I need to clear the toolbar without reloading the grid in my jqgrid. It should just reset the toolbar to its default values.
I tried using,
$("#TransactionsGrid")[0].clearToolbar();
My grid datatype:local and i don't use loadonce:true.
This made the toolbar clear and refresh the grid. I dont want that to happen.
Any ideas?
I find the question interesting.
To implement the requirement I suggest to use register jqGridToolbarBeforeClear to execute the handler only once. The handler should 1) unregister itself as the event handler and return "stop" to prevent reloading of the grid:
$grid.jqGrid("filterToolbar", { defaultSearch: "cn" });
$("#clearToolbar").button().click(function () {
var myStopReload = function () {
$grid.unbind("jqGridToolbarBeforeClear", myStopReload);
return "stop"; // stop reload
};
$grid.bind("jqGridToolbarBeforeClear", myStopReload);
if ($grid[0].ftoolbar) {
$grid[0].clearToolbar();
}
});
The corresponding demo shows it live.
Related
I have a form which has a tab and in this tab is a quickview form. On the quickview form, I have a subgrid and a text field.
The tab has a default state of 'collapsed'. When I open the form, only the text field is displayed. It seems as if the subgrid in no rendering at all.
If I change the tab default state to 'expanded', then when I open the form, the
subgrid is rendering correctly.
I have tried to refresh the quickform view outlined here
https://msdn.microsoft.com/en-us/library/mt736908.aspx
But it does not seem to work.
UPDATE:
I have tried the following, but still no success.
FIRST VERSION
// Triggering when the tab is expanded
function onChange(){
console.log('on change');
// get quick view form
var qv = Xrm.Page.ui.quickForms.get("myquickformview");
qv.refresh();
// get subgrid
try {
qv.getControl(0).refresh();
}
catch (e)
{
console.log(e);
}
}
SECOND VERSION
function onLoad(){
console.log('onload');
Xrm.Page.getAttribute('new_person').addOnChange(refresh);
}
function onChange(){
Xrm.Page.getAttribute('new_person').fireOnChange();
}
function refresh(){
console.log('on change');
// get quick view form
var qv = Xrm.Page.ui.quickForms.get("myquickformview");
// get subgrid
try {
qv.getControl(0).setVisible(false);
qv.getControl(0).setVisible(true);
qv.getControl(0).refresh();
}
catch (e)
{
console.log(e);
}
qv.refresh();
}
Any advice appreciated. Thanks in advance.
1.Add onchange event handler for the lookup (on which Quick view form is rendered) to have the code to refresh the quick view control.
Xrm.Page.getAttribute("lookup_fieldname").addOnChange(function);
Keep the below code in function.
var quickViewControl = Xrm.Page.ui.quickForms.get(“your quick view form name”);
if (quickViewControl != undefined) {
if (quickViewControl.isLoaded()) {
quickViewControl.refresh();
}
}
2.Trigger fireOnChange() of lookup on tab expanded handler, so that onchange will refresh QVform totally.
Xrm.Page.getAttribute("lookup_fieldname").fireOnChange();
Got a hint from this. I just answered here (in mobile without testing) to unblock you.
I'm using Kendo UI Grid with server paging and sorting. When sort is changed, grid refreshes the data, but current page remains the same.
How to catch sort event and move to first page?
P.S. I've read this thread, but there discussed another case...
Consider the following approach:
use the change event of the Kendo UI DataSource to save the current sort state in some variable.
use the requestStart event to compare the previous sort state with the new sort state.
if the sort state has changed, prevent the request with e.preventDefault()
use the page method to navigate to first page
you will also need a flag variable to prevent an endless loop in the requestStart handler, as changing the page will trigger a new requestStart event
Here is a demo:
http://dojo.telerik.com/OXoYu
var sortState;
var resetPageFlag = false;
// ...
requestStart: function(e) {
//console.log(e.sender.sort(), sortState);
if (!resetPageFlag &&
JSON.stringify(e.sender.sort()) != JSON.stringify(sortState)) {
//console.log(e.sender.sort(), sortState);
e.preventDefault();
resetPageFlag = true;
e.sender.page(1);
} else {
resetPageFlag = false;
}
},
change: function(e) {
sortState = e.sender.sort();
}
// ...
Does anyone know of a way to trigger the editing of a row just by clicking the row?
I would like to see the same functionality that I see when I click an edit command button, but triggered by selecting the row.
You can add this to your change event for your grid:
myGrid.setOptions({
editable: {
mode: "inline"
},
change: function(){
this.editRow(this.select());
}
});
I know this is an old question, but I just had need for a solution and this is what worked for me. I wanted to use double-click, but the click event should also work.
var grid = $('#grid').data('kendoGrid');
$('#grid .k-grid-content table').on(
'dblclick',
'tr',
function () { grid.editRow($(this)); }
);
The selector ("#grid .k-grid-content table") works for my current configuration (mainly I have virtual scrolling turned on) and so may need to be adjusted for your specific situation.
I've created a Kendo Scheduler that binds to a remote data source. The remote datasource is actually a combination of two separate data sources. This part is working okay.
Question is... is there any way to prevent certain events from being destroyed?
I've stopped other forms of editing by checking a certain field in the event's properties and calling e.preventDefault() on the edit, moveStart and resizeStart events if it should be read-only. This works fine, but I can't prevent deletes.
Any suggestions greatly appreciated.
Just capture the remove event and process it as you have with the edit, moveStart, and reviseStart events. You should see a remove event option off the kendo scheduler. I can see it and capture it in version 2013.3.1119.340.
I think better way is to prevent user from going to remove event in the first place. Handling the remove event still has its validity as you can delete event for example by pressing "Delete" key).
In example below I'm assuming event has custom property called category and events with category equal to "Holiday" can't be deleted.
remove: function(e)
{
var event = e.event;
if (event.category === "Holiday")
{
e.preventDefault();
e.stopPropagation();
}
},
dataBound: function(e)
{
var scheduler = e.sender;
$(".k-event").each(function() {
var uid = $(this).data("uid");
var event = scheduler.occurrenceByUid(uid);
if (event.category === "Holiday")
{
// use .k-event-delete,.k-resize-handle if you want to prevent also resizing
$(this).find(".k-event-delete").hide();
}
});
},
edit: function (e) {
var event = e.event;
if (event.category === "Holiday")
{
e.container.find(".k-scheduler-delete").hide();
}
}
FYI, you can do this...
#(Html.Kendo().Scheduler<ScheduledEventViewModel>()
.Name("scheduler")
.Editable(e => e.Confirmation(false))
)
which will deactivate the default confirmation prompt for the scheduler. Then you can do your own prompt on items you want.
There is also a
.Editable(e => e.Destroy(false))
that you can do to remove the X on the event window. This particular example would remove it for all of the events, but there might be a way to remove it for specific ones.
Does anyone know how to trigger the stock jqGrid "Loading..." overlay that gets displayed when the grid is loading? I know that I can use a jquery plugin without much effort but I'd like to be able to keep the look-n-feel of my application consistent with that of what is already used in jqGrid.
The closes thing I've found is this:
jqGrid display default "loading" message when updating a table / on custom update
n8
If you are searching for something like DisplayLoadingMessage() function. It does not exist in jqGrid. You can only set the loadui option of jqGrid to enable (default), disable or block. I personally prefer block. (see http://www.trirand.com/jqgridwiki/doku.php?id=wiki:options). But I think it is not what you wanted.
The only thing which you can do, if you like the "Loading..." message from jqGrid, is to make the same one. I'll explain here what jqGrid does to display this message: Two hidden divs will be created. If you have a grid with id=list, this divs will look like following:
<div style="display: none" id="lui_list"
class="ui-widget-overlay jqgrid-overlay"></div>
<div style="display: none" id="load_list"
class="loading ui-state-default ui-state-active">Loading...</div>
where the text "Loading..." or "Lädt..." (in German) comes from $.jgrid.defaults.loadtext. The ids of divs will be constructed from the "lui_" or "load_" prefix and grid id ("list"). Before sending ajax request jqGrid makes one or two of this divs visible. It calls jQuery.show() function for the second div (id="load_list") if loadui option is enable. If loadui option is block, however, then both divs (id="lui_list" and id="load_list") will be shown with respect of .show() function. After the end of ajax request .hide() jQuery function will be called for one or two divs. It's all.
You will find the definition of all css classes in ui.jqgrid.css or jquery-ui-1.8.custom.css.
Now you have enough information to reproduce jqGrid "Loading..." message, but if I were you I would think one more time whether you really want to do this or whether the jQuery blockUI plugin is better for your goals.
I use
$('.loading').show();
$('.loading').hide();
It works fine without creating any new divs
Simple, to show it:
$("#myGrid").closest(".ui-jqgrid").find('.loading').show();
Then to hide it again
$("#myGrid").closest(".ui-jqgrid").find('.loading').hide();
I just placed below line in onSelectRow event of JQ grid it worked.
$('.loading').show();
The style to override is [.ui-jqgrid .loading].
You can call $("#load_").show() and .hide() where is the id of your grid.
its is worling with $('div.loading').show();
This is also useful even other components
$('#editDiv').dialog({
modal : true,
width : 'auto',
height : 'auto',
buttons : {
Ok : function() {
//Call Action to read wo and
**$('div.loading').show();**
var status = call(...)
if(status){
$.ajax({
type : "POST",
url : "./test",
data : {
...
},
async : false,
success : function(data) {
retVal = true;
},
error : function(xhr, status) {
retVal = false;
}
});
}
if (retVal == true) {
retVal = true;
$(this).dialog('close');
}
**$('div.loading').hide();**
},
Cancel : function() {
retVal = false;
$(this).dialog('close');
}
}
});
As mentioned by #Oleg the jQuery Block UI have lots of good features during developing an ajax base applications. With it you can block whole UI or a specific element called element Block
For the jqGrid you can put your grid in a div (sampleGrid) and then block the grid as:
$.extend($.jgrid.defaults, {
ajaxGridOptions : {
beforeSend: function(xhr) {
$("#sampleGrid").block();
},
complete: function(xhr) {
$("#sampleGrid").unblock();
},
error: function(jqXHR, textStatus, errorThrown) {
$("#sampleGrid").unblock();
}
}
});
If you want to not block and not make use of the builtin ajax call to get the data
datatype="local"
you can extend the jqgrid functions like so:
$.jgrid.extend({
// Loading function
loading: function (show) {
if (show === undefined) {
show = true;
}
// All elements of the jQuery object
this.each(function () {
if (!this.grid) return;
// Find the main parent container at level 4
// and display the loading element
$(this).parents().eq(3).find(".loading").toggle(show);
});
return show;
}
});
and then simple call
$("#myGrid").loading();
or
$("#myGrid").loading(true);
to show loading on all your grids (of course changing the grid id per grid) or
$("#myGrid").loading(false);
to hide the loading element, targeting specific grid in case you have multiple grids on the same page
In my issues I used
$('.jsgrid-load-panel').hide()
Then
$('.jsgrid-load-panel').show()