I'm wondering if any Yii2 experts can help me understand how best to work with ajax forms combined with Yii ajax validation. I think I can explain the issue without taking you through all of my code.
I am working on a Promo Code entry form where the user enters their promo code into the form, the form is submit via ajax. We then perform a database lookup for the promo code details, validate the code and if the code validates, we want to display the registration form that is hidden on the page.
I have a custom validation function for the form field "code", which is the active field in a model scenario named "register".
class UserCode extends ActiveRecord
{
...
public function scenarios()
{
return [
'register' => ['code'],
];
}
public function rules()
{
return [
[['code'], 'required'],
[['code'], 'validateUserCode', 'on' => ['register']],
];
}
public function validateUserCode($attribute, $params)
{
// perform all my custom logic to determine if the code is valid
if ($code_invalid) {
$this->addError($attribute, 'Sorry, this code is invalid.');
}
}
...
}
Then in the controller, as the Yii2 Guide suggests, I trap this ajax validation with the following code:
public function actionValidate() {
$model = new UserCode(['scenario' => 'register']);
if (Yii::$app->request->isAjax && $model->load(Yii::$app->request->post())) {
Yii::$app->response->format = Response::FORMAT_JSON;
return ActiveForm::validate($model);
}
// no logic can be run after the above code b/c the form is submit with ajax
// and therefore always trapped in the Yii::$app->request->isAjax conditional
}
The above code all works fine and if I remove focus from the $form->field($model, 'code') field on my form, Yii's ajax validation kicks in and displays my custom error message based off of my custom validation logic.
My challenge arises when I go to submit the form. The form submission is also handled through ajax, and therefore the controller action always returns the result of the ActiveForm::validate($model); because if (Yii::$app->request->isAjax && $model->load(Yii::$app->request->post())) will get apply to both the ajax form validation AND on the form submit.
With the above approach, I am forced to return only the results of the ajax validation and not any json data that I may need for additional client side validation, such as displaying the registration form after a valid use code is submitted through the ajax form.
I realize that I can set 'enableAjaxValidation' => false on the ActiveForm and then return my own json data inside the if (Yii::$app->request->isAjax && $model->load(Yii::$app->request->post())) condition. If I do this, I am able to show the registration form because I have my own json data to work with.
Is there a way to have ajax validation on a form that is submitted with ajax? How could you trap the ajax validation separately from the ajax form submission to handle the two events in different manners?
Any suggestions or alternate approaches are GREATLY appreciated!
You should set up validationUrl with a different URL compared to the URL that you are submitting the form to. In this way you can have the validation function that would validate and return the return ActiveForm::validate($model); and the normal submit form that does something else.
You can read more about validationUrl here:
I have found solution :
Form :
<?php
$form = ActiveForm::begin(['id' => 'form-add-contact', 'enableAjaxValidation' => true, 'validationUrl' => Yii::$app->urlManager->createUrl('contacts/contacts/contact-validate')]);
?>
Submit Via Ajax :
<?php
$script = <<< JS
$(document).ready(function () {
$("#form-add-contact").on('beforeSubmit', function (event) {
event.preventDefault();
var form_data = new FormData($('#form-add-contact')[0]);
$.ajax({
url: $("#form-add-contact").attr('action'),
dataType: 'JSON',
cache: false,
contentType: false,
processData: false,
data: form_data, //$(this).serialize(),
type: 'post',
beforeSend: function() {
},
success: function(response){
toastr.success("",response.message);
},
complete: function() {
},
error: function (data) {
toastr.warning("","There may a error on uploading. Try again later");
}
});
return false;
});
});
JS;
$this->registerJs($script);
?>
Controller :
/*
* CREATE CONTACT FORM AJAX VALIDATION ACTION
*/
public function actionContactValidate() {
$model = new ContactsManagement();
if (Yii::$app->request->isAjax && $model->load(Yii::$app->request->post())) {
$model->company_id = Yii::$app->user->identity->company_id;
$model->created_at = time();
\Yii::$app->response->format = Response::FORMAT_JSON;
return ActiveForm::validate($model);
}
}
/**
* Quick Add Contact Action
* #param type $id
* #return type
*/
public function actionAddContact() {
$model = new ContactsManagement();
if (Yii::$app->request->isAjax && $model->load(Yii::$app->request->post())) {
$transaction = \Yii::$app->db->beginTransaction();
try {
if ($model->validate()) {
$flag = $model->save(false);
if ($flag == true) {
$transaction->commit();
return Json::encode(array( 'status' => 'success', 'type' => 'success', 'message' => 'Contact created successfully.'));
} else {
$transaction->rollBack();
}
} else {
return Json::encode(array('status' => 'warning', 'type' => 'warning', 'message' => 'Contact can not created.'));
}
} catch (Exception $ex) {
$transaction->rollBack();
}
}
return $this->renderAjax('_add_form', [
'model' => $model,
]);
}
Related
I'm Trying to Save The Product into The Database By Clicking On Add To Cart
But It's Not Adding I Also Use Ajax `
I Want To Add The Cart To DataBase And It's Not Adding.
This is The Error That I cant Add Any Product To The Cart Because Of It
message: "Call to undefined method App\User\Cart::where()", exception: "Error",…
enter image description here
Model Page.
class Cart extends Model
{
use HasFactory; I
protected $table = 'carts';
protected $fillable = [
'user_id',
'prod_id',
'prod_qty',
];
}
Controller page.
public function addToCart(Request $request)
{
$product_qty = $request->input('product_qty');
$product_id = $request->input ('product_id');
if(Auth::check())
{
$prod_check = Product::where('id',$product_id)->first();
if($prod_check)
{
if(Cart::where('prod_id',$product_id)->where('user_id',Auth::id())->exists())
{
return response()->json(['status' => $prod_check->pname." Already Added to cart"]);
}
else
{
$cartItem - new Cart();
$cartItem->user_id = Auth::id();
$cartItem->prod_qty = $product_qty;
$cartItem->save();
return response()->json(['status' => $prod_check->pname." Added to cart"]);
}
}
}
else{
return response()->json(['status' => "Login to Continue"]);
}
}
javascript page.
This Is MY First Time To Use Ajax And Sure That Every Thing Is Correct I Want Know Why Its Not Add
$('.addToCartBtn').click(function (e) {
e.preventDefault();
var product_id = $(this).closest('.product_data').find('.prod_id').val();
var product_qty = $(this).closest('.product_data').find('.qty-input').val();
$.ajaxSetup({
headers: {
'X-CSRF-TOKEN': $('meta[name="csrf-token"]').attr('content')
}
});
$.ajax({
method: "POST",
url: "/add-to-cart",
data: {
'product_id': product_id,
'product_qty': product_qty,
},
success: function (response) {
alert(response.status);
}
});
// alert(product_id);
// alert(product_qty);
// // alert ("test ") ;
});
Route:
Route::middleware(['auth'])->group(function () {
Route::post('/add-to-cart', [App\Http\Controllers\User\indexController::class, 'addToCart' ]);});
So why this error occurs, how can I fix it?`
This look like an error in importation like App\Models\Cart not like this?
verify if you had added use App\Models\Cart;
I am using CakePHP 2.9 to send data on the URL using ajax and get the related response.
I tried may method to get the response, I also want to know why this //URL:'/Pages/dropdownbox/'+id is not working.
bellow are ajax code which I wrote in the index.ctp.
$("#certificatedetail").on('change',function() {
var id = 'subcribe';
$("#usertype").find('option').remove();
$("#certificateclass").find('option').remove();
$("#certificatetyp").find('option').remove();
if (id) {
$.ajax({
type: 'POST',
url:'<?= Router::url(array('controller' => 'Pages', 'action' => 'dropdownbox','id')); ?>',
//url:'/Pages/dropdownbox/'+id,
dataType:'json',
cache: false,
async:true,
success: function(html)
{
$('<option>').val('').text('select').appendTo($("#usertype"));
$('<option>').val('').text('select').appendTo($("#certificateclass"));
$('<option>').val('').text('Select').appendTo($("#certificatetyp"));
$.each(html, function(key, value)
{
$('<option>').val(key).text(value).appendTo($("#usertype"));
});
}
});
}
});
I have written this controller code in PagesController,PHP and I declared the dropdownbox in AppController.php
public function dropdownbox($id = null)
{
Configure::write('debug', 0);
$this->layout = null;
$this->autoRender = false;
$category = array();
switch ($id)
{
case $id == "subcribe":
if ($id == 'subcribe') {
$category = array(
'individual' => 'Individual',
'organization'=>'Organization',
'organizationgovt' => 'Organization-Govt',
'organizationbank' => 'Organization-Bank'
);
break;
}
}
}
/ bellow is the code where I specify the dropdownbox function in AppController.php
public function beforeFilter() {
parent::beforeFilter();
$this->Auth->allow(
'login','add','index','contact','dropdownbox',
'cityres','stateres','sectorres','productres',
'project','service','about','apply','tender',
'decregistration','search','searchresult',
'tenderdetails'
);
}
You are generating the URL on your server, and using the string literal 'id' in it. The JavaScript id variable is never referenced. What you probably want is:
url:'<?= Router::url(array('controller' => 'Pages', 'action' => 'dropdownbox')); ?>' + id,
You are not returning any response from the controller. Do few things to debug it
Check in Browser's Network tab whether the called URL is correct or not.
Check the parameters are correct or not.
This is how it looks in Firefox Developer Edition
If URL is correct. Add below code in the dropdownbox() method. (Before the closing of the method)
echo json_encode($category);
Check Response Tab in the Network tab. (Example image above).
Also, console the response in the javascript code. Maybe you will be getting some other response which is not JSON.
success: function(html) {
console.log(html);
...
}
Hope it helps.
I am working on Yii 2 form and I want to reinitialize model when client side validation fails. For example with certain rules like below:
public function rules()
{
return [
[['username'], 'required', 'message' => 'You must enter your username'],
['username','email'],
[['password'], 'required', 'message' => 'You must enter your password'],
];
}
When validation fails I want all fields to be empty (for example when user enters invalid email address). How can I do that?
I assume you use standard Yii 2 way of loading the model:
$model = new SomeModel();
if ($model->load(\Yii::$app->request->post()) && $model->save()) {
// ...
}
return $this->render('view', ['model' => $model]);
Set fields to null when validation fails. You don't want to create new instance (which would be easier) because you would lost all validation messages.
$model = new SomeModel();
if ($model->load(\Yii::$app->request->post())) {
if ($model->save()) {
// ....
} else {
$model->username = null;
$model->password = null;
}
}
return $this->render('view', ['model' => $model]);
UPDATE: for the client side validation add this JS code in view:
$("#form-ID").on("afterValidateAttribute", function (event, attribute, messages) {
if (event.result === false) {
attribute.value = "";
}
});
Replace #form-ID with proper form element JS identifier.
I was trying to use ajax to redirect to a controller action in zend framework 2 but the ajax is not responding rightly as well as I am not receiving the data alert.
Here is the ajax code:
$(".save_btn").click(function (){ //the class of submit button is save_btn
$.ajax({
type : 'POST',
url : '/template/addtemplate',
data : {'id':'test'},
success : function(data,status)
{
alert(data.message);
}
});
});
this is my controller code:
public function addtemplateAction()
{
$result = array('status' => 'error',
'message' => 'There was some error. Try again.'
);
$request = $this->getRequest();
if($request->isXmlHttpRequest()){
$data = $request->getPost();
if(isset($data['id']) && !empty($data['id'])){
return new JsonModel($result);
$result['status'] = 'success';
$result['message'] = 'We got the posted data successfully.';
}
}
return new JsonModel($result);
}
I have also added these particular things in my module.config.php file :
'strategies' => array (
'ViewJsonStrategy'
),
I think the problem lies in $request->isXmlHttpRequest() which returns blank.
Any help will be accepted..
Use any kind of developer tools. Chrome => f12 => Network tab and check your response
I'm trying to build up Ajax-Validations by using the jQuery-Event .blur()
I've set the field names to the id of the input-fields to identify them and giving the required data for validation by an ajax-request to the Controller. So far, so good, I could start with the validation, but here's the question:
If there's an error - How do I send the Errormessage back to jQuery, so that I can do another ajax-request to give it out?
Thanks to all help, that'll hopefully come.
Here's the JQuery-Script so far:
$('.registration').blur(function(){
var id = $(this).attr('id');
var value = $(this).val();
var dataString = 'id=' + id +'&value=' + value;
$.ajax({
type: "POST",
url: "users/validate",
data: dataString,
cache: false,
success: function(){ }
});
});
I would recommend using Cake's RequestHandler component to detect the ajax request. Then you'll set the layout to false so that only the view is returned.
Then perform your validation as normal with your preferred method.
Finally, if the validation fails, you can return a 'json' view in which you render the returned validation errors.
Here's a basic example covering just the ajax request and the failed validation:
Users controller:
/**
* use the RequestHandler component
*/
public $components = array('RequestHandler');
/**
* validate action
*/
public function validate()
{
/**
* check if it's an ajax request
*/
if ($this->RequestHandler->isAjax()) {
$this->layout = false;
/**
* set incoming data in the user models data property
*/
$this->User->set($this->data);
if (!$this->User->validates()) {
/**
* return the validation errors and use a view than renders the json
*/
$this->set('errors', $this->User->invalidFields());
$this->render('/users/json/validate');
}
}
}
users/json/validate.ctp
<?php echo $javascript->object($errors); ?>
The page that validates it should print a JSON with the results; something like this
View:
<?php
echo $javascript->object($result);
?>
or
<?php
echo json_encode($result);
?>
Controller
assuming you do you your validations and have $validate variable that is true if evcrything is ok
$this->layout='json_cont';
//do your validations here
if ($validate)
$result = array(
'result' => 1,
'error' => null
);
else
$result = array(
'result' => 0,
'error' => 'error validating'
);
$this->set('result', '$result);
You also need the layout json_cont
<?php
header("Pragma: no-cache");
header("Cache-Control: no-store, no-cache, max-age=0, must-revalidate");
header('Content-Type: text/x-json');
echo $content_for_layout;
?>
finally you just need to change your ajax function just a little like this
$.ajax({
type: "POST",
url: "users/validate",
data: dataString,
cache: false,
dataType: "json",
dataFilter: function(data, type) {
return data;
},
success: function(data) {
if (data != null && data.result == 0) {
alert(data.error);
}
else {
//do here something that accepts your validation, like a js function to give some info to the user or something
}
},
error: function(data) {
try {
alert('error doing the validation');
} catch (e) { }
}
});
i think im not missing anything, hope this helps you :D