Delete <feff> from text file, UTF 8 - bash

Question

I use this BASH script to filter text from one text file to another. Text is encoded in UTF 8.
#!/bin/bash
mid=$1
infile="/var/www/tmp/textgrid_uploads/${mid}.txt"
outfile="/home/var/www/vids/$mid/${mid}_textgrid.mlf"
tmpfile="/home/var/www/vids/$mid/${mid}.tmp"
i=1
touch $tmpfile
cat $infile | grep "text =" | cut -d '"' -f2 | tr -d ',' | tr -d '.' | tr -d ':' | tr -d ';' | tr -d '!' | tr -d '?' > $tmpfile
#| awk '{ print tolower($0) }'
#cat $infile | grep -v "<" | egrep -v '^[[:space:]]*$' | tr -d '.' | tr -d "," | tr -d ";" | tr -d ":" | tr -d "^" | tr -d '#' | tr -d '?' | tr -d '!' | tr -d '%' | tr -d '#' | tr -d '*' | tr -d '~' | grep -v '((xxxxx))' | awk '{ print tolower($0) }' > $tmpfile
#cat $infile | grep -v 'WEBVTT' | grep -v "\--" | grep -v '^$' | sed 's/?/./g' | sed 's/!/./g' | tr -d '.' | tr -d "," | tr -d ";" | tr -d ":" | awk '{ print tolower($0) }' > $tmpfile
nlines=$(cat $tmpfile | wc -l)
echo "#!MLF!#" >> $outfile
echo "\"*/dummyfile.lab\"" >> $outfile
while [ $i -le $nlines ]
do
line=$(cat $tmpfile | sed $i'q;d') #zobrazi konkretny riadok
printf '%s\n' $line | sed '/^\s*$/d' | cut -d "/" -f1 | egrep -v '^[[:space:]]*$' >> $outfile #zapis po riadkoch s odstranenim znaciek
i=$[$i+1] #pocitadlo
done
echo "." >> $outfile
rm $tmpfile
Output of this script is:
#!MLF!#
"*/dummyfile.lab"
<feff> V utorok o devätnástej bude vo fejs
I want to remove first word feff with both brackets. Please give me whole example how to do it. I am new in Bash and I just use this script I didn't create it. Thanks guys.