Lumen (Laravel) routing not passing route parameter to controller - laravel-5

I'm having some trouble with Lumen's routing. I'm trying to capture the uri using regex in a route.
When I try to pass the captured data to a controller method, the variable is empty, yet when I do the same using a closure, the variable shows as expected. Here's the code:
This works:
$app->get('{categoryUrlPath:[a-zA-Z0-9\-\/]+}', function($categoryUrlPath) {
echo $categoryUrlPath;
});
This doesn't work:
$app->get('{categoryUrlPath:[a-zA-Z0-9\-\/]+}', ['uses' => 'App\Http\Controllers\FrontController#showSearch']);
and inside the controller:
public function showSearch($categoryUrlPath) {
return $categoryUrlPath;
}
Debugging the controller's showSearch method with
print_r(app('request')->route());
shows that the variable is there:
Array ( [0] => 1 [1] => Array ( [uses] => App\Http\Controllers\FrontController#showSearch ) [2] => Array ( [categoryUrlPath] => this/is/a/captured/uri ) )
But still it isn't passed as $categoryUrlPath
Any help appreciated - I'm puzzled. Also, I realise the are other (easier) ways to capture just the URI but I have a specific reason for doing it this way and, besides, I'd like to understand what I'm doing wrong with the router here.
Thanks!

Type hinting on a controller method will make your variable "go empty". Simply don't type hint. Your closure approach doesn't have the type hint, but your controller method does.

Related

How to call resource route Codeigniter 4

Please I need help to enable me know how to map the resource route to http request.
for example am trying to call this url via axios
http://localhost/nmc/public/api/unregisteredpatients?userid=hen11#gmail.com
and i have created the following resource routes to call my api
//$routes->resource('api/unregisteredpatients/(:any)', 'UnregisteredPatients::show/$1', ['namespace' => 'Api']);
//$routes->get('api/unregisteredpatients/(:any)', 'UnregisteredPatients::show/$1', ['namespace' => 'Api']);
$routes->resource('api/unregisteredpatients/(:any)', ['controller' => 'Api/UnregisteredPatients']);
None of these was able to call my api method instead they all called the index() method, whereas I wanted it to call the show($id) method to enable me utilise the $id to fetch data.
public function show($id = null) {
.....
}
Please I need help
This solves it for me, though I couldn't have a way to capture query parameters but passing the parameter as a segment gives me an AFAIK solution.
$routes->match(['get'], 'api/unregisteredpatients/(:any)', 'Api\UnregisteredPatients::show/$1');

Laravel routing with or without parameter in a group

For my application I am trying to create a few routes entries.
One entry to initialise the application and another for AJAX requests.
So my application should hit the initialise function if I type https.test.com/app/drive but also if I want to type some additional parameters at the end something like this: https:test.com/app/drive/specificTabA or https:test.com/app/drive/specificTabB
The problem is that when ever I type https.test.com/drive/specificTabNameA this clashes with the fetchData get route used by my AJAX call.
How can I access the initialise function when hitting this URl https.test.com/app/drive or also hitting something like this: https:test.com/app/drive/specificTabA or https:test.com/app/drive/specificTabB?
Route::group(['prefix' => 'drive'], function () {
Route::get('', 'CustomController#initialise');
Route::get('fetchData', 'CustomController#fetchData');
});
I've done some tests, and came with the following conclusion/solution:
Route::group(['prefix' => 'drive'], function () {
Route::get('fetchData', 'CustomController#fetchData');
Route::get('{param?}', 'CustomController#initialise');
});
CustomerController:
function initialise($param = null)
{
...
}
Note that by changing the order of the routes you will actually load the correct route.
When you visit /drive/fetchData it will load fetchData route
When you visit /drive/ it will load initialise route without arguments
When you visit /drive/xyz it will load initialise route with $param being xyz
Hope it helps :)
My friend I want to get your attention to Laravel docs https://laravel.com/docs/5.0/routing#route-parameters especially this one Route Parameters. You can tell router that this route can have parameter but also can not have it. Look at this example
Route::get('/{specific?}')
Now you can get this specific parameter in your Controller function after request
public function initialize (Request $request, $specific = null)
Set it default to null as this param can both be past and not, so it should have some default value.
Good luck ;)
The following should work for you:
Route::group(['prefix' => 'drive'], function () {
Route::get('fetchData', 'CustomController#fetchData');
Route::get('{path?}', 'CustomController#initialise')->where(['path' => '.*']);
});
This will allow the following path:
/drive => initialise
/drive/1 => initalize
/drive/1/2/3 => initalize
/drive/fetchData => fetchData
Adding ->where(['path' => '.*']) will route any path to initalize, e.g. /1, /1/2, /1/2/3.
If you only want to allow the path to be one level deep you can remove the where:
Route::get('{path?}', 'CustomController#initialise');

Laravel Routes and 'Class#Method' notation - how to pass parameters in URL to method

I am new to Laravel so am uncertain of the notation. The Laravel documentation shows you can pass a parameter this way:
Route::get('user/{id}', function ($id) {
return 'User '.$id;
});
Which is very intuitive. Here is some existing coding in a project I'm undertaking, found in routes.php:
Route::get('geolocate', 'Api\CountriesController#geolocate');
# which of course will call geolocate() in that class
And here is the code I want to pass a variable to:
Route::get('feed/{identifier}', 'Api\FeedController#feed');
The question being, how do I pass $identifier to the class as:
feed($identifier)
Thanks!
Also one further sequitir question from this, how would I notate {identifier} so that it is optional, i.e. simply /feed/ would match this route?
You should first create a link which looks like:
/feed/123
Then, in your controller the method would look like this:
feed($identifier)
{
// Do something with $identifier
}
Laravel is smart enough to map router parameters to controller method arguments, which is nice!
Alternatively, you could use the Request object to return the identifier value like this:
feed()
{
Request::get('identifier');
}
Both methods have their merits, I'd personally use the first example for grabbing one or two router parameters and the second example for when I need to do more complicated things.

Get part of url from Laravel named route

Is there a possibility to get the part of url, that is defined in route?
For example with this route:
Route::get('/editor/{id}', 'EditorController#editor')->name('editorNew');
after using mentioned functionality, let's say route_link(); i would like to get:
$route_link = route_link('editorNew', array('id' => 1));
//$route_link containts "/editor/1"
I tried to use route(), but i got http://localhost/app/public/editor-new/1 instead of /editor-new/1 and that's not what i wanted.
For clarity need this functionality to generate links depending on machine, that the app is fired on (integration with Shopify).
You can use route method to get the relative path by passing false in the third parameter as:
route('editorNew', [1], false); // returns '/editor-new/1'
You could use the following:
$route_link = route('editorNew', [1]);
1 is the first value that will be on the route, at this moment {id}.
If you want to use the paramater (id) in your method, it will be the following:
public function editor($id) {
//your code
}
And in the view you could use:
Route::input('id');
Hope this works!

Get last part of current URL in Laravel 5 using Blade

How to get the last part of the current URL without the / sign, dynamically?
For example:
In www.news.com/foo/bar get bar.
In www.news.com/foo/bar/fun get fun.
Where to put the function or how to implement this in the current view?
Of course there is always the Laravel way:
request()->segment(count(request()->segments()))
You can use Laravel's helper function last. Like so:
last(request()->segments())
This is how I did it:
{{ collect(request()->segments())->last() }}
Use basename() along with Request::path().
basename(request()->path())
You should be able to call that from anywhere in your code since request() is a global helper function in Laravel and basename() is a standard PHP function which is also available globally.
The Route object is the source of the information you want. There are a few ways that you can get the information and most of them involve passing something to your view. I strongly suggest not doing the work within the blade as this is what controller actions are for.
Passing a value to the blade
The easiest way is to make the last part of the route a parameter and pass that value to the view.
// app/Http/routes.php
Route::get('/test/{uri_tail}', function ($uri_tail) {
return view('example')->with('uri_tail', $uri_tail);
});
// resources/views/example.blade.php
The last part of the route URI is <b>{{ $uri_tail }}</b>.
Avoiding route parameters requires a little more work.
// app/Http/routes.php
Route::get('/test/uri-tail', function (Illuminate\Http\Request $request) {
$route = $request->route();
$uri_path = $route->getPath();
$uri_parts = explode('/', $uri_path);
$uri_tail = end($uri_parts);
return view('example2')->with('uri_tail', $uri_tail);
});
// resources/views/example2.blade.php
The last part of the route URI is <b>{{ $uri_tail }}</b>.
Doing it all in the blade using the request helper.
// app/Http/routes.php
Route::get('/test/uri-tail', function () {
return view('example3');
});
// resources/views/example3.blade.php
The last part of the route URI is <b>{{ array_slice(explode('/', request()->route()->getPath()), -1, 1) }}</b>.
Try request()->segment($number) it should give you a segment of the URL.
In your example, it should probably be request()->segment(2) or request()->segment(3) based on the number of segments the URL has.
YourControllor:
use Illuminate\Support\Facades\URL;
file.blade.php:
echo basename(URL::current());
It was useful for me:
request()->path()
from www.test.site/news
get -> news
I just had the same question. In the meantime Laravel 8. I have summarised all the possibilities I know.
You can test it in your web route:
http(s)://127.0.0.1:8000/bar/foo || baz
http(s)://127.0.0.1:8000/bar/bar1/foo || baz
Route::get('/foo/{lastPart}', function(\Illuminate\Http\Request $request, $lastPart) {
dd(
[
'q' => request()->segment(count(request()->segments())),
'b' => collect(request()->segments())->last(),
'c' => basename(request()->path()),
'd' => substr( strrchr(request()->path(), '/'), 1),
'e' => $lastPart,
]
)->where('lastPart', 'foo,baz'); // the condition is only to limit
I prefer the variant e).
As #Qevo had already written in his answer. You simply make the last part part of the request. To narrow it down you can put the WHERE condition at the route.
Try with:
{{ array_pop(explode('/',$_SERVER['REQUEST_URI'])) }}
It should work well.

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