I have a file (file1.txt) with text as:
aaa,,,,,
aaa,10001781,,,,
aaa,10001782,,,,
bbb,10001783,,,,
My file2 contents are:
11111111
10001781
11111222
I need to search second field of file1 in file2 and delete the line from file1 if pattern is matching.So output will be:
aaa,,,,,
aaa,10001782,,,,
bbb,10001783,,,,
Can I use grep and cut commands for this?
This prints lines from file1.txt only if the second field is not in file2:
$ awk -F, 'FNR==NR{a[$1]=1; next;} !a[$2]' file2 file1.txt
aaa,,,,,
aaa,10001782,,,,
bbb,10001783,,,,
How it works
This works by reading file2 and keeping track of all lines seen in an associative array a. Then, lines in file1.txt are printed only if its column 2 is not in a. In more detail:
FNR==NR{a[$1]=1; next;}
When reading file2, set a[$1] to 1 to signal that we have seen the value on this line. We then instruct awk to skip the rest of the commands and start over on the next line.
This section is only run for file2 because file2 is listed first on the command line and FNR==NR only when we are reading the first file listed on the command line. This is because FNR is the number of lines read from the current file and NR is the total number of lines read so far. These two are equal only for the first file.
!a[$2]
When reading file1.txt, a[$2] evaluates to true if column 2 was seen in file2. Since ! is negation, !a[$2] evaluates to true when column 2 was not seen. When this evaluates to true, the line is printed.
Alternative
This is the same logic, expressed in a slightly different style, as suggested in the comments by Tom Fenech:
$ awk -F, 'FNR==NR{a[$1]; next;} !($2 in a)' file2 file1.txt
aaa,,,,,
aaa,10001782,,,,
bbb,10001783,,,,
Soulution with grep
$ grep -vf file2 file1.txt
aaa,,,,,
aaa,10001782,,,,
bbb,10001783,,,,
John1024's awk soulution would be faster for large files though.
Related
Im a bit new using AWK and im trying to print lines in a file1 that a specific field exists in a file2. I copied exactly examples that I found here but i dont know why its just printing only the last match of the file1.
File1
58000
72518
94850
File2
58000;123;abc
69982;456;rty
94000;576;ryt
94850;234;wer
84850;576;cvb
72518;345;ert
Result Expected
58000;123;abc
94850;234;wer
72518;345;ert
What Im getting
94850;234;wer
awk -F';' 'NR==FNR{a[$1]++; next} $1 in a' file1 file2
What im doing wrong?
awk (while usable here), isn't the correct tool for the job. grep with the -f option is. The -f file option will read the patterns from file one per-line and search the input file for matches.
So in your case you want:
$ grep -f file1 file2
58000;123;abc
94850;234;wer
72518;345;ert
(note: I removed the trailing '\' from the data file, replace it if it wasn't a typo)
Using awk
If you did want to rewrite what grep is doing using awk, that is fairly simple. Just read the contents of file1 into an array and then for processing records from the second file, just check if field-1 is in the array, if so, print the record (default action), e.g.
$ awk -F';' 'FNR==NR {a[$1]=1; next} $1 in a' file1 file2
58000;123;abc
94850;234;wer
72518;345;ert
(same note about the trailing slash)
Thanks #RavinderSingh13!
The file1 really had some hidden characters and I could see it using cat.
$ cat -v file1
58000^M
72518^M
94850^M
I removed using sed -e "s/\r//g" file1 and the AWK worked perfectly.
I have two files file1 and file2. I want to print the new line added to file2 using diff.
file1
/root/a
/root/b
/root/c
/root/d
file2
/root/new
/root/new_new
/root/a
/root/b
/root/c
/root/d
Expected output
/root/new
/root/new_new
I looked into man page but there was no any info on this
If you don't need to preserve the order, you could use the comm command like:
comm -13 <(sort file1) <(sort file2)
comm compares 2 sorted files and will print 3 columns of output. First is the lines unique to file1, then lines unique to file2 then lines common to both. You can supress any columns, so we turn of 1 and 3 in this example with -13 so we will see only lines unique to the second file.
or you could use grep:
grep -wvFf file1 file2
Here we use -f to have grep get its patterns from file1. We then tell it to treat them as fixed strings with -F instead of as patterns, match whole words with -w, and print only lines with no matches with -v
Following awk may help you on same. This will tell you all those lines which are present in Input_file2 and not in Input_file1.
awk 'FNR==NR{a[$0];next} !($0 in a)' Input_file1 Input_file2
Try using a combination of diff and sed.
The raw diff output is:
$ diff file1 file2
0a1,2
> /root/new
> /root/new_new
Add sed to strip out everything but the lines beginning with ">":
$ diff file1 file2 | sed -n -e 's/^> //p'
/root/new
/root/new_new
This preserves the order. Note that it also assumes you are only adding lines to the second file.
So I have two files.
Example of file 1 content.
/n01/mysqldata1/mysql-bin.000001
/n01/mysqldata1/mysql-bin.000002
/n01/mysqldata1/mysql-bin.000003
/n01/mysqldata1/mysql-bin.000004
/n01/mysqldata1/mysql-bin.000005
/n01/mysqldata1/mysql-bin.000006
Example of file 2 content.
/n01/mysqlarch1/mysql-bin.000004
/n01/mysqlarch1/mysql-bin.000001
/n01/mysqlarch2/mysql-bin.000005
So I want to match based only on mysql-bin.00000X and not the rest of the file path in each file as they differ between file1 and file2.
Here's the command I'm trying to run
cat file1 | egrep -v file2
The output I'm hoping for here would be...
/n01/mysqldata1/mysql-bin.000002
/n01/mysqldata1/mysql-bin.000003
/n01/mysqldata1/mysql-bin.000006
Any help would be much appreciated.
Just compare based on everything from /:
$ awk -F/ 'FNR==NR {a[$NF]; next} !($NF in a)' f2 f1
/n01/mysqldata1/mysql-bin.000002
/n01/mysqldata1/mysql-bin.000003
/n01/mysqldata1/mysql-bin.000006
Explanation
This reads file2 in memory and then compares with file1.
-F/ set the field separator to /.
FNR==NR {a[$NF]; next} while reading the first file (file2), store every last piece into an array a[]. Since we set the field separator to /, this is the mysql-bin.00000X part.
!($NF in a) when reading the second file (file1) check if the last field (mysql-bin.00000X part) is in the array a[]. If it does not, print the line.
I'm having one problem that I've noticed when testing. If file2 is
empty nothing is returned at all where as I would expected every line
in file1 to be returned. Is this something you could help me with
please? – user2841861.
Then the problem is that FNR==NR matches when reading the second file. To prevent this, just cross check that the "reading into a[] array" action is done on the first file:
awk -F/ 'FNR==NR && argv[1]==FILENAME {a[$NF]; next} !($NF in a)' f2 f1
^^^^^^^^^^^^^^^^^^^^
From man awk:
ARGV
The command-line arguments available to awk programs are stored in an
array called ARGV. ARGC is the number of command-line arguments
present. See section Other Command Line Arguments. Unlike most awk
arrays, ARGV is indexed from zero to ARGC - 1
I have 2 file
file1:
12342015010198765hello
12342015010188765hello
12342015010178765hello
whose each line contains fields at fixed positions, for example, position 13 - 17 is for account_id
file2:
98765
88765
which contains a list of account_ids.
In Korn Shell, I want to print lines from file1 whose position 13 - 17 match one of account_id in file2.
I can't do
grep -f file2 file1
because account_id in file2 can match other fields at other positions.
I have tried using pattern in file2:
^.{12}98765.*
but did not work.
Using awk
$ awk 'NR==FNR{a[$1]=1;next;} substr($0,13,5) in a' file2 file1
12342015010198765hello
12342015010188765hello
How it works
NR==FNR{a[$1]=1;next;}
FNR is the number of lines read so far from the current file and NR is the total number of lines read so far. Thus, if FNR==NR, we are reading the first file which is file2.
Each ID in in file2 is saved in array a. Then, we skip the rest of the commands and jump to the next line.
substr($0,13,5) in a
If we reach this command, we are working on the second file, file1.
This condition is true if the 5 character long substring that starts at position 13 is in array a. If the condition is true, then awk performs the default action which is to print the line.
Using grep
You mentioned trying
grep '^.{12}98765.*' file2
That uses extended regex syntax which means that -E is required. Also, there is no value in matching .* at the end: it will always match. Thus, try:
$ grep -E '^.{12}98765' file1
12342015010198765hello
To get both lines:
$ grep -E '^.{12}[89]8765' file1
12342015010198765hello
12342015010188765hello
This works because [89]8765 just happens to match the IDs of interest in file2. The awk solution, of course, provides more flexibility in what IDs to match.
Using sed with extended regex:
sed -r 's#.*#/^.{12}&/p#' file2 |sed -nr -f- file1
Using Basic regex:
sed 's#.*#/^.\\{12\\}&/p#' file1 |sed -n -f- file
Explanation:
sed -r 's#.*#/^.{12}&/p#' file2
will generate an output:
/.{12}98765/p
/.{12}88765/p
which is then used as a sed script for the next sed after pipe, which outputs:
12342015010198765hello
12342015010188765hello
Using Grep
The most convenient is to put each alternative in a separate line of the file.
You can look at this question:
grep multiple patterns single file argument list too long
I want to compare two files.
If values from file2 are matching with the first two columns of file1 need to delete the whole line from file1 and print the result into output as shown below.
Below contains values of file1:
1,aplle,melle,cyborg
2,bplle,less,vgm
3,minipl,vicy,bgm
4,tag,mob,calic
6,Centurion,sa,hh
Below contains values of file2
2,bplle
4,tag
5,Centurion
And output must contains below:
1,aplle,melle,cyborg
3,minipl,vicy,bgm
6,Centurion,sa,hh
Is it possible to achieve this awk ?
This awk should work:
awk -F, 'FNR==NR{a[$1,$2];next} !(($1,$2) in a)' file2 file1
1,aplle,melle,cyborg
3,minipl,vicy,bgm
6,Centurion,sa,hh
This would also work: grep -Fwvf file2 file1
-F
Interpret PATTERN as a list of fixed strings,
-w
Select only those lines containing matches that form whole words.
-v
Invert the sense of matching, to select non-matching lines.
-f FILE
Obtain patterns from FILE, one per line.