atmega8 UART- doesn't show character in realterm - avr

Question

Hi i'm new to this and i need help. It's suppose to just show the 'S' in the realterm instead it gives 'null'. What would be the problem? could it be the register? or the code itself?
#include <avr/io.h>
#include <util/delay.h>
void UART_Init(unsigned int ubrr)
{
UBRRH=(unsigned int)(ubrr>>8);
UBRRL=(unsigned int)ubrr;
UCSRA=0x00;
UCSRB=(1<<TXEN)|(1<<RXEN);
UCSRC=(0<<USBS)|(1<<UCSZ0)|(1<<UCSZ1);
}
void UART_Tx(unsigned char chr)
{
while (bit_is_clear(UCSRA,UDRE)){}
UDR=chr;
}
int main(void)
{
UART_Init(95);
DDRD|=0B11111111;
PORTD|=0B11111111;
while(1){
_delay_ms(10);
UART_Tx('S');
}
}
System is running on xtal with 14745600 Hz. Speed on host is 9600 baud. all settings should be 8N1.

Answer 1

You need to set the URSEL when writing to the UCSRC register.
Change
UCSRC=(0<<USBS)|(1<<UCSZ0)|(1<<UCSZ1);
to
UCSRC=(1<<URSEL)|(0<<USBS)|(1<<UCSZ0)|(1<<UCSZ1);
From the data sheet:
The UBRRH Register shares the same I/O location as the UCSRC Register. Therefore some
special consideration must be taken when accessing this I/O location. When doing a write access of this I/O location, the high bit of the value written, the USART Register Select (URSEL) bit, controlswhich one of the two registers that will be written. If URSEL is
zero during a write operation, the UBRRH value will be updated. If URSEL is one, the UCSRC
setting will be updated.
The rest of the code looks fine to me.

Answer 2

change UART_Tx('S'); using UART_Tx("S");