I've got two sets of dates being passed into a query and I would like to find all the months/years between both sets of dates.
When I try this:
WITH CTE_Dates (cte_date) AS (
SELECT cast(date '2014-01-27' as date) from dual
UNION ALL
SELECT cast(ADD_MONTHS(TRUNC(cte_date, 'MONTH'),1) as date)
FROM CTE_Dates
WHERE ( TO_DATE(ADD_MONTHS(TRUNC(cte_date, 'MONTH'), 1)) BETWEEN TO_DATE ('27-01-2014','DD-MM-YYYY') AND TO_DATE ('27-04-2014','DD-MM-YYYY'))
OR
( TO_DATE(ADD_MONTHS(TRUNC(cte_date, 'MONTH'), 1)) BETWEEN TRUNC(TO_DATE('27-11-2014','DD-MM-YYYY'), 'MONTH') AND TO_DATE ('27-01-2015','DD-MM-YYYY'))
)
SELECT * from CTE_Dates
I get:
27-JAN-14
01-FEB-14
01-MAR-14
01-APR-14
I would also want to get:
01-NOV-14
01-DEC-14
01-JAN-15
It looks like the OR portion of the WHERE clause gets ignored.
Suggestions on how to create this query?
Thanks
Cory
The problem with what you have now (aside from extra cast() and to_date() calls) is that on the fourth iteration both the conditions are false so the recursion stops; there's nothing to make it skip a bit and pick up again, otherwise it would continue forever. I don't think you can achieve both ranges within the recursion.
You can put the latest date you want inside the recursive part, and then filter the two ranges you want afterwards:
WITH CTE_Dates (cte_date) AS (
SELECT date '2014-01-27' from dual
UNION ALL
SELECT ADD_MONTHS(TRUNC(cte_date, 'MONTH'), 1)
FROM CTE_Dates
WHERE ADD_MONTHS(TRUNC(cte_date, 'MONTH'), 1) <= date '2015-01-27'
)
SELECT * from CTE_Dates
WHERE cte_date BETWEEN date '2014-01-27' AND date '2014-04-27'
OR cte_date BETWEEN date '2014-11-27' AND date '2015-01-27';
CTE_DATE
---------
27-JAN-14
01-FEB-14
01-MAR-14
01-APR-14
01-DEC-14
01-JAN-15
6 rows selected
You can replace the hard-coded values with your pairs of start and end dates. If the ranges might overlap or the second range could be (or end) before the first one, you could pick the higher date:
WHERE ADD_MONTHS(TRUNC(cte_date, 'MONTH'), 1)
<= greatest(date '2015-01-27', date '2014-04-27')
... though that only makes sense with variables, not fixed values.
Related
I am trying to separate the time and date in one column to be independent off each other. I am new at writing scripts
this is my query:
select
*
from
[tablename]
where
to_date([column_name]) in ( '15-Jun-2021', '16-Jun-2021' )
and
to_char([column_name],'dd-Mon-yyyy HH:MM:ss') < '15-Jun-2021 19:54:30'
The way you put it, it would be
select *
from your_table
where date_column >= date '2021-06-15'
and date_column < to_date('15.06.2021 19:54:30', 'dd.mm.yyyy hh24:mi:ss')
because
date_column should be of date datatype. If it isn't, you'll have problems of many kinds in the future. Therefore,
don't to_date it, it is already a date
don't to_char it either, because you'd be comparing strings and get unexpected result. Use that function when you want to nicely display the result
the second condition you wrote makes the first one questionable. If date_column is less than value you wrote, then you can omit date '2021-06-16' from the first condition because you won't get any rows for that date anyway
date literal (date '2021-06-15') sets time to midnight, so condition I wrote should return rows you want
SQL> select date '2021-06-15' first,
2 to_date('15.06.2021 19:54:30', 'dd.mm.yyyy hh24:mi:ss') second
3 from dual;
FIRST SECOND
------------------- -------------------
15.06.2021 00:00:00 15.06.2021 19:54:30
SQL>
Just had a user answer this correctly for TSQL, but wondering how best to achieve this now in SQL Developer/PLSQL seeing as there is no DATEDIFF function.
Table I want to query on has some 'CODE' values, which can naturally have multiple primary key records ('OccsID') in a table 'Occs'. There is also a datetime column called 'CreateDT' for each OccsID.
Just want to find the maximum possible time variance between any 2 consecutive rows in 'Occs', per 'CODE'.
If you subtract the "next" date and "this" date (using the LEAD analytic function), you'll get the date difference. Then fetch the maximum difference per code. Something like this:
with diff as
(select occsid,
code,
nvl(lead(createdt) over (partition by code order by createdt), createdt) - createdt date_diff
from test
)
select code,
max(date_diff)
from diff
group by code;
Assuming that this T-SQL version works for you (from the prior question)
SELECT x.code, MAX(x.diff_sec) FROM
(
SELECT
code,
DATEDIFF(
SECOND,
CreateDT,
LEAD(CreateDT) OVER(PARTITION BY CODE ORDER BY CreateDT) --next row's createdt
) as diff_sec
FROM Occs
)x
GROUP BY x.code
The simplest option is just to subtract the two dates to get a difference in days. You can then multiply to get the difference in hours, minutes, or seconds
SELECT x.code, MAX(x.diff_day), MAX(x.diff_sec)
FROM
(
SELECT
code,
CreateDT -
LEAD(CreateDT) OVER(PARTITION BY CODE ORDER BY CreateDT) as diff_day,
24*60*60* (CreateDT -
LEAD(CreateDT) OVER(PARTITION BY CODE ORDER BY CreateDT)) as diff_sec
FROM Occs
)x
GROUP BY x.code
I am trying to add a day with a specific date using add_months in oracle database.
I wrote this line:
SELECT ADD_MONTHS('01-JAN-2018', MONTHS_BETWEEN('02-JAN-2018', '01-JAN-2018')) FROM DUAL;
this returns:
01-JAN-18
Why doesn't it return 02-JAN-18?? Can I add one day to the date using this function?
Why doesn't it return 02-JAN-18??
According to MONTHS_BETWEEN documentation,
The MONTHS_BETWEEN function calculates the number of months between
two dates. When the two dates have the same day component or are both
the last day of the month, then the return value is a whole number.
Otherwise, the return value includes a fraction that considers the
difference in the days based on a 31-day month
So,
select MONTHS_BETWEEN('02-JAN-2018', '01-JAN-2018') FROM DUAL ;
yields
.0322580645161290322580645161290322580645
ADD_MONTHS returns the date date plus integer months.
So, .0322.. is considered as integer 0 and your query is equivalent to
SELECT ADD_MONTHS('01-JAN-2018', 0) FROM DUAL;
In order to add 1 months, simply take the difference of two dates.
SELECT ADD_MONTHS(DATE '2018-01-01', DATE '2018-01-02' - DATE '2018-01-01') FROM DUAL;
Or better, add an INTERVAL of 1 month
SELECT DATE '2018-01-01' + INTERVAL '1' MONTH FROM DUAL;
To answer your question, add 1 day, simply use
SELECT DATE '2018-01-01' + 1 FROM DUAL;
I ran these two scripts below and they give two different results. The first did not include data for the 30th of April but the latter does. I am using oracle sql. Could someone assist?
select distinct * from a where (m_date between'01-MAY-17' AND '30-MAY-17');
select distinct * from a where m_date like '%-MAY-17';
I used the to_date function and it worked:
select distinct * from a where to_date (m_date) between'01-MAY-17' AND '30-MAY-17'
This produced the same results as with the like clause:
select distinct * from a where m_date like '%-MAY-17'
Your between clause
select distinct * from a where to_date (m_date) between'01-MAY-17' AND '30-MAY-17'
is the same as saying (pseudo-code)
...where to_date (m_date) between '01-may-17 00:00:00' AND '30-may-17 00:00:00'...
which excludes and date values on 5/30 where there is any time element other than 12AM in the morning. (Also, May does have 31 days).
It would be more correct to do the following, assuming m_date is a date data type and assuming you want all values during the month of may.
... where m_date >= to_date('01-may-17') and m_date < to_date('01-jun-17')...
I need to query 2 tables, one contains a TIMESTAMP(6) column, other contains a DATE column. I want to write a select statement that prints both values and diff between these two in third column.
SB_BATCH.B_CREATE_DT - timestamp
SB_MESSAGE.M_START_TIME - date
SELECT SB_BATCH.B_UID, SB_BATCH.B_CREATE_DT, SB_MESSAGE.M_START_TIME,
to_date(to_char(SB_BATCH.B_CREATE_DT), 'DD-MON-RR HH24:MI:SS') as time_in_minutes
FROM SB_BATCH, SB_MESSAGE
WHERE
SB_BATCH.B_UID = SB_MESSAGE.M_B_UID;
Result:
Error report -
SQL Error: ORA-01830: date format picture ends before converting entire input string
01830. 00000 - "date format picture ends before converting entire input string"
You can subtract two timestamps to get an INTERVAL DAY TO SECOND, from which you calculate how many minutes elapsed between the two timestamps. In order to convert SB_MESSAGE.M_START_TIME to a timestamp you can use CAST.
Note that I have also removed your implicit table join with an explicit INNER JOIN, moving the join condition to the ON clause.
SELECT t.B_UID,
t.B_CREATE_DT,
t.M_START_TIME,
EXTRACT(DAY FROM t.diff)*24*60 +
EXTRACT(HOUR FROM t.diff)*60 +
EXTRACT(MINUTE FROM t.diff) +
ROUND(EXTRACT(SECOND FROM t.diff) / 60.0) AS diff_in_minutes
FROM
(
SELECT SB_BATCH.B_UID,
SB_BATCH.B_CREATE_DT,
SB_MESSAGE.M_START_TIME,
SB_BATCH.B_CREATE_DT - CAST(SB_MESSAGE.M_START_TIME AS TIMESTAMP) AS diff
FROM SB_BATCH
INNER JOIN SB_MESSAGE
ON SB_BATCH.B_UID = SB_MESSAGE.M_B_UID
) t
Convert the timestamp to a date using cast(... as date). Then take the difference between the dates, which is a number - expressed in days, so if you want it in minutes, multiply by 24*60. Then round the result as needed. I made up a small example below to isolate just the steps needed to answer your question. (Note that your query has many other problems, for example you didn't actually take a difference of anything anywhere. If you need help with your query in general, please post it as a separate question.)
select ts, dt, round( (sysdate - cast(ts as date))*24*60, 2) as time_diff_in_minutes
from (select to_timestamp('2016-08-23 03:22:44.734000', 'yyyy-mm-dd hh24:mi:ss.ff') as ts,
sysdate as dt from dual )
;
TS DT TIME_DIFF_IN_MINUTES
-------------------------------- ------------------- --------------------
2016-08-23 03:22:44.734000000 2016-08-23 08:09:15 286.52