Am at the end of my tether so hoping someone can help me! I'm really new to Oracle, but do have a SQL background which is why I'm finding this so frustrating!
We have a system that runs Oracle at the back end. I've got very limited access to the system and can only write select queries.
I've written a query that gets the data I want but the date format is coming out as mm dd yyyy what I need is dd/mm/yyyy
I ran SELECT sysdate FROM dual and that come back as:
SYSDATE
03 11 2015
So my select statement reads (action_date is the column in question)
Select username, action_date from adminview
I've tried everything I can think of to change the date format including:
to_date(action_date,'dd/mm/yyyy')
to_date(action_date,'dd/mm/yyyy','nls_language=English')
to_date(to_date(action_date,'mm dd yyyy'),'dd/mm/yyyy')
I've also tried to_char along the same lines.
If you want to format a DATE value, use TO_CHAR():
SELECT username, TO_CHAR(action_date, 'DD/MM/YYYY') AS action_date
FROM adminview;
If it's not a DATE value, then you'll want to convert it to a DATE (based on what it currently looks like), then use TO_CHAR() to format.
Related
I want to get display of future and past dates in mm/dd/yyyy and dd/mm/yyyy format in Oracle SQL 18C using SQL functions, so I want the code for it. I tried code select sysdate from dual and I get the output 21-JAN-23, but I want output of future and past dates like 23/11/2033 and 16/12/2009 in mm/dd/yyyy and dd/mm/yyyy format.
Format date using TO_CHAR() function
SELECT
TO_CHAR( SYSDATE, 'FMMonth DD, YYYY' )
FROM
dual;
The output would be:
August 1, 2017
Creating a Future or Past Date
In Oracle, a DATE is a binary data type that ALWAYS consists of 7 bytes representing century, year-of-century, month, day, hour, minute and second and is NEVER stored in any particular human-readable format.
Therefore, if you want to get a DATE data type in a particular format then it is impossible as dates never have any format when they are stored.
If you want to get a date you can use:
A date literal:
SELECT DATE '2023-12-31' FROM DUAL;
or, the TO_DATE function:
SELECT TO_DATE('31/12/2023', 'MM/DD/YYYY') FROM DUAL;
Displaying Dates in a Client Application
However, if the problem is how to display a date in a particular format then you need to convert the binary DATE value to a string.
Most client applications (SQL*Plus, SQL Developer, TOAD, C#, Java, etc.) will implicitly convert a binary date to something that is human-readable when they display it and will have settings in the application that determine the default format that it applies to dates.
For SQL*Plus and SQL Developer, you can modify the NLS_DATE_FORMAT session parameter to change how that client application displays dates (note: this does not change how Oracle stores the dates internally, only how it is displayed by the client).
For example:
ALTER SESSION SET NLS_DATE_FORMAT = 'YYYY-MM-DD HH24:MI:SS';
or:
ALTER SESSION SET NLS_DATE_FORMAT = 'MM/DD/YYYY';
And then the client application will display dates in that format when you use a SELECT statement.
For other client applications you will need to check the documentation for that application.
Explicitly Formatting Dates as Strings
If you want to display a DATE in a particular format independent of any settings in the client application then you will need to convert the date to a string.
Using TO_CHAR:
SELECT TO_CHAR(DATE '2023-12-31', 'MM/DD/YYYY') AS formatted_date FROM DUAL;
Or, if you are generating the date and formatting it (rather than taking an existing date and formatting it) then you could just use a string literal:
SELECT '31/12/2023' AS formatted_date FROM DUAL;
I'm trying to store date type data from Oracle FORMS with format mask as like DD-MM-YYYY but every time it store as like DD/MON/YY.
I already alter session with NLS_DATE_FORMAT, but result is as same as before.
Oracle internal date format that is written in the table is something you can't change in any way, but, in the same time, it is irrelevant. If you are dealing with DATE type column then you should know that it containes both the date and the time. How, where and when you will show it or use it is on you. Here is a sample of a few formats derived from that original Oracle DATE format...
WITH
t AS
(
Select SYSDATE "MY_DATE_COLUMN" From Dual
)
Select
MY_DATE_COLUMN "DATE_DEFAULT_FORMAT",
To_Char(MY_DATE_COLUMN, 'mm-dd-yyyy') "DATE_1",
To_Char(MY_DATE_COLUMN, 'yyyy/mm/dd') "DATE_2",
To_Char(MY_DATE_COLUMN, 'dd.mm.yyyy') "DATE_3",
To_Char(MY_DATE_COLUMN, 'dd.mm.yyyy hh24:mi:ss') "DATE_4"
From t
DATE_DEFAULT_FORMAT
DATE_1
DATE_2
DATE_3
DATE_4
22-OCT-22
10-22-2022
2022/10/22
22.10.2022
22.10.2022 10:59:44
You can find a lot more about the theme at https://www.oracletutorial.com/oracle-basics/oracle-date/
Regards...
In Oracle, a DATE is a binary data-type consisting of 7-bytes (representing century, year-of-century, month, day, hour, minute and second). It ALWAYS has those 7 components and it is NEVER stored in any particular human-readable format.
every time it store as like DD/MON/YY.
As already mentioned, no, it does not store a date like that; the database stores dates as 7 bytes.
What you are seeing is that the client application, that you are using to connect to the database, is receiving the 7-byte binary date value and is choosing to convert it to something that is more easily comprehensible to you, the user, and is defaulting to converting the date to a string with the format DD/MON/RR.
What you should be doing is changing how the dates are displayed by the client application by either:
Change the settings in the Toad (View > Toad Options > Data Grids > Data and set the Date Format option) and allow Toad to implicitly format the string; or
Use TO_CHAR to explicitly format the date (TO_CHAR(column_name, 'DD-MM-YYYY')).
I'm trying to store data as like DD-MM-YYYY.
If you want to store a date then STORE it as a date (which has no format) and format it when you DISPLAY it.
If you have a valid business case to store it with a format then you will need to store it as a string, rather than as a date, because you can format strings; however, this is generally considered bad practice and should be avoided.
Sadman, to add to what others have posted I suggest you do not write your applications with reliance on the NLS_DATE_FORMAT parameter but rather you screens and application should specify the expected DATE entry format and the code should use the TO_DATE function to store the data into the database. All application SQL should use the TO_CHAR function to format date output for display.
I'm using the following the query to get the date out of string (20191101154559) in Hadoop(hive).
select max(cast(to_date(from_unixtime(unix_timestamp(substr(column3,1,8), 'yyyymmdd'))) as date)) as dt from databasea.table_name_b;
The output i'm getting after running the above script is '31/01/2019' where as the table holds dates of nov 2019. Not sure where i'm going wrong here.
Appreciate if anyone can look into this issue.
from_unixtime you can use it to get in 'yyyymmdd' or 'yyyy-MM-dd'
whatever format you want data in.
For Eg - select from_unixtime(unix_timestamp(substr('20191101154559',1,8), 'yyyymmdd'),'yyyymmdd');
This will return 20191101
I have to query all_objects table where last_ddl_time='01 jan 2010' but it refuses the date format...
Any body give me the exact format to query?
As AKF said, you should be using Trunc unless you know the exact time the DDL was modified. Your query you added in the comments is looking for any objects where the DDL changed at 1/1/2010 00:00:00. Try:
SELECT *
FROM all_objects
WHERE trunc(last_ddl_time) = to_date('01-01-2010','dd-mm-yyyy');
I suggest you to use de date literal:
where trunc(last_ddl_time) = date '2010-01-01'
You can use the to_date function to format your date. If you enter a literal string, Oracle will attempt to convert that string using to_date with a default format 'DD-MON-YY', so your date would look like "01-JAN-10". As Oracle will be using this same function, you might want to put it in yourself and enjoy the finer granularity that custom formatting can provide.
It would be good to note that the dates stored in that column most likely have more precise dates, including hours and minutes, etc. Though you will be taking a bit of a performance hit, you might be better served using trunc(last_ddl_time) if you are testing with =.
There is some good info on Dates in Oracle at this link.
SELECT *
FROM all_objects t
WHERE trunc(t.last_ddl_time, 'DD') = to_date('2010-JAN-01', 'YYYY-MON-DD');
I've had some brilliant help before and I'm hoping you can get me out of a hole again.
I've got a date coming in from a web service in this format:
2009-02-13T11:46:40+00:00
which to me looks like standard UTC format.
I need to insert it into an Oracle database, so I'm using to_date() on the insert. Problem is, I cant get a matching formatting string for it and keep getting "ORA-01861: literal does not match format string" errors.
I know its a fairly trivial problem but for some reason I cannot get it to accept the right format string. Any help appreciated.
Thanks :)
Gareth
You can directly convert it to a TIMESTAMP_WITH_TIME_ZONE datatype.
select
to_timestamp_tz('2009-02-13T11:46:40+00:00','YYYY-MM-DD"T"HH24:MI:SSTZH:TZM')
from
dual
TO_TIMESTAMP_TZ('2009-02-13T11:46:40+00:00','YYYY-MM-DD"T"HH24:MI:SSTZH:TZM
---------------------------------------------------------------------------
13-FEB-09 11.46.40.000000000 AM +00:00
(I'm assuming the input string is using a 24-hour clock since there is no AM/PM indicator.)
If you want to convert that to a simple DATE, you can, but it will lose the time zone information.
SELECT CAST(TO_TIMESTAMP_TZ(REPLACE('2009-02-13T11:46:40+00:00', 'T', ''), 'YYYY-MM-DD HH:MI:SS TZH:TZM') AS DATE)
FROM dual
To import date in specified format you can set nls_date_format.
Example:
alter session set nls_date_format='YYYY-MM-DD HH24:MI:SS'
This way your SQL statements can be shorter (no casts). For various mask look at Datetime Format Models