The code saying that there is "unexpected end of file" error in line 16. Could someone please tell me my mistake?
#!/bin/bash
total=0
for i in `grep 01/Oct/2006 log.txt | cut -d' ' -f1 | sort | uniq -c | sort -n | tail`;
do if [[ $i =~ ^[0-9]+$ ]]; then
total=$(( $total + $i )); fi
for i in `grep 01/Oct/2006 log.txt | cut -d' ' -f1 | sort | uniq -c | sort -rn | head -10 | tr -s ' ' | cut -d' ' -f2,3 | sed -E 's/(\S*) (\S*)/\2 - \1/' | nl -s'. '`;
do
if ! [[ $i =~ ^[0-9]+$ ]];
then
printf $i;
printf " ";
else
printf " $i - $(echo "scale=0; $i * 100 / $total" | bc )%% \n" ;
fi
done
Your first for loop lacks a done.
Here's a working version with improved formatting (but with all original flaws and bugs left inside, I just fixed the one issue asked for here):
#!/bin/bash
$total;
for i in $(
grep 01/Oct/2006 log.txt |
cut -d' ' -f1 |
sort |
uniq -c |
tail);
do
if [[ $i =~ ^[0-9]+$ ]]
then
$total += $i
fi
done
for i in $(
grep 01/Oct/2006 log.txt |
cut -d' ' -f1 |
sort |
uniq -c |
sort -rn |
head -10 |
tr -s ' ' |
cut -d' ' -f2,3 |
sed -E 's/(\S*) (\S*)/\2 - \1/' |
nl -s'. ')
do
if ! [[ $i =~ ^[0-9]+$ ]];
then
printf " $i - ";
else
printf " $i - 0$(echo "scale=0; $i / $total" | bc)%% " ;
fi
done
Related
I am writing a script that will loop through columns to find an instance of a word.
I decided I do it through nested loops and after executing my code, I get this error:
./gallupscript.sh: line 115: syntax error near unexpected token done'
./gallupscript.sh: line 115:done'
Here is the area where my code fails:
token=2 #token is the column number
starter=0
s1="First" ; s2="Second" ; s3="Third" ; s4="Fourth" ; s5="Fifth"
s=s ; a=1
while [ $token -le 6 ]
do
cat gallup.csv | cut -d',' -f"$token" | grep -n $strength1 | cut -d':' -f1 > str1
if [ -s str1 ]
then
for i in $(cat str1)
do
if [[ $i -ne $number && $starter -eq 0 ]]
then
save=$(cat gallup.csv | head -$i | tail +$i | cut -d',' -f1)
s=s ; s+=$a ; starter=1
printf "-- $strength1 --"
printf "${!s} Strength: $save"
elif [[ $i -ne $number && $starter -ne 0 ]]
then
save=$(cat gallup.csv | head -$i | tail +$i | cut -d',' -f1)
printf ", $save"
fi
done
starter=0
a=$((a+1))
token=$((token+1))
echo #new line
done
This code is expected to output the names (in first columns) where the word is matched with the one I am searching for.
You are not closing your if statement, it doesn't have to do with for.
Use the following code instead:
token=2 #token is the column number
starter=0
s1="First" ; s2="Second" ; s3="Third" ; s4="Fourth" ; s5="Fifth"
s=s ; a=1
while [ $token -le 6 ]
do
cat gallup.csv | cut -d',' -f"$token" | grep -n $strength1 | cut -d':' -f1 > str1
if [ -s str1 ]
then
for i in $(cat str1)
do
if [[ $i -ne $number && $starter -eq 0 ]]
then
save=$(cat gallup.csv | head -$i | tail +$i | cut -d',' -f1)
s=s ; s+=$a ; starter=1
printf "-- $strength1 --"
printf "${!s} Strength: $save"
elif [[ $i -ne $number && $starter -ne 0 ]]
then
save=$(cat gallup.csv | head -$i | tail +$i | cut -d',' -f1)
printf ", $save"
fi
done
fi # <------------ add this line
starter=0
a=$((a+1))
token=$((token+1))
echo #new line
done
I'm completely new to coding and this is my first script. I've been receiving this error from my code and can't seem to figure out what I'm doing wrong.
| LAST NAME | FIRST NAME | JOB | OLD | NEW | MESSAGE
: line 25: syntax error near unexpected token `|'
: line 25: ` else | '
The script is just supposed to read a text file. II've attempted to use gedit to see my mistake and all I've noticed is my JOB= line is discolored.
#!/bin/bash
printf "| % -15s | % -10s | % -6s | % -6s | % -6s | % -40s\n" "LAST NAME" "FIRST NAME" "JOB" "OLD" "NEW" "MESSAGE"
while read line
do
USER ID=` echo $line | cut -d '|' -f1 `
LAST NAME=` echo $line | cut -d '|' -f2 `
FIRST NAME=` echo $line | cut -d '|' -f3 `
JOB=` echo $line | cut -d '|' -f4 `
OLD NICE=` echo $line | cut -d '|' -f5 `
PREFERRED PASSWORD=` echo $line | cut -d '|' -f6 `
FULL NAME="$FIRST_NAME $LAST_NAME"
if [ "$JOB" == "P" ]
then
NEW_NICE=3
elif [ "$JOB" == "S" ]
then
NEW_NICE=6
else |
NEW_ICE=7
fi
test -e /home/$USER_ID
if [ "$?" == "0" ]
then
MESSAGE="$USER_ID already exists"
else
ENCRYPTED_PASSWORD=` echo "$PREFERRED_PASSWORD" | openssl passwd -1 -stdin `
useradd -m -c "$FULL_NAME" -p $ENCRYPTED_PASSWORD $USER_ID
mkdir "/home/$USER_ID/${LAST_NAME}_backup"
chown -r $USER_ID "/home/$USER_ID/${LAST_NAME}_backup"
echo "$USER_ID created"
fi
printf "| % -15s | % -10s | % -6s | % -6s | % -6s | % -40s\n" "$LAST NAME" "$FIRST NAME" "$JOB" "$OLD" "$NEW" "$MESSAGE"
done < test3_data.txt
I have following bash script
while read -r line; do
FILEPATH=$(echo $line | cut -d : -f 1)
L=$(echo $line | cut -d : -f 2)
C=$(echo $line | cut -d : -f 3)
TYPE=$(echo $line | cut -d : -f 4 | cut -c 2-)
MESSAGE=$(echo $line | cut -d : -f 5 | cut -c 2-)
DESCRIPTION=$(echo $line | cut -d : -f 6 | cut -c 2-)
if [ "$TYPE" == 'error' ]; then
printf "\n \e[31m$TYPE\e[39m\n"
else
printf "\n \e[33m$TYPE\e[39m\n"
fi
printf " \e[90m$FILEPATH:$L:$C\e[39m\n"
printf " $MESSAGE - $DESCRIPTION\n"
done <<< "$RESULT"
In terminal colors works perfectly.
How to hide colors in Xcode & Source Tree?
i have a file /ws/$1-rcd/temp.txt which has only one line as follows
198|/vob/ccm_tpl/repository/open_source/commons_collections/3_2_2/...
i have a script to get the value repository/open_source/commons_collections and 3_2_2 by reading the file and looping through it using for loop
i have my code as follows
grep -n "$4" /ws/$1-rcd/raw-vobs-config-spec | cut -d " " -f1,2 | sed -e 's/\:element/|/g' | sed -e 's/ //g' > /ws/$1-rcd/temp.txt
for i in `cat /ws/$1-rcd/temp.txt`
do
line=`echo $i | cut -d"|" -f1`
path=`echo $i | cut -d"|" -f2`
whoami
directory_temp=`echo $path | awk -F "/" '{ print $(NF-2)}'`
if [ "$directory_temp" == "$4" ]
then
OLD_VERSION=`sed -n "${line}p" /ws/$1-rcd/raw-vobs-config-spec | cut -d " " -f2 | awk -F "/" '{ print $(NF-1)}'`
total_fields=`sed -n "${line}p" /ws/$1-rcd/raw-vobs-config-spec | cut -d " " -f2 | awk -F "/" '{ print NF }'`
dir_path=`expr ${total_fields} - 2`
loc=`sed -n "${line}p" /ws/$1-rcd/raw-vobs-config-spec | cut -d " " -f2 | cut -d"/" -f1-"${dir_path}"`
location=`echo $loc | cut -d"/" -f4,5,6`
fi
done
but when i run this code it gives me an error as
-bash: line 45: syntax error near unexpected token |'
-bash: line 45:for i in 198|/vob/ccm_tpl/repository/open_source/commons_collections/3_2_2/...'
can anyone please suggest what am i doing wrong
If you want to iterate through each line of a file, use while loop like below
while read -r line ;do
echo $line
done <file.txt
so, your code can be rewritten as
grep -n "$4" /ws/$1-rcd/raw-vobs-config-spec | cut -d " " -f1,2 | sed -e 's/\:element/|/g' | sed -e 's/ //g' > /ws/$1-rcd/temp.txt
while read i ; do
line=`echo $i | cut -d"|" -f1`
path=`echo $i | cut -d"|" -f2`
whoami
directory_temp=`echo $path | awk -F "/" '{ print $(NF-2)}'`
if [ "$directory_temp" == "$4" ]
then
OLD_VERSION=`sed -n "${line}p" /ws/$1-rcd/raw-vobs-config-spec | cut -d " " -f2 | awk -F "/" '{ print $(NF-1)}'`
total_fields=`sed -n "${line}p" /ws/$1-rcd/raw-vobs-config-spec | cut -d " " -f2 | awk -F "/" '{ print NF }'`
dir_path=`expr ${total_fields} - 2`
loc=`sed -n "${line}p" /ws/$1-rcd/raw-vobs-config-spec | cut -d " " -f2 | cut -d"/" -f1-"${dir_path}"`
location=`echo $loc | cut -d"/" -f4,5,6`
fi
done < /ws/$1-rcd/temp.txt
You may be better served relying on parameter expansion and substring removal. For example:
#!/bin/sh
a=$(<dat/lline.txt) ## read file into a
a=${a##*ccm_tpl/} ## remove from left to ccm_tpl/
num=${a##*collections/} ## remove from left to collections/
num=${num%%/*} ## remove from right to /
a=${a%%${num}*} ## remove from right to $num
Input File
$ cat dat/lline.txt
198|/vob/ccm_tpl/repository/open_source/commons_collections/3_2_2/..
Output
$ sh getvals.sh
a : repository/open_source/commons_collections/
num : 3_2_2
If you need to trim in some other way, just let me know and I'm happy to help further.
I use this BASH script to filter text from one text file to another. Text is encoded in UTF 8.
#!/bin/bash
mid=$1
infile="/var/www/tmp/textgrid_uploads/${mid}.txt"
outfile="/home/var/www/vids/$mid/${mid}_textgrid.mlf"
tmpfile="/home/var/www/vids/$mid/${mid}.tmp"
i=1
touch $tmpfile
cat $infile | grep "text =" | cut -d '"' -f2 | tr -d ',' | tr -d '.' | tr -d ':' | tr -d ';' | tr -d '!' | tr -d '?' > $tmpfile
#| awk '{ print tolower($0) }'
#cat $infile | grep -v "<" | egrep -v '^[[:space:]]*$' | tr -d '.' | tr -d "," | tr -d ";" | tr -d ":" | tr -d "^" | tr -d '#' | tr -d '?' | tr -d '!' | tr -d '%' | tr -d '#' | tr -d '*' | tr -d '~' | grep -v '((xxxxx))' | awk '{ print tolower($0) }' > $tmpfile
#cat $infile | grep -v 'WEBVTT' | grep -v "\--" | grep -v '^$' | sed 's/?/./g' | sed 's/!/./g' | tr -d '.' | tr -d "," | tr -d ";" | tr -d ":" | awk '{ print tolower($0) }' > $tmpfile
nlines=$(cat $tmpfile | wc -l)
echo "#!MLF!#" >> $outfile
echo "\"*/dummyfile.lab\"" >> $outfile
while [ $i -le $nlines ]
do
line=$(cat $tmpfile | sed $i'q;d') #zobrazi konkretny riadok
printf '%s\n' $line | sed '/^\s*$/d' | cut -d "/" -f1 | egrep -v '^[[:space:]]*$' >> $outfile #zapis po riadkoch s odstranenim znaciek
i=$[$i+1] #pocitadlo
done
echo "." >> $outfile
rm $tmpfile
Output of this script is:
#!MLF!#
"*/dummyfile.lab"
<feff> V utorok o devätnástej bude vo fejs
I want to remove first word feff with both brackets. Please give me whole example how to do it. I am new in Bash and I just use this script I didn't create it. Thanks guys.