How can I make relationship with union in laravel eloquent? I've already tried two different approaches.
User::with(['url' => function($query) use(&$some_property) {
$favouriteUrls = \DB::table('urls')
->select('urls.*')
->join('favourite_urls', function($join) {
$join->on('favourite_urls.url_id', '=', 'urls.id');
})
->where('some_condition', '=', $some_property);
$query = $query->union($favouriteUrls);
}]);
In the first attempt there wasn't any union in the query. Then I tried to move the logic to the model.
class User extends \Eloquent {
public function urls() {
$favouriteUrls = \DB::table('urls')
->select('urls.*')
->join('favourite_urls', function($join) {
$join->on('favourite_urls.url_id', '=', 'urls.id');
})
->where('some_condition', '=', $this->some_property);
return $this->belongsTo('Url')->union($favouriteUrls);
}
}
It has executed successfully but $this->some_property was set inside the query to the null value.
I can't create two separate relationship in this case. It has to be one with union. How can I fix it?
If you call that relation as User::with('urls') you will get that $this->some_property doesn't exists, because the object itself doesn't exists. But if you call the urls() method on an object, it should work. Something like this:
$user = User::find(1);
$user->urls; // here $this->some_property should have a value
Assuming you're calling the urls() method from a User object, the $this->some_property should give you the value. If for some reason you cannot access a property directly on an Eloquent model you can always refer to the attributes[] array inside of the model. For example
// calling
$this->some_property
// should be the same as
$this->attributes['some_property']
Fetch all the users joining with the condition
Assuming users is the table for all the users, in your query you could change $this->some_property with 'users.some_property' and everything should work as expected, for each user it will query based on that property. Here is the code:
class User extends \Eloquent {
public function urls() {
$favouriteUrls = \DB::table('urls')
->select('urls.*')
->join('favourite_urls', function($join) {
$join->on('favourite_urls.url_id', '=', 'urls.id');
})
->where('some_condition', '=', 'users.some_property');
return $this->belongsTo('Url')->union($favouriteUrls);
}
}
And then just call the method like this:
User::with('urls')->get();
Related
My user model has a 'prevregistration' attribute
public function prevregistration()
{
return $this->hasMany(Prevregistration::class, 'prevregistration_userid');
}
My prevregistraton model has a 'prev' attribute
public function prev()
{
return $this->hasOne(Prev::class,'prev_id', 'prevregistration_previd');
}
In my controller I show prevregistrations for the current user:
mynextprevs = Auth::user()->prevregistration ;
Now I want to only show prevregistrations from which the connected prev its prev_date in the future, like this:
$mynextprevs = Auth::user()->prevregistration::whereDate('prev_date', '>=', Carbon::today()->toDateString());
But then I get:
BadMethodCallException
Method Illuminate\Database\Eloquent\Collection::whereDate does not exist.
I also tried like this:
$mynextprevs = Auth::user()->prevregistration->prev::whereDate('prev_date', '>=', Carbon::today()->toDateString());
But then I get:
Property [prev] does not exist on this collection instance.
Should I/how can I filter the collection? I'm curious why Auth::user()->prevregistration->prev is not working, since that are attributes.
Thanks
You need to use the condition whereHas on your prevregistration
$mynextprevs = Auth::user()->prevregistration()->whereHas('prev',function($prev) {
$prev->whereDate('prev_date', '>=', Carbon::today()->toDateString());
})->get();
Notice we used the relation as a method prevregistration() to access it as a query builder and not as a collection hence the need for the ->get() at the end.
i have a simple query that looks like this:
$category = Category::with('translation')
->with(['childCategories' => function ($query) {
$query->active();
}])
->where('id', $id)->first();
Scope and relation:
public function scopeActive($query)
{
return $query->where('active', 1);
}
public function childCategories()
{
return $this->hasManyThrough('App\SupremeShop\Models\Category',
'App\SupremeShop\Models\CategoryToCategory',
'id_parent_category', //category_to_categories
'id', //categories
'id',
'id_category'); // category_to_categories.
}
So i am looking for category, some translations and child categories of given "main" category. And query returns 15 child categories. But in query is scope that should only take active ones and it's not working correctly. When i use dd it shows inactive child categories also. I've tried to remove scope and write simple WHERE but result was the same.
Have somebody any ides why condition is not working properly?
I believe the problem is the column is ambiguous since Category and its relation childCategories are both the same model and share the same table.
The active() scope is getting applied to the parent Category instead of the child Categories.
Try and see if this works
$category = Category::from('categories as c')
->with(['childCategories' => function ($query) {
$query->active();
}])
->where('id', $id)->first();
I'm trying to do where clause for fortune_code inside joindraw table, comparing with the lucky_fortune_code from product table. How can i access and do the check?
Product::where('status', StatusConstant::PT_ENDED_PUBLISHED)
->where('lucky_fortune_code', '<>', '')
->with(['joindraw' => function ($query){
$query->where('fortune_code', $this->lucky_fortune_code)
->with('user');}])->desc()->get();
Product.php
class Product extends Model
{
public function joindraw(){
return $this->hasMany('App\Models\Joindraw');
}
Joindraw.php
class Joindraw extends Model
{
public function product(){
return $this->belongsTo('App\Models\Product', 'product_id');
}
What you can do is a join:
Product::where('status', StatusConstant::PT_ENDED_PUBLISHED)
->where('lucky_fortune_code', '!=', '')
->join('joindraws', 'joindraws.fortune_code', '=', 'products.lucky_fortune_code')->get();
By the way, you can also omit the second 'product_id' parameter in the belongsTo() relation, as this column name is already assumed by convention.
Also, there is no desc() method on the query builder. Use orderBy('lucky_fortune_code', 'desc') instead.
However, whenever you have to write joins in Laravel, you should think about your relationship structure, because there's probably something wrong.
i get:
Relationship method must return an object of type
Illuminate\Database\Eloquent\Relations\Relation
code of model:
class Order extends Model{
public function order_status(){
$q = self::GetQueryWithCurrentOrderStatus();
return $q->where('order.id', '=', $this->id)->get();
}
private static function GetQueryWithCurrentOrderStatus(){
$rawSql = OrderOrderStatus::selectRaw('order_order_status.order_id as id, max(created_at)')->groupBy('order_order_status.order_id')->toSql();
$query = OrderStatus::join('order_order_status', 'order_order_status.order_status_id', '=', 'order_status.id')
->join('order', 'order.id', '=', 'order_order_status.order_id')
->join(DB::raw('( ' . $rawSql . ') CurrentOrderStatus'), function ($join) {
$join->on('order_order_status.id', '=', 'CurrentOrderStatus.id');
});
return $query;
}
}
db structure is written in the answer here:
https://dba.stackexchange.com/questions/151193/good-database-structure-for-scenario-with-orders-that-have-a-state-and-the-state/151195#151195
order_status_history is order_order_status
now i could write in the blade file just:
$order->order_status() instead of $order->order_status ... but why? is there a solution?
If you're trying to call a method, call a method. order_status isn't a property.
If you access it as a property, it requires an Eloquent relationship (like it says) which are created through the hasOne, hasMany, belongsTo, belongsToMany methods: https://laravel.com/docs/master/eloquent-relationships
In Laravel we can setup relationships like so:
class User {
public function items()
{
return $this->belongsToMany('Item');
}
}
Allowing us to to get all items in a pivot table for a user:
Auth::user()->items();
However what if I want to get the opposite of that. And get all items the user DOES NOT have yet. So NOT in the pivot table.
Is there a simple way to do this?
Looking at the source code of the class Illuminate\Database\Eloquent\Builder, we have two methods in Laravel that does this: whereDoesntHave (opposite of whereHas) and doesntHave (opposite of has)
// SELECT * FROM users WHERE ((SELECT count(*) FROM roles WHERE user.role_id = roles.id AND id = 1) < 1) AND ...
User::whereDoesntHave('Role', function ($query) use($id) {
$query->whereId($id);
})
->get();
this works correctly for me!
For simple "Where not exists relationship", use this:
User::doesntHave('Role')->get();
Sorry, do not understand English. I used the google translator.
For simplicity and symmetry you could create a new method in the User model:
// User model
public function availableItems()
{
$ids = \DB::table('item_user')->where('user_id', '=', $this->id)->lists('user_id');
return \Item::whereNotIn('id', $ids)->get();
}
To use call:
Auth::user()->availableItems();
It's not that simple but usually the most efficient way is to use a subquery.
$items = Item::whereNotIn('id', function ($query) use ($user_id)
{
$query->select('item_id')
->table('item_user')
->where('user_id', '=', $user_id);
})
->get();
If this was something I did often I would add it as a scope method to the Item model.
class Item extends Eloquent {
public function scopeWhereNotRelatedToUser($query, $user_id)
{
$query->whereNotIn('id', function ($query) use ($user_id)
{
$query->select('item_id')
->table('item_user')
->where('user_id', '=', $user_id);
});
}
}
Then use that later like this.
$items = Item::whereNotRelatedToUser($user_id)->get();
How about left join?
Assuming the tables are users, items and item_user find all items not associated with the user 123:
DB::table('items')->leftJoin(
'item_user', function ($join) {
$join->on('items.id', '=', 'item_user.item_id')
->where('item_user.user_id', '=', 123);
})
->whereNull('item_user.item_id')
->get();
this should work for you
$someuser = Auth::user();
$someusers_items = $someuser->related()->lists('item_id');
$all_items = Item::all()->lists('id');
$someuser_doesnt_have_items = array_diff($all_items, $someusers_items);
Ended up writing a scope for this like so:
public function scopeAvail($query)
{
return $query->join('item_user', 'items.id', '<>', 'item_user.item_id')->where('item_user.user_id', Auth::user()->id);
}
And then call:
Items::avail()->get();
Works for now, but a bit messy. Would like to see something with a keyword like not:
Auth::user()->itemsNot();
Basically Eloquent is running the above query anyway, except with a = instead of a <>.
Maybe you can use:
DB::table('users')
->whereExists(function($query)
{
$query->select(DB::raw(1))
->from('orders')
->whereRaw('orders.user_id = users.id');
})
->get();
Source: http://laravel.com/docs/4.2/queries#advanced-wheres
This code brings the items that have no relationship with the user.
$items = $this->item->whereDoesntHave('users')->get();