I have a folder work and the below script searches for .txt or .csv files and moves the files into completed folder. I created one more folder (APEX) inside work folder, but the files from APEX folder are not moving to the completed folder and giving below error. I would like all the .txt or .csv files in my-test-folder/work and my-test-folder/work/APEX files to be moved to my-test-folder/done.I do not have a folder /my-test-folder/completed/APEX/ ,nor I want the files to be moved there.
Error : mv: cannot move ./my-test-folder/work/APEX/test1.txt to ./my-test-folder/completed/APEX/test1.txt: No such file or directory
find . -path "*work*" \( -iname "*.txt" -o -iname "*.csv" \) -exec bash -c "mv {} \`echo {} | sed -e 's/work/completed/g' \` " \;
If you don't want to keep the same directory hierarchy in my-test-folder/completed as in my-test-folder/work, you can simplify your command:
find full/path/to/work -iname "*.txt" -o -iname "*.csv" -exec mv "{}" full/path/to/completed \;
Note that this will not remove empty directories left after moving all the files out. You can do this if you are using GNU find with the following command:
find work -empty -delete
Related
I want to write a shell script to do the following :
I have a folder with many subfolders. Each of these subfolders has a *.gz file and some other files which I don't need. I want to move all .gz files into a new subfolder called needed_files (I have already created this subfolder). So I did the following :
I went to the parent folder with all the subfolder and cp /.gz > needed_files/., but this did not work. Can you suggest what I should be doing?
grep is irrelevant here. Use find:
find . ! \( -type d -name needed_files -prune \) -type f -name '*.gz' \
-exec echo mv -t needed_files {} +
POSIX equivalent of that -exec is
-exec sh -c 'echo mv "$#" needed_files' _ {} +
If its output looks good, remove echo.
Btw I noticed that the title says copy but you also say I want to move, so decide on what you exactly want to do and let me know so I can edit my answer.
I have files of type mp3 and flac. Lets say my basic directory structure is
/music/artist/album
I have (already) made
/music/artist/album/flac/
/music/artist/album/mp3/
with a recursive batch operation.
I want to loop through all of /music/ and do the following:
If /music/artist/album/ has mp3s, move them to /music/artist/album/mp3/.
If /music/artist/album/ has flacs, move them to /music/artist/album/flac/.
Some folders have mp3 and flac. Looking for either script file or command line solutions
find /music/ -name '*.mp3' -execdir mv {} mp3/ \;
find /music/ -name '*.flac' -execdir mv {} flac/ \;
-execdir runs the specified command in the directory of the current file. This lets you use mp3/ and flac/ directories relative to the current artist/album.
Here you have one way to do it :
find /music -type f -name "*.mp3" | xargs mv $1 /music/artist/album/mp3/
find /music -type f -name "*.flac" | xargs mv $1 /music/artist/album/flac/
Hope it works for you.
Greetings!
Change the current directory to where your music files are, then move mp3s to the mp3 folder and flacs to the flac folder.
cd /music/artist/album/
mv *.mp3 mp3/
mv *.flac flac/
I want to delete all files and sub directories created by using the specified files. I am currently using the command to delete files and directories
find . ! -name file.txt -type d -exec rm -r {} + #this is for sub directories
find . ! -name file.txt -type f -exec rm -f {} + #this is for files
It deletes all the files and sub directories when I run these command twice but I want to delete all files and directories created leaving one file at once sort. Any help is highly appreciable.
Regards
Jitendra
GNU find can directly delete files and directories:
find ! -name file.txt -delete
It will give error messages, because it cannot delete the directories up to file.txt, but everything else will still be deleted.
If you want to keep the files file1.txt, file2.txt, and file3.txt, chain the conditions like this:
find ! \( -name file1.txt -o -name file2.txt -o -name file3.txt \) -delete
I have a folder with tens of thousands of different file types. Id like to copy them all to a new folder (Copy1) but also rename them all to $RANDOM but keep the extension intact. I realize I can write a line specifying which extension to find and how to name it, but there is got to be a way to do it dynamically, because there are at least 100 file types and may be more in the future.
I have the following so far:
find ./ -name '*.*' -type f -exec bash -c 'cp "$1" "${1/\/123_//_$RANDOM}"' -- {} \;
but that puts the random number after the extension, and also it puts the all in the same folder. I cant figure out how to do the following 2 things:
1 - Keep all paths intact, but in a new root folder (Copy1)
2 - How to have name be $RANDOM.extension, instead of .extension.$RANDOM
PS - by $RANDOM i mean actual randomly generated number. I am interested in keeping folder structure, so we are dealing with a few hundred files at most per directory, but all directories/files need to be renamed to $RANDOM. Another way to look at what I need to do. Copy all contents or Folder1 with all subdirectories and files to Folder2 (where Fodler2 is a $RANDOM name), then rename all folders and files to random names but keep all extensions.
EDIT: Ok i figured out how to rename and keep extension. But I have a problem where its dumping all of the files into the root directory where script is run from. How do I keep them in their respective folders? Command Im using is:
find ./ -name '*.*' -type f -exec bash -c 'mv "$1" $RANDOM.${1##*.}' -- {} \;
Thanks!
Ok i figured out how to rename and keep extension. But I have a
problem where its dumping all of the files into the root directory
where script is run from. How do I keep them in their respective
folders? Command Im using is:
find ./ -name '*.*' -type f -exec bash -c 'mv "$1" $RANDOM.${1##*.}' -- {} \;
Change your command to:
PATH=/bin:/usr/bin find . -name '*.*' -type f -execdir bash -c 'mv "$1" $RANDOM.${1##*.}' -- {} \;
Or alternatively using uuids instead of random numbers:
PATH=/bin:/usr/bin find . -name '*.*' -type f -execdir bash -c 'mv "$1" $(uuidgen).${1##*.}' -- {} \;
Here's what I came up with :
i=1
random="whatever"
find . -name "*.*" -type f | while read f
do
newbase=${f/*./$random$i.} //added counter to filename
cp $f /Path/Name/"$newbase"
((i++))
done
I had to add a counter to random (i), otherwise, if the extensions are similar, your files would overwrite themselves when copied.
In your new folder, your files should look like this :
whatever1.txt
whatever2.txt
etc etc
I hope this is what you were looking for.
Here is the command that worked for me.
find . -name '*.pdf' -type f -exec bash -c 'echo "{}" && cp "$1" ./$RANDOM.${1##*.}' -- {} \;
I've so far figured out how to use find to recursively unzip all the files:
find . -depth -name `*.zip` -exec /usr/bin/unzip -n {} \;
But, I can't figure out how to remove the zip files one at a time after the extraction. Adding rm *.zip in an -a -exec ends up deleting most of the zip files in each directory before they are extracted. Piping through a script containing the rm command (with -i enabled for testing) causes find to not find any *.zips (or at least that's what it complains). There is, of course, whitespace in many of the filenames but at this point syntaxing in a sed command to add _'s is a bit beyond me. Thank for your help!
have you tried:
find . -depth -name '*.zip' -exec /usr/bin/unzip -n {} \; -exec rm {} \;
or
find . -depth -name '*.zip' -exec /usr/bin/unzip -n {} \; -delete
or running a second find after the unzip one
find . -depth -name '*.zip' -exec rm {} \;
thx for the 2nd command with -delete! helped me a lot..
just 2 (maybe helpful) remarks from my side:
-had to use '.zip' instead of `.zip` on my debian system
-use -execdir instead of -exec > this will extract each zip file within its current folder, otherwise you end up with all extracted content in the dir you invoked the find cmd.
find . -depth -name '*.zip' -execdir /usr/bin/unzip -n {} \; -delete
THX & Regards,
Nord
As mentioned above, this should work.
find . -depth -name '*.zip' -execdir unzip -n {} \; -delete
However, note two things:
The -n option instructs unzip to not overwrite existing files. You may not know if the zip files differ from the similarly named target files. Even so, the -delete will remove the zip file.
If unzip can't unzip the file--say because of an error--it might still delete it. The command will certainly remove it if -exec rm {} \; is used in place of -delete.
A safer solution might be to move the files following the unzip to a separate directory that you can trash when you're sure you have extracted all the files successfully.
Unzip archives in subdir based on the file name (../file.zip -> ../file/..):
for F in $(find . -depth -name *.zip); do unzip "$F" -d "${F%.*}/" && rm "$F"; done
I have a directory filling up with zipped csv files. External processes are writing new zipped files to it often. I wish to bulk unzip and remove the originals as you do.
To do that I use:
unzip '*.zip'
find . | sed 's/$/\.zip/g' | xargs -n 1 rm
It works by searching and expanding all zip files presently in the directory. Later, after it finishes there are potentially new unzipped new files mixed in there too that are not to be deleted yet.
So I delete by finding successfully unzipped *.csv files, and using sed to regenerate the original filenames for deletion which is then fed to rm via the xargs command.