Open Facebook profile in app - xcode

Question

I am trying to make that when the user press Facebook button, it opens the Facebook application, or in browser.
Import code:
import Foundation
Extension code:
extension UIApplication {
class func tryURL(urls: [String]) {
let application = UIApplication.sharedApplication()
for url in urls {
if application.canOpenURL(NSURL(string: url)!) {
application.openURL(NSURL(string: url)!)
return
}
}
}
}
Function code:
func fimageTapped()
{
UIApplication.tryURL([
"fb://profile/1357163924", // App
"http://www.facebook.com/1357163924" // Website if app fails
])
}
I get error at line:
class func tryURL(urls: [String]) {
Error message:
Invalid redeclaration of "tryURL"
This is where i found the code from: Xcode swift link to facebook page
Anyone has any idea what is wrong here?

Answer 1

In Swift 3 use this:
let facebookID: String = "000000000000"
let facebookName: String = "name"
let facebookURLID = URL(string: "fb://profile/\(facebookID)")!
let facebookURLWeb = URL(string: "https://m.facebook.com/\(facebookName)?id=\(facebookID)")!
if(UIApplication.shared.canOpenURL(facebookURLID)){
UIApplication.shared.openURL(facebookURLID)
} else {
UIApplication.shared.openURL(facebookURLWeb)
}
Remember that from iOS 9 and 10 you need to declare in the Info.plist:
<key>LSApplicationQueriesSchemes</key>
<array>
<string>fb</string>
</array>
With this the queries for the Facebook schemes will not fail with a permission error:
"This app is not allowed to query for scheme fb"

Answer 2

Used this, worked fine:
var fbURLWeb: NSURL = NSURL(string: "https://www.facebook.com/ID")!
var fbURLID: NSURL = NSURL(string: "fb://profile/ID")!
if(UIApplication.sharedApplication().canOpenURL(fbURLID)){
// FB installed
UIApplication.sharedApplication().openURL(fbURLID)
} else {
// FB is not installed, open in safari
UIApplication.sharedApplication().openURL(fbURLWeb)
}

Answer 3

Swift 3:
Important: UIApplication is declared in UIKit so make sure you import UIKit aswell.
import Foundation
import UIKit
extension UIApplication {
class func tryURL(_ urls: [String]) {
let application = UIApplication.shared
for url in urls {
if application.canOpenURL(URL(string: url)!) {
application.open(URL(string: url)!, options: [:], completionHandler: nil)
return
}
}
}
}
Furthermore:
application.openURL(NSURL(string: url)!)
have in Swift 3 changed to open and with completionHandler:
application.open(URL(string: url)!, options: [:], completionHandler: nil)
Next in your viewController: declare your facebook app and web-urls above viewDidLoad and create a function or IBAction func where you do your UIapplication.tryURL:
import UIKit
class ViewController: UIViewController {
let fbAppUrl = "facebook://profile/yourFBprofileID"
let fbWebUrl = "https://www.facebook.com/yourFBprofileID"
override func viewDidLoad() {
super.viewDidLoad()
}
func openFacebook() {
UIApplication.tryURL([fbAppUrl, fbWebUrl])
}
}
First iOS will try to open the fbAppUrl but if the facebook app is not installed on the device it will open fbWebUrl in Safari instead.

Answer 4

For Swift 4
let webURL: NSURL = NSURL(string: "https://www.facebook.com/ID")!
let IdURL: NSURL = NSURL(string: "fb://profile/ID")!
if(UIApplication.shared.canOpenURL(IdURL as URL)){
// FB installed
UIApplication.shared.open(webURL as URL, options: [:], completionHandler: nil)
} else {
// FB is not installed, open in safari
UIApplication.shared.open(webURL as URL, options: [:], completionHandler: nil)
}