How to condition route model bindings by actions in RouteServiceProvider - laravel

Question

I have an application which needs to accomplish this in RouteServiceProvider.php:
//in \App\Providers\RouteServiceProvider.php
public function boot(Router $router)
{
//
parent::boot($router);
//somehow can get the current action
$action = $router->getCurrentAction();
if($action == 'edit'){
$router->model('articles','App\Article');
} else{
$router->bind('articles', function($id){
return Article::published()->findOrFail($id);
});
}
}
Here is my route:
Route::resource('articles', 'ArticlesController');
Here is my Controller:
public function show(Article $article){
return view('articles.show',compact('article'));
}
public function edit(Article $article){
return view('articles.edit',compact(['article','tags']));
}
The reason I want to do it because I want show action only shows published articles while edit action can change both published and unpublished articles.
if there is any better solution, please teach me. Thank you !

Answer 1

Why don't you make a middleware, that will work only for 'published' routes, where you will check if your Article is published?

Answer 2

Based in your route, I assume that you have the following paths:
example.com/edit
example.com/3 - article ID
So, you could use a pattern to bind the article:
public function boot(Router $router)
{
parent::boot($router);
// bind
$router->bind('article', function($id){
return Article::published()->findOrFail($id);
});
// id pattern
$router->pattern('id', '[0-9]+');
}
Now, just declare the respective routes:
Route::get('articles', 'ArticlesController#showAll');
Route::get('{id}', 'ArticlesController#edit');
Finally, your controller could looks like this:
class ArticlesController{
public funcion showAll(){
// show a list of articles
}
public function edit(Article $article){
// selected article
}
}
Try to get the best of Laravel using class injection and keeping cleaning code.