Trying to get a bash script together, however I'm stuck at this. The rar is splited into x files, within the rar is 1 single file. What I'm doing is as below:
cd $dir
for rarfile in $(find -iname "*.part1.rar")
do
echo "Rar file: " $rarfile >> $dir/execute.log
name = $(unrar lb "$rarfile")
echo "Name of file inside rar container: " $name >> $dir/execute.log
extension ="${name##*.}"
echo "Extension: " $extension >> $dir/execute.log
filename = ${name%.*}
echo "Name: " $filename >> $dir/execute.log
# unrar x -y -o- $rarfile $uprar_dir
done
The excecute.log is as below:
Rar file: ./file.part1.rar
Name of file inside rar container:
Extension:
Name:
Cant seem to get the $name working. The unrar is however working fine as it should. Pls help.
in bash to assign value to a variable you cannot have spaces ie:
name=$(unrar lb "$rarfile")
instead of:
name = $(unrar lb "$rarfile")
Related
I have a project with bash, python, and C files where I would like to simply print the contents of the bash file in the doxygen documentation.
I am using Doxygen 1.9.4 and my Doxyfile has the following modified settings:
JAVADOC_AUTOBRIEF = YES
PYTHON_DOCSTRING = NO
OPTIMIZE_OUTPUT_JAVA = YES
EXTENSION_MAPPING = sh=C
EXTRACT_ALL = YES
SORT_BRIEF_DOCS = YES
INPUT = .
FILTER_PATTERNS = *.sh="sh_filter"
FILE_PATTERNS += *.sh
The sh_filter file has the following contents
#!/bin/bash
echo "\verbatim"
echo "$(cat $1)"
echo "\endverbatim"
After running doxygen, there is nothing that appears in the file reference for the bash file that is within the working directory.
How can I get the file contents to be printed verbatim?
A bit long for a comment. The construction as requested is quite unusual as normally the purpose is to document routines / variables / classes / namespaces etc and support this with code. In this case the requirement is to just show the contents of the file.
The bests solution I found is to create the filter like:
#!/bin/bash
echo "/** \file"
echo "\details \verbinclude $1 */"
echo "$(cat $1)"
and have the following added to the doxygen settings file:
EXTENSION_MAPPING = sh=C
INPUT = .
FILTER_PATTERNS = *.sh="./sh_filter"
FILE_PATTERNS += *.sh
EXAMPLE_PATH = .
(where the different paths are depending on the local situation)
Hello I'm new here I need a script to check, if a folder exist and then run a file from the folder. If not, it should extract a ZIP file into a specific location. Thanks in advance!
'Objects
Set fso = CreateObject("Scripting.FileSystemObject")
Set shl = CreateObject("WScript.Shell")
path="C:\SomeFolderToExist\" 'path to folder
exists = fso.FolderExists(path)
if (exists) then
program="myprog.exe" 'Program name to run
shl.Run(path & program) 'Run a program
end if
For unzipping, I can only tell you to see this: Extract files from ZIP file with VBScript
Dim FILE, tmpfilepath, uniqueid As String
uniqueid = Row.uniqueid
tmpfilepath = "G:\Files\" + uniqueid
If System.IO.Directory.Exists(tmpfilepath) Then
do something
Else
System.IO.Directory.CreateDirectory(tmpfilepath)
End If
If I understand correctly :
create a script: sudo vim script.sh
#!/bin/bash
echo "enter your path"
read path
if [[ -d "$path" ]]
then
echo $(sudo $path/yourprograme)
else
echo "enter your specific location"
read spec
$ mkdir -p $spec
$ unzip yourfiles.zip -d $spec
fi
run the scrip.sh : sudo ./script.sh
I have a FTP folder receiving files from a remote camera. The camera stores the video file name always as ./rec_YYYY-MM-DD_HH-MM.mkv. The video files are stored all in the same folder, the root folder from the FTP server.
I need to move these files to another folder, with this new scheme:
Remove rec_ from the file name.
Change date format to DD-MM-YY.
Remove date from the file name and make it a folder instead, where that same file and all the others in the same date will be stored in.
Final file path would be: ./DD-MM-YYYY/HH-MM.mkv.
The process would continue to all the files, putting them in the folder corresponding to the day it was created.
Summing up: ./rec_YYYY-MM-DD_HH-MM.mkv >> ./DD-MM-YYYY/HH-MM.mkv. The same should apply to all files that are in the same folder.
As I can't make it happen directly from the camera, this needs to be done with Bash on the server that is receiving the files.
So far, what I got is script, which would get the file's creation date and use it to make a folder, and then get creation time to move the file with the new name, based on it's creation time.:
for f in *.mp4
do
mkdir "$f" "$(date -r "$f" +"%d-%m-%Y")"
mv -n "$f" "$(date -r "$f" +"%d-%m-%Y/%H-%M-%S").mp4"
done
I'm getting this output (with testfile 1.mp4):
It creates the folder based on the file's creation date;
it renames the file to it's creation time;
Then, it returns mkdir: cannot create directory ‘1.mp4’: File exists
If two or more files, only one gets renamed and moved as described. The others stay the same and terminal returns:
mkdir: cannot create directory ‘1.mp4’: File exists
mkdir: cannot create directory ‘2.mp4’: File exists
mkdir: cannot create directory ‘12-12-2018’: File exists
Could someone help me out? Better suggestions? Thanks!
Honestly I would just use Perl or Python for this. Here's how to embed either in a shell script.
Here's a perl script that doesn't use any libraries, even ones that ship with Perl (so it'll work without extra packages on distributions like CentOS that don't ship with the entire Perl library). The perl script launches one new process per file in order to perform the copy.
perl -e '
while (<"*.m{p4,kv}">) {
my $path = $_;
my ($prefix, $year, $month, $day, $hour, $minute, $ext) =
split /[.-_]/, $path;
my $sec = q[00];
die "unexpected prefix ($prefix) in $path"
unless $prefix eq q[rec];
die "unexpected extension ($ext) in $path"
unless $ext eq q[mp4] or $ext eq q[mkv];
my $dir = "$day-$month-$year";
my $name = "$hour-$min-$sec" . q[.] . $ext;
my $destpath = $dir . q[/] . $name;
die "$dir . $name is unexpectedly a directory" if (-d $dir);
system("cp", "--", $path, $destpath);
}
'
Here's a Python example, it's compatible with either Python 2 or Python 3 but does use the standard library. The Python script does not spawn any additional processes.
python3 -c '
import os.path as path
import re
from glob import iglob
from itertools import chain
from os import mkdir
from shutil import copyfile
for p in chain(iglob("*.mp4"), iglob("*.mkv")):
fields = re.split("[-]|[._]", p)
prefix = fields[0]
year = fields[1]
month = fields[2]
day = fields[3]
hour = fields[4]
minute = fields[5]
ext = fields[6]
sec = "00"
assert prefix == "rec"
assert ext in ["mp4", "mkv"]
directory = "".join([day, "-", month, "-", year])
name = "".join([hour, "-", minute, "-", sec, ".", ext])
destpath = "".join([directory, "/", name])
assert not path.isdir(destpath)
try:
mkdir(directory)
except FileExistsError:
pass
copyfile(src=p, dst=destpath)
'
Finally, here's a bash solution. It splits paths using -, ., and _ and then extracts various subfields by indexing into $# inside a function. The indexing trick is portable, although regex substitution on variables is a bash extension.
#!/bin/bash
# $1 $2 $3 $4 $5 $6 $7 $8
# path rec YY MM DD HH MM ext
process_file() {
mkdir "$5-$4-$3" &> /dev/null
cp -- "$1" "$5-$4-$3"/"$6-$7-00.$8"
}
for path in *.m{p4,kv}; do
[ -e "$path" ] || continue
# NOTE: two slashes are needed in the substitution to replace everything
# read -a ARRAYVAR <<< ... reads the words of a string into an array
IFS=' ' read -a f <<< "${path//[-_.]/ }"
process_file "$path" "${f[#]}"
done
If you cd /to/some/directory/containing_your_files then you could use the following script
#!/usr/bin/env bash
for f in rec_????-??-??_??-??.m{p4,kv} ; do
dir=${f:4:10} # skip 4 chars ('rec_') take 10 chars ('YYYY_MM_DD')
fnm=${f:15} # skip 15 chars, take the remainder
test -d "$dir" || mkdir "$dir"
mv "$f" "$dir"/"$fnm"
done
note ① that I have not exchanged the years and the days, if you absolutely need to do the swap you can extract the year like this, year=${dir::4} etc and ② that this method of parameter substitution is a Bash-ism, e.g., it doesn't work in dash.
your problem is: mkdir creates folder but you are giving filename for folder creation.
if you want to use fileName for folder creation then use it without extension.
the thing is you are trying to create folder with the already existing fileName
I have a script I am working on that reads off of a text file and will use the information stored in the text file to put each line entered in as an array. This array is a reference to files that are imported to a directory in another script. The problem is i built a function to zip the contents of the directory and change it's ownerships, but when I run the script it was zipping and attempting to change ownerships of the pwd. Here is my code below:
file=~/exporttool/zipFiles.txt
index=0
declare -a studyinstanceuids
while read line ; do
studyinstanceuids[$index]="$line"
index=$((index+1))
echo $line
done < $file
for i in "${studyinstanceuids[#]}"
do
echo "$i" | ./cmd2;
done
echo "Exams are in!";
##Function with argument that will take prompt to change ownerships
echo "What is the name of the owner: "
read $owner
zipForOwner(){
arg1=$1
for i in "${studyinstanceuids[#]}"; do
zip -r ~/export/"${studyinstanceuids[#]}"/20140620_"${studyinstanceuids[#]}".zip .
sudo chown $1:$1 ~/export/"${studyinstanceuids[#]}"/"${studyinstanceuids[#]}".zip
sudo mv ~/export/"${studyinstanceuids[#]}"/"${studyinstanceuids[#]}".zip ~/home/"$1"
done
}
zipForOwner $owner
exit;
Does anyone have any suggestions
EDIT: Heere are my results running in xterm
+ file=/home/support/exporttool/zipFiles.txt
+ index=0
+ declare -a studyinstanceuids
+ read line
+ studyinstanceuids[$index]=1.3.46.670589.16.11.8.34254330145.20140603.134057.0
+ index=1
+ echo 1.3.46.670589.16.11.8.34254330145.20140603.134057.0
1.3.46.670589.16.11.8.34254330145.20140603.134057.0
+ read line
+ for i in '"${studyinstanceuids[#]}"'
+ echo 1.3.46.670589.16.11.8.34254330145.20140603.134057.0
+ ./cmd2
Please enter StudyInstanceUID:
+ echo 'Exams are in!'
Exams are in!
+ echo 'What is the name of the owner: '
What is the name of the owner:
+ read
sftpuser
+ zipForOwner
+ arg1=
+ for i in '"${studyinstanceuids[#]}"'
+ zip -r /home/support/export/1.3.46.670589.16.11.8.34254330145.20140603.134057.0/20140620_1.3.46.670589.16.11.8.34254330145.20140603.134057.0.zip .
adding: .studiesToExportSend.txt.swp^C
zip error: Interrupted (aborting)
+ sudo chown : /home/support/export/1.3.46.670589.16.11.8.34254330145.20140603.134057.0/1.3.46.670589.16.11.8.34254330145.20140603.134057.0.zip
[sudo] password for support:
This line is your problem:
zip -r ~/export/"${studyinstanceuids[#]}"/20140620_"${studyinstanceuids[#]}".zip .
You're attempting to create a zip file called ~/export/"${studyinstanceuids[#]}"/20140620_"${studyinstanceuids[#]}".zip (good) with all of the contents in the current directory . (bad).
You need to change the . to be the folder you want zipped.
I have a series of subfolders, each with images on them.
Structure looks like
/stuff/
IMG_012.JPG
IMG_013.JPG
IMG_014.JPG
/morestuff/
IMG_022.JPG
IMG_023.JPG
IMG_024.JPG
I would like to write a script on my mac terminal to loop through each folder and rename the images sequentially including the folder name. So, the above structure would look like:
/stuff/
stuff_1.JPG
stuff_2.JPG
stuff_3.JPG
/morestuff/
morestuff_1.JPG
morestuff_1.JPG
morestuff_1.JPG
I orignally tried creating a Automator workflow and using variables, but had difficulty assigning the folder name as the variable and getting the loop to work.
I'm hoping there is an elegant solution with the terminal.
Any ideas?
This should work nicely for you. Save it in your HOME directory as "RenameImages", then make it executable like this:
cd
chmod +x RenameImages
Then you can run it (-exec) it on every directory (-type d) like this:
find . -type d -exec ./RenameImages {} \;
Here is the script:
#!/bin/bash
# Ignore case, i.e. process *.JPG and *.jpg
shopt -s nocaseglob
shopt -s nullglob
# Go to where the user says
echo Processing directory $1
cd "$1" || exit 1
# Get last part of directory name
here=$(pwd)
dir=${here/*\//}
i=1
for image in *.JPG
do
echo mv "$image" "${dir}${i}.jpg"
((i++))
done
At the moment it does nothing except show you what it would do. If you like what it is doing, simply remove the word echo from the 3rd to last line and run it again.
I would just like to throw out another way to do this since you mentioned you tried using Automator. This file search and process software: http://www.softpedia.com/get/File-managers/JFileProcessor.shtml https://github.com/stant/jfileprocessor
Will let you search for files with glob or regex, in subfolders to X or all depth, by name, size, date. You can save to a List window or file. Then you can run a groovy (think java) script to do whatever you want to the list of files; zip or tar them, modify the list strings like sed, delete, move, copy files, grep or ls -l them, whatever. In your case you can modify an existing groovy example to do something like:
int numItems = defaultComboBoxModel.getSize();
System.out.println( "defaultComboBoxModel.getSize() num of items =" + numItems + "=" );
String str = "";
for( int i = 0; i < numItems; i++ )
{
str = defaultComboBoxModel.getElementAt( i ).toString();
System.out.println( "file of index =" + i + " str =" + str + "=" );
String cmd = "mv " + str + " " + i + ".jpg"; // or whatever
def list = cmd.execute().text // this stuff just captures output and write to a log file
list.eachLine{
outFile << it;
}
outFile << System.getProperty("line.separator") + "-------------------------------------" + System.getProperty("line.separator");
}
It will also let you massage your list like add to, delete from, subtract one list from another.