Oracle Sibling Structure - oracle

I have a structure that I store equal records in a database table. You can think that these records are siblings. For example I have two records in this table; 1=2 and 1=3. And I need a query that will return all siblings of a given record. Let me give an example;
This is my table with two columns:
create table SIBLINGSTEST(col1 number, col2 number);
I have 2 records, 1=2 and 1=3
insert into SIBLINGSTEST values(1,2);
insert into SIBLINGSTEST values(1,3);
I thought using connect by is the best solution for this situation, and write the following query:
SELECT * FROM SIBLINGSTEST
START WITH (col1 = 1 or col2 = 1)
CONNECT BY NOCYCLE (
(PRIOR col1 = col1) or
(PRIOR col1 = col2) OR
(PRIOR col2 = col1) or
(PRIOR col2 = col2))
This query returns correct results, returning both rows.
If I use 2 as a parameter, the query also runs correctly, returning again both rows.
But if I use 3 as a parameter, the query does not run as I expected, returning only the start row.
SELECT * FROM SIBLINGSTEST
START WITH (col1 = 3 or col2 = 3)
CONNECT BY NOCYCLE (
(PRIOR col1 = col1) or
(PRIOR col1 = col2) OR
(PRIOR col2 = col1) or
(PRIOR col2 = col2))
I wonder why the results of 2 and 3 differs. Any help or idea will be appriciated.
Thanks.

I get both rows with your last query as expected:
SQL> SELECT * FROM SIBLINGSTEST
2 START WITH (col1 = 3 or col2 = 3)
3 CONNECT BY NOCYCLE (
4 (PRIOR col1 = col1) or
5 (PRIOR col1 = col2) OR
6 (PRIOR col2 = col1) or
7 (PRIOR col2 = col2));
COL1 COL2
---------- ----------
1 3
1 2
However I would not choose to model it this way. If what you really want is to record that 1, 2, 3 are siblings then I would use:
create table siblings_group (group_id number);
create table people (person_id number, group_id number);
insert into siblings_group values (1);
insert into people values (1, 1);
insert into people values (2, 1);
insert into people values (3, 1);
Then to find all siblings of 3:
SQL> select person_id from people where group_id =
2 (select group_id from people where person_id=3);
PERSON_ID
----------
1
2
3

Related

how to split one string column of `(12345)some_string` to two column `12345`, `some_string` in Oracle

As the question,
how to split one string column of (12345)some_string to two-column 12345and some_string in Oracle?
Notice: Not all the columns are (12345)some_string, part of columns are only some_string without (12345), the two columns are null and some string
With sample data you posted, this could be one option (line #5 onward):
SQL> with test (col) as
2 (select '(12345)some_string' from dual union all
3 select 'another_string' from dual
4 )
5 select regexp_substr(col, '\d+') col1,
6 substr(col, instr(col, ')') + 1) col2
7 from test;
COL1 COL2
------------------ ------------------
12345 some_string
another_string
SQL>
Assuming the following table:
create table my_table (my_column varchar2(30));
insert into my_table values ('(12345)some_string');
commit;
1) Add a new column to the table
alter table my_table add new_column number;`
2) Fill the new column
update my_table set new_column = regexp_substr(my_column, '^\(([1-9]+)\)', 1, 1, NULL, 1);
3) Update the original column
update my_table set my_column = regexp_replace(my_column, '^\([1-9]+\)', '');

Fetch name based on comma-separated ids

I have two tables, customers and products.
products:
productid name
1 pro1
2 pro2
3 pro3
customers:
id name productid
1 cust1 1,2
2 cust2 1,3
3 cust3
i want following result in select statement,
id name productid
1 cust1 pro1,pro2
2 cust2 pro1,pro3
3 cust3
i have 300+ records in both tables, i am beginner to back end coding, any help?
Definitely a poor database design but the bad thing is that you have to live with that. Here is a solution which I created using recursive query. I don't see the use of product table though since your requirement has nothing to do with product table.
with
--Expanding each row seperated by comma
tab(col1,col2,col3) as (
Select distinct c.id,c.prdname,regexp_substr(c.productid,'[^,]',1,level)
from customers c
connect by regexp_substr(c.productid,'[^,]',1,level) is not null
order by 1),
--Appending `Pro` to each value
tab_final as ( Select col1,col2, case when col3 is not null
then 'pro'||col3
else col3
end col3
from tab )
--Displaying result as expected
SELECT
col1,
col2,
LISTAGG(col3,',') WITHIN GROUP( ORDER BY col1,col2 ) col3
FROM
tab_final
GROUP BY
col1,
col2
Demo:
--Preparing dataset
With
customers(id,prdname,productid) as ( Select 1, 'cust1', '1,2' from dual
UNION ALL
Select 2, 'cust2','1,3' from dual
UNION ALL
Select 3, 'cust3','' from dual),
--Expanding each row seperated by comma
tab(col1,col2,col3) as (
Select distinct c.id,c.prdname,regexp_substr(c.productid,'[^,]',1,level)
from customers c
connect by regexp_substr(c.productid,'[^,]',1,level) is not null
order by 1),
--Appending `Pro` to each value
tab_final as ( Select col1,col2, case when col3 is not null
then 'pro'||col3
else col3
end col3
from tab )
--Displaying result as expected
SELECT
col1,
col2,
LISTAGG(col3,',') WITHIN GROUP( ORDER BY col1,col2 ) col3
FROM
tab_final
GROUP BY
col1,
col2
PS: While using don't forget to put your actual table columns as in my example it may vary.

Update multiple columns with the value of a single select

Right now I got something like this:
UPDATE TableA
SET a = (SELECT b FROM TableB),
aa = (SELECT b FROM TableB)
Is there a more elegant solution?
You can write:
UPDATE TableA
SET (a, aa) = (SELECT b, b FROM TableB);
Note: this assumes that TableB contains exactly one row. If not, exception will be raised.
Be careful when updating one table with the values from another, or you will update ALL rows in the target table even if you think you're only updating a few rows. On large tables, this will be very painful (and corrupt your data). For example:
update tab_x x
set (col2, col3) = (
select col2, col3
from tab_y y
where x.col1 = y.col1)
-- the following part will make sure we only update rows
-- that match the join condition (x.col1 = y.col1)
-- without this part, we'd update all rows in the x table!
where exists (
select 1
from tab_y y
where x.col1 = y.col1
)
The full example would be:
SQL> set display on
SQL> drop table tab_x
Table dropped.
SQL> create table tab_x
(
col1 number,
col2 varchar2(20),
col3 varchar2(20)
)
Table created.
SQL> drop table tab_y
Table dropped.
SQL> create table tab_y
(
col1 number,
col2 varchar2(20),
col3 varchar2(20)
)
Table created.
SQL> insert into tab_x values (1, 'Col2 from x','Col3 from x')
1 row created.
SQL> insert into tab_x values (2, 'Col2 from x','Col3 from x')
1 row created.
SQL> insert into tab_x values (3, 'Col2 from x','Col3 from x')
1 row created.
SQL> insert into tab_y values (1, 'Col2 from y','Col3 from y')
1 row created.
SQL> insert into tab_y values (2, 'Col2 from y','Col3 from y')
1 row created.
SQL> insert into tab_y values (9, 'Col2 from y','Col3 from y')
1 row created.
SQL> commit
Commit complete.
SQL> select * from tab_x
COL1 COL2 COL3
---------- -------------------- --------------------
1 Col2 from x Col3 from x
2 Col2 from x Col3 from x
3 Col2 from x Col3 from x
3 rows selected.
SQL> update tab_x x
set (col2, col3) = (
select col2, col3
from tab_y y
where x.col1 = y.col1)
-- the following part will make sure we only update rows
-- that match the join condition (x.col1 = y.col1)
-- without this part, we'd update all rows in the x table!
where exists (
select 1
from tab_y y
where x.col1 = y.col1
)
2 rows updated.
SQL> select * from tab_x
COL1 COL2 COL3
---------- -------------------- --------------------
1 Col2 from y Col3 from y
2 Col2 from y Col3 from y
3 Col2 from x Col3 from x
3 rows selected.

How to display comma separated descriptions based on comma separated values in Oracle 10g?

I am new to Oracle technology. Earlier I posted 2 posts for the same issue due to lack of understanding the requirement.
Table 1:
MSGID
-----
1,2,3
2,3
4
null
null
Table 2:
MID MSGDESC
---- -------
1 ONE
2 TWO
3 THREE
4 FOUR
Expected output:
XCOL DESC
----- -----
1,2,3 ONE,TWO,THREE
2,3 TWO,THREE
4 FOUR
I am not able to fulfil this requirement. Please provide me one solution.
Note: tables don't have any unique or primary key values. Table 1 has 5000 records and table 2 only has 80 records with descriptions.
create table Table1 (MSGID varchar2(100));
insert into Table1 values ('1,2,3');
insert into Table1 values ('2,3');
insert into Table1 values ('4');
insert into Table1 values (null);
insert into Table1 values (null);
create table Table2 (MID varchar2(100), MSGDESC varchar2(100));
insert into Table2 values ('1','ONE');
insert into Table2 values ('2','TWO');
insert into Table2 values ('3','THREE');
insert into Table2 values ('4','FOUR');
select
msgid as xcol,
"DESC",
col1, col2, ..., col12
from
Table1
left join (
select
msgid,
wm_concat(msgdesc) as "DESC"
from
(
select
msgid,
msgdesc
from
(select distinct msgid from Table1 where ...)
cross join (
select level as occ from dual connect by level <= 100)
)
left join Table2
on mid = regexp_substr(msgid, '[^,]+', 1, occ)
where
occ <= regexp_count(msgid, ',') + 1
order by msgid, occ
)
group by msgid
) using (msgid)

Delete with Left Join in Oracle 10g

I have the following code that works fine in MS SQL Server:
delete grp
from grp
left join my_data
on grp.id1 = my_data.id1
and grp.id2 = my_data.id2
and grp.id3 = my_data.id3
and grp.id4 = my_data.id4
where my_data.id1 is NULL
Basically, I want to delete all occurrence that can be found in grp and don't have any equivalence in my_data. Sadly, it doesn't work in Oracle 10g. I tried using the old syntax for left join (+) but it doesn't work either. Like this:
delete grp
from grp,
my_data
where grp.id1 = my_data.id1 (+)
and grp.id2 = my_data.id2 (+)
and grp.id3 = my_data.id3 (+)
and grp.id4 = my_data.id4 (+)
and my_data.id1 is NULL
A IN clause would works if I didn't have multiple keys but I don't see how I could use it with my data. So, what is the alternative?
Shannon's solution is the way to go: use the operator NOT IN (or NOT EXISTS).
You can however delete or update a join in Oracle, but the synthax is not the same as MS SQL Server:
SQL> DELETE FROM (SELECT grp.*
2 FROM grp
3 LEFT JOIN my_data ON grp.id1 = my_data.id1
4 AND grp.id2 = my_data.id2
5 AND grp.id3 = my_data.id3
6 AND grp.id4 = my_data.id4
7 WHERE my_data.id1 IS NULL);
2 rows deleted
Additionally, Oracle will only let you update a join if there is no ambiguity as to which base row will be accessed by the statement. In particular, Oracle won't risk an update or a delete (the statement will fail) if there is a possibility that a row may appear twice in the join. In this case, the delete will only work if there is a UNIQUE constraint on my_data(id1, id2, id3, id4).
Tables and data:
SQL> create table grp (id1 number null, id2 number null, id3 number null, id4 number null);
Table created.
SQL> create table my_data (id1 number null, id2 number null, id3 number null, id4 number null);
Table created.
SQL> insert into grp values (1, 2, 3, 4);
1 row created.
SQL> insert into grp values (10, 20, 30, 40);
1 row created.
SQL> insert into grp values (1, 2, 30, 40);
1 row created.
SQL> insert into my_data values (1, 2, 3, 4);
1 row created.
SQL> commit;
Commit complete.
Using in. Note Do not use if the IDs in the subquery can be null. Not in of null never returns true.
SQL> delete grp where (id1, id2, id3, id4) not in (select id1, id2, id3, id4 from my_data);
2 rows deleted.
SQL> select * from grp;
ID1 ID2 ID3 ID4
---------- ---------- ---------- ----------
1 2 3 4
Using exists
SQL> rollback;
Rollback complete.
SQL> delete grp where not exists (select * from my_data where grp.id1 = my_data.id1 and grp.id2 = my_data.id2 and grp.id3 = my_data.id3 and grp.id4 = my_data.id4);
2 rows deleted.
SQL> select * from grp;
ID1 ID2 ID3 ID4
---------- ---------- ---------- ----------
1 2 3 4
SQL>
If you want to ensure there is no ambiguity in what's being deleted, you could change Vincent's solution to:
delete from grp where rowid in
(
select
grp.rowid
from
grp left outer join my_data on
grp.id1 = my_data.id1
and grp.id2 = my_data.id2
and grp.id3 = my_data.id3
and grp.id4 = my_data.id4
where
my_data.id1 is NULL
)
Either Vincent's answer https://stackoverflow.com/a/3675205 does not work at all, or it does not work in Oracle 12c. That answer should be improved by specifying the lowest or highest version of Oracle where this works. The proof:
SELECT * FROM v$version where banner like 'Oracle%';
/*
Oracle Database 12c Standard Edition Release 12.2.0.1.0 - 64bit Production
*/
create table a (id int);
create table b (id int);
insert into a select 1 from dual union select 2 from dual;
insert into b select 1 from dual union select 2 from dual union select 3 from dual;
select * from a right join b on b.id = a.id;
/*
1 1
2 2
null 3
*/
delete from (
select b.*
from b
inner join a on a.id = b.id
)
/*
Error at Command Line : 7 Column : 13
Error report -
SQL Error: ORA-01752: cannot delete from view without exactly one key-preserved table
01752. 00000 - "cannot delete from view without exactly one key-preserved table"
*Cause: The deleted table had
- no key-preserved tables,
- more than one key-preserved table, or
- the key-preserved table was an unmerged view.
*Action: Redefine the view or delete it from the underlying base tables.
*/
delete from b
where rowid in (
select b.rowid
from b
inner join a on a.id = b.id
)
/*
2 rows deleted.
*/
select * from a right join b on b.id = a.id
/*
null 3
*/
drop table a;
drop table b;
Bottom line is, use WHERE ROWID IN () at least in 12c.
I can't add a comment because it need 50 reps,so I add a answer here.
I tested Vincent's delete from query, that syntax can't let you delete what you want,at least it's not a common use for all the delete join cases.
At first I create a table using oracle default user scott:
create table emp1 as select * from emp where sal<2000;
I want to delete the records from emp where empno in emp1(just a simple test),so I used this delete from query:
delete from (select a.* from emp a join emp1 b on a.empno=b.empno);
No matter what the table or join order is,left join or inner join,no matter what where clause I use,the sql will delete the corresponding records in emp1.
So I think this delete from query can not let you delete from a specified table.
Loop a cursor will be a better way for these cases.

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