How to reinitialize model when client side validation fails in Yii 2? - validation

I am working on Yii 2 form and I want to reinitialize model when client side validation fails. For example with certain rules like below:
public function rules()
{
return [
[['username'], 'required', 'message' => 'You must enter your username'],
['username','email'],
[['password'], 'required', 'message' => 'You must enter your password'],
];
}
When validation fails I want all fields to be empty (for example when user enters invalid email address). How can I do that?

I assume you use standard Yii 2 way of loading the model:
$model = new SomeModel();
if ($model->load(\Yii::$app->request->post()) && $model->save()) {
// ...
}
return $this->render('view', ['model' => $model]);
Set fields to null when validation fails. You don't want to create new instance (which would be easier) because you would lost all validation messages.
$model = new SomeModel();
if ($model->load(\Yii::$app->request->post())) {
if ($model->save()) {
// ....
} else {
$model->username = null;
$model->password = null;
}
}
return $this->render('view', ['model' => $model]);
UPDATE: for the client side validation add this JS code in view:
$("#form-ID").on("afterValidateAttribute", function (event, attribute, messages) {
if (event.result === false) {
attribute.value = "";
}
});
Replace #form-ID with proper form element JS identifier.

Related

Put other function on FormRequest in Laravel

I'm building a Laravel 6 application, and I am concerned about "best practices." I have one controller named CustomerController. In my controller, I want to update the Customer model, so I will have a function like the following.
public function update(UpdateCustomer $request, Customer $customer){
//
}
UpdateCustomer is my form request and where I will do the validation. In my update() method, I have classic validation.
public function rules()
{
$validationArray = [];
$validationArray['customer.name'] = 'string|required';
$validationArray['customer.vat'] = 'string|required';
$validationArray['customer.email'] = 'email|required';
return $validationArray;
}
Now I have to do some particular validation other the classic.
Let's assume that I have more data in my model, and I don't want these values to be changed.
For example, I have the following: address, cap, locality. I have a second method on the UpdateCustomer request that I can validate.
public function validateForDataCantChange()
{
$data = $this->input("customer");
$customer = $this->route("customerID");
$validator = Validator::make([], []); // Empty data and rules fields
$arrayDataThatCantChange = [
'address' => $data['address'] ?? NULL,
'cap' => $data['cap'] ?? NULL,
'locality' => $data['locality'] ?? NULL
];
foreach ($arrayDataThatCantChange as $key => $v) {
if ($customer->{$key} !== $v) {
$validator->errors()->add($key, __("messages.the field :field can't be changed", ['field' => $key]));
}
}
if ($validator->errors()->any()) {
throw new ValidationException($validator);
}
}
And then in my controller, I've added the following.
public function update(UpdateCustomer $request, Customer $customer){
$request->validateForDataCantChange();
}
Is this a bad practice? Should I create a new FormRequest? How, in this case (two form requests), can I use two different requests for a single controller?
For the little effort required, I'd personally create a new form request.
If you wish to use the same form request you can do the following:
public function rules()
{
$rules = [
'title' => 'required:unique:posts'
];
// when editing i.e. /posts/2/edit
if ($id = $this->segment(2)) {
$rules['title'] .= ",$id";
}
return $rules;
}
However, I always use a separate class for each action.

How to check data exists in the database

I have a function to add new property. But i want to check for duplicate data at column "code" before add new data into database. If data exists will appear a message error.
function addPro(Request $req)
{
$id = $req->type_id;
$type = AssetType::find($id);
if($req->save == 'save'){
$pro = new TypeProperties;
$pro->name = $req->name;
$pro->code = $req->code;
$pro->type = $req->type;
$pro->assettype_id = $req->type_id;
$pro->save();
Schema::table($type->code, function ($table) use ($pro) {
if ($pro->type == "textbox")
$table->string($pro->code )->nullable();
if ($pro->type == "textarea")
$table->text($pro->code )->nullable();
});
return redirect(url($type->id.'/add/property'))->with('message','Save successful');
}
return redirect(url('asset/type/'.$type->id));
}
You can use laravel Request Validation
function addPro(Request $req)
{
$id = $req->type_id;
$type = AssetType::find($id);
if($req->save == 'save'){
$req->validate([
'code' => 'required|unique:tablename'
]);
$pro = new TypeProperties;
$pro->name = $req->name;
$pro->code = $req->code;
$pro->type = $req->type;
$pro->assettype_id = $req->type_id;
$pro->save();
Schema::table($type->code, function ($table) use ($pro) {
if ($pro->type == "textbox")
$table->string($pro->code )->nullable();
if ($pro->type == "textarea")
$table->text($pro->code )->nullable();
});
return redirect(url($type->id.'/add/property'))->with('message','Save successful');
}
return redirect(url('asset/type/'.$type->id));
}
The most simple way to do this is by checking if code is_null :
if (is_null($pro->code)) {
// It does not exist
} else {
// It exists
}
The other way is to make a validation using Laravel's built in ValidateRequest class. The most simple use-case for this validation, is to call it directly in your store() method like this:
$this->validate($req, [
'code' => 'required|unique,
//... and so on
], $this->messages);
With this, you're validating users $req by saying that specified columns are required and that they need to be unique, in order for validation to pass. In your controller, you can also create messages function to display error messages, if the condition isn't met:
private $messages = [
'code.required' => 'Code is required',
'code.unique' => 'Code already exists',
//... and so on
];
You can also achieve this by creating a new custom validation class:
php artisan make:request StorePro
The generated class will be placed in the app/Http/Requests directory. Now, you can add a few validation rules to the rules method:
public function rules()
{
return [
'code' => 'required|unique,
//... and so on
];
}
All you need to do now is type-hint the request on your controller method. The incoming form request is validated before the controller method is called, meaning you do not need to clutter your controller with any validation logic:
public function store(StorePro $req)
{
// The incoming request is valid...
// Retrieve the validated input data...
$validated = $req->validated();
}
If you have any additional question about this, feel free to ask. Source: Laravel official documentation.
What does your migration look like for AssetType?
I ask because you can do this in the schema with ->unique() added to the column on the creation or make a migration to add the constraint.
You can also check with something like this:
// Search database table for entry
$entry = AssetType::where('code', '=', $pro->code)->first();
// If not found
if ($entry === null) {
// Save method here.
}
Otherwise, you can use the manual validator or create a Request with validation
References:
https://laravel.com/docs/5.8/queries#where-clauses
https://laravel.com/docs/5.8/validation#creating-form-requests
https://laravel.com/docs/5.8/validation#manually-creating-validators

One-shot laravel validator

I have a form where someone searches for something. Based on this form, I validate if the input is correct:
$validator = Validator::make(Input::all() , array(
'address' =>'required',
));
if($validator->fails()) {
return Redirect::to('/')->withErrors($validator);
}
After this, I want to validate something else (that a result object isn't empty), which is completely unrelated to the search. In other words, it's NOT input from a form.
1) Do I create another validator to validate this? Or
2) Is there a better way to simply check this value and spawn an object that can be returned with "withErrors"?
UPDATE
This isn't working for me:
$validator = Validator::make(
array(
'searches' => sizeof($search)
) ,
array(
'searches' => 'required|min:1'
)
);
if($validator->fails()) {
return Redirect::to('/')->withErrors($validator);
}
It's not working because for some reason it's picking up that the "searches" item should only be validated "sometimes"
you have two ways. one is custom validator
or there is a simpler way,
suppose,
private function foo()
{
$data = ''; //retrieved the data error here with whatever call you want to make
return !empty($data) ? true : false;
}
in the controller,
public function bar()
{
if(!$this->foo())
{
$messages = new \Illuminate\Support\MessageBag;
// you should use interface here. i directly made the object call for the sake of simplicity.
$messages->add('custom', 'custom error');
return Redirect::back()->withErrors($messages)->withInput();
}
}
in the view:
#if($errors->has('custom'))
<p>custom error output.</p>
#endif
it is just the outline to give you the idea.

Why I am getting error message when using Yii CActiveForm::validate() with array

I have a problem related to CActiveForm::validate(). I have a form and and sending data to database using Ajax, my form contains a multiple selectable drop-down list. In data saving section of controller produced the following error initially
mb_strlen() expects parameter 1 to be string, array given (.../framework/validators/CStringValidator.php:84)
and after updating framework to newer version, that error gone, and got the below validation message instead.
Category Ids is invalid.
If the form is fully filled(I mean all the rules in the model satisfied), it will not produce any such bug or error message.
controller action
public function actionCompany() {
$model = new Company;
if (isset($_POST['Company'])) {
$model->attributes = $_POST['Company'];
$category_ids = "";
if (is_array($_POST['Company']['category_ids']))
$category_ids = implode(',', $_POST['Company']['category_ids']);
$model->category_ids = $category_ids;
if ($model->validate()) {
/*$temp = Company::model()->findByPK($model->id);
if ($temp !== null) {
$model = $temp;
}*/
$model->save();
echo CJSON::encode(array('status' => 'success'));
Yii::app()->end();
} else {
$error = CActiveForm::validate($model);
if ($error != '[]')
echo $error;
}
}
}
Model rules
public function rules()
{
return array(
array('...., category_ids,...', 'required'),
array('..., category_ids, ...', 'length', 'max'=>255),
....
.....
array('...., category_ids,...', 'safe', 'on'=>'search'),
);
}
What is actually I'm missing?
By default, CActiveForm::validate($model) loads the model attributes from $_POST and overrides current attribute values, thus destroying your transformed values. Pass false as the third argument to avoid this.

cakephp validation response returning data to controller

Hi i have made a custom validation in the model. How can i access the result($visitor) from this in the controller?
model:
<?php
class Visitors extends AppModel
{
var $name = 'Visitors';
var $validate = array(
'xxx' => array(
'rule' => array('checkxxx'),
'message' => 'yyy.'
)
);
function checkIxxx($check){
$visitor = $this->find('first', array('conditions' => $check));
return $visitor;
}
}
?>
in my controller i want this:
function start() {
$this->Visitors->set($this->data);
if($this->Visitors->validates())
{
if($this->Visitors->xxx->type == 'value') //this is a value from the $visitor array in the model**
{
//do something
}
}
is this possible?
Updated to be a relevant answer, apologies.
//Model
var myField = 'invalid';
function myValidation($var){
if($var === true){
// Passed your validation test
$this->myField = 'valid';
}else{
$this->myField = 'invalid';
}
}
// Controller
$this->Model->set($this->data);
$this->Model->validates($this->data);
if($this->Model->myfield == 'valid'){
// Field has passed validation
}
You will want to use
$this->Model->invalidFields()
PS: You dont follow cake conventions
the model should be "Visitor" (singular)

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