Save list of files in array - c++11

I am making a C++ program which should be able to list the files from particular directory and save each file name as a string(which will be processed further for conversion). Do I need array of strings? Which functionality should I use. The number of files is not fixed.
Main thing is I can't enter the names manually. I must accept the names from the list generated.

In this case you want to use a vector:
#include <vector>
#include <string>
using namespace std;
int main()
{
vector<string> file_names;
file_names.push_back("file1.txt");
file_names.push_back("file2.txt");
file_names.push_back("file3.txt");
file_names.push_back("file4.txt");
return 0;
}

Have you thought about using some command line tools to deal with this? Even input redirection will work for this. Example:
./Cpp < echo somedir/*
Where Cpp is the name of your compiled binary, and somedir is the directory you want to read from
Then in your c++ program, you simply use std::cin to read each filename from standard in.
#include <vector>
#include <string>
#include <iterator> // std::istream_iterator, std::back_inserter
#include <algorithm> //std::copy
#include <iostream> // std::cin
int main()
{
std::vector<string> file_names;
// read the filenames from stdin
std::copy(std::istream_iterator<std::string>(std::cin), std::istream_iterator<std::string>(), std::back_inserter(file_names));
// print the filenames
std::copy(file_names.begin(), file_names.end(), std::ostream_iterator<std::string>(std::cout, "\n"));
return 0;
}

Related

Visual Studio VS 2022 won't display cout simplest Code

#include <iostream>
#include <string>
#include <fstream>
using namespace std;
int main(){
string fileTxt;
cout << "disply ok";
return 0;
}
i was working on file handling C++ ifstream but i can't get the Code to open my .txt, so i start troubleshoot and removing all the Codes to only have "hello world" program remaining...
And that still won't work, all i got is a Terminal that goes off instantly...without any text i asked it to display eg. "dsply ok";

Why does this std::map not display in a useable way in the watch window of Visual C++?

I'm unable to view certain std::map in the watch window. Looking into the .natvis file, there are multiple implementations for std::map. Is there a way to select one or the other?
https://developercommunity.visualstudio.com/content/problem/1056550/im-unable-to-inspect-a-variable-of-type-stdmap-in.html
#include <iostream>
#include <map>
#include <string>
#include <vector>
#include <set>
#include <memory>
typedef std::shared_ptr<std::string> PTR_STRING;
typedef std::map<PTR_STRING, std::size_t> accessFunction2Order;
typedef std::set<accessFunction2Order> setOfAccessFunction2Order;
typedef std::map<std::vector<std::size_t>, setOfAccessFunction2Order> A2B;
typedef std::map<PTR_STRING, std::shared_ptr<A2B> > MAP;
int main()
{ MAP s{
{ std::make_shared<std::string>("asdasdasdasdasdasdasdasdasdasd"),
std::make_shared<A2B>()
}
};
const auto &r1 = *s.begin();
}
The map s cannot be watched (something regarding std::_Tree<> being displayed). Curiously a reference to the first element can.
The problem is caused by a (I think hardcoded) limit in the visual studio debugger.
In order to display one variable, the debugger is adapting what he finds in the .natvis file -- but he gives up after some fixed number of attempts to resolve a type.
The solution to this problem is to use something like std::any
(or boost::any for those of us not blessed with being able to use an uptodate C++ version)
to break this STL type into chunks the debugger can deal with.
This is of course only a workaround.
Let's hope that this problem will be solved soon.
#include <iostream>
#include <map>
#include <string>
#include <vector>
#include <set>
#include <any>
#include <memory>
typedef std::shared_ptr<std::string> PTR_STRING;
typedef std::map<PTR_STRING, long> accessFunction2Order;
typedef std::set<accessFunction2Order> setOfAccessFunction2Order;
#if 1
typedef std::map<std::vector<std::size_t>, std::any> A2B;
#else
typedef std::map<std::vector<std::size_t>, setOfAccessFunction2Order> A2B;
#endif
typedef std::map<PTR_STRING, std::shared_ptr<A2B> > MAP;
typedef std::shared_ptr<std::size_t> PTR_INT;
int main()
{ const MAP s{
{ std::make_shared<std::string>("asdasdasdasdasdasdasdasdasdasd"),
std::make_shared<A2B>()
}
};
}

How fix my codeblocks compile programm use fstream, cannot open files large 20 mbs?

#include <iostream>
#include <fstream>
#include <string>
using namespace std;
int main(){
char fileInputPath[256] = "D:\25mb.file";
ifstream fileInput(fileInputPath, ios::in|ios::binary);
if (fileInput.is_open() != true) cout << "File not opened.\n";
return 0;
}
programm result:
File not opened
tesing system win7 x32

Why including cpp makes different result

l learned "include" keyword are just copy & paste.
But including cpp file makes different compile result.
(gcc6~8 + boost1.69)
// main.cpp
#include <iostream>
// I'll move next code to why.cpp
#include <boost/archive/iterators/base64_from_binary.hpp>
#include <boost/archive/iterators/binary_from_base64.hpp>
#include <boost/archive/iterators/transform_width.hpp>
#include <boost/archive/iterators/insert_linebreaks.hpp>
#include <boost/archive/iterators/remove_whitespace.hpp>
void testFunc()
{
using namespace boost::archive::iterators;
typedef transform_width<binary_from_base64<remove_whitespace<std::string::const_iterator>>, 8, 6> ItBinaryT;
std::string input;
std::string output(ItBinaryT(input.begin()), ItBinaryT(input.end()));
}
// -----------------------------
int main()
{
return 0;
}
Above code compiled without warning.
But, I replace some code with include cpp..
// main.cpp
#include <iostream>
#include "why.cpp" // <----------
int main()
{
return 0;
}
// why.cpp - just copy&paste
#include <boost/archive/iterators/base64_from_binary.hpp>
#include <boost/archive/iterators/binary_from_base64.hpp>
#include <boost/archive/iterators/transform_width.hpp>
#include <boost/archive/iterators/insert_linebreaks.hpp>
#include <boost/archive/iterators/remove_whitespace.hpp>
void testFunc()
{
using namespace boost::archive::iterators;
typedef transform_width<binary_from_base64<remove_whitespace<std::string::const_iterator>>, 8, 6> ItBinaryT;
std::string input;
std::string output(ItBinaryT(input.begin()), ItBinaryT(input.end()));
}
It makes warning [-Wsubobject-linkage]
~~ has a field ~~ whose type uses the anonymous namespace
~~ has a base ~~ whose type uses the anonymous namespace
Please look at this link : https://wandbox.org/permlink/bw53IK2ZZP5UWMGk
What makes this difference?
Your compiler treats the main CPP file specially under the assumption that things defined in it are very unlikely to have more than one definition and so some tests for possible violation of the One Definition Rule are not done inside that file. Using #include takes you outside that file.
I would suggest just not using -Wsubobject-linkage since its logic is based on a heuristic that is not applicable to your code.

initializer_lists of streams (C++11)

I'm trying to pass variable number of ofstreams over to a function that accepts an initializer_list but doesn't seem to work and throws all possible errors from the initializer_list structure and about how my function is with an array of ofstreams cannot be matched to any defined function.
Is it actually possible to pass a reference of ofstreams over in an initializer_list?
test.cpp
#include "extension.h"
ofstream outputFile, outputFile2;
int main(void) {
outputFile.open(("data_1.txt");
outputFile2.open("data_2.txt");
writeSomething({outputFile, outputFile2});
outputFile.close();
outputFile2.close();
}
extension.h
#include <stdio.h>
#include <stdlib.h>
#include <stdint.h>
#include <iostream>
#include <fstream>
#include <unistd.h>
#include <string.h>
#include <initializer_list>
using namespace std;
void writeSomething(initializer_list<ofstream&> args);
extension.cpp
#include "extension.h"
void writeSomething(initializer_list<ofstream&> args) {
for (auto f : args ) {
f << "hello" << endl;
}
}
clang 3.4 (trunk 194324) produces a pretty clear error message:
initializer_list:54:23: error: 'iterator' declared as a pointer to a
reference of type
'std::basic_ofstream<char> &'
typedef const _E* iterator;
So no, it is not possible. See also Error: forming pointer to reference type 'const std::pair&'… I can't understand this error.
(gcc 4.7.2 and 4.8.1 crashes on this code due to some internal compiler error. I have submitted a bugreport.)
What you could do instead is to pass a pointer instead of a reference, something like this:
#include <fstream>
#include <initializer_list>
using namespace std;
void writeSomething(initializer_list<ofstream*> args) {
for (auto f : args )
*f << "hello" << endl;
}
int main() {
ofstream outputFile("data_1.txt");
ofstream outputFile2("data_2.txt");
writeSomething({&outputFile, &outputFile2});
}
However, I would much rather use a std::vector instead. Using an initializer list for this purpose is very strange and confusing for me.

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