During website development in asp.net, there's an issue of back button after logout.
I have tried writing the following code, it still doesn't work:
Session.Abandon();
Session.Clear();
Session.Contents.RemoveAll();
FormsAuthentication.SignOut();
Roles.DeleteCookie();
FormsAuthentication.RedirectToLoginPage();
Response.Cache.SetCacheability(HttpCacheability.NoCache);
Response.Cache.SetExpires(DateTime.UtcNow.AddMinutes(-1));
Response.Cache.SetNoStore();
Response.Cache.SetRevalidation(HttpCacheRevalidation.AllCaches);
Response.Redirect("~/Login.aspx");
On pressing the logout button, I don't want to get back to the previous URL. Help me out pls
Here is a working solution for the browser back button issue.
Step 1: Add the following hidden field on your page:
<input id="reloadValue" type="hidden" name="reloadValue" value="" />
Step 2: Add the following code on your page. Note that you should keep any existing document.ready() as it is and also add this one.
<script type="text/javascript">
$(document).ready(function () {
var d = new Date();
d = d.getTime();
if ($('#reloadValue').val().length == 0)
{
$('#reloadValue').val(d);
$('body').show();
}
else
{
$('#reloadValue').val('');
location.reload();
}
});
</script>
Note: This can be done in the master page as well, thus working for all pages.
Session.Abandon();
Response.Redirect("~/Home.aspx");
after session abandon redirect to any page with session on it
and session should be like this
if (Session["anyhthing"] == null)
{
Response.Redirect("~/Login.aspx");
}
Related
Got a Typo3 Installation where i've added Googles reCaptcha to a Form.
Did that already successful on other Typo3 installations, but this time, i get the blocked frame error in the Browser.
Blocked frame with origin "https://www.google.com" from accessing a cross-origin frame.
at um.f.hc (https://www.gstatic.com/recaptcha/api2/....)
This happens two times and after that, i get this massage in the frontend.
Please upgrade to a supported browser to get a reCAPTCHA challenge.
Alternatively if you think you are getting this page in error, please check your internet connection and reload.
Why is this happening to me?
This is happening in all Browsers i checked (Chrome, FF, IE11).
To include the reCaptcha i've adde the following to the Template:
<script src="//www.google.com/recaptcha/api.js" async defer></script>
<script type="text/javascript">
var captchaCallback = function() { document.getElementById("captchaResponse").value = document.getElementById("g-recaptcha-response").value }
var onSuccess = function(response) {
var errorDivs = document.getElementsByClassName("recaptcha-error");
if (errorDivs.length) {
errorDivs[0].className = "";
}
var errorMsgs = document.getElementsByClassName("recaptcha-error-message");
if (errorMsgs.length) {
errorMsgs[0].parentNode.removeChild(errorMsgs[0]);
}
captchaCallback();
document.getElementById("fhcallback").submit();
};
</script>
<input type="hidden" id="captchaResponse" name="fhcb[recaptcha]" value="" />
<div id="recaptcha-demo" class="g-recaptcha" data-sitekey="[MYPUBLICKEY]" data-callback="onSuccess" data-bind="inp-submit"></div>
<button class="orderButton bold" id="inp-submit" ###submit_nextStep###>Senden</button>
And in PHP:
$secret = '[MYSECRETKEY]';
$url = 'https://www.google.com/recaptcha/api/siteverify';
$apiResponse = json_decode(\TYPO3\CMS\Core\Utility\GeneralUtility::getUrl($url.'?secret='.$secret.'&response='.$this->gp[$this->formFieldName]), true);
if($apiResponse['success'] == FALSE) {
$checkFailed = $this->getCheckFailed();
}
The Form is not visible on pageload. Its a slide in at the right side of the page, after clicking its toggle element.
I'am out of ideas and the client is bugging me already.
I found the Issue. On this Installation, the JavaScript Library Mootools was included.
After removing the include of Mootools, no further problems with blocked Frames occurred.
I have a link in a razor view (.NET MVC3) which is part of a sort function which shows all records (active and archived) or the active ones (the default on page load). It works fine in Firefox. But it only works when I click on the text part of the link not when the checkbox is checked for chrome and IE. Here is the code I've used.
<a id="lnkShowAll" href="#Url.Action("showAll", "myController", new { showOnlyActive = !Model.Active })" >
<input id="chkShowAll" type="checkbox"
#if(!Model.Active){
#: checked="checked"
} >
Show All (<span class="activeFont">Active</span> / <span class="archivedFont">Archived</span> )
</a>
This is the Controller but I doubt the problem is with the controller since no call is being made to it when the check box is checked
public ActionResult Index(bool showOnlyActive = true)
{
RecordList recordList = searchForRecordList(showOnlyActive);
return View("Index", recordList) ;
}
Does anyone have any Idea what I am missing?
I am still not sure why it works in firefox but not in Chrome and IE, but I found a solution that works for all.
I wrote an event for the click function of the link in jquery.
$("#lnkShowAll").click(function(event)
{
var link = $(this);
var target = link.attr("target");
if($.trim(target).length > 0)
{
window.open(link.attr("href"), target);
}
else
{
window.location = link.attr("href");
}
event.preventDefault();
});
And added a click function to trigger a click event of the link when the checkbox is checked/unchecked.
$("#chkShowAll").click(function(){
$("#lnkShowAll").click();
});
This ensures that the link is clicked whenever the checkbox is clicked on no matter what browser you are using.
I have this html page with the form
<form method="post" id="form1" name="form1" action="/status_comment/save">
//Some text inputs
<input type="text" name="new_comment" id="new_comment" onkeydown="post_comment(event,'13')" >
</form>
And this is my javascript function to do the POST call
function post_comment(event,item_id)
{
var keyCode = ('which' in event) ? event.which : event.keyCode;
if(parseInt(keyCode)==13 && event.shiftKey!=1)
{
var str = $('#form1').serialize(); // Gets all the filled details
$.post('/status_comment/save',
str,
function(data){
alert(data);
});
}}
Backend is done using Django and this is the return statement
data=simplejson.dumps(data)
return HttpResponse(data, mimetype='application/json')
The referral url is say "/xyz".
The thing is, after the form gets submitted, it is being automatically redirect to the "/status_comment/save" page instead of remaining on the same page.
I tried the get method and it works fine but not the POST method.
I tried debugging it, so changed the url in post call to the referral url, then it refreshs the page instead of doing nothing.
Also the alert() command inside the function above doesnt work, so its probably not being entered into.
Interesting thing I have noticed, when looking at the web developer console, the Initiator for the POST call in this page is being displayed as "Other" while the initiator for GET call and POST call (in other pages, where its working) is "jquery-1.8.0.min.js:2"
Any thoughts? Thanks...
First you really shouldn't try to capture the enter if you can avoid it. Use the submit binding. It makes everything more obvious and easier for your fellow developers (I bet I am not the only one who thought "What the heck is KeyCode 13?").
I'm wondering if perhaps being more explicit might help. Have you tried calling preventDefault and stopImmediatePropagation?
$('#form1').submit(function(evt) {
evt.preventDefault();
evt.stopImmediatePropagation();
// serialize and be AJAXy yada yada yada
If that doesn't work, or for some reason you prefer to handle capturing enter on your own, then you might want to have the above code in addition to your keydown handler. So it would be:
<input type="text" name="new_comment" id="new_comment" onkeydown="post_comment(event,'13')" >
...
$('#form1').submit(function(event) {
event.preventDefault();
event.stopImmediatePropagation();
}
function post_comment(event,item_id)
{
event.preventDefault();
event.stopImmediatePropagation();
var keyCode = ('which' in event) ? event.which : event.keyCode;
if(parseInt(keyCode)==13 && event.shiftKey!=1)
{
var str = $('#form1').serialize(); // Gets all the filled details
$.post('/status_comment/save',
str,
function(data){
alert(data);
});
}
}
Start by getting rid of the onkeydown attribute from the input:
<form method="post" id="form1" name="form1" action="/status_comment/save">
//Some text inputs
<input type="text" name="new_comment" id="new_comment" />
</form>
And then simply subscribe to the .submit() event of this form using jquery and perform the AJAX request in there. Don't forget to return false from it to ensure that the default action is canceled and the browser stays on the same page:
$('#form1').submit(function() {
var str = $(this).serialize(); // Gets all the filled details
$.post(this.action, str, function(data) {
alert(data);
});
return false; // <!-- that's the important part
});
I am having some difficulty passing a correct id function back to AJAX.
I'm creating a product bulletin generator that lets items to be added by their SKU code (which works fine). My problem is that when a bulletin is clicked on, a preview of that bulletin is loaded into a div and shows all products associated with that bulletin.
From inside those results, I am trying to add the ability to delete a product from the bulletin. The problem is that the value being passed back to AJAX belongs to the first product only. It won't send the value belonging to the particular item if it is any other item than the first one.
This is the code (belonging to main.php) that gets loaded via AJAX into a div and is looped with each product associated with a selected bulletin
echo "<form name='myDelForm'>
$news_gen_id<br>
<input type='hidden' id='delccode' value='".$news_gen_id."'>
<input type='hidden' id='deledit' value='".$edit."'>
<input type='button' onclick='ajaxDelCcode()' value='Delete' /><br></form>
</td>";
The AJAX code (on index.php, where the div that calls in main.php is also located) is this
function ajaxDelCcode(){
var ajaxRequest; // The variable that makes Ajax possible!
try{
// Opera 8.0+, Firefox, Safari
ajaxRequest = new XMLHttpRequest();
} catch (e){
// Internet Explorer Browsers
try{
ajaxRequest = new ActiveXObject("Msxml2.XMLHTTP");
} catch (e) {
try{
ajaxRequest = new
ActiveXObject("Microsoft.XMLHTTP");
} catch (e){
// Something went wrong
alert("Your browser broke!");
return false;
}
}
}
// Create a function that will receive data sent from the server
ajaxRequest.onreadystatechange = function(){
if(ajaxRequest.readyState == 4){
var ajaxDisplay = document.getElementById("ajaxMain2");
ajaxDisplay.innerHTML = ajaxRequest.responseText;
}
}
var deledit = document.getElementById("deledit").value;
var delccode = document.getElementById("delccode").value;
var queryString = "?delccode=" + delccode + "&deledit=" + deledit;
ajaxRequest.open("GET", "main.php" + queryString, true);
ajaxRequest.send(null);
}
//-->
</script>
Currently, using those two pieces of code, I can successfully delete only the first product. The delccode variables do not seem to change when the products are looped (although when I echo the variables during the loop, it is definitely changing to the appropriate value...it's just not passing it correctly back to AJAX.)
I tried taking the AJAX code, putting it inside the main.php product loop, and change the function name during each loop (so ajaxDelCcode$news_gen_id() for example) and also to the button itself so that it is calling the AJAX specific to it. And it works if you are visiting main.php directly...but not from index.php after main.php has been called into the div.
I can't figure out how to pass the correct looped value from main.php within the div, back to the AJAX code on index.php
Can anyone help me with this?
Thanks,
Dustin
Instead of storing the id in the input, just pass it as an argument to the function:
function ajaxDelCcode(delccode) { ...
<input type='button' onclick='ajaxDelCcode(\"".$news_gen_id."\")' value='Delete' />
Also, I'd swap the quotes if I were you. Or better yet, instead of using echo, break the PHP code and just write HTML:
<? ... ?><input type="button" onclick="ajaxDelCcode('<?= $news_gen_id ?>')" value="Delete" /><? ... ?>
What does the code you use to delete look like? Is it in the same php file as the form you posted above? If so, is the form getting submitted to itself accidentally? Like perhaps when a user presses enter while on an input type=text control? I understand that you want to do this by ajax but I am suspecting that the form is your problem.
Seconding the jQuery comment.
Here try this
1) add jquery to your document.
<script type="text/javascript" src="//ajax.googleapis.com/ajax/libs/jquery/1.7.1/jquery.min.js"></script>
2) give your inputs name attributes
<input type='hidden' name='delcode' id='delccode' value='".$news_gen_id."'>
<input type='hidden' name='deledit' id='deledit' value='".$edit."'>
3) Use a function something like this instead of all that code above
function ajaxDelCcode() {
$.ajax({
url: "main.php",
type: "GET",
dataType: "text",
data: $("#myDelForm").serialize(),
success: function(rText) {
$("#ajaxMain2").text(rText);
}
});
}
I am writing a function that well keep the user in lightbox images while he adds to cart.
When you click any image it well enlarge using lightbox v2, so when the user clicks the Add image, it will refresh the page. When I asked about it at jcart support they told me to use jquery live, but I dont know how to do that. T tried this code but still nothing is happening:
jQuery(function($) {
$('#button')
.livequery(eventType, function(event) {
alert('clicked'); // to check if it works or not
return false;
});
});
I also used
jQuery(function($) {
$('input=[name=addto')
.livequery(eventType, function(event) {
alert('clicked'); // to check if it works or not
return false;
});
});
yet nothing worked.
for code to create those images http://pasite.org/code/572
I also tried:
function adding(form){
$( "form.jcart" ).livequery('submit', function() {var b=$(this).find('input[name=<?php echo $jcart['item_id']?>]').val();var c=$(this).find('input[name=<?php echo $jcart['item_price']?>]').val();var d=$(this).find('input[name=<?php echo $jcart['item_name']?>]').val();var e=$(this).find('input[name=<?php echo $jcart['item_qty']?>]').val();var f=$(this).find('input[name=<?php echo $jcart['item_add']?>]').val();$.post('<?php echo $jcart['path'];?>jcart-relay.php',{"<?php echo $jcart['item_id']?>":b,"<?php echo $jcart['item_price']?>":c,"<?php echo $jcart['item_name']?>":d,"<?php echo $jcart['item_qty']?>":e,"<?php echo $jcart['item_add']?>":f}
});
return false;
}
and it seems to add to jcart but yet it still refreshes
.live() is to assign handlers to future creating elements. On your site, however, you are re-loading the page so .live would have no bearing. (you are submitting a form)
It sounds like you want to make an ajax request to add the item to the cart and update that display on the site? That would be in the submit of the form and if jcart is dynamically created then yes, live is the answer.
$('.jcart').live('submit', function() {
// aggregate form elements into object and send via ajax
// update the cart on the page, since we haven't reloaded the page the light box is still displayed
});
Regarding comment:
When you send an ajax request, jquery takes an object as an argument. Such as $.post('urlToPostTo.php', { title: 'title of whatever', id: 5 } );
The server sees this the same as:
<form id="myForm" action="uroToPostTo.php" method="POST" >
<input type="text" name="title" value="title of whatever" />
<input type="hidden" name="id" value="5" />
<input type="submit" name="submit" value="submit" />
</form>
So if you were to aggregate the form inputs into an object, there's a few ways (even some jquery plugins to help you out). The primitive way would be:
var $form = $('#myForm'); // instead of finding myForm over and over, cache it as a variable to use
var objToSend = {};
objToSend.title = $form.find('input[name=title]').val();
objTosend.id = $form.find('input[name=id]').val();
$.post( 'urlToPostTo.php', objToSend );
A more Elegant solution is to have something loop through all form elements and put them into an object for you. Plugins like http://docs.jquery.com/Plugins:Forms make that a bit easier.
The end result is the form elements are stuffed into an object to send to your script.