Fetch name based on comma-separated ids - oracle

Question

I have two tables, customers and products.
products:
productid name
1 pro1
2 pro2
3 pro3
customers:
id name productid
1 cust1 1,2
2 cust2 1,3
3 cust3
i want following result in select statement,
id name productid
1 cust1 pro1,pro2
2 cust2 pro1,pro3
3 cust3
i have 300+ records in both tables, i am beginner to back end coding, any help?

Answer 1

Definitely a poor database design but the bad thing is that you have to live with that. Here is a solution which I created using recursive query. I don't see the use of product table though since your requirement has nothing to do with product table.
with
--Expanding each row seperated by comma
tab(col1,col2,col3) as (
Select distinct c.id,c.prdname,regexp_substr(c.productid,'[^,]',1,level)
from customers c
connect by regexp_substr(c.productid,'[^,]',1,level) is not null
order by 1),
--Appending `Pro` to each value
tab_final as ( Select col1,col2, case when col3 is not null
then 'pro'||col3
else col3
end col3
from tab )
--Displaying result as expected
SELECT
col1,
col2,
LISTAGG(col3,',') WITHIN GROUP( ORDER BY col1,col2 ) col3
FROM
tab_final
GROUP BY
col1,
col2
Demo:
--Preparing dataset
With
customers(id,prdname,productid) as ( Select 1, 'cust1', '1,2' from dual
UNION ALL
Select 2, 'cust2','1,3' from dual
UNION ALL
Select 3, 'cust3','' from dual),
--Expanding each row seperated by comma
tab(col1,col2,col3) as (
Select distinct c.id,c.prdname,regexp_substr(c.productid,'[^,]',1,level)
from customers c
connect by regexp_substr(c.productid,'[^,]',1,level) is not null
order by 1),
--Appending `Pro` to each value
tab_final as ( Select col1,col2, case when col3 is not null
then 'pro'||col3
else col3
end col3
from tab )
--Displaying result as expected
SELECT
col1,
col2,
LISTAGG(col3,',') WITHIN GROUP( ORDER BY col1,col2 ) col3
FROM
tab_final
GROUP BY
col1,
col2
PS: While using don't forget to put your actual table columns as in my example it may vary.