How to get article alias name by using article title in joomla? i want the alias name which one is stored in database.
You can try something like this:
$title = 'Article title'; // Your article title
$db = JFactory::getDbo();
$query = $db->getQuery(true);
$query->select($db->quoteName('alias'))
->from($db->quoteName('#__content'))
->where($db->quoteName('title') . ' = ' . $db->quote($title));
$db->setQuery($query);
try
{
$alias = $db->loadResult(); // variable has now article alias
}
catch (Exception $ex)
{
$alias = null;
}
if ($alias)
{
// Do something with alias
}
Related
I have build my own component in joomla and client wants now a friendly urls f.e
website.com/someplace/{product-id}-{product-name}. So i Build my own router like this.
function componentBuildRoute(&$query)
{
$segments = [];
if (isset($query['view'])) {
$segments[] = "szkolenie";
unset($query['view']);
}
if (isset($query['product_id'])) {
$productName = JFilterOutput::stringURLSafe(strtolower(getProductName($query['product_id'])));
$newName = $query['product_id'] . '-' . $productName;
$segments[] = $newName;
unset($query['product_id']);
}
return $segments;
}
and parse route function
function componentParseRoute($segments)
{
$app = JFactory::getApplication();
$menu = $app->getMenu();
$item =& $menu->getActive();
$count = count($segments);
switch ($item->query['view']) {
case 'catalogue' : {
$view = 'training';
$id = $segments[1];
}
break;
}
$data = [
'view' => $view,
'product_id' => $id
];
return $data;
}
While on the end of buildroute function segments are ok I have exactly what I want that on the beginning of parse route I have something like
website.com/szkolenie/1-krakow <-- I dont know wtf is this krakow( I know it is city i Poland) but still where is it get from ? The getProductName function implementation is
function getProductName($productId)
{
$db = JFactory::getDbo();
$query = $db->getQuery(true);
$query->select('#__component_training.id as id, #__component_product' . name)
->from($db->quoteName('#__component_training'))
->where('#__s4edu_product.product_id = ' . $productId)
->leftJoin('#__component_product ON
#__component_training.product_id=#__component_product.product_id');
$training = $db->loadObject();
return trim($training->name);
}
So taking all this into consideration I think that something is happening between the buildRoute and parseRoute, something what filters the $segment[1] variable, but how to disable that and why is it happening ?
P.S
Please do not send me to https://docs.joomla.org/Joomla_Routes_%26_SEF
I already know all the tutorials on joomla website which contains anything with sef.
P.S.S
It is built on joomla 3.7.0
You do not have a product named "krakow" ?
If not you can try to remove the $productName from the build function, just to check if this "krakow" is added automaticaly or it's from the getProductName() function.
Also i noticed that you have an error i guess in the function getProductName()
->where('#__s4edu_product.product_id = ' . $productId)
It's should be
->where('#__component_product.product_id = ' . $productId)
I am making payment through paypal. After payment completion it redirect to my website(complete.php) page. I have code in complete.php that will update the credit in database. when i refresh the same page then it automatically update credits in database. I want to update credit only when payment is done. The code i am using in complete.php is:
$db = JFactory::getDBO();
$result = null;
$user = JFactory::getUser();
if ($user->guest) {
return false;
}
$query = 'SELECT credit' .
' FROM #__vodes_credits' .
' WHERE userid = ' . (int) $user->id
;
$db->setQuery($query);
$result = $db->loadResult();
$result_final=$result+20;
$query = 'update #__vodes_credits SET credit='.$result_final.
' WHERE userid = ' . (int) $user->id
;
//echo $query;
//echo $query;
$db->setQuery($query);
$result = $db->loadResult();
if ($db->getErrorNum()) {
JError::raiseWarning( 500, $db->stderr());
}
return $result;
?>
Please help me to sought it out.
I recommend you to create a COOKIE before the payment and then destroy that COOKIE after the first time the user has visited the complete.php, that will work.
Regards.
In case you want to redirect, I am not sure where are you writing your code but try the below code
$app=JFactory::getApplication();
$app->setRedirect('url','msg');
How to use:
JFactory::getDbo()->insertObject('#__card_bonus', $object);
with on duplicate key update ?
You have a few options:
1) Check for an entity id. This is my preferred option, because it only uses a single query, is reusable for any object, and is database agnostic - meaning it will work on whichever DBMS you choose, whereas the other two options are exclusive to MySQL.
if (isset($object->id)) {
$db->updateObject('#__card_bonus', $object);
}
else {
$db->insertObject('#__card_bonus', $object, 'id');
}
I often create an abstract model with a save(stdClass $object) method that does this check so I don't have to duplicate it.
2) Write your own query using the MySQL ON DUPLICATE KEY UPDATE syntax, which is a proprietary extension to the SQL standard, that you have demonstrated understanding of.
3) Write your own query using MySQL's proprietary REPLACE INTO extension.
<?php
$jarticle = new stdClass();
$jarticle->id = 1544;
$jarticle->title = 'New article';
$jarticle->alias = JFilterOutput::stringURLSafe($jarticle->title);
$jarticle->introtext = '<p>re</p>';
$jarticle->state = 1;
$jarticle->catid = 13;
$jarticle->created_by = 111;
$jarticle->access = 1;
$jarticle->language = '*';
$db = JFactory::getDbo();
try {
$query = $db->getQuery(true);
$result = JFactory::getDbo()->insertObject('#__content', $jarticle);
}
catch (Exception $e){
$result = JFactory::getDbo()->updateObject('#__content', $jarticle, 'id');
}
I use this method - are not fully satisfied, but ...
or for not object method:
$query = $db->getQuery(true);
$columns = array('username', 'password');
$values = array($db->quote($username), $db->quote($password));
$query
->insert($db->quoteName('#__db_name'))
->columns($db->quoteName($columns))
->values(implode(',', $values));
$query .= ' ON DUPLICATE KEY UPDATE ' . $db->quoteName('password') . ' = ' . $db->quote($password);
$db->setQuery($query);
JFactory::getDbo()->insertObject('#__card_bonus', $object, $keyName);
The name of the primary key. If provided the object property is updated.
Joomla doc ...
How i can get some parameters from a disabled/not yet actived plugin in joomla 1.6/2.5?
$module = JPluginHelper::getPlugin('system','myplugin');
$moduleParams = new JParameter($module->params);
$val = $moduleParams->get("key");
This method didn't work becouse i need to use within an element JFormField generator.
Thanks for help!
With JPluginHelper::getPlugin it's possible to access only enabled plugins, so here's the code for direct access to database.
// Build query
$db = JFactory::getDbo();
$query = $db->getQuery(true);
$query
->select( 'params' )
->from( '#__extensions' )
->where( 'type = ' . $db->q('plugin') )
->where( 'folder = ' . $db->q('authentication') ) // Plugin type
->where( 'element = ' . $db->q('gmail') ) // Plugin element
;
// Execute query
$db->setQuery($query);
try
{
$result = $db->loadResult();
}
catch (RuntimeException $e)
{
return false;
}
// Parse parameters
if (!empty($result))
{
$params = new JRegistry($result);
$val = $params->get('key', 'defaultValue');
}
You may store query results in in the JFormField Object so save database queries in case field is availabile multiple times.
protected $results = null;
Perhaps you may want to try this:
// Get plugin parameters
$db = JFactory::getDBO();
$query = $db->getQuery(true);
$query->select('`params`')
->from ('`#__extensions`')
->where ("`type` = 'plugin'")
->where ("`folder` = 'system'")
->where ("`element` = 'myplugin'");
$db->setQuery($query);
$res = json_decode($db->loadResult(), true);
$val = $res['key'];
Just find the answer by myself.
$data = null;
foreach ((array) $this->form as $k => $v) {
if($val instanceof JRegistry){
$data = &$v;
break;
}
}
$data = $data->toArray();
$val = $data['params']['key'];
Thanks! Bye!
I have this simple code to select custom string from database:
protected function getListQuery()
{
$db = JFactory::getDBO();
$query = $db->getQuery(true);
$query->select('*')
->from('#__person');
$name = 'tom';
$query->where('name LIKE %'.$db->quote($name).'%');
return $query;
}
Unfortunately it gives me an error:
Warning: mysql_num_rows() expects parameter 1 to be resource, boolean
given in xxx\public\libraries\joomla\database\database\mysql.php on
line 293
If I remove where call, so everything goes ok. Can I debug the datase query? I would like to see whats the final query goes to MySQL server.
Your help would be appreciated.
I've managed to work this for me:
protected function getListQuery()
{
$db = JFactory::getDBO();
$query = $db->getQuery(true);
$query->select('*')
->from('#__person');
$name = 'tom';
$name = $db->Quote('%'.$db->escape($name, true).'%');
$query->where($db->nameQuote('name').' LIKE '.$name);
//debug the query
// echo nl2br(str_replace('#__','prefix_',$query)); die;
return $query;
}