I have created Spring Standalone application and I have deployed that on Unix box. I have created jar file that I am executing using java -jar JarName.jar command.
Is there any way to stop this standalone process apart from using JMX?
Thanks
Sach
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There is a way I can start the spring boot jar file as part of tomcat start(catalina.bat start).
I have a spring cloud api gateway which does not support war file deployment.
In a bare metal box, I have installed the tomcat, and as part of deployment I have converted all microservice into war file and able to deploy it into tomcat/webapp folder and up and running.
As spring cloud api gateway does not support war file, I kept this application with embed tomcat.
Now I need this jar file as well get started along with the tomcat [catalina.bat start].
In tomcat I have seen there is something shared.loader option in catalina.properties file.
I have kept the jar file in below path as shown below and when I try to start it, jar file is not getting picked up.
Need to know if there is a way to start the spring boot application [jar file] as part of tomcat [catalina.bat start] start.
Please help me to deploy microservice without using dockers,and how can I run multiple service using single command
Spring boots fat jar enables you to just start the jar by using Java - jar command.
Just write a script, that does it on your server.
I want to use Websphere liberty in spring boot application instead of tomcat server. If I am correct it is not supported out of the box. How can I configure spring boot/websphere liberty to achieve this?
Using the Liberty app accelerator you can download a zip containing a Maven buildable 'Spring Boot with Spring MVC' app as your starting point. Just run mvn install and you'll get the app running at http://localhost:9080/myLibertyApp/
Actually, you can now create runnable jar files with WebSphere Liberty. You need v8.5.5.9 or higher. Create a runnable jar this way:
server package {server name} --archive={jar name}.jar --include=minify,runnable
Resultant jar can be run as you'd expect:
java -jar {jar name}.jar
Since very recently (May 2018) you can deploy a Spring Boot jar with Liberty, as it seems. See https://developer.ibm.com/wasdev/blog/2018/05/11/spring-boot-applications-on-liberty/. Haven't tried it out yet, though.
Using spring boot maven plugin we are able to generate executable jars. And we can execute the jar using java -jar ...
In spring boot there is another option for installation . This generates the jar which can be added in init.d.
But is it possible to generate a sh|cmd file which can be used to start|stop|restart spring boot applications?
The executable true flag to create a 'fully executable’ jar actually pre-pends a shell script into the beginning of the jar.
It works outside init.d too. Try this:
./myapp.jar start
i'm using the new spring-boot 1.3.0 feature to run tomcat embedded spring-boot application jar as a unix service.
All is working fine but i don't know how to tune jvm (with -Xms and -Xmx parameters for example)
I've searched in spring documentation and around the web without success.
It's missing from the documentation (I've opened an issue to correct that), but you should be able to use the JAVA_OPTS environment variable.
You can configure it in a .conf file that's situated next to the jar. For example, if you jar file is /var/myapp/myapp.jar, the file /var/myapp/myapp.conf will be sourced by the launch script.
There is one more option to achieve the same , if you are running jar with mvn you can do something like this
mvn spring-boot:run -Drun.jvmArguments="-Xmx512m"
And If you are running with java -jar ,you can try something like this
java -Xmx1G -jar myapp.jar