needed. To fix this just use push() method instead or rethink your approach to the problem to avoid that.
Example of a problem:
$cars = Car::all();
$bikes = Bike::all();
$vehicles = $cars->merge($bikes);
// if there is a car and a bike with the same id, one will overwrite the other
A possible solution:
$collection = collect();
$cars = Car::all();
$bikes = Bike::all();
foreach ($cars as $car)
$collection->push($car);
foreach ($bikes as $bike)
$collection->push($bike);
Source: https://medium.com/#tadaspaplauskas/quick-tip-laravel-eloquent-collections-merge-gotcha-moment-e2a56fc95889
I know i'm bumping a 4 years old thread but i came across this and none of the answers were what i was looking for; so, like #Tadas, i'll leave my answer for people who will come across this. After Looking at the laravel 5.5 documentation thoroughly i found that concat was the go-to method.
So, in the OP's case the correct solution would be:
$receipts = Receipt::all();
$reports = Report::all();
$collection = $receipts->concat($reports);
This way every element in the Report collection will be appended to every element in the Receipts collection, event if some fields are identical.
Eventually you could shuffle it to get a more visual appealing result for e.g. a view:
$collection->shuffle();
Another way to go about it is to convert one of your collections to a base collection with toBase() method. You can find it in Illuminate\Support\Collection
Method definition:
/**
* Get a base Support collection instance from this collection.
*
* #return \Illuminate\Support\Collection
*/
public function toBase()
{
return new self($this);
}
Usage:
$receipts = Receipt::all();
$reports = Report::all();
$collection = $receipts->toBase()->merge($reports);
You could put all collections in an array and use this. Depends on what you want to do with the collection.
$list = array();
$list = array_merge($list, Receipt::all()->toArray());
$list = array_merge($list, Report::all()->toArray());
Is there any way to preserve sort order in xquery? My problem is that the data has to get passed to the MVC framework's get-response() function on the return, so I think it's automatically reverting to document order. I thought that doing the sort right in the first paramter of the subsequence() function would capture the first 'n' items after they are sorted, but it does not. I also tried having the $search-results parameter sorted before the call to subsequence(), but that did not work either. See the following code:
let $data :=
<figures count="{$count}"
mediatypes="{$mtypes}"
start="{$start}"
end="{$start+$myns:image-paging-default}"
page="{$page}"
increment="{$myns:image-paging-default}"
total-pages="{
if ($count lt $myns:image-paging-default) then
1
else
ceiling(($count + 1) div $myns:image-paging-default)
}"
{
subsequence(
( for $item in ($search-results)
order by $item//figure/#ftype descending
return $item),
$start,
$myns:image-paging-default)
}
</figures>
let $sidebar := xdmp:get-server-field('imagefacets')
return utils:get-response($req, ($data,$sidebar) )
I'm copying a vtiger query in a similar way but there is one change that the query given first having only one output so there is kept 0 in 2nd argument,
but in my customized query there are multiple outputs so what should I kept instead of 0
both are given as below:
original query
$is_recurring_event_query = $adb->pquery('SELECT recurring_group_id from vtiger_activity where activityid=?',array($id));
$is_recurring_event = $adb->query_result($is_recurring_event_query,0,'recurring_group_id');
copying it to use at different way
$is_recurring_event_activity_query = $adb->pquery('SELECT activityid from vtiger_activity where recurring_group_id='.$is_recurring_event);
$is_recurring_event_activity = $adb->query_result ($is_recurring_event_activity_query,0,'activityid');
You have to put variable and have to use for loop for your query to execute and get multiple values.
Suppose your query is like this
$result = $adb->pquery ('SELECT * from vtiger_activity where id='.$recordId);
$noofrow = $adb->num_rows($result );
for($i=0; $i<$noofrow ; $i++) {
$Data['activityid']=$adb->query_result($result,$i,'activityid');
$Data['activityname']=$adb->query_result($result,$i,'activityname');
}
Here in $Data you will get an array of the values.
I'm using codeigniter and the pagination class. This is such a basic question, but I need to make sure I'm not missing something. In order to get the config items necessary to paginate results getting them from a MySQL database it's basically necessary to run the query twice is that right?
In other words, you have to run the query to determine the total number of records before you can paginate. So I'm doing it like:
Do this query to get number of results
$this->db->where('something', $something);
$query = $this->db->get('the_table_name');
$num_rows = $query->num_rows();
Then I'll have to do it again to get the results with the limit and offset. Something like:
$this->db->where('something', $something);
$this->db->limit($limit, $offset);
$query = $this->db->get('the_table_name');
if($query->num_rows()){
foreach($query->result_array() as $row){
## get the results here
}
}
I just wonder if I'm actually doing this right in that the query always needs to be run twice? The queries I'm using are much more complex than what is shown above.
Unfortunately, in order to paginate you must know how many elements you are breaking up into pages.
You could always cache the result for the total number of elements if it is too computationally expensive.
Yeah, you have to run two queries, but $this->db->count_all('table_name'); is one & line much cleaner.
Pagination requires reading a record set twice:
Once to read the whole set so that it can count the total number records
Then to read a window of records to display
Here's an example I used for a project. The 'banner' table has a list of banners, which I want to show on a paginated screen:
Using a public class property to store the total records (public $total_records)
Using a private function to build the query (that is common for both activities). The parameter ($isCount) we pass to this function reduces the amount of data the query generate, because for the row count we only need one field but when we read the data window we need all required fields.
The get_list() function first calls the database to find the total and stores it in $total_records and then reads a data window to return to the caller.
Remember we cannot access $total_records without first calling the get_list() method !
class Banner_model extends CI_Model {
public $total_records; //holds total records for get_list()
public function get_list($count = 10, $start = 0) {
$this->build_query();
$query = $this->db->get();
$result = $query->result();
$this->total_records = count($result); //store the count
$this->build_query();
$this->db->limit($count, $start);
$query = $this->db->get();
$result = $query->result();
return $result;
}
private function build_query($isCount = FALSE) {
$this->db->select('*, b.id as banner_id, b.status as banner_status');
if ($isCount) {
$this->db->select('b.id');
}
$this->db->from('banner b');
$this->db->join('company c', 'c.id = b.company_id');
$this->db->order_by("b.id", "desc"); //latest ones first
}
And now from the controller we call:
$data['banner_list'] = $this->banner_model->get_list();
$config['total_rows'] = $this->banner_model->total_records;
Things get complicated when you start using JOINs, like in my example where you want to show banners from a particular company! You may read my blog post on this issue further:
http://www.azmeer.info/pagination-hitting-the-database-twise/