i have a simple query that looks like this:
$category = Category::with('translation')
->with(['childCategories' => function ($query) {
$query->active();
}])
->where('id', $id)->first();
Scope and relation:
public function scopeActive($query)
{
return $query->where('active', 1);
}
public function childCategories()
{
return $this->hasManyThrough('App\SupremeShop\Models\Category',
'App\SupremeShop\Models\CategoryToCategory',
'id_parent_category', //category_to_categories
'id', //categories
'id',
'id_category'); // category_to_categories.
}
So i am looking for category, some translations and child categories of given "main" category. And query returns 15 child categories. But in query is scope that should only take active ones and it's not working correctly. When i use dd it shows inactive child categories also. I've tried to remove scope and write simple WHERE but result was the same.
Have somebody any ides why condition is not working properly?
I believe the problem is the column is ambiguous since Category and its relation childCategories are both the same model and share the same table.
The active() scope is getting applied to the parent Category instead of the child Categories.
Try and see if this works
$category = Category::from('categories as c')
->with(['childCategories' => function ($query) {
$query->active();
}])
->where('id', $id)->first();
Related
i have a question about accessing relation in laravel model. I have category model which has relation to translation model and category model(same model/itself - one category can be displayed in other categories using pivot table CategoryToCategory):
category model:
public function childCategories(){
return $this->hasManyThrough('App\Models\Category',
'App\Models\CategoryToCategory',
'id_parent_category',
'id',
'id',
'id_category');
}
public function translation($locale = null)
{
if ($locale == null) {
$locale = \App::getLocale();
}
return $this->hasOne('App\Models\CategoryLanguage', 'id_category', 'id')->where('locale', '=', $locale);
}
Now i take current category + translation + child categories:
$category = Category::with('translation', 'childCategories')->active()->where('id', $id)->first();
And display all childs names:
#forelse($category->childCategories as $category)
{{ $category->translation->name }}
#endforelse
I works but each child category makes another query to get translation(it's not loaded for elements in forelse). So how to load relation "translation" in category model which is foreaching loaded relation?
I could query model CategoryToCategory to get all child categories + load translation for that model and result be the same:
$categories = CategoryToCategory::with('translation')->where('id_parent_category', $id)->get();
And there will be one query for translations. Still i'm curious about using first solution instead query categoryToCategory.
Any ideas?
Have a nice day!
To eager load a distant relationship you can use the dot notation like so:
$category = Category::with('translation', 'childCategories.translations')
->active()
->where('id', $id)
->first();
This is known as "nested eager loading" and is referenced in the docs here:
https://laravel.com/docs/5.8/eloquent-relationships#eager-loading
I am developing a e-commerce website.
I have 3 tables
1.prodcts table
2.conditions table
3.condition_product table
A product can have many conditions.
particular condition belongs to many products.
Now I have a product which belongs to 3 conditions.
I want to get all related products which belongs to these 3 conditions.
How can i achieve this?
product.php
public function conditions(){
return $this->belongsToMany(Condition::class)->withTimestamps();
}
condition.php
public function products(){
return $this->belongsToMany(Product::class)->withTimestamps();
}
This is my code:
public function productDetails(Product $product)
{
$a = $product->id;
$relatedProducts = Product::whereHas('conditions.products', function($q) use($a) {
$q->where('id', $a);
})
->get();
return view('pages/product', compact('product','relatedProducts'));
}
But I am getting error.
Use the whereHas() method with nested relationships:
Product::whereHas('conditions.products', function($q) use($productId) {
$q->where('id', $productId);
})
->get();
This will give you products that have conditions of a specified product.
Alternatively, you could do this:
$conditionIds = Product::find($productId)->conditions->pluck('id');
$products = Product::whereHas('conditions', function($q) use($conditionIds) {
$q->whereIn('id', $conditionIds);
})
->get();
A good practice is to always specify witch table the 'id' field is referencing too, because if not, it could both reference the 'conditions' table or the 'products' table 'id' field :
$relatedProducts = Product::whereHas('conditions.products', function($q) use($a) {
$q->where('products.id', $a);
})
->get();
You could see this answer about SQL ambiguous column name.
How can I make relationship with union in laravel eloquent? I've already tried two different approaches.
User::with(['url' => function($query) use(&$some_property) {
$favouriteUrls = \DB::table('urls')
->select('urls.*')
->join('favourite_urls', function($join) {
$join->on('favourite_urls.url_id', '=', 'urls.id');
})
->where('some_condition', '=', $some_property);
$query = $query->union($favouriteUrls);
}]);
In the first attempt there wasn't any union in the query. Then I tried to move the logic to the model.
class User extends \Eloquent {
public function urls() {
$favouriteUrls = \DB::table('urls')
->select('urls.*')
->join('favourite_urls', function($join) {
$join->on('favourite_urls.url_id', '=', 'urls.id');
})
->where('some_condition', '=', $this->some_property);
return $this->belongsTo('Url')->union($favouriteUrls);
}
}
It has executed successfully but $this->some_property was set inside the query to the null value.
I can't create two separate relationship in this case. It has to be one with union. How can I fix it?
If you call that relation as User::with('urls') you will get that $this->some_property doesn't exists, because the object itself doesn't exists. But if you call the urls() method on an object, it should work. Something like this:
$user = User::find(1);
$user->urls; // here $this->some_property should have a value
Assuming you're calling the urls() method from a User object, the $this->some_property should give you the value. If for some reason you cannot access a property directly on an Eloquent model you can always refer to the attributes[] array inside of the model. For example
// calling
$this->some_property
// should be the same as
$this->attributes['some_property']
Fetch all the users joining with the condition
Assuming users is the table for all the users, in your query you could change $this->some_property with 'users.some_property' and everything should work as expected, for each user it will query based on that property. Here is the code:
class User extends \Eloquent {
public function urls() {
$favouriteUrls = \DB::table('urls')
->select('urls.*')
->join('favourite_urls', function($join) {
$join->on('favourite_urls.url_id', '=', 'urls.id');
})
->where('some_condition', '=', 'users.some_property');
return $this->belongsTo('Url')->union($favouriteUrls);
}
}
And then just call the method like this:
User::with('urls')->get();
I have an eloquent object Performer that has Albums and Albums have Images
Here is setup:
Model Performer->albums():
public function albums()
{
return $this->belongsToMany('Album','performer_albums','performer_id','album_id');
}
Model Album->images()
public function images()
{
return $this->belongsToMany('Image','album_images','album_id','image_id')->withPivot(['type','size']);
}
I have performer object stored as such:
$performer = Performer::where...->first();
Now I need to get Performer's Albums with images where size is 'large'
So to avoid nesting queries, can I use with()?
I tried
$performer->albums()
->with('images')
->wherePivot('size','large')
->get();
But laravel tells me it's trying to use wherePivot for Performer-Album relationship (M-2-M)
PS. I am also aware that I can do this,
$performer = Performer::with('albums')
->with('albums.images')
->.....-conditions for additional fields in album_images....
->get();
but question remains the same.
You need eager load constraints:
$performer->albums()
->with(['images' => function ($q) {
$q->wherePivot('size','large');
}])
->get();
And btw, no, you can't do this:
Performer::with('albums')
->with('albums.images')
->.....-conditions for additional fields in album_images....
->get();
instead you could do:
Performer::with(['albums.images' => function ($q) {
$q-> .....-conditions for additional fields in album_images....
}])->get();
I am testing eloquent for the first time and I want to see if it suit my application.
I have Product table:
id, name
and model:
class Produit extends Eloquent {
public function eavs()
{
return $this->belongsToMany('Eav')
->withPivot('value_int', 'value_varchar', 'value_date');
}
}
and eav table:
id, name, code, field_type
and pivot table:
product_id, eav_id, value_int, value_varchar, value_date
class Eav extends Eloquent {
public function produitTypes()
{
return $this->belongsToMany(
'ProduitType'
->withPivot('cs_attributs_produits_types_required');
}
All this is working.
But I want to search in that relashionship:
e.g: all product that have eav_id=3 and value_int=3
I have tested this:
$produits = Produit::with( array('eavs' => function($query)
{
$query->where('id', '3')->where('value_int', '3');
}))->get();
But I get all the product, and eav data only for these who have id=3 and value_int=3.
I want to get only the product that match this search...
Thank you
I know the question is very old. But added the answer that works in the latest versions of Laravel.
In Laravel 6.x+ versions you can use whereHas method.
So your query will look like this:
Produit::whereHas('eavs', function (Builder $query) {
// Query the pivot table
$query->where('eav_id', 3);
})->get()
My suggestion and something I like to follow is to start with what you know. In this case, we know the eav_id, so let's go from there.
$produits = Eav::find(3)->produits()->where('value_int', '3')->get();
Eager loading in this case isn't going to save you any performance because we are cutting down the 1+n query problem as described in the documentation because we are starting off with using find(). It's also going to be a lot easier to read and understand.
Using query builder for checking multiple eavs
$produits = DB::table('produits')
->join('eav_produit', 'eav_produit.produit_id', '=', 'produits.id')
->join('eavs', 'eavs.id', '=', 'eav_produit.eav_id')
->where(function($query)
{
$query->where('eav_produit.value_int','=','3');
$query->where('eavs.id', '=', '3');
})
->orWhere(function($query)
{
$query->where('eav_produit.value_int','=','1');
$query->where('eavs.id', '=', '1');
})
->select('produits.*')
->get();
Making it work with what you already have...
$produits = Produit::with( array('eavs' => function($query)
{
$query->where('id', '3')->where('value_int', '3');
$query->orWhere('id', '1')->where('value_int', '1');
}))->get();
foreach($produits as $produit)
{
if(!produit->eavs)
continue;
// Do stuff
}
From http://four.laravel.com/docs/eloquent:
When accessing the records for a model, you may wish to limit your results based on the existence of a relationship. For example, you wish to pull all blog posts that have at least one comment. To do so, you may use the has method
$posts = Post::has('comments')->get();
Using the "has()" method should give you an array with only products that have EAV that match your criteria.
$produits = Produit::with( array('eavs' => function($query)
{
$query->where('id', '3')->where('value_int', '3');
}))->has('eavs')->get();