I have 2 sqlite3 tables :
FND is a Table of names and their likely gender i.e.:
nm,gndr <-column names
Aliyah,F
Moses,M
Peter,M
Members is second table i.e.
Fname,Lname <-column names
DAVID X, BAKER
MARY MIA,MCGEE
TINA HEATHER,JOHNSON
JIM PETER TOM, SANTINO
The members table has first and middle names in the fname column.
I am trying to write a query to list the Members table fnames column, with a generated column indicating gender based on the first word in the fname column.
I tried this but it didn't work:
select m.fname,(select gndr from FND where upper(nm) like m.fname||'%')as gender
from Members m
can anyone correct my sql statement?
... upper(nm) like m.fname||'%'
Let's look at some example values:
nm: 'David'
fname: 'DAVID X'
SQL: 'DAVID' LIKE 'DAVID X%'
This obviously does not match.
You have to reverse the LIKE operands:
m.fname LIKE nm||'%'
Related
I have a google form linked to a google sheet. The google form let me choose a date and select names. These persons are clients of a meeting at this date.
The google form gives me a date in the 1st column and a list of names separated by commas in the 2nd column. Eg
8.15.2020 John, Mike, Eva
8.20.2020 John, Eva, Gudrun, Pete
Now I want to sort this tab by names - 1st column list of names, 1st row list of meeting dates, an 'x' where the person joined the meetiing and save it in a new tab. Eg
8.15.2020 8.20.2020
John x x
Mike x
Eva x x
Gudrun x
Pete x
How can I solve this problem?
try:
=ARRAYFORMULA(QUERY(SPLIT(FLATTEN(
IF(IFERROR(SPLIT(Sheet1!B1:B; ", "))="";;
Sheet1!A1:A&"♦"&SPLIT(Sheet1!B1:B; ", "))); "♦");
"select Col2,count(Col2)
where Col2 is not null
group by Col2
pivot Col1"))
to get xes try:
=ARRAYFORMULA(REGEXREPLACE(TO_TEXT(QUERY(SPLIT(FLATTEN(
IF(IFERROR(SPLIT(Sheet1!B1:B; ", "))="";;
Sheet1!A1:A&"♦"&SPLIT(Sheet1!B1:B; ", "))); "♦");
"select Col2,count(Col2)
where Col2 is not null
group by Col2
pivot Col1")); "^\d+$"; "x"))
I hava one MySQL Table
id name birthdate city
1 Owen 2011/01/01 USA
2 Mark 2012/05/01 UK
3 Marry 2011/01/01 JP
4 John 2011/01/01 JP
First，I uesd jqgrid to read all row data. But Now,I want to know when birthdate=2011/01/01，how many different city in the table.
Can don't used sql，only used jqgrid plugin?
You are looking for distinct function.
SELECT DISTINCT(city) FROM table WHERE birthday = "2011/01/01";
I have Google spreadsheet with a list of names in a column. (EX: David, Daniel, John, Cooper).
I made a drop down list of those names. Lets say I two more columns with Age and Birthday.
I want to show the age and birthday column information pertaining to 'David' when I choose 'David' from the drop down list.
A drop down list acting as a 'in spreadsheet filter'.
Any way to do this?
Ive tried the =FILTER() and =UNIQUE() but they don't quite get me what I want. Thanks for the help
Assuming you have the drop down list in cell A1 (of sheet 2) and the columns with data are in sheet1
col A names
col B age
col C birthday
in cell B1 (of sheet2)
=QUERY(Sheet1!A1:C, "Select B, C where A = """&A1&""" ", 1)
I have been asked this question;
You list county names and the surnames of the representatives if the representatives in the counties have the same surname.
and I have the following tables;
***REPRESENTATIVE***
REPI SURNAME FIRSTNAME COUNTY CONS
---- ---------- ---------- ---------- ----
R100 Gorege Larry kent CON1
R101 shneebly john kent CON2
R102 shneebly steve kent CON3
I cant seem to figure out the correct way to ask Orical to display a surname that exists more then twice and the surnames are in the same country.
I know how to ask WHERE something = something, but that's doesn't ask what I want to know.
It sounds like you want to use the HAVING clause after doing a GROUP BY
SELECT surname, county, count(*)
FROM you_table
GROUP BY surname, county
HAVING count(*) > 1;
If you really mean "more than twice" as you wrote, none of the data you'd want HAVING count(*) > 2 but then none of your sample data would be returned.
In words, this SQL statement says
Group the data into buckets by surname and county. Each distinct combination of surname and county is a separate bucket.
Count the number of rows in each bucket
Return those buckets where there are at least two rows
Let's say I have table data similar to the following:
123456 John Doe 1 Green 2001
234567 Jane Doe 1 Yellow 2001
234567 Jane Doe 2 Red 2001
345678 Jim Doe 1 Red 2001
What I am attempting to do is only isolate the records for Jane Doe based upon the fact that she has more than one row in this table. (More that one sequence number)
I cannot isolate based upon ID, names, colors, years, etc...
The number 1 in the sequence tells me that is the first record and I need to be able to display that record, as well as the number 2 record -- The change record.
If the table is called users, and the fields called ID, fname, lname, seq_no, color, date. How would I write the code to select only records that have more than one row in this table? For Example:
I want the query to display this only based upon the existence of the multiple rows:
234567 Jane Doe 1 Yellow 2001
234567 Jane Doe 2 Red 2001
In PL/SQL
First, to find the IDs for records with multiple rows you would use:
SELECT ID FROM table GROUP BY ID HAVING COUNT(*) > 1
So you could get all the records for all those people with
SELECT * FROM table WHERE ID IN (SELECT ID FROM table GROUP BY ID HAVING COUNT(*) > 1)
If you know that the second sequence ID will always be "2" and that the "2" record will never be deleted, you might find something like:
SELECT * FROM table WHERE ID IN (SELECT ID FROM table WHERE SequenceID = 2)
to be faster, but you better be sure the requirements are guaranteed to be met in your database (and you would want a compound index on (SequenceID, ID)).
Try something like the following. It's a single tablescan, as opposed to 2 like the others.
SELECT * FROM (
SELECT t1.*, COUNT(name) OVER (PARTITION BY name) mycount FROM TABLE t1
)
WHERE mycount >1;
INNER JOIN
JOIN:
SELECT u1.ID, u1.fname, u1.lname, u1.seq_no, u1.color, u1.date
FROM users u1 JOIN users u2 ON (u1.ID = u2.ID and u2.seq_no = 2)
WHERE:
SELECT u1.ID, u1.fname, u1.lname, u1.seq_no, u1.color, u1.date
FROM users u1, thetable u2
WHERE
u1.ID = u2.ID AND
u2.seq_no = 2
Check out the HAVING clause for a summary query. You can specify stuff like
HAVING COUNT(*) >= 2
and so forth.