I have done SQL queries but have not done any procedure writing that uses loops so I am at a lost here. I'm using Oracle SQL Developer. Can be done in SQL or PL/SQL
I have a table that resemble this:
Person_ID Score Name Game_ID
1 10 jack 1
1 20 jack 2
2 15 carl 1
2 3 carl 3
4 17 steve 1
How can I loop through this table so that I can grab a players total score for all games played. Result would be like this:
Person_ID Score Name
1 30 jack
2 18 carl
4 17 steve
Also extra credit what If i wanted to just grab say games 1 2?
EDIT: Sorry for not being clear but I do need to do this with a loop even though it can be done without it.
Solution after post edition
This procedure list scores for given game_id. If you omit parameter all games will be summed:
create or replace procedure player_scores(i_game_id number default null) as
begin
for o in (select person_id, name, sum(score) score
from games where game_id = nvl(i_game_id, game_id)
group by person_id, name)
loop
dbms_output.put_line(o.person_id||' '||o.name||' '||o.score);
end loop;
end player_scores;
Previous solution:
You don't need procedure for that, just simple query:
select person_id, name, sum(score)
from your_table
where game_id in (1, 2)
group by person_id, name
Related
I'm trying to cut down on rows a report has. There are 2 assets that return on this query but I want them to show up on one row.
Basically if dc.name LIKE '%CT/PT%' then I want it to be same row as the asset. The SP.SVC_PT_ID is the common field to join them.
There will be times when there is no dc.name LIKE '%CT/PT%' however I still want the DV.MFG_SERIAL_NUM to populated just with a Null to the right.
Select SP.SVC_PT_ID, SP.DEVICE_ID, DV.MFG_SERIAL_NUM, dc.name,
substr(dc.name,26)
From EIP.SVC_PT_DEVICE_REL SP,
eip.device_class dc,
EIP.DEVICE DV
Where SP.EFF_START_TIME < To_date('20170930', 'YYYYMMDD') + 1
and SP.EFF_END_TIME is null
and dc.id = DV.device_class_id
and DV.ID = SP.device_id
ORDER BY SP.SVC_PT_ID, DV.MFG_SERIAL_NUM;
I'm not sure I understand what you are saying; test case would certainly help. You said that query you posted returns two rows (only if we saw which ones ...) but you want them to be displayed as the image you attached to the message.
Generally speaking, you can do that using an aggregate function (such as MAX) on certain column(s), along with the GROUP BY clause that contains the rest of them.
Just for example:
select svc_pt_id, max(ctpt_name) ctpt_name, sum(ctpt_multipler) ctpt_multipler
from ...
group by svc_pt_id
As I said: a test case would help people who'd want to answer the question. True - someone might have understood it far better than I did and will provide assistance nevertheless.
EDIT: after you posted sample data (which, by the way, don't match screenshot you posted previously), maybe something like this might do the job: use analytic function to check whether name contains CT/PT; if so, take its data. Otherwise, display both rows.
SQL> with test as (
2 select 14 svc_pt_id, 446733 device_id, 'Generic Electric' name from dual union
3 select 14, 456517, 'Generic CT/PT, Multiplier' from dual
4 ),
5 podaci as
6 (select svc_pt_id, device_id, name,
7 rank() over (partition by svc_pt_id
8 order by case when instr(name, 'CT/PT') > 1 then 1
9 else 2
10 end) rnk
11 from test
12 )
13 select svc_pt_id, device_id, name
14 from podaci
15 where rnk = 1;
SVC_PT_ID DEVICE_ID NAME
---------- ---------- -------------------------
14 456517 Generic CT/PT, Multiplier
SQL>
My TEST table (created by WITH factoring clause) would be the result of your current query.
I did search the forum before posting this and found some topics which were close to the same issue but I still had questions so am posting it here.
EMP_ID SEQ_NR NAME
874830 3 JOHN
874830 4 JOE
874830 21 MIKE
874830 22 BILL
874830 23 ROBERT
874830 24 STEVE
874830 25 JERRY
My output should look like this.
EMP ID SEQ3NAME SEQ4NAME SEQ21NAME SEQ22NAME SEQ23NAME SEQ24NAME SEQ25NAME
874830 JOHN JOE MIKE BILL ROBERT STEVE JERRY
SELECT A.EMP_ID
,A.NAME SEQ3NAME
,B.NAME SEQ4NAME
FROM AC_XXXX_CONTACT A
INNER JOIN AC_XXXX_CONTACT B ON A.EMP_ID = B.EMP_ID
WHERE A.SEQ_NR = '03' AND B.SEQ_NR = '04'
AND B.EMP_ID = '874830';
The above query helped me get the below results.
EMP_ID SEQ3NAME SEQ4NAME
874830 JOHN JOE
My question is to get all the fields(i.e till seq nr = 25) should I be joining the table 5 more times.
Is there a better way to get the results ?
I m querying against the Oracle DB
Thanks for your help.
New Requirement
New Input
STU-ID SEM CRS-NBR
12345 1 100
12345 1 110
12345 2 200
New Output
stu-id crs1 crs2
12345 100 200
12345 110
Not tested since you didn't provide test data (from table AC_XXXX):
(using Oracle 11 PIVOT clause)
select *
from ( select emp_id, seq_nr, name
from ac_xxxx
where emp_id = '874830' )
pivot ( max(name) for seq_nr in (3 as seq3name, 4 as seq4name, 21 as seq21name,
22 as seq22name, 23 as seq23name, 24 as seq24name, 25 as seq25name)
)
;
For Oracle 10 or earlier, pivoting was done "by hand", like so:
select max(emp_id) as emp_id, -- Corrected based on comment from OP
max(case when seq_nr = 3 then name end) as seq3name,
max(case when seq_nr = 4 then name end) as seq4name,
-- etc. (similar expressions for the other seq_nr)
from ac_xxxx
where emp_id = '874830'
;
Or, emp_id doesn't need to be within max() if we add group by emp_id - which then will work even without the WHERE clause, for a different but related question.
In the school assignment I'm working on I need to display the 3 criminals with the most crimes. But I'm having a few problems
Here's the code I have so far, and its output:
`Select Last, First, Count(Crime_ID)
From Criminals Natural Join crimes
Group by Last, First, Criminal_ID
order by Count(Crime_Id) Desc`
`LAST FIRST COUNT(CRIME_ID)
--------------- ---------- ---------------
Panner Lee 2
Sums Tammy 1
Statin Penny 1
Dabber Pat 1
Mansville Nancy 1
Cat Tommy 1
Phelps Sam 1
Caulk Dave 1
Simon Tim 1
Pints Reed 1
Perry Cart 1
11 rows selected `
I've been toying around with ROWNUM, but when I include it in the SELECT it won't run because of my GROUP BY. But If you put ROWNUM in the GROUP BY it just separates everything back out.
I just want to display the top 3 with the most crimes, which is weird because only 1 guy has more than 1 crime. Theoretically, more criminals would be added to the Database, but these are the tables given in the assignment.
select *
from
( Select Last, First, Count(Crime_ID)
From Criminals Natural Join crimes
Group by Last, First, Criminal_ID
order by Count(Crime_Id) Desc )
where ROWNUM <= 3;
Let's say I have table data similar to the following:
123456 John Doe 1 Green 2001
234567 Jane Doe 1 Yellow 2001
234567 Jane Doe 2 Red 2001
345678 Jim Doe 1 Red 2001
What I am attempting to do is only isolate the records for Jane Doe based upon the fact that she has more than one row in this table. (More that one sequence number)
I cannot isolate based upon ID, names, colors, years, etc...
The number 1 in the sequence tells me that is the first record and I need to be able to display that record, as well as the number 2 record -- The change record.
If the table is called users, and the fields called ID, fname, lname, seq_no, color, date. How would I write the code to select only records that have more than one row in this table? For Example:
I want the query to display this only based upon the existence of the multiple rows:
234567 Jane Doe 1 Yellow 2001
234567 Jane Doe 2 Red 2001
In PL/SQL
First, to find the IDs for records with multiple rows you would use:
SELECT ID FROM table GROUP BY ID HAVING COUNT(*) > 1
So you could get all the records for all those people with
SELECT * FROM table WHERE ID IN (SELECT ID FROM table GROUP BY ID HAVING COUNT(*) > 1)
If you know that the second sequence ID will always be "2" and that the "2" record will never be deleted, you might find something like:
SELECT * FROM table WHERE ID IN (SELECT ID FROM table WHERE SequenceID = 2)
to be faster, but you better be sure the requirements are guaranteed to be met in your database (and you would want a compound index on (SequenceID, ID)).
Try something like the following. It's a single tablescan, as opposed to 2 like the others.
SELECT * FROM (
SELECT t1.*, COUNT(name) OVER (PARTITION BY name) mycount FROM TABLE t1
)
WHERE mycount >1;
INNER JOIN
JOIN:
SELECT u1.ID, u1.fname, u1.lname, u1.seq_no, u1.color, u1.date
FROM users u1 JOIN users u2 ON (u1.ID = u2.ID and u2.seq_no = 2)
WHERE:
SELECT u1.ID, u1.fname, u1.lname, u1.seq_no, u1.color, u1.date
FROM users u1, thetable u2
WHERE
u1.ID = u2.ID AND
u2.seq_no = 2
Check out the HAVING clause for a summary query. You can specify stuff like
HAVING COUNT(*) >= 2
and so forth.
I have two tables, let's call them PERSON and NAME.
PERSON
person_id
dob
NAME
name_id
person_id
name
And let's say that the NAME table has data like:
name_id person_id name
1 1 Joe
2 1 Fred
3 1 Sam
4 2 Jane
5 2 Kim
I need a query (Oracle 10g) that will return
name_id names
1 Joe, Fred, Sam
2 Jane, Kim
Is there a simple way to do this?
Update:
According to the article that figs was kind enough to provide, starting in 9i you can do:
SELECT wmsys.wm_concat(dname) departments FROM dept;
For this example, the answer becomes:
SELECT name_id, wmsys.wm_concat(name) from names group by name_id
The short answer is to use a PL/SQL function. For more details, have a look in this post.