If loop with OR - shell

Question

I have following strings in input.txt file.
Running
isn't running
is running
Stopped
stopped
Aborted
aborted
Here I would need to match everything except "Running" and "is running". So far I have done below but it seems to be printing "Running" and "is running" as well. Can some help ?
exec < input.txt
while read line
do
if [[ $line =~ [Aa]borted || [Ss]topped || isn*t ]]; then
echo "$line"
else
echo "FINE"
fi
done

Answer 1

Why don't use grep?
grep -v "unning" < input.txt
gives you desired lines.

Answer 2

grep -vE '\<(R|is r)unning\>' input.txt
The \< and \> markers are word boundaries, so you won't filter out "this running"
In shell
while IFS= read -r line; do
case $line in
*"Running"* | *"is running"*) echo FINE ;;
*) echo "$line" ;;
esac
done < input.txt
Problem in your code: this line
[[ $line =~ [Aa]borted || [Ss]topped || isn*t ]]
is not equivalent to this
[[ $line =~ [Aa]borted ]] || [[ $line =~ [Ss]topped ]] || [[ $line =~ isn*t ]]
it is equivalent to this
[[ $line =~ [Aa]borted ]] || [[ -n "[Ss]topped" ]] || [[ -n "isn*t" ]]
because the "or" operator || has higher precedence than the regex match operator =~
Since the last 2 conditions are always true, each line passes.
Note also that you're using glob patterns with a regular expression match operator, so this [[ $line =~ isn*t ]] will not match isn't, it will match is and t with zero or more n in between. (ist, isnt, isnnt, etc)
You intended to write this
[[ $line == [Aa]borted || $line == [Ss]topped || $line == isn*t ]]
which is mote concisely written with case:
case $line in
[Aa]borted | [Ss]topped | isn*t) echo "$line" ;;
*) echo FINE ;;
esac
which is the inverse of my answer.